Batch column search / replace user input - batch-file

Question

I need to get a batch file running, which helps our employees to change text files without trouble.
As you can see, there are a lot of whit space in this file and they need to be there, otherwise it could not be imported in other programs.
My question: Is it possible to search for a specific column and replace this value with an user input?
I've tried to get something done with help of google and this was the result:
#echo off
for /f "skip=5 delims=" %%a in (Muster.dat) do set "var=%%a"&goto :done
:done
set "R_sph=%var:~126,5%"
echo R_sph: %R_sph%
set /p R_sph_new=Enter new sph:
echo R_sph neu: %R_sph_new%
set "search=R_sph"
set "replace=R_sph_new"
set "textfile=Muster.dat"
set "newfile=Muster2.dat"
(for /f "delims=" %%i in (%textfile%) do (
set "line=%%i"
setlocal enabledelayedexpansion
set "line=!line:%search%=%replace%!"
echo(!line!
endlocal
))>"%newfile%"
del %textfile%
rename %newfile% %textfile%
pause
PS: My batch experience is worse and it would be great to explain every step in the code you send me.
Edit: We generate a lot of files like this every day and only some of them need so be edited. The construction of this files is always the same but with other values so it's important so search via column.

Answer 1

Change the main loop in your batch file so that:
it only changes the 6th line;
it only changes the 5 characters from position 126 to 130.
And just to make the batch script more robust, you can also validate user input to ensure that they've entered exactly 5 characters as the replacement string.
Here's the whole file with suggested changes:
#echo off
setlocal enabledelayedexpansion
for /f "skip=5 delims=" %%a in (Muster.dat) do set "var=%%a"&goto :done
:done
set "R_sph=%var:~126,5%"
echo R_sph: %R_sph%
set /p R_sph_new=Enter new sph:
echo R_sph neu: %R_sph_new%
rem Validate user input - ensure it's exactly 5 characters
set "replace=%R_sph_new% "
set "replace=%replace:~0,5%"
if not "%R_sph_new%" == "%replace%" (
echo Don't be silly.
exit /b 1
)
set "textfile=Muster.dat"
set "newfile=Muster2.dat"
set /a lineNumber = 0
(for /f "delims=" %%i in (%textfile%) do (
set /a lineNumber += 1
set "line=%%i"
if !lineNumber! == 6 set "line=!line:~0,126!%replace%!line:~131!"
echo(!line!
))>"%newfile%"
rem It might be safer to rename %textfile% to %textfile%.BAK instead of deleting it.
del %textfile%
rename %newfile% %textfile%
endlocal
pause

Answer 2

set "search=R_sph"
set "replace=R_sph_new"
should
set "search=%R_sph%"
set "replace=%R_sph_new%"
that is, set the values of search and replace to the contents of the variables. Your code sets search to the string R_sph.
? Are you sure that the value in R_sph will be unique in your file?

Answer 3

Thank you very much Klitos Kyriacou, that's exactly what I was looking for!
But unfortunately this batch does not change anything in this text file, the whole code looks like this:
#echo off
:R_sph
for /f "skip=5 delims=" %%a in (Muster.dat) do set "var=%%a"&goto :done
:done
set "R_sph=%var:~49,5%"
echo R_sph: %R_sph%
set /p R_sph_new=Enter new sph:
set "replace=%R_sph_new%"
set "textfile=Muster.dat"
set "newfile=Muster2.dat"
setlocal enabledelayedexpansion
set /a lineNumber = 0
(for /f "delims=" %%i in (%textfile%) do (
set /a lineNumber += 1
set "line=%%i"
if !lineNumber! == 6 set "line=!line:~0,49!%replace%!line:~54!"
echo(!line!
))>"%newfile%"
endlocal
:replace file
del %textfile%
rename %newfile% %textfile%
pause
Edit: I was in hurry and dind't get how to set it up. Now I changed the code and it's working!