How to fix inconsistency in Jackrabbit JCR (BundleFsPersistenceManager) - jackrabbit

We are using JackRabbit in production. Unfortunately we have some inconsistencies in the repositories which make the data not unreadable:
ERROR ResourceServiceImpl - RepositoryException to JCR javax.jcr.PathNotFoundException: 1661b5c
The spring bean configuration looks like this:
<bean id="repository" class="org.apache.jackrabbit.core.RepositoryImpl" destroy-method="shutdown">
<constructor-arg index="0" ref="config" />
</bean>
<bean id="config" class="org.apache.jackrabbit.core.config.RepositoryConfig" factory-method="create">
<constructor-arg index="0" ref="jcrXml"/>
<constructor-arg index="1" value="${instance.repository}" />
</bean>
<bean id="jcrXml" class="com.example.misc.InputStreamBeanFactory" factory-method="createStream">
<constructor-arg value="/jackrabbit-repository.xml" />
</bean>
<bean name="jcrSession" factory-bean="repository" factory-method="login" scope="session" destroy-method="logout" />
The workspaces.xml looks like this:
<?xml version="1.0" encoding="UTF-8"?><Workspace name="default">
<FileSystem class="org.apache.jackrabbit.core.fs.local.LocalFileSystem">
<param name="path" value="${wsp.home}"/>
</FileSystem>
<PersistenceManager class="org.apache.jackrabbit.core.persistence.bundle.BundleFsPersistenceManager"/>
</Workspace>
From what I've learned (too late) here, the above configured BundleFsPersistenceManager can become inconsistent. It is also writen here that this should NOT be used into production. Well, it is now in production and no one has noticed this before and we would like to exchange this. However first we have to migrate the data and for this reason we need to fix it.
My question: Is there a way to fix this or are these data lost for good?
My second question: What can we do to avoid these issues in the future?.

There's some notes about additional check.. params that can be set on persistence managers on Adobe CQ - Repository Inconsistency (uses Jackrabbit). The Magnolia - JCR Troubles has a script example for searching for and removing broken nodes. I've seen an approach that combined the logic from this script (written in java) and the checking params allow for a repository to be brought back up and running long enough to get the content out.
To avoid the issues in future - where you want a standalone setup that doesn't use a RDBMS - I'd suggest org.apache.jackrabbit.core.persistence.pool.DerbyPersistenceManager.
<PersistenceManager class="org.apache.jackrabbit.core.persistence.pool.DerbyPersistenceManager">
<param name="url" value="jdbc:derby:${wsp.home}/db;create=true"/>
<param name="schemaObjectPrefix" value="${wsp.name}_"/>
</PersistenceManager>

Related

How to use properties with the SimpleRegistry in Apache Camel (Spring XML)

I want to use a SimpleRegistry to store properties (as global variables). The property is changed with setProperty in a route with a jms endpoint. The camel documentation changed last week and has many dead links, also the Registry page. I did not found any samples that describe the use of the simpleRegistry.
I used the camel-example-servlet-tomcat as base. I do not use Fuse or the patched camel wildfly, because is to huge for our simple module.
<beans .... >
.
.
.
<bean id="simpleRegistry" class="org.apache.camel.support.SimpleRegistry" />
<camelContext xmlns="http://camel.apache.org/schema/spring">
<propertyPlaceholder id="properties" location="ref:simpleRegistry" />
<route id="storeConfig">
<from id="myTopic" uri="jms:topic:myTopic?selector=Configuration %3D 'xyz'" />
<log id="printHeader2" message="Received header: ${headers}" />
<log id="logToken" message="Received token: ${headers[myToken]}" />
<setProperty id="setMyToken" name="myProperty">
<simple>${headers[myToken]}</simple>
</setProperty>
</route>
<route id="externalIncomingDataRoute">
<from uri="servlet:hello" />
<transform>
<simple>The Token is: {{myProperty}}</simple>
</transform>
</route>
</camelContext>
</beans>
With the camel context deined like above, I got a java.io.FileNotFoundException Properties simpleRegistry not found in registry.
When I use <propertyPlaceholder id="properties" location="classpath:test.properties" /> and create a test.properties file, everything works fine but I cannot change the property. The operation in the setProperty tag is ignored.
The reason why I need a global variable is, I send a dynamic configuration (the myToken) via a jms topic to the camel context. A single route should store this configuration globaly. If an other route is called via an rest component, this route need the token to make a choice.
Alternatively you can achieve the same result following the below approach which uses the PropertiesComponent
<bean id="applicationProperties" class="java.util.Properties"/>
<bean id="properties" class="org.apache.camel.component.properties.PropertiesComponent">
<property name="location" value="classpath:application.properties"/>
<property name="overrideProperties" ref="applicationProperties" />
</bean>
Define the property place holder in the camel context:
<propertyPlaceholder id="propertiesRef" location="ref:applicationProperties" />
Set a property as shown below :
<bean ref="applicationProperties" method="setProperty(token, 'Test'})" />
And to fetch the property : ${properties:token}
OK, there are multiple subjects in your question.
You write you want to use Camel SimpleRegistry, but you obviously have a Spring application.
If you got Spring available, the Camel Registry automatically uses the Spring bean registry. The Camel Registry is just a thin wrapper or provider interface that uses whenever possible an available registry of another framework.
The Camel SimpleRegistry is only used when nothing else is available. This is basically an in-memory registry based on a Map.
You want to set an application property with <setProperty>.
<setProperty> sets an Exchange property, NOT an application property. With this you can save values in the Exchange of a message.
You want to use "global variables".
You could perhaps use a Spring singleton bean that is a Map. You could then autowire it where you need it, it would be like an application wide available map.
However, think twice why you need this kind of variable. This could also be a symptom of a design problem.

Configuring 2 database in mybatis + springs

I have an existing setup of mybatis + springs for working with Oracle DB. I have a set of java mapper interfaces, a set of corresponding mapper xmls (each having reference to their corresponding java mapper). I need to setup support for MSSQL also, but finding it hard to do that. I have created a separate set of xmls (specific to queries of MSSQL) in com/mycomp/mob/db/mappers/mssql.
Below is the extract of my applicationConext.xml (Here DBDataSource is an internal class which reads a config files to get all DB details).
<bean name="dataSource" class="com.mycomp.mob.core.db.DBDataSource">
<constructor-arg index="0" name="dbAlias" value="mob" />
<constructor-arg index="1" name="cfgSection" value="primary" />
</bean>
<bean class="org.mybatis.spring.mapper.MapperScannerConfigurer">
<property name="basePackage" value="com.mycomp.mob.db.mappers.oracle" />
</bean>
<bean id="sqlSessionFactory" class="org.mybatis.spring.SqlSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="typeAliasesPackage" value="com.mycomp.mob.db.mappers.oracle" />
<property name="configLocation" value="classpath:mybatis-config.xml" />
</bean>
<bean id="sqlSession" class="org.mybatis.spring.SqlSessionTemplate">
<constructor-arg index="0" ref="sqlSessionFactory" />
</bean>
Below is part of mybatis-config.xml (here ${} params are replaced using the earlier DBDatasource)
<configuration>
<typeAliases>
<package name="com.mycomp.mob.db.model" />
</typeAliases>
<environments default="development">
<environment id="development">
<transactionManager type="JDBC" />
<dataSource type="POOLED">
<property name="driver" value="${driver}" />
<property name="url" value="${url}" />
<property name="username" value="${username}" />
<property name="password" value="${password}" />
</dataSource>
</environment>
</environments>
<mappers>
<mapper resource="com/mycomp/mob/db/mappers/oracle/tenant.xml" />
<mapper resource="com/mycomp/mob/db/mappers/oracle/functionenty.xml" />
</mappers>
</configuration>
com.mycomp.mob.db.model contains POJO for tenant and functionentry.
Usage is as below :
ITenantMapper mappper = sqlSessionFactory.openSession().getMapper(ItenantMapper.class)
Tenant t = mapper.getTenant();
Now at a time only one DB (which is configured as primary in DB config file) will be used. So how to make sure that XML corresponding to that particular DB is invoked by the java mapper interface.
Also need to know can I configure same java mapper class name inside the mapper xmls of mssql ?
Is the flow used correct or I need to change the flow for supporting multiple databases.
Create two datasources and two SessionFactories in spring one for Oracle another for MSSQL.

Multiple data models Apache camel Bindy

I am working with Apache Camel Bindy to process csv files of different data models.
e.g. file one is of data model on and file two is of data model two.
In the camel route, I associated two calls of the BindyCsvDataFormat with different data models as:
<bean id="bindyDataformat" class="org.apache.camel.dataformat.bindy.csv.BindyCsvDataFormat">
<constructor-arg name="type" value="com.barclays.creditit.cls.eoddata.model.risk.DataModel1" />
</bean>
<bean id="aBindyDataformat" class="org.apache.camel.dataformat.bindy.csv.BindyCsvDataFormat">
<constructor-arg name="type" value="DataModel2" />
</bean>
route looks like this:
<from uri="direct:start"/>
<bean ref="fileReader"/>
<unmarshal ref="bindyDataformat" />
<bean ref="flattener"/>
<bean ref="fileReader"/>
<unmarshal ref="aBindyDataformat" />
<bean ref="flattener"/>
When I run the code though, the factory has two models associated automatically, not one per run. And both the files are read into objects of the first data model and never the second data model. Any suggestions about how I could get this to work?
Thanks!
Create two different routes with different file filters and process them separately with one of the Bindy formaters.

cxf-rs-ws authorization under karaf

I'm trying to configure a cxf soap webservice with authorization and authentication to be deployed on Servicemix.
I configured the LDAP authentication module as follows:
<!-- Bean to allow the $[karaf.base] property to be correctly resolved -->
<ext:property-placeholder placeholder-prefix="$[" placeholder-suffix="]"/>
<jaas:config name="myRealm">
<jaas:module className="org.apache.karaf.jaas.modules.ldap.LDAPLoginModule" flags="required">
connection.url = ldap://srv-ldap:389
user.base.dn = ou=people,dc=intranet,dc=company,dc=com
user.filter = (uid=%u)
user.search.subtree = false
role.base.dn = ou=groups,dc=intranet,dc=company,dc=com
role.filter = (member:=uid=%u,ou=people,dc=intranet,dc=company,dc=com)
role.name.attribute = cn
role.search.subtree = true
authentication = simple
</jaas:module>
</jaas:config>
<service interface="org.apache.karaf.jaas.modules.BackingEngineFactory">
<bean class="org.apache.karaf.jaas.modules.properties.PropertiesBackingEngineFactory"/>
</service>
And here is the beans.xml file
<jaxws:endpoint id="myService"
implementor="com.myorg.services.impl.MyServiceWSImpl"
address="/myService">
<jaxws:inInterceptors>
<bean class="org.apache.cxf.ws.security.wss4j.WSS4JInInterceptor">
<constructor-arg>
<map>
<entry key="action" value="UsernameToken" />
<entry key="passwordType" value="PasswordText" />
</map>
</constructor-arg>
</bean>
<ref bean="authenticationInterceptor" />
<ref bean="authorizationInterceptor" />
</jaxws:inInterceptors>
<jaxws:properties>
<entry key="ws-security.validate.token" value="false" />
</jaxws:properties>
</jaxws:endpoint>
<bean id="authenticationInterceptor"
class="org.apache.cxf.interceptor.security.JAASLoginInterceptor">
<property name="contextName" value="myRealm" />
</bean>
<bean id="authorizationInterceptor"
class="org.apache.cxf.interceptor.security.SecureAnnotationsInterceptor">
<property name="securedObject" ref="securedBean"/>
</bean>
Finally, in my WebService implementation I annotated a method with #RolesAllowed.
#RolesAllowed("Role1")
public Department get(String name) throws IdMException {
return service.get(name);
}
The authentication interceptor is retrieving the user, authenticating it and retrieving the groups as RolePrincipal instances.
Then, in the authorization interceptor (SecureAnnotationsInterceptor), the method configuration is read, the expectedRoles are "Role1", but the SimpleAuthorizingInterceptor.isUserInRole method returns false.
I haven't found any example trying to do more or less the same and the few information I found was from the CXF documentation page http://cxf.apache.org/docs/security.html#Security-Authorization
I have to be missing something important, hope somebody could help me.
Thanks in advance and kind regards.
Your problem is because of Karaf's RolePricipal do not implements Group as CXF expected. Instead of it, it implements Pricipal so CXF thinks that 1st role name is a username. That is why "SimpleAuthorizingInterceptor.isUserInRole method returns false".
A solution is to wait for fixed versions of CXF (2.7.11 and 3.0.0).
If not possible to update to newer version, then an odd and temporary solution (simply workaround) is to add more than one role to a user in LDAP and to method.
You can find more about that bug here: CXF-5603

JPA does not write to table

I have the following JPA code, with all the values checked (ticket contains a valid bean, it ends without exception, etc.) It is executed, it does not throw any exceptions, yet in the end no data is written into the table.
I tried also retrieving a bean from the table, it also "works" (it is empty, so no data is returned).
The setup is
JBoss 6.1 Final
SQLServer 2008 Express (driver SQL JDBC 3 from MS)
The persistence code:
public String saveTicket() {
System.out.println("Controller saveTicket() ");
EntityManagerFactory factory = Persistence.createEntityManagerFactory("GesMan"); /* I know it would be better to share a single instance of factory, this is just for testing */
EntityManager entityMan = factory.createEntityManager();
entityMan.persist(this.ticket);
entityMan.close();
}
The persistence unit is
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="GesMan" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<jta-data-source>java:/GesManDS</jta-data-source>
<class>es.caib.gesma.gesman.Ticket</class>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.SQLServerDialect"/>
<property name="hibernate.transaction.manager_lookup_class"
value="org.hibernate.transaction.JBossTransactionManagerLookup"/>
<property name="hibernate.show_sql" value="true"/>
</properties>
</persistence-unit>
</persistence>
The datasource
<datasources>
<local-tx-datasource>
<jndi-name>GesManDS</jndi-name>
<connection-url>jdbc:sqlserver://spsigeswnt14.caib.es:1433;DatabaseName=TEST_GESMAN</connection-url>
<driver-class>com.microsoft.sqlserver.jdbc.SQLServerDriver</driver-class>
<user-name>thisis</user-name>
<password>notthepassword</password>
<check-valid-connection-sql>SELECT * FROM dbo.Ticket</check-valid-connection-sql>
<metadata>
<type-mapping>MS SQLSERVER</type-mapping>
</metadata>
</local-tx-datasource>
</datasources>
call entityMan.flush() or transaction.commit() befor closing it, otherwise it will discard all changes queued on close.
In the end it looks like I was using the wrong approach.... In JBoss you can`t (better said, I could not get to) access JPA directly (as you would do in JSE).
I ended creating an EJB (with transactions) and passing all JPA logic there.
PS: Of course, if I am wrong please tell me (now it is more of an academic issue, but still I want to know)

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