I have this selector:
$this->Table->find('list',array('contain'=>false,'conditions'=>array('status'=>1,'unit_id'=>null,'country_id'=>$countryId,'eday'=>$eday),'fields'=>'id'));
And this works perfect. But now i need to have another one i cant find how to do this ;)
I need to select all records from Table but with condition:
'eday'>=$eday AND 'eday'<$eday+7
Its this posibble in easy way? Maybe this is stupid question but i dont have exp in PHP ;)
In cakephp the equivalent for and condition is
Example: column1 = 'value' AND column2 = 'value'
'AND' => array(
'column1' => 'value',
'column2' => 'value'
)
So your query builder would be like this
$this->Table->find('list',array(
'contain' => false,
'conditions' => array(
'status' => 1,
'unit_id' => null,
'country_id' => $country,
'AND' => array(
'eday >=' => $eday,
'eday <' => ($eday+7)
)
),
'fields'=>'id'
));
Just pass an AND array with in your current conditions array :
$this->Table->find('list',array('contain'=>false, 'conditions'=>array('status'=>1,'unit_id'=>null,'country_id'=>$countryId,'eday'=>$eday, AND => array( array('eday >=' => $eday) , array( 'eday <' => $eday+7) )), 'fields'=>'id' ));
Have you tried something like this :
$conditions['status'] = 1;
$conditions['unit_id'] = null;
$conditions['country_id'] = $countryId;
$conditions['eday >='] = $eday;
$conditions['eday <'] = $eday + 7;
$this->Table
->find('list') //either use this
->find('all') //or use this
->find() //or this
->where($conditions)
->select(['addFiledsToSelectHere'])
This looks more cleaner.
What's the CakePHP way to do such queries?
SELECT news.* FROM news, users
INNER JOIN news_users nu ON nu.user_id = users.id
WHERE users.id = $user_id
I have a link table news_users, so trying with something like $news = $this->News->findByUserId($this->User->id); does not work, because it looks for news.user_id
P.S. The above query works, I just desire to make the script shorter.
You can declare findByUserId function in your News model:
//put this code in your News model
public function findByUserId($user_id = null)
{
return $this->find('all', array(
'conditions' => array(
'NewsUser.user_id' => $user_id
),
'joins' => array(
array(
'table' => 'news_users',
'alias' => 'NewsUser',
'type' => 'INNER',
'conditions' => array(
'NewsUser.news_id = News.id'
)
)
)
));
}
Then you can use your findByUserId function enywhere in your NewsController
//this code in NewsController
$news = $this->News->findByUserId($this->User->id);
How we can write Join query using two table with where condition in cake php?
You can!!
check this if it would help you
$table = 'table_name';
$query['conditions'] = array($table.'.entity_id' => $entity_id, $table.'.is_active' => 1);
$query['fields'] = array('creator.first_name AS cf_name', 'creator.last_name AS cl_name', 'creator.email AS c_email', 'usr.first_name', 'usr.last_name',
$table.'.id AS id', $table.'.guid', $table.'.updated_date',
'usr.email AS email');
// To do joining to get attribute with value
$query['joins'] = array(
array(
'table' => $this->user,
'alias' => 'usr',
'type' => 'INNER',
'conditions' => array('usr.id = '.$table.'.user_id')
),
array(
'table' => $this->user,
'alias' => 'creator',
'type' => 'INNER',
'conditions' => array('creator.id = '.$table.'.creator_id')
),
);
$query['order'] = array($table.'.updated_date' => 'DESC');
// Cache implementation
$result = $this->find('all', $query);
I am struggeling with a custom find in cakephp 2.1.
In my model I have this function:
public function findByGenres($data = array()) {
$this->Item2genre->Behaviors->attach('Containable', array('autoFields' => false));
$this->Item2genre->Behaviors->attach('Search.Searchable');
$query = $this->Item2genre->getQuery('all', array(
'conditions' => array('Genre.name' => $data['genre']),
'fields' => array('item_id'),
'contain' => array('Genre')
));
return $query;
}
This returns the following query:
SELECT `Item`.`id` FROM `items` AS `Item`
WHERE `Item`.`id`
IN(SELECT `Item2genre`.`item_id` FROM `item2genre` AS Item2genre
LEFT JOIN `genres` AS Genre ON(`genre_id` = `Genre`.`id`)
WHERE `Genre`.`name`
IN ('Comedy', 'Thriller')
)
The result of the query returns Items with either 'Comedy' or 'Thriller' genre associated to them.
How can I modify the query to only return Items with 'Comedy' AND 'Thriller' genre associated to them?
Any suggestions?
edit:
content of data is:
'genre' => array(
(int) 0 => 'Comedy',
(int) 1 => 'Thriller'
)
You would want your 'conditions' key to be this:
'conditions' => array(
array('Genre.name' => 'Comedy'),
array('Genre.name' => 'Thriller')
)
So specifically to your problem your $data['genre'] is array('Comedy', 'Thriller'). So you could create a variable that has contents similar to what you need by doing:
$conditions = array();
foreach ($data['genre'] as $genre) {
$conditions[] = array('Genre.name' => $genre);
}
I've been working with cakephp paginations options for 2 days. I need to make a INNER Joins to list a few fields, but I have to deal with search to filter results.
This is portion of code in which I deal with search options by $this->passedArgs
function crediti() {
if(isset($this->passedArgs['Search.cognome'])) {
debug($this->passedArgs);
$this->paginate['conditions'][]['Member.cognome LIKE'] = str_replace('*','%',$this->passedArgs['Search.cognome']);
}
if(isset($this->passedArgs['Search.nome'])) {
$this->paginate['conditions'][]['Member.nome LIKE'] = str_replace('*','%',$this->passedArgs['Search.nome']);
}
and after
$this->paginate = array(
'joins' => array(array('table'=> 'reservations',
'type' => 'INNER',
'alias' => 'Reservation',
'conditions' => array('Reservation.member_id = Member.id','Member.totcrediti > 0' ))),
'limit' => 10);
$this->Member->recursive = -1;
$this->paginate['conditions'][]['Reservation.pagamento_verificato'] = 'SI';
$this->paginate['fields'] = array('DISTINCT Member.id','Member.nome','Member.cognome','Member.totcrediti');
$members = $this->paginate('Member');
$this->set(compact('members'));
INNER JOIN works good, but $this->paginations ignore every $this->paginate['conditions'][] by $this->passedArgs and I cannot have idea how I can work it out.
No query in debug, just the original INNER JOIN.
Can someone helps me ?
Thank you very much
Update:
No luck about it.
I've been dealing with this part of code for many hours.
If I use
if(isset($this->passedArgs['Search.cognome'])) {
$this->paginate['conditions'][]['Member.cognome LIKE'] = str_replace('*','%',$this->passedArgs['Search.cognome']);
}
$this->paginate['conditions'][]['Member.sospeso'] = 'SI';
$this->Member->recursive = 0;
$this->paginate['fields'] = array(
'Member.id','Member.nome','Member.cognome','Member.codice_fiscale','Member.sesso','Member.region_id',
'Member.district_id','Member.city_id','Member.date','Member.sospeso','Region.name','District.name','City.name');
$sospesi = $this->paginate('Member');
everything goes well, and from debug I receive the first condition and the conditions from $this->paginate['conditions'][]['Member.cognome LIKE'], as you can see
array $this->passedArgs
Array
(
[Search.cognome] => aiello
)
Array $this->paginate['conditions'][]
(
[0] => Array
(
[Member.cognome LIKE] => aiello
)
[1] => Array
(
[Member.sospeso] => NO
)
But, if I write the joins with paginate , $this->paginate['conditions'][] will ignore all the stuff, and give me from debug, just $this->paginate['conditions'][]['Reservation.pagamento_verificato'] = 'SI';
Another bit of information.
If I put all the stuff dealing with $this->paginate['conditions'][]['Reservation.pagamento_verificato'] = 'SI';
before the $this->paginate JOIN, nothing will be in $this->paginate['conditions'][].
This is an old question, so I'll just review how to do a JOIN in a paginate for others who got here from Google like I did. Here's the sample code from the Widget's Controller, joining a Widget.user_id FK to a User.id column, only showing the current user (in conditions):
// Limit widgets shown to only those owned by the user.
$this->paginate = array(
'conditions' => array('User.id' => $this->Auth->user('id')),
'joins' => array(
array(
'alias' => 'User',
'table' => 'users',
'type' => 'INNER',
'conditions' => '`User`.`id` = `Widget`.`user_id`'
)
),
'limit' => 20,
'order' => array(
'created' => 'desc'
)
);
$this->set( 'widgets', $this->paginate( $this->Widget ) );
This makes a query similar to:
SELECT widgets.* FROM widgets
INNER JOIN users ON widgets.user_id = users.id
WHERE users.id = {current user id}
And still paginates.
I'm not sure if you need those [] - try just doing this:
$this->paginate['conditions']['Reservation.pagamento_verificato'] = 'SI';
I use the conditions when I call paginate method.
$this->paginate($conditions)
This works ok for me, I hope it works for you!
If you have setted previous params, you may use:
$this->paginate(null,$conditions)
This might be help full to someone....
This is how I did complicated joins with pagination in cakephp.
$parsedConditions['`Assessment`.`showme`'] = 1;
$parsedConditions['`Assessment`.`recruiter_id`'] = $user_id;
$this->paginate = array(
'conditions' => array($parsedConditions ),
'joins' => array(
array(
'alias' => 'UserTest',
'table' => 'user_tests',
'type' => 'LEFT',
'conditions' => '`UserTest`.`user_id` = `Assessment`.`testuser_id`'
),
array(
'alias' => 'RecruiterUser',
'table' => 'users',
'type' => 'LEFT',
'conditions' => '`Assessment`.`recruiter_id` = `RecruiterUser`.`id`'
)
,
array(
'alias' => 'OwnerUser',
'table' => 'users',
'type' => 'LEFT',
'conditions' => '`Assessment`.`owner_id` = `OwnerUser`.`id`'
)
),
'fields' => array('Assessment.id', 'Assessment.recruiter_id', 'Assessment.owner_id', 'Assessment.master_id', 'Assessment.title', 'Assessment.status', 'Assessment.setuptype','Assessment.linkkey', 'Assessment.review', 'Assessment.testuser_email', 'Assessment.counttype_2', 'Assessment.bookedtime', 'Assessment.textqstatus', 'Assessment.overallperc', 'UserTest.user_id', 'UserTest.fname', 'UserTest.lname', 'RecruiterUser.company_name', 'OwnerUser.company_name'),
'limit' => $limit,
'order'=> array('Assessment.endtime' => 'desc')
);