For loop won't stop - c

Question

I've made an array that is between [0,1000], and I've printed it. Next step is to arrange the array using switch statements into five different cases 0 to 199, etc. When trying to do so the for loop won't stop. I tried putting a printf after countOne in case 1, no printout occurs either.
Any suggestions
Thanks for your help
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int n;
int arraySize;
int randN;
int rand();
int countOne = 0;
int countTwo = 0;
int countThree = 0;
int countFour = 0;
int countFive = 0;
int countSix = 0;
int *p;
int *p1;
int main()
{
printf("What is the size of the array\n");
scanf("%d", &n);
//MAKING THE N-size ARRAY
int array[n];
int i;
for (i = 0; i < n; i++) {
randN = rand() % 999;
array[i] = randN;
p = (int*)malloc(i * sizeof(int));
p[i] = array[i];
}
//SORTING THE N-size ARRAY
for (i = 0; i < n; i++) {
printf("%i\n", array[i]);
}
p = (int*)malloc(sizeof(int));
p1 = (int*)malloc(5 * sizeof(int));
p1[0] = countOne;
p1[1] = countTwo;
for (i = 0; i < n; i++) {
switch (i) {
case 1:
for (i = 0; array[i] >= 0 && array[i] <= 199; i++) {
countOne++;
}
case 2:
for (i = 0; array[i] >= 200 && array[i] <= 399; i++) {
countTwo++;
return countTwo;
}
}
}
}
HERE IS MY CODE AS OF CURRENT:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
int n;
int arraySize;
int randN;
int rand();
int countOne = 0;
int countTwo = 0;
int countThree = 0;
int countFour = 0;
int countFive = 0;
int countSix = 0;
int *p;
int *p1;
printf("What is the size of the array\n");
scanf("%d", &n);
//MAKING THE N-size ARRAY
int array[n];
int i;
for (i = 0 ; i < n; i++ )
{
randN=rand() % 999;
array[i]=randN;
p=(int*)malloc(i*sizeof(int));
p[i]= array[i];
}
//PRINTING THE N-size ARRAY
for (i = 0; i < n; i++)
{
printf("%i\n", array[i]);
}
//SORTING THE N-size ARRAY
int j;
for (j = 0 ; j < n ; j++)
{
switch(j)
{
case 1:
for(i = 0 ; array[i] >= 0 && array[i] <= 199; i++)
{
countOne++;
return countOne;
}
case 2:
for(i = 0 ; array[i] >= 200 && array[i] <= 399; i++)
{
countTwo++;
return countTwo;
}
}
}
HERE IS THE PRINT OUT:
What is the size of the array
3
823
7
347
There is 0 integers between 0 and 199
There is 0 integers between 200 and 399

Answer 1

The program has many problems.
Here is a simpler version:
#include <stdio.h>
#include <stdlib.h>
int compare_ints(const void *a, const void *b) {
const int *pa = a, *pb = b;
return (*pa > *pb) - (*pa < *pb);
}
int main(void) {
int i, n;
int stats[5] = { 0, 0, 0, 0, 0 };
printf("What is the size of the array?\n");
scanf("%d", &n);
//MAKING THE N-size ARRAY
int *array = malloc(n * sizeof(int));
int *saved = malloc(n * sizeof(int));
if (array == NULL || saved == NULL) {
printf("cannot allocate arrays\n");
exit(1);
}
for (i = 0; i < n; i++) {
int randN = rand() % 999;
saved[i] = array[i] = randN;
stats[randN / 200] += 1;
}
printf("initial array contents:\n);
for (i = 0; i < n; i++) {
printf("%i\n", array[i]);
}
printf("\n");
//SORTING THE N-size ARRAY
qsort(array, n, sizeof(*array), compare_ints);
printf("sorted array:\n);
for (i = 0; i < n; i++) {
printf("%i\n", array[i]);
}
printf("\n");
for (i = 0; i < 5; i++) {
printf("%d values between %d and %d\n", stats[i], i * 200, (i + 1) * 200 - 1);
}
printf("\n");
// do whatever else you are supposed to with array and saved
//...
free(array);
free(saved);
return 0;
}