Pulling individual integer value from hexadecimal value - c

Question

Here is my hex code:
42 4D C6 00 00 00 00 00 00 00 76 00 00 00 28 00
00 00 0A 00 00 00 0A 00 00 00 01 00 04 00 00 00
00 00 50 00 00 00 12 0B 00 00 12 0B 00 00 10 00
00 00 10 00 00 00 FF 00 00 00 00 FF 00 00 00 00
42 00 5A 5A 84 00 00 00 FF 00 FF 00 FF 00 00 FF
FF 00 08 FF FF 00 5A FF FF 00 FF FF FF 00 FF FF
FF 00 FF FF FF 00 FF FF FF 00 FF FF FF 00 FF FF
FF 00 FF FF FF 00 92 59 00 16 47 00 00 00 25 90
01 64 61 00 00 00 59 90 11 64 61 00 00 00 99 00
16 48 11 00 00 00 90 01 64 61 11 00 00 00 00 16
64 61 00 00 00 00 01 16 46 10 09 00 00 00 11 64
41 00 99 00 00 00 16 64 11 09 95 00 00 00 66 48
10 09 53 00 00 00
I know that the pixel "assignment" starts with the first line being (10 pixels wide):
92 59 00 16 47 00 00 00
I need to count how many times each colour is in the image, but I am unable to pull the individual integer value (ie: just the 9, then just the 2, then just the 5, and so on). The only value I am able to pull is "92" then "59" then "00"...
This is my code for that segment (the offset is 118 and the total hex values remaining are 80):
int nbr_each[NBRCOLOURS];
int ch, pixel;
fseek(fptr, 118, SEEK_SET);
for (count = 0; count < 81; count++)
{
pixel = fgetc(fptr);
nbr_each[pixel] = nbr_each[pixel] + 1;
}

Answer 1

fgetc will get you the individual characters.
first = fgetc(fptr); // '9'
second = fgetc(fptr); // '2'
space = fgetc(fptr); // ' '
Then convert each digit to a number 0..9 by subtracting off '0':
first -= '0';
second -= '0';
Then to count each digit, something like this:
nbr_each[first]++;
nbr_each[second]++;