latest full half hour as per the clock time data in SQL - sql-server

I trying to fetch data for the latest full half hour as per the clock time.
for example if getdate() return me '2016-11-14 10:14:25.567' , i want data from '2016-11-14 09:30:00.000' to '2016-11-14 10:00:00.000'

I think you want something like this;
DECLARE #DateVariable datetime; SET #DateVariable = GETDATE()
SELECT
#DateVariable Current_DateTime
,DATEADD(mi,-30, CONVERT(smalldatetime, ROUND(CAST(#DateVariable AS float) * 48.0,0,1)/48.0) ) From_Time
,CONVERT(smalldatetime, ROUND(CAST(#DateVariable AS float) * 48.0,0,1)/48.0) To_Time
Where the date variable is now (2016-11-14 16:26:52) it will give you the last full half hour
The result will look like this;
Current_DateTime From_Time To_Time
2016-11-14 16:26:52.073 2016-11-14 15:30:00 2016-11-14 16:00:00

Use DateADD(mi, -30, getdate())

Related

How to format a date with my own time part in SQL

I'm working on a SQL query which returns a integer which is the number of minutes between two given dates as follows
DATEDIFF(mi, date_one, getdate())
The above query returns difference in two dates in minutes but for getdate() I would want to supply my own time.
For example, consider
date_one= 2015-12-29 13:39:03.000
getdate() return current date and time ie., 2015-12-29 14:33:50.000
But, I want to change time part in getdate() to some 10:00:00.00 so that the getdate() is 2015-12-29 10:00:00.00 by passing an hour integer say 10.
May I know a good way to do that?
This will use getDate, but let you set your own hour. Just replace that second parameter (which is 10 with whichever hour you want). Use this expression in place of getDate() in your dateDiff function.
DATEADD(hh, 10, DATEADD(d, DATEDIFF(d, 0, getDate()), 0))
You can also add minutes, seconds, milliseconds, etc. to get what you need.
Here I am adding 633 minutes to make it 10:33 (change the first parameter to mi for minutes).
select DATEADD(mi, 633, DATEADD(d, DATEDIFF(d, 0, getDate()), 0))
See the documentation for other value for the first parameter: https://msdn.microsoft.com/en-us/library/ms186819.aspx
Here is how to use it:
DATEDIFF(mi, getDate(),
DATEADD(mi, 633, DATEADD(d, DATEDIFF(d, 0, getDate()), 0))
)
This will give you the minutes from the current time to 10:33 on the current day. Here is a sqlfiddle: http://sqlfiddle.com/#!6/9eecb7/5407
I find this function useful:
CREATE FUNCTION [dbo].[StripTimeFromDateTime]
(
#date DateTime
)
RETURNS DateTime
AS
BEGIN
RETURN DATEADD(dd, DATEDIFF(dd, 0, #date), 0)
END
This will knock the time off a datetime leaving it at 00:00:00.000. Then you can:
SELECT DATEADD(hour, 10, dbo.StripTimeFromDateTime(GetDate()))
Notice the example below:
select
cast('2015-12-28 12:15:00' as datetime),
getdate(),
cast(cast(convert(date, getdate()) as varchar(20)) + ' 10:00:00' as datetime);
|----------------------------|----------------------------|----------------------------|
| December, 28 2015 12:15:00 | December, 29 2015 20:42:35 | December, 29 2015 10:00:00 |
An example like the one you used:
with example as (
select cast('2015-12-28 12:15:00' as datetime) as date_one
)
select
date_one,
cast(cast(convert(date, getdate()) as varchar(20)) + ' 10:00:00' as datetime) as myown,
datediff(
mi,
date_one,
cast(cast(convert(date, getdate()) as varchar(20)) + ' 10:00:00' as datetime)
) as minutes
from example;
Result:
| date_one | myown | minutes |
|----------------------------|----------------------------|---------|
| December, 28 2015 12:15:00 | December, 29 2015 10:00:00 | 1305 |
Example on SQLFiddle: http://sqlfiddle.com/#!3/9eecb7/6599
The reason I used varchar is to have flexibility of typing a time such as '10:15:00' or other variations of time.
This one-liner will gives the current date with the time part replaced with the constant you want
select cast(cast(getdate() as date) as datetime) + cast(cast('10:00:00' as time) as datetime)
How this works:
Cast the getdate() result to date and then back to datetime to get the current date without the time.
select cast(cast(getdate() as date) as datetime)
Cast '10:00:00' to time and then to datetime to get 10:00:00 as datetime.
select cast(cast('10:00:00' as time) as datetime)
Add the two
select cast(cast(getdate() as date) as datetime) + cast(cast('10:00:00' as time) as datetime)
That's all
select DATEADD (hh,10, CONVERT(Datetime, CONVERT (date, GETDATE())))
First remove time and then add 10 hours.

Select records created in a 24 hour time-frame

I'm trying to query our database to find all records that were created between 6am yesterday and 6am today. This will be run in a report at any point during the day so set times/dates are useless.
I have this so far:-
SELECT * FROM DaySummaryDetail DSD
WHERE DSD.FromDateTime BETWEEN DATEADD(DAY, -1, GetDate())
AND DATEADD(Day, 1, GetDate())
But obviously this only works for 24 hours ago from right now until right now. I can't figure out how to apply a time as well as date.
Every example I find online seems slightly different and uses set dates/times ie, >= 20/02/2015 06:00:00.
I normally use Oracle SQL which would simply work using this:-
ptt.mod_date_time >= TRUNC (SYSDATE - 1) - 2 / 24
AND ptt.mod_date_time <= TRUNC (SYSDATE - 1) + 22 / 24
This would return results from 10pm to 10pm but the format appears totally different in SQL Server.
You can get the datetime values you are after by doing the following:
SELECT DATEADD(HOUR,6,CONVERT(DATETIME, CONVERT(DATE ,GETDATE()))) Today6AM,
DATEADD(HOUR,-18,CONVERT(DATETIME, CONVERT(DATE ,GETDATE()))) Yesterday6AM
By doing this: CONVERT(DATE ,GETDATE()) you are stripping off the time portion of today's date. Converting it back to datetime gives you midnight for today.
The query adds 6 hours to midnight of the current day for 6am today and subtracts 18 hours from midnight of the current day to give you 6am on the previous day.
Output:
Today6AM Yesterday6AM
================================================
2015-02-20 06:00:00.000 2015-02-19 06:00:00.000
So adding that to your query:
SELECT *
FROM DaySummaryDetail DSD
WHERE DSD.FromDateTime
BETWEEN DATEADD(HOUR,-18,CONVERT(DATETIME, CONVERT(DATE ,GETDATE())))
AND DATEADD(HOUR,6,CONVERT(DATETIME, CONVERT(DATE ,GETDATE())))
DECLARE #StartTimestamp datetime
DECLARE #EndTimestamp datetime
DECLARE #HourPartOfSearchRange nvarchar(6)
SET #HourPartOfSearchRange = ' 06:30'
SET #StartTimestamp =
CAST((CONVERT(varchar(11), DATEADD(DAY,-1,#CurrentUTCDateTime), 106) + #HourPartOfSearchRange) AS datetime)
SET #EndTimestamp =
CAST((CONVERT(varchar(11), #CurrentUTCDateTime, 106) + #HourPartOfSearchRange) AS datetime)
SELECT * FROM dbo.Test Where Timestamp Between #StartTimestamp AND #EndTimestamp
today 6am is
dateadd(hour,6,cast(cast(getdate() as date) as datetime))
cast(getdate() as date) truncates the timepart, cast it back as datetime because dateadd won't add hours otherwise and add 6hours
One solution would be like so:
select *
from DaySummaryDetail DSD
where DSD.FromDateTime between cast(cast(cast(getdate()-1 as date) as varchar(30)) + ' 06:00:00.000' as datetime)
and cast(cast(cast(getdate() as date) as varchar(30)) + ' 06:00:00.000' as datetime)
This should help ...
SELECT DATEADD( hour, 6, CAST(CAST(GETDATE(), AS Date) AS DateTime) ) AS 'Today#6am'
SELECT DATEADD( hour, 6, CAST(CAST(GETDATE()-1, AS Date) AS DateTime) ) AS 'Yesterday#6am'
In SQL Server 2012 you can use SMALLDATETIMEFROMPARTS to construct a datetime value that is today at 6am like this:
SMALLDATETIMEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), DAY(GETDATE()), 6, 0)
Output: 2015-02-20 06:00:00
then you can use the above expression in place of GETDATE() in the WHERE clause:
DECLARE #TodayAt6AM DATETIME = SMALLDATETIMEFROMPARTS(YEAR(GETDATE()),
MONTH(GETDATE()),
DAY(GETDATE()),
6,
0)
SELECT *
FROM DaySummaryDetail DSD
WHERE DSD.FromDateTime BETWEEN DATEADD(DAY, -1, #TodayAt6AM) AND
DATEADD(Day, 1, #TodayAt6AM)

SQL Date Range only show data for the last hour

I want to do a mssql date range to return the data for an hour time range. Meaning, I want to return the data for the last hour, but not for the last hour from the current time.
Declare #today datetime
set #today=GETDATE()
select * from table1 where
datetime>= DATEADD(hh,-2,#Today)
For example, the current time is 11:50:00 a.m. I would like the query to return all the data between 10:00:00 a.m. to 10:59:00 a.m. My variables cannot be static. I would like it dynamic, so no matter what time of the day I run the query it only return the last hour data no matter what time is it now. So it could be any time between 11:00:00 a.m. until 11:59:00 a.m., I still want the result to return data from 10 a.m until 10:59 a.m.
Thank you
Here's a slightly simpler way:
DECLARE #d SMALLDATETIME;
SELECT #d = DATEADD(HOUR, DATEDIFF(HOUR, '20000101', GETDATE()) - 1, '20000101');
SELECT #d;
Now you can use #d in your query, e.g.
WHERE col >= #d AND col < DATEADD(HOUR, 1, #d);
This is an open-ended date range. Please don't think about the "end" of the range or consider this a BETWEEN query. BETWEEN 10:00 AND 10:59 is not a very wise approach, because you may miss data from 10:59:00.003 -> 10:59:59.997. Background info on why BETWEEN is evil.
Try this one :
declare #lowerRange datetime =
dateadd(hh,datepart(hour,dateadd(hh,-1,getdate())) ,
cast(cast(getdate() as date) as smalldatetime) )
declare #upperRange datetime = dateadd(hour,1,#lowerRange)
select * from yourtable where yourdate between #lowerRange and #upperRange
This returns an hour range, of the previous hour to now; meaning that if it was 11:35AM, it would return 10 AM to 11 AM:
DECLARE #today DATETIME, #hour DATETIME, #hourtwo DATETIME
SET #today = GETDATE()
-- Test other times
--SET #today = '2013-11-04 11:37.22'
SELECT #hour = DATEADD(hh,-2,#today)
SELECT #hourtwo = DATEADD(hh,-1,#today)
SELECT CONVERT(SMALLDATETIME,ROUND(CAST(#hour as float) * (24/1),0)/(24/1)) AS PreviousHourBegin
SELECT CONVERT(SMALLDATETIME,ROUND(CAST(#hourtwo as float) * (24/1),0)/(24/1)) AS PreviousHourEnd
This should work:
DECLARE #D DATETIME
SET #D = GETDATE()
SELECT #D AS 'Date',
DATEADD(HOUR,-1,DATEADD(MINUTE,-(DATEPART(MINUTE, #D)),DATEADD(SECOND,-(DATEPART(SECOND, #D)),DATEADD(MILLISECOND,-(DATEPART(MILLISECOND, #D)),#D)))) AS 'Range start',
DATEADD(MINUTE,-(DATEPART(MINUTE, #D)),DATEADD(SECOND,-(DATEPART(SECOND, #D)),DATEADD(MILLISECOND,-(DATEPART(MILLISECOND, #D)),#D))) AS 'Range end'
For the date:
2013-11-04 17:35:51.843
This will return a range like:
Start: 2013-11-04 16:00:00.000
End: 2013-11-04 17:00:00.000
For times between 00:00:00-01:00:00 it will get the range 23:00:00-00:00:00 from the previous day.
declare #today datetime
set #today=GETDATE()
select #today, DATEADD(HOUR, -2, DATEADD(HOUR, DATEDIFF(HOUR, 0, #today), 0)), DATEADD(MINUTE, -1, DATEADD(HOUR, -1, DATEADD(HOUR, DATEDIFF(HOUR, 0, #today), 0)))
result:
2013-11-04 17:42:17.933 2013-11-04 15:00:00.000 2013-11-04 15:59:00.000

SQL Server remove milliseconds from datetime

select *
from table
where date > '2010-07-20 03:21:52'
which I would expect to not give me any results... EXCEPT I'm getting a record with a datetime of 2010-07-20 03:21:52.577
how can I make the query ignore milliseconds?
You just have to figure out the millisecond part of the date and subtract it out before comparison, like this:
select *
from table
where DATEADD(ms, -DATEPART(ms, date), date) > '2010-07-20 03:21:52'
If you are using SQL Server (starting with 2008), choose one of this:
CONVERT(DATETIME2(0), YourDateField)
LEFT(RTRIM(CONVERT(DATETIMEOFFSET, YourDateField)), 19)
CONVERT(DATETIMEOFFSET(0), YourDateField) -- with the addition of a time zone offset
Try:
SELECT *
FROM table
WHERE datetime >
CONVERT(DATETIME,
CONVERT(VARCHAR(20),
CONVERT(DATETIME, '2010-07-20 03:21:52'), 120))
Or if your date is an actual datetime value:
DECLARE #date DATETIME
SET #date = GETDATE()
SELECT CONVERT(DATETIME, CONVERT(VARCHAR(20), #date, 120))
The conversion to style 120 cuts off the milliseconds...
select * from table
where DATEADD(ms, DATEDIFF(ms, '20000101', date), '20000101') > '2010-07-20 03:21:52'
You'll have to trim milliseconds before comparison, which will be slow over many rows
Do one of these to fix this:
created a computed column with the expressions above to compare against
remove milliseconds on insert/update to avoid the read overhead
If SQL Server 2008, use datetime2(0)
Use CAST with following parameters:
Date
select Cast('2017-10-11 14:38:50.540' as date)
Output: 2017-10-11
Datetime
select Cast('2017-10-11 14:38:50.540' as datetime)
Output: 2017-10-11 14:38:50.540
SmallDatetime
select Cast('2017-10-11 14:38:50.540' as smalldatetime)
Output: 2017-10-11 14:39:00
Note this method rounds to whole minutes (so you lose the seconds as well as the milliseconds)
DatetimeOffset
select Cast('2017-10-11 14:38:50.540' as datetimeoffset)
Output: 2017-10-11 14:38:50.5400000 +00:00
Datetime2
select Cast('2017-10-11 14:38:50.540' as datetime2)
Output: 2017-10-11 14:38:50.5400000
For this particular query, why make expensive function calls for each row when you could just ask for values starting at the next higher second:
select *
from table
where date >= '2010-07-20 03:21:53'
Use 'Smalldatetime' data type
select convert(smalldatetime, getdate())
will fetch
2015-01-08 15:27:00
There's more than one way to do it:
select 1 where datediff(second, '2010-07-20 03:21:52', '2010-07-20 03:21:52.577') >= 0
or
select *
from table
where datediff(second, '2010-07-20 03:21:52', date) >= 0
one less function call, but you have to be beware of overflowing the max integer if the dates are too far apart.
One more way I've set up SQL Server queries to ignore milliseconds when I'm looking for events from a particular second (in a parameter in "YYYY-MM-DD HH:TT:SS" format) using a stored procedure:
WHERE
...[Time_stamp] >= CAST(CONCAT(#YYYYMMDDHHTTSS,'.000') as DateTime) AND
...[Time_stamp] <= CAST(CONCAT(#YYYYMMDDHHTTSS,'.999') as DateTime)
You could use something similar to ignore minutes and seconds too.
Please try this
select substring('12:20:19.8470000',1,(CHARINDEX('.','12:20:19.8470000',1)-1))
(No column name)
12:20:19
I'm very late but I had the same issue a few days ago. None of the solutions above worked or seemed fit. I just needed a timestamp without milliseconds so I converted to a string using Date_Format and then back to a date with Str_To_Date:
STR_TO_DATE(DATE_FORMAT(your-timestamp-here, '%Y-%m-%d %H:%i:%s'),'%Y-%m-%d %H:%i:%s')
Its a little messy but works like a charm.
May be this will help..
SELECT [Datetime] = CAST('20120228' AS smalldatetime)
o/p:
2012-02-28 00:00:00
Review this example:
declare #now datetimeoffset = sysdatetimeoffset();
select #now;
-- 1
select convert(datetimeoffset(0), #now, 120);
-- 2
select convert(datetimeoffset, convert(varchar, #now, 120));
which yields output like the following:
2021-07-30 09:21:37.7000000 +00:00
-- 1
2021-07-30 09:21:38 +00:00
-- 2
2021-07-30 09:21:37.0000000 +00:00
Note that for (1), the result is rounded (up in this case), while for (2) it is truncated.
Therefore, if you want to truncate the milliseconds off a date(time)-type value as per the question, you must use:
declare #myDateTimeValue = <date-time-value>
select cast(convert(varchar, #myDateValue, 120) as <same-type-as-#myDateTimeValue>);

How to calculate difference in hours (decimal) between two dates in SQL Server?

I have to calculate the difference in hours (decimal type) between two dates in SQL Server 2008.
I couldn't find any useful technique to convert datetime to decimal with 'CONVERT' on MSDN.
Can anybody help me with that?
UPDATE:
To be clear, I need the fractional part as well (thus decimal type). So from 9:00 to 10:30 it should return me 1.5.
DATEDIFF(hour, start_date, end_date) will give you the number of hour boundaries crossed between start_date and end_date.
If you need the number of fractional hours, you can use DATEDIFF at a higher resolution and divide the result:
DATEDIFF(second, start_date, end_date) / 3600.0
The documentation for DATEDIFF is available on MSDN:
http://msdn.microsoft.com/en-us/library/ms189794%28SQL.105%29.aspx
Just subtract the two datetime values and multiply by 24:
Select Cast((#DateTime2 - #DateTime1) as Float) * 24.0
a test script might be:
Declare #Dt1 dateTime Set #Dt1 = '12 Jan 2009 11:34:12'
Declare #Dt2 dateTime Set #Dt2 = getdate()
Select Cast((#Dt2 - #Dt1) as Float) * 24.0
This works because all datetimes are stored internally as a pair of integers, the first integer is the number of days since 1 Jan 1900, and the second integer (representing the time) is the number of (1) ticks since Midnight. (For SmallDatetimes the time portion integer is the number of minutes since midnight). Any arithmetic done on the values uses the time portion as a fraction of a day. 6am = 0.25, noon = 0.5, etc... See MSDN link here for more details.
So Cast((#Dt2 - #Dt1) as Float) gives you total days between two datetimes. Multiply by 24 to convert to hours. If you need total minutes, Multiple by Minutes per day (24 * 60 = 1440) instead of 24...
NOTE 1: This is not the same as a dotNet or javaScript tick - this tick is about 3.33 milliseconds.
DATEDIFF but note it returns an integer so if you need fractions of hours use something like this:-
CAST(DATEDIFF(ss, startDate, endDate) AS decimal(precision, scale)) / 3600
Using Postgres I had issues with DATEDIFF, but had success with this:
DATE_PART('day',(delivery_time)::timestamp - (placed_time)::timestamp) * 24 +
DATE_PART('hour',(delivery_time)::timestamp - (placed_time)::timestamp) +
DATE_PART('minute',(delivery_time)::timestamp - (placed_time)::timestamp) / 60
which gave me an output like "14.3"
You are probably looking for the DATEDIFF function.
DATEDIFF ( datepart , startdate , enddate )
Where you code might look like this:
DATEDIFF ( hh , startdate , enddate )
DATEDIFF(minute,startdate,enddate)/60.0)
Or use this for 2 decimal places:
CAST(DATEDIFF(minute,startdate,enddate)/60.0 as decimal(18,2))
Declare #date1 datetime
Declare #date2 datetime
Set #date1 = '11/20/2009 11:00:00 AM'
Set #date2 = '11/20/2009 12:00:00 PM'
Select Cast(DateDiff(hh, #date1, #date2) as decimal(3,2)) as HoursApart
Result = 1.00
SELECT DATEDIFF(hh, firstDate, secondDate)
FROM tableName
WHERE ...

Resources