I have a table with a data as bellow :
+--------+----------+-------+------------+--------------+
| month | code | type | date | PersonID |
+--------+----------+-------+------------+--------------+
| 201501 | 178954 | 3 | 2014-12-3 | 10 |
| 201501 | 178954 | 3 | 2014-12-3 | 10 |
| 201501 | 178955 | 2 | 2014-12-13 | 10 |
| 201501 | 178955 | 2 | 2014-12-13 | 10 |
| 201501 | 178956 | 2 | 2014-12-11 | 10 |
| 201501 | 178958 | 1 | 2014-12-10 | 10 |
| 201501 | 178959 | 2 | 2014-12-12 | 15 |
| 201501 | 178959 | 2 | 2014-12-12 | 15 |
| 201501 | 178954 | 1 | 2014-12-11 | 13 |
| 201501 | 178954 | 1 | 2014-12-11 | 13 |
+--------+----------+-------+------------+--------------+
In my first 6 lines i have the same PersonID in the same Month What i want if i have the same personID in the same Month i want to select the person who have the type is 2 with the recent date in my case the output will be like as bellow:
+--------+--------+------+------------+----------+
| month | code | type| date | PersonID |
+--------+--------+------+------------+----------+
| 201501 | 178955 | 2 | 2014-12-13 | 10 |
| 201501 | 178959 | 2 | 2014-12-12 | 15 |
| 201501 | 178954 | 2 | 2014-12-11 | 13 |
+--------+--------+------+------------+----------+
Also if they are some duplicate rows i don't want to display it
They are any solution to that ?
Simply use GROUP BY:
https://msdn.microsoft.com/de-de/library/ms177673(v=sql.120).aspx
SELECT mont, code, ... FROM tabelname GROUP BY PersonID, date, ...
Note that you have to specifiy all columns in the group by.
SELECT DISTINCT A.month, A.code, A.type, B.date, B.PersonID FROM YourTable A
INNER JOIN (SELECT PersonID, MAX(date) as date FROM YourTable
GROUP BY PersonID) B
ON (A.PersonID = B.PersonID
AND A.date = B.date)
WHERE A.type = 2 ORDER BY B.date DESC, A.PersonID
Just in case you/others are still wondering.
Related
I have 2 tables, with the same exact fields and fields names. i am trying to inner join them but im having some difficulty determining how i can get my results in my desired format.
I know i can do select a.customer, a.id, a.date, a.line, a.product, b.customer, b.id, b.date, b.line, b.product but instead of having my A data and B data on the same row, id like for them to be on seperate rows.
I have 2 tables, with the same exact fields and fields names, i am trying to inner join them so that unique line becomes a row.
Table A:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 123 | 1/1/22 | 10 | 88975 |
| 853652 | 456 | 1/10/22 | 5 | 55876 |
| 845689 | 789 | 1/25/22 | 1 | 45587 |
TABLE B:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 489 | 1/1/22 | 1 | 87574 |
| 853652 | 853 | 1/10/22 | 12 | 45678 |
| 587435 | 157 | 2/12/22 | 3 | 25896 |
DESIRED RESULTS:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 123 | 1/1/22 | 10 | 88975 |
| 445678 | 489 | 1/1/22 | 1 | 87574 |
| 853652 | 456 | 1/10/22 | 5 | 55876 |
| 853652 | 853 | 1/10/22 | 12 | 45678 |
my query:
select a.customer, a.id, a.date, a.line, a.product
from data1 a
inner join data2 b
on a.date = b.date
and a.customer = b.customer
I am having trouble narrowing down sales in top regions that occurred in consecutive months. I know I need to use some form of window function with Row_Number or Dense_Rank, but I am having trouble getting the final output
Here is my source data:
+--------+-----------+------------+
| Fruit | SaleDate | Top_Region |
+--------+-----------+------------+
| Apple | 1/1/2017 | 1 |
| Apple | 2/1/2017 | 1 |
| Apple | 3/1/2017 | 1 |
| Apple | 4/1/2017 | 0 |
| Apple | 5/1/2017 | 0 |
| Apple | 6/1/2017 | 0 |
| Apple | 7/1/2017 | 1 |
| Apple | 8/1/2017 | 1 |
| Apple | 9/1/2017 | 1 |
| Apple | 10/1/2017 | 1 |
| Apple | 11/1/2017 | 0 |
| Apple | 12/1/2017 | 0 |
| Banana | 1/1/2017 | 0 |
| Banana | 2/1/2017 | 0 |
| Banana | 3/1/2017 | 1 |
| Banana | 4/1/2017 | 1 |
| Banana | 5/1/2017 | 1 |
| Banana | 6/1/2017 | 1 |
| Banana | 7/1/2017 | 1 |
| Banana | 8/1/2017 | 1 |
| Banana | 9/1/2017 | 0 |
| Banana | 10/1/2017 | 1 |
| Banana | 11/1/2017 | 1 |
| Banana | 12/1/2017 | 0 |
+--------+-----------+------------+
This is the expected output:
+--------+-----------+-----------+-------+
| Fruit | Start | End | Total |
+--------+-----------+-----------+-------+
| Apple | 1/1/2017 | 3/1/2017 | 3 |
| Apple | 7/1/2017 | 10/1/2017 | 4 |
| Banana | 3/1/2017 | 8/1/2017 | 6 |
| Banana | 10/1/2017 | 11/1/2017 | 2 |
+--------+-----------+-----------+-------+
The goal is to have instances of top region sales in succession with missing in one month.
So far I have tried a few different combinations, with this being the closest.
SELECT fruit,
MIN(saledate) AS spanStart ,
MAX(saledate) AS spanEnd,
COUNT(*) AS spanLength
FROM ( SELECT s.* ,
( ROW_NUMBER() OVER ( ORDER BY month )
- ROW_NUMBER() OVER ( PARTITION BY fruit, topregion ORDER BY month ) ) AS fruits
FROM #salesdata s
) s
GROUP BY fruit,fruits ,
topregion
HAVING topregion = 1
ORDER BY COUNT(*) DESC;
Any help would be greatly appreciated
This is a typical gaps-and-island problem. One strategy is to identify the groups of adjacent rows groups by computing the difference between two row_number()s. We can then filter on groups having top_region = 1 and use aggregation to get the start date, end date and number of records per group.
Your query is really close, but the first row_number() is missing a partition by fruit in its over() clause. And I find that aliasing that column fruits where another column is called fruit is error prone.
select
fruit,
min(sale_date) start_date,
max(sale_date) end_date,
count(*) total
from (
select
t.*,
row_number() over(partition by fruit order by sale_date) rn1,
row_number() over(partition by fruit, top_region order by sale_date) rn2
from mytable t
) t
where top_region = 1
group by fruit, rn1 - rn2
order by fruit, start_date
You can run the inner query separately to see the result it produces.
Demo on DB Fiddle:
fruit | start_date | end_date | total
:----- | :--------- | :--------- | ----:
Apple | 2017-01-01 | 2017-01-03 | 3
Apple | 2017-01-07 | 2017-01-10 | 4
Banana | 2017-01-03 | 2017-01-08 | 6
Banana | 2017-01-10 | 2017-01-11 | 2
I have following SQL Server table ITEM:
+------------+-----------+------+--------+-----------+------------+
| Date | item_code | name | in/out | total_qty | SortNumber |
+------------+-----------+------+--------+-----------+------------+
| 08/07/2019 | 001 | A | -50 | 100 | 8 |
| 07/07/2019 | 001 | A | 50 | 100 | 7 |
| 06/07/2019 | 003 | C | 25 | 25 | 6 |
| 05/07/2019 | 001 | A | 50 | 50 | 5 |
| 04/07/2019 | 002 | B | 100 | 200 | 4 |
| 03/07/2019 | 003 | C | -25 | 0 | 3 |
| 02/07/2019 | 003 | C | 25 | 25 | 2 |
| 01/07/2019 | 002 | B | 100 | 100 | 1 |
+------------+-----------+------+--------+-----------+------------+
I've tried:
select itemcode, max(Sort_Number)
from ITEM
group by item_code
order by item_code asc
but I want result:
+---------------------+-----------+------------------+
| Distinct(item_code) | Total_qty | Max(Sort_Number) |
+---------------------+-----------+------------------+
| 001 | 100 | 8 |
| 002 | 200 | 4 |
| 003 | 25 | 6 |
+---------------------+-----------+------------------+
Can anyone help me?
The below query gives you the desired result -
With cteItem as
(
select item_code, total_qty, SortNumber,
Row_Number() over (partition by item_code order by SortNumber desc) maxSortNumber
from ITEM
)
select item_code, total_qty, SortNumber from cteItem where maxSortNumber = 1
just need to add max(sort_number) to your query
select item_code ,max(total_qty), max(sort_number)
from ITEM
group by item_code
order by item_code asc
i have a SQL that displays turnover, stock and other values for stores grouped by month. Logically, if there is no value for a month, the month doesn't appear. The target is that the empty month should appear and display "NULL" for the values. The empty months should range from the #FROM to the #TO parameter (201807 to 201907) in this case.
Before:
+-------+--------+----------+----------+-------+
| Store | Month | Incoming | Turnover | Stock |
+-------+--------+----------+----------+-------+
| 123 | 201810 | 5 | 4 | 1 |
| 123 | 201811 | 0 | 1 | 0 |
| 123 | 201901 | 25 | 5 | 20 |
| 123 | 201902 | 5 | 10 | 15 |
| 123 | 201903 | 8 | 9 | 14 |
| 123 | 201904 | 5 | 4 | 15 |
| 123 | 201905 | 10 | 5 | 20 |
+-------+--------+----------+----------+-------+
After:
+-------+--------+----------+----------+-------+
| Store | Month | Incoming | Turnover | Stock |
+-------+--------+----------+----------+-------+
| 123 | 201807 | NULL | NULL | NULL |
| 123 | 201808 | NULL | NULL | NULL |
| 123 | 201809 | NULL | NULL | NULL |
| 123 | 201810 | 5 | 4 | 1 |
| 123 | 201811 | 0 | 1 | 0 |
| 123 | 201812 | NULL | NULL | NULL |
| 123 | 201901 | 25 | 5 | 20 |
| 123 | 201902 | 5 | 10 | 15 |
| 123 | 201903 | 8 | 9 | 14 |
| 123 | 201904 | 5 | 4 | 15 |
| 123 | 201905 | 10 | 5 | 20 |
| 123 | 201906 | NULL | NULL | NULL |
| 123 | 201907 | NULL | NULL | NULL |
+-------+--------+----------+----------+-------+
Code Example: db<>fiddle
I have absolutely no idea how to solve this and will thank you in advance for your help! :)
You can try to use cte recursive make a calendar table, then do outer-join
;WITH CTE AS (
SELECT CAST(CAST(#FROM AS VARCHAR(10)) + '01' AS DATE) fromDt,
CAST(CAST(#TO AS VARCHAR(10)) + '01' AS DATE) toDt,
Store
FROM (SELECT DISTINCT Store FROM #Test) t1
UNION ALL
SELECT DATEADD(MONTH,1,fromDt),toDt,Store
FROM CTE
WHERE DATEADD(MONTH,1,fromDt) <= toDt
)
SELECT FORMAT(fromDt,'yyyyMM') Month,
c.Store,
t.Incoming,
t.Turnover,
t.Stock
FROM CTE c
LEFT JOIN #Test t on
c.fromDt = CAST(CAST(t.Month AS VARCHAR(10)) + '01' AS DATE)
and
c.Store = t.Store
sqlfiddle
I have a table that holds values for particular months:
| MFG | DATE | FACTOR |
-----------------------------
| 1 | 2013-01-01 | 1 |
| 2 | 2013-01-01 | 0.8 |
| 2 | 2013-02-01 | 1 |
| 2 | 2013-12-01 | 1.55 |
| 3 | 2013-01-01 | 1 |
| 3 | 2013-04-01 | 1.3 |
| 3 | 2013-05-01 | 1.2 |
| 3 | 2013-06-01 | 1.1 |
| 3 | 2013-07-01 | 1 |
| 4 | 2013-01-01 | 0.9 |
| 4 | 2013-02-01 | 1 |
| 4 | 2013-12-01 | 1.8 |
| 5 | 2013-01-01 | 1.4 |
| 5 | 2013-02-01 | 1 |
| 5 | 2013-10-01 | 1.3 |
| 5 | 2013-11-01 | 1.2 |
| 5 | 2013-12-01 | 1.5 |
What I would like to do is pivot these using a calendar table (already defined):
And finally, cascade the NULL columns to use the previous value.
What I've got so far is a query that will populate the NULLs with the last value for mfg = 3. Each mfg will always have a value for the first of the year. My question is; how do I pivot this and extend to all mfg?
SELECT c.[date],
f.[factor],
Isnull(f.[factor], (SELECT TOP 1 factor
FROM factors
WHERE [date] < c.[date]
AND [factor] IS NOT NULL
AND mfg = 3
ORDER BY [date] DESC)) AS xFactor
FROM (SELECT [date]
FROM calendar
WHERE Datepart(yy, [date]) = 2013
AND Datepart(d, [date]) = 1) c
LEFT JOIN (SELECT [date],
[factor]
FROM factors
WHERE mfg = 3) f
ON f.[date] = c.[date]
Result
| DATE | FACTOR | XFACTOR |
---------------------------------
| 2013-01-01 | 1 | 1 |
| 2013-02-01 | (null) | 1 |
| 2013-03-01 | (null) | 1 |
| 2013-04-01 | 1.3 | 1.3 |
| 2013-05-01 | 1.2 | 1.2 |
| 2013-06-01 | 1.1 | 1.1 |
| 2013-07-01 | 1 | 1 |
| 2013-08-01 | (null) | 1 |
| 2013-09-01 | (null) | 1 |
| 2013-10-01 | (null) | 1 |
| 2013-11-01 | (null) | 1 |
| 2013-12-01 | (null) | 1 |
SQL Fiddle
Don't know if you need the dates to be dynamic from the calender table or if mfg can be more than 5 but this should give you some ideas.
select *
from (
select c.date,
t.mfg,
(
select top 1 f.factor
from factors as f
where f.date <= c.date and
f.mfg = t.mfg and
f.factor is not null
order by f.date desc
) as factor
from calendar as c
cross apply(values(1),(2),(3),(4),(5)) as t(mfg)
) as t
pivot (
max(t.factor) for t.date in ([20130101], [20130201], [20130301],
[20130401], [20130501], [20130601],
[20130701], [20130801], [20130901],
[20131001], [20131101], [20131201])
) as P
SQL Fiddle