SQL Server : to get Max date value - sql-server

I have the following data in the table:
I have tried using the below query to get the latest CMBR_MBST with its respective CMBR_CCMP
SELECT CMBR_CCMP, MAX(CMBR_MBST) AS CMBR_MBST
FROM CMBR
GROUP BY CMBR_CCMP
The result is close to what I need. I just need the extra 2 columns, CMBR_MMBR & CMBR_MBED to be displayed.
For example:
Can someone please help me with the query? Your help would be very much appreciated. Thanks

Here is one way using ROW_NUMBER
SELECT TOP 1 with ties *
FROM CMBR
Order by row_number()over(parition by CMBR_CCMP order by CMBR_MBST desc)
Another way (commonly used technique)
select * from
(
SELECT *,row_number()over(parition by CMBR_CCMP order by CMBR_MBST desc) Rn
FROM CMBR
) A
Where Rn =1

Related

Find customer who placed order every month and who did not place order every month

I am looking for a query than can list the customers
who placed order every month form the following table? A: 123
who did not place an order every month? A:everyone except 123
I am not proficient in such codes and I tried build sub-queries and cte's but I am not able to build my logic. I tried the following but not able to progress.
; with cte as(
SELECT customer_id,DATEPART(MONTH,Customer) as month,count(units) as no_of_order
from dwqc.dbo.orders
group by customer_id,DATEPART(MONTH,Customer))
select * from cte
Could someone please help me out with this? Thanks!
SELECT customer_id
from dwqc.dbo.orders
group by customer_id
having count(distinct DATEPART(MONTH,Customer))
= (select count(distinct DATEPART(MONTH,Customer)) from dwqc.dbo.orders)
Thanks #Nick.McDermaid

How to calculate the days between 2 dates from 2 successive IDs

I need some help to create a new column in a database in SQL Server 2008.
I have the following data table
Please have a look at a snapshot of my table
Table
In the blank column I would like to put the difference between the current status date and the next status' date. And for the last ID_Status for each ID_Ticket I would like to have the difference between now date and it's date !
I hope that you got an idea about my problem.
Please share if you have any ideas about how to do .
Many thanks
kind regards
You didn't specify your RDBMS, so I'll post an answer for both since they are almost identical :
SQL-Server :
SELECT ss.id_ticket,ss.id_status,ss.date_status,
DATEDIFF(day,ss.date_status,ss.coalesce(ss.next_date,GETDATE())) as diffStatus
FROM (
SELECT t.*,
(SELECT TOP 1 s.date_status FROM YourTable s
WHERE t.id_ticket = s.id_ticket and s.date_status > t.date_status
ORDER BY s.date_status ASC) as next_date)
FROM YourTable t) ss
MySQL :
SELECT ss.id_ticket,ss.id_status,ss.date_status,
DATEDIFF(ss.date_status,ss.coalesce(ss.next_date,now())) as diffStatus
FROM (
SELECT t.*,
(SELECT s.date_status FROM YourTable s
WHERE t.id_ticket = s.id_ticket and s.date_status > t.date_status
ORDER BY s.date_status ASC limit 1) as next_date)
FROM YourTable t) ss
This basically first use a correlated sub query to bring the next date using limit/top , and then wrap it with another select to calculate the difference between them using DATEDIFF().
Basically it can be done without the wrapping query, but it won't be readable since the correlated query will be inside the DATEDIFF() function, so I prefer this way.

Row_Number Over Where RowNumber between

I'm try to select a certain rows from my table using the row_number over. However, the sql will prompt the error msg "Invalid column name 'ROWNUMBERS' ". Anyone can correct me?
SELECT ROW_NUMBER() OVER (ORDER BY Price ASC) AS ROWNUMBERS, *
FROM Product
WHERE ROWNUMBERS BETWEEN #fromCount AND #toCount
Attempting to reference the aliased column in the WHERE clause does not work because of the logical query processing taking place. The WHERE is evaluated before the SELECT clause. Therefore, the column ROWNUMBERS does not exist when WHERE is evaluated.
The correct way to reference the column in this example would be:
SELECT a.*
FROM
(SELECT ROW_NUMBER() OVER (ORDER BY Price ASC) AS ROWNUMBERS, *
FROM Product) a
WHERE a.ROWNUMBERS BETWEEN #fromCount AND #toCount
For your reference, the order for operations is:
FROM
WHERE
GROUP BY
HAVING
SELECT
ORDER BY
There is another answer here that solves the specific error reported. However, I also want to address the wider problem. It looks a lot like what you are doing here is paging your results for display. If that is the case, and if you can use Sql Server 2012, there is a better way now. Take a look at OFFSET/FETCH:
SELECT First Name + ' ' + Last Name
FROM Employees
ORDER BY First Name
OFFSET 10 ROWS FETCH NEXT 5 ROWS ONLY;
That would show the third page of a query where the page size is 5.

Replace Group By clause with any other clause

In below query, I am using GROUP BY clause to get list of recently updated records depends on updated date. But I would like to have the query without a GROUP BY clause because of some internal reasons. Can please any one help me to solve this.
SELECT Proj_UpdatedDate,
Proj_UpdatedBy
FROM ProjectProgress PP
WHERE Proj_UpdatedDate IN (SELECT MAX(Proj_UpdatedDate)
FROM ProjectProgress
GROUP BY
Proj_ProjectID)
ORDER BY
Proj_ProjectID
Using TOP 1 should give you the same result assuming you meant the MAX(Proj_UpdatedDate):
SELECT Proj_UpdatedDate,
Proj_UpdatedBy
FROM ProjectProgress PP
WHERE Proj_UpdatedDate IN (SELECT TOP 1 Proj_UpdatedDate
FROM ProjectProgress
ORDER BY Proj_UpdatedDate DESC)
ORDER BY
Proj_ProjectID
However your query actually returns multiple dates since it's GROUPED BY Proj_ProjectId (the max date for each project). Is that your desired outcome - to show a list of dates that the projects were updated and by whom?
If so, try using ROW_NUMBER():
SELECT Proj_UpdatedDate, Proj_UpdatedBy
FROM (
SELECT ROW_NUMBER() OVER (PARTITION BY Proj_ProjectID ORDER BY Proj_UpdatedBy DESC) rn,
Proj_UpdatedDate,
Proj_UpdatedBy
FROM ProjectProgress
) t
WHERE rn = 1
And here is the SQL Fiddle. This assumes you are running SQL Server 2005 or greater.
Good luck.

SQL Error with Order By in Subquery

I'm working with SQL Server 2005.
My query is:
SELECT (
SELECT COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
And the error:
The ORDER BY clause is invalid in views, inline functions, derived
tables, subqueries, and common table expressions, unless TOP or FOR
XML is also specified.
How can I use ORDER BY in a sub query?
This is the error you get (emphasis mine):
The ORDER BY clause is invalid in
views, inline functions, derived
tables, subqueries, and common table
expressions, unless TOP or FOR XML is
also specified.
So, how can you avoid the error? By specifying TOP, would be one possibility, I guess.
SELECT (
SELECT TOP 100 PERCENT
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
If you're working with SQL Server 2012 or later, this is now easy to fix. Add an offset 0 rows:
SELECT (
SELECT
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id OFFSET 0 ROWS
) as dorduncuay
Besides the fact that order by doesn't seem to make sense in your query....
To use order by in a sub select you will need to use TOP 2147483647.
SELECT (
SELECT TOP 2147483647
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
My understanding is that "TOP 100 PERCENT" doesn't gurantee ordering anymore starting with SQL 2005:
In SQL Server 2005, the ORDER BY
clause in a view definition is used
only to determine the rows that are
returned by the TOP clause. The ORDER
BY clause does not guarantee ordered
results when the view is queried,
unless ORDER BY is also specified in
the query itself.
See SQL Server 2005 breaking changes
Hope this helps,
Patrick
If building a temp table, move the ORDER BY clause from inside the temp table code block to the outside.
Not allowed:
SELECT * FROM (
SELECT A FROM Y
ORDER BY Y.A
) X;
Allowed:
SELECT * FROM (
SELECT A FROM Y
) X
ORDER BY X.A;
You don't need order by in your sub query. Move it out into the main query, and include the column you want to order by in the subquery.
however, your query is just returning a count, so I don't see the point of the order by.
A subquery (nested view) as you have it returns a dataset that you can then order in your calling query. Ordering the subquery itself will make no (reliable) difference to the order of the results in your calling query.
As for your SQL itself:
a) I seen no reason for an order by as you are returning a single value.
b) I see no reason for the sub query anyway as you are only returning a single value.
I'm guessing there is a lot more information here that you might want to tell us in order to fix the problem you have.
Add the Top command to your sub query...
SELECT
(
SELECT TOP 100 PERCENT
COUNT(1)
FROM
Seanslar
WHERE
MONTH(tarihi) = 4
GROUP BY
refKlinik_id
ORDER BY
refKlinik_id
) as dorduncuay
:)
maybe this trick will help somebody
SELECT
[id],
[code],
[created_at]
FROM
( SELECT
[id],
[code],
[created_at],
(ROW_NUMBER() OVER (
ORDER BY
created_at DESC)) AS Row
FROM
[Code_tbl]
WHERE
[created_at] BETWEEN '2009-11-17 00:00:01' AND '2010-11-17 23:59:59'
) Rows
WHERE
Row BETWEEN 10 AND 20;
here inner subquery ordered by field created_at (could be any from your table)
In this example ordering adds no information - the COUNT of a set is the same whatever order it is in!
If you were selecting something that did depend on order, you would need to do one of the things the error message tells you - use TOP or FOR XML
Try moving the order by clause outside sub select and add the order by field in sub select
SELECT * FROM
(SELECT COUNT(1) ,refKlinik_id FROM Seanslar WHERE MONTH(tarihi) = 4 GROUP BY refKlinik_id)
as dorduncuay
ORDER BY refKlinik_id
For me this solution works fine as well:
SELECT tbl.a, tbl.b
FROM (SELECT TOP (select count(1) FROM yourtable) a,b FROM yourtable order by a) tbl
Good day
for some guys the order by in the sub-query is questionable.
the order by in sub-query is a must to use if you need to delete some records based on some sorting.
like
delete from someTable Where ID in (select top(1) from sometable where condition order by insertionstamp desc)
so that you can delete the last insertion form table.
there are three way to do this deletion actually.
however, the order by in the sub-query can be used in many cases.
for the deletion methods that uses order by in sub-query review below link
http://web.archive.org/web/20100212155407/http://blogs.msdn.com/sqlcat/archive/2009/05/21/fast-ordered-delete.aspx
i hope it helps. thanks you all
For a simple count like the OP is showing, the Order by isn't strictly needed. If they are using the result of the subquery, it may be. I am working on a similiar issue and got the same error in the following query:
-- I want the rows from the cost table with an updateddate equal to the max updateddate:
SELECT * FROM #Costs Cost
INNER JOIN
(
SELECT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype -- *** This causes an error***
) CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, Costs.costtype
-- *** To accomplish this, there are a few options:
-- Add an extraneous TOP clause, This seems like a bit of a hack:
SELECT * FROM #Costs Cost
INNER JOIN
(
SELECT TOP 99.999999 PERCENT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype
) CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, Costs.costtype
-- **** Create a temp table to order the maxCost
SELECT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
INTO #MaxCost
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype
SELECT * FROM #Costs Cost
INNER JOIN #MaxCost CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, costs.costtype
Other possible workarounds could be CTE's or table variables. But each situation requires you to determine what works best for you. I tend to look first towards a temp table. To me, it is clear and straightforward. YMMV.
On possible needs to order a subquery is when you have a UNION :
You generate a call book of all teachers and students.
SELECT name, phone FROM teachers
UNION
SELECT name, phone FROM students
You want to display it with all teachers first, followed by all students, both ordered by. So you cant apply a global order by.
One solution is to include a key to force a first order by, and then order the names :
SELECT name, phone, 1 AS orderkey FROM teachers
UNION
SELECT name, phone, 2 AS orderkey FROM students
ORDER BY orderkey, name
I think its way more clear than fake offsetting subquery result.
I Use This Code To Get Top Second Salary
I am Also Get Error Like
The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP or FOR XML is also specified.
TOP 100 I Used To Avoid The Error
select * from (
select tbl.Coloumn1 ,CONVERT(varchar, ROW_NUMBER() OVER (ORDER BY (SELECT 1))) AS Rowno from (
select top 100 * from Table1
order by Coloumn1 desc) as tbl) as tbl where tbl.Rowno=2

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