I've a Spring MVC application that is wrapped with Swagger annotations.
<spring.version>4.1.8.RELEASE</spring.version>
<java-version>1.7</java-version>
<springfox-version>2.1.2</springfox-version>
I've a controller with two resource endpoints to allow file upload - one endpoint for a single file upload and other with multiple file upload.
Single file upload -->
public #ResponseBody UploadAPIResponse postInboundFile(
#ApiParam(value = "file to upload") #RequestParam("file") MultipartFile file,
#ApiParam(value = "Inbound trigger flag ") #RequestParam("triggerInbound") Boolean triggerInbound)
throws SQLException, Exception {
Multi file upload -->
public #ResponseBody BulkUploadAPIResponse postInboundFilesAsync(
#ApiParam(value = "files to upload") #RequestParam("files") MultipartFile[] files,
#ApiParam(value = "Inbound trigger flag ") #RequestParam("triggerInbound") Boolean triggerInbound,
HttpServletRequest request) throws SQLException, Exception {
On viewing the Swagger UI for the api documentation,
I see that for single file upload API, against the "file" parameter, I get a file upload button.
However for the multi file upload API, I get the "files" parameter as a text box.
Can someone pls help me how can I get a file upload button against the "files" parameter of multi-files upload API and I'm able to upload multiple files as part of single request ?
I've gone through various other posts on this context but not able to find a concrete approach to address this issue.
PS : I've the understanding that naming the parameter as "file" provides the file upload button automatically through Swagger-UI. I tried to use the parameter name as "file" instead of "files" for the multi-file upload API but that didn't help; i still end up getting a text box (probably reason being that argument is an array of MultipartFile).
Thanks in advance for any pointers/suggestions.
Related
I have an autocomplete section that searches movies through MovieDB api.
The result of the api has a field called poster_path that contains the path where the image exists.
"poster_path": "/lRQiJXETkCnVVurHmglNvMXrZOx.jpg"
I have a react project for front-end and a spring boot project for backend.
The thing I want to do is to get the image convert it to file and the send it to the backend controller as a multipart file.
How can I convert the image from url to file in React?
I've tried this but re.data returns the byte array I think:
axios.get(e.image).then(re => {
setFile(re.data)
});
And here is the controller:
public ResponseEntity<Post> post(#RequestPart(required = false) MultipartFile file, #RequestPart #Valid PostResource postResource, Principal principal)
I am trying to select a local json file and load it in my blazor client component.
<input type="file" onchange="LoadFile" accept="application/json;.json" class="btn btn-primary" />
protected async Task LoadFile(UIChangeEventArgs args)
{
string data = args.Value as string;
}
P,S I do not understand , do i need to keep track both the name of the file and the content when retrieving it ?
I guess you're trying to read the contents of a JSON file on the client (Blazor), right? Why not on the server !?
Anyhow, args.Value can only furnish you with the name of the file. In order to read the contents of the file, you can use the FileReader API (See here: https://developer.mozilla.org/en-US/docs/Web/API/FileReader). That means that you should use JSIntrop to communicate with the FileReader API. But before you start, I'd suggest you try to find out if this API have been implemented by the community (something like the localStorage, etc.). You may also need to deserialize the read contents into something meaningful such as a C# object.
Hope this helps...
There is a tool that can help, but it currently doesn't support the 3.0 preview. https://github.com/jburman/W8lessLabs.Blazor.LocalFiles
(no affiliation with the developer)
The input control will give you the location of the file as a full path along with the name of the file. Then you still have to retrieve the file and download it to the server.
Late response but with 3.1 there is an additional AspNetCore.Components module you can download via NuGet to get access to HttpClient extensions. These make it simple:
// fetch mock data for now
var results = await _http.GetJsonAsync<WellDetail[]>("sample-data/well.json");
You could inject the location of the file from your input control in place of the "sample-data/well.json" string.
Something like:
using Microsoft.AspNetCore.Components;
private async Task<List<MyData>> LoadFile(string filePath)
{
HttpClient _http;
// fetch data
// convert file data to MyData object
var results = await _http.GetJsonAsync<MyData[]>(filePath);
return results.ToList();
}
How to get an Absolute URI of a file that exists in codenameone FileSystemStorage?
In my project, I need to send a file that exists in CodeNameOne FileSystemStorage as an email attachment. I am using Message - getAttachments().put(...) method that forces me to use an uri (as string) of this file as a parameter.
How can I get this URI. Or better, How can I send a file in FileSistemStorage as an email attachment?
This is pretty easy, use FileSystemStorage.getAppHomePath(), and append your filename to the string it returns.
More here : https://www.codenameone.com/javadoc/index.html
I am using spark as the backend to a project I am working on. I noticed that spark has the ability to serve templated html, using a templating engine such as velocity, freemaker, etc.
However, this isn't quite what I want. Instead of serving an html template, I would like to serve a plaintext file, while still allowing me to insert parameters where needed. For context, I am trying to allow the user to download code examples based on the parameters they have supplied.
Does anything like this exist, or do I need to essentially build the desired file's content and return it as a string?
Example of what I am trying to do
// example.java
public class Example {
public static void main(String [] args) {
System.out.println( {{ param }} );
}
}
So this ^ would be the plain text template that I am attempting to serve... "param" would be passed to the backend via http request, and inserted into the file. Then I would serve the file to the frontend.
So, (as mentioned in the comment :), glad it helped) you can serve this content as HTML page (then you can use template manager) containing only this plaintext content only. Only exception will be the extension which will be .html instead of .java if the user saves the file.
You could declare a route whose return type is 'text/plain'
get(Main.API_PUBLIC + "/sourcecode", (req, res) -> {
res.status(200);
res.type("text/plain");
return " /* This will be the code snippet you'll be returning */ ";
});
Another alternative would be putting your source code files into the static files directory and link to them in your html.
I have been trying to parse a multipart request by using apache commons file upload over JBOSS 5.1 .
The problem is when request is parsed, FileItem list is not being filled .(FileItem list is empty) Here is the code block that is working on windows but not on Unix :
DiskFileItemFactory factory = new DiskFileItemFactory();
factory.setSizeThreshold(1024*1024*3);
factory.setRepository(new File("/root/loads/temp"));
// Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload(factory);
upload.setFileSizeMax(100000);
upload.setSizeMax(100000);
boolean isMulti =upload.isMultipartContent(request);
// Parse the request
try {
List<FileItem> items = upload.parseRequest(request);
Note : I am reaching the HTTPServletRequest via HttpEvent.getHTTPServletRequest().Also request has not being handled before.java version = 1.6_021
I found the solution, jboss security and our project's platform rules does not allow to access any file which are not in the specified directory.
I used jboss temp directory and can access the items in the request.