turn array columns into rows ruby [closed] - arrays

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I have an array of arrays called puzzle and I'm trying to return a new array with the first array consisting of
["a", "s", "i", "o", "s", "u", "z"]
Then the next array consisting of the array"s second index
["k", "o", "t", "t", "e", "r", "s"]
etc etc. What are some good ways to do this. I was thinking of using map and two counters but could not get them to operate or or increase at different times properly. Any help would be awesome. Thanks!
I want to return a new array from this puzzle:
puzzle = [
["a", "k", "f", "o", "x", "e", "s"],
["s", "o", "a", "w", "a", "h", "p"],
["i", "t", "c", "k", "e", "t", "n"],
["o", "t", "s", "d", "h", "o", "h"],
["s", "e", "x", "g", "s", "t", "a"],
["u", "r", "p", "i", "w", "e", "u"],
["z", "s", "b", "n", "u", "i", "r"]
]

Answer 1

Array#transpose is there for you:
puzzle = [
["a", "k", "f", "o", "x", "e", "s"],
["s", "o", "a", "w", "a", "h", "p"],
["i", "t", "c", "k", "e", "t", "n"],
["o", "t", "s", "d", "h", "o", "h"],
["s", "e", "x", "g", "s", "t", "a"],
["u", "r", "p", "i", "w", "e", "u"],
["z", "s", "b", "n", "u", "i", "r"]
]
puzzle.transpose
# => [["a", "s", "i", "o", "s", "u", "z"],
# ["k", "o", "t", "t", "e", "r", "s"],
# ["f", "a", "c", "s", "x", "p", "b"],
# ["o", "w", "k", "d", "g", "i", "n"],
# ["x", "a", "e", "h", "s", "w", "u"],
# ["e", "h", "t", "o", "t", "e", "i"],
# ["s", "p", "n", "h", "a", "u", "r"]]

Answer 2

class Array
def my_transpose!
size.times do |i|
0.upto(i) do |j| # iterate only through lower half
self[i][j], self[j][i] = self[j][i], self[i][j] # swap rows and cols
end
end
self # return the array itself
end
def my_transpose
dup.map(&:dup).my_transpose! # inner arrays are dup'ed, too
end
end
OR if you don't need a mutator....
.transpose method then pick the array you want with []
puzzle.transpose[0]
The [0] says give me the first result.
puzzle.transpose[0]
=> ["a", "s", "i", "o", "s", "u", "z"]
puzzle.transpose[1]
=> ["k", "o", "t", "t", "e", "r", "s"]