SQL Distinct function din't work - sql-server

Question

Here i have a table called tblemployee which consists id,name and salary column.The name and salary column consists five rows, name column consists 3 different name (i.e each name in name column does not match with another name) while the salary column consists the same integer value (i.e 40,000 in each row of salary column).
Table tblemployee structure
name|salary
-----------
max |40000
rob |40000
jon |40000
Now what i want is that, i want all the names from name column but only one salary value from salary column as shown below:
name|salary
-----------
max |40000
rob |
jon |
Sql Server query i have tried which didn't give the expected output
select DISTINCT salary,name from tblabca

Answer 1

Declare #tblemployee table (name varchar(25),salary int)
Insert Into #tblemployee values
('max',40000),
('rob',40000),
('jon',40000),
('joseph',25000),
('mary',25000)
Select Name
,Salary = case when RN=1 then cast(Salary as varchar(25)) else '' end
From (
Select *
,RN = Row_Number() over (Partition By Salary Order By Name)
,DR = Dense_Rank() over (Order By Salary)
From #tblemployee
) A
Order by DR Desc,RN
Returns
Name Salary
jon 40000
max
rob
joseph 25000
mary

Answer 2

"GROUP BY" and group_concat would suit your case. Please try like this
select salary, group_concat(name) from tblabca group by salary;
Reference: GROUP BY, GROUP_CONCAT

Answer 3

You will never get the result as you stated. Because DISTINCT operator works on a SET. not on individual column. In a relational database you will only work with sets.
So the combination of Salary and Name will be treated as Distinct.
But if you want you can get names in comma concatenated list like below
SELECT SALARY
, STUFF ((SELECT ','+NAME From TableA T2
WHERE T1.SALARY = T2.SALARY FOR XML PATH('')
),1,1,'') FROM TABLEA T1

Answer 4

As others already stated, you are definately not looking for DISTINCT operator.
The distinct operator will work upon the entire result set, meaning you'll get result rows that are unique (column by column).
Although with some rework you might end up with the result you want, do you really want the result in such a not uniform way? I mean, getting a list of names on the name column and only one salary on the salary column do not look like a nice result set to work with.
Maby you should work on your code to account for the change you want to make in the query.

Answer 5

declare #tblemployee Table(
id int identity(1,1) primary key not null,
name nvarchar(MAX) not null,
salary int not null
);
declare #Result Table(
name nvarchar(MAX) not null,
salaryString nvarchar(MAX)
);
insert into #tblemployee(name,salary) values ('joseph' ,25000);
insert into #tblemployee(name,salary) values ('mary' ,25000);
insert into #tblemployee(name,salary) values ('Max' ,40000);
insert into #tblemployee(name,salary) values ('rob' ,40000);
insert into #tblemployee(name,salary) values ('jon' ,40000);
declare #LastSalary int = 0;
declare #name nvarchar(MAX);
declare #salary int;
DECLARE iterator CURSOR LOCAL FAST_FORWARD FOR
SELECT name,
salary
FROM #tblemployee
Order by salary desc
OPEN iterator
FETCH NEXT FROM iterator INTO #name,#salary
WHILE ##FETCH_STATUS = 0
BEGIN
IF (#salary!=#LastSalary)
BEGIN
SET #LastSalary = #salary
insert into #Result(name,salaryString)
values(#name,#salary+'');
END
ELSE
BEGIN
insert into #Result(name,salaryString)
values(#name,'');
END
FETCH NEXT FROM iterator INTO #name,#salary
END
Select * from #Result