TSQL Accumulate rows every monday with distinct rows - sql-server

Question

I'm trying to get a query that returns customers I've attended per day, and i have this dataset:
fecha RecargadorPDV
2016/12/19 1
2016/12/19 2
2016/12/19 3
2016/12/20 1
2016/12/20 4
2016/12/20 5
2016/12/21 2
2016/12/21 6
2016/12/21 7
2016/12/21 8
..
...
2016/12/26 1
2016/12/26 2
2016/12/26 1
2016/12/27 2
2016/12/27 6
2016/12/27 7
2016/12/27 8
but the output I'd want to have is this:
date attended acum_customers
2016/12/19 3 3 -- Every monday it restart
2016/12/20 3 5
2016/12/21 4 8
.
..
2016/12/26 3 3 -- Every monday it restart
2016/12/27 4 3
.
..
As you can see, every monday it restart the values and if some customers are in a date and in the next day are present it needs to be ignored.

Answer 1

Here is a version that returns what you need for any arbitrary date. I have included sample data for a full week + two days to confirm its functionality.
DECLARE #t table (fecha date,
RecargadorPDV int
)
INSERT INTO #t VALUES
('2016/12/19', 1),
('2016/12/19', 2),
('2016/12/19', 3),
('2016/12/20', 1),
('2016/12/20', 4),
('2016/12/20', 5),
('2016/12/21', 2),
('2016/12/21', 6),
('2016/12/21', 7),
('2016/12/21', 8),
('20161222', 12),
('20161222', 1),
('20161222', 8),
('20161223', 11),
('20161223', 13),
('20161223', 15),
('20161223', 9),
('20161224', 1),
('20161225', 22),
('2016/12/26', 1),
('2016/12/26', 2),
('2016/12/26', 1),
('2016/12/27', 2),
('2016/12/27', 6),
('2016/12/27', 7),
('2016/12/27', 8)
;
With a as (
SELECT DISTINCT
fecha,
Dateadd(day, -(
case
when datepart(weekday, fecha) >=2
THEN datepart(weekday, fecha) - 2
ELSE 6
END), fecha) as LastMonday
FROM #t
)
SELECT
a.fecha as [date],
-- count(Distinct(CASE when t.fecha = a.fecha Then t.recargadorPDV else -1 END)) - 1 as attended,
SUM(CASE when t.fecha = a.fecha Then 1 else 0 END) as attended,
Count(distinct recargadorPDV) as acum_customers
FROM #t t
INNER JOIN a
ON t.fecha BETWEEN a.LastMonday and a.fecha
Group by a.fecha
ORDER BY a.fecha
Output of the above (as corrected) is:
date attended acum_customers
2016-12-19 3 3
2016-12-20 3 5
2016-12-21 4 8
2016-12-22 3 9
2016-12-23 4 13
2016-12-24 1 13
2016-12-25 1 14
2016-12-26 3 2
2016-12-27 4 5

Answer 2

I think your second week acum_customers is off based off the test data so check on that. I also assumed that the recargadorPDVcould only attend once per day since it's unique so I removed the one record noted below. With that... this should get you what you want. Let me know if it needs more explanation.
--change the ##DATEFIRST from 7 (english default) to 1 for the start of the week calculations
SET DATEFIRST 1;
--load some test data
declare #table table (fetcha datetime, recargadorPDV int)
insert into #table(fetcha, recargadorPDV)
values
('2016/12/19',1),
('2016/12/19',2),
('2016/12/19',3),
('2016/12/20',1),
('2016/12/20',4),
('2016/12/20',5),
('2016/12/21',2),
('2016/12/21',6),
('2016/12/21',7),
('2016/12/21',8),
--this is the break in the weeks
('2016/12/26',1),
('2016/12/26',2),
--('2016/12/26',1), -- removed this value since a unique ID shouldn't be allowed to attend twice for a single day
('2016/12/27',2),
('2016/12/27',6),
('2016/12/27',7),
('2016/12/27',8)
--temp table to hold some aggregated data
if object_id('tempdb..#tempT') is not null drop table #tempT
select
y.YR
,y.WK
,y.fetcha
,count(y.recargadorPDV) as attend
,sum(y.CTforWK) as accum
into #tempT
from(
select x.*
from
(select
fetcha
,recargadorPDV
,datepart(yy,fetcha) as YR
,datepart(wk,fetcha) as WK
--the case statment is my way of assigning 1 to each recargadorPDV ONLY once for each week so the running total is correct, ignoring duplicates as you stated
,case when count(recargadorPDV) over (partition by datepart(yy,fetcha), datepart(wk,fetcha), recargadorPDV order by fetcha) = 1 then 1 else 0 end as CTforWK
from #table) x) y
group by
y.YR
,y.WK
,y.fetcha
--see the inital results without the running total
select * from #tempT
--see the final results with the running total
select
a.fetcha
,a.attend
,sum(x.accum) as acum_customers
from #tempT a
inner join #tempT x on x.fetcha <= a.fetcha and x.YR = a.YR and x.WK = a.WK
group by a.fetcha, a.attend
order by a.fetcha
--change back the ##DATEFIRST setting
SET DATEFIRST 7;