I wonder if it somehow is possible to extend the block context menu in episerver? What we want to do is to somehow get two display option menus and to use them combined to render our output.
Screenshot of the block context menu
We would like to give the user the possibility to have two display options like this:
RIGHT | LEFT | CENTER
Render for 1 | 2 | 3 | 4 columns
This could be solved with only some CSS magic, but we do not want the behaviour overall. Only if defined.
Hope to get some input on this :)
I agree with Ted Nyberg, I don't think there is an easy fix to this either. To achieve this behavior, I think you will have to modify how Display Options are retrieved.
Mattias Olsson wrote a blog post on localizing Display Options in 2015. It does not solve your problem, but modifies the way display options are fetched from Episerver. I would suggest implementing that, and adding an extra rest store (or modifying the existing) for your secondary display option type, and finally modifying the dojo widget to accommodate the new display options.
Related
I'm new on reactjs, and I want to create a table to show some data. In the project I'm working, we are using Ag-Grid datagrid.
I already have created it with basic usage, but my question is:
Supose I have 100 rows as enter, how I can display in datagrid just the 10 firsts?
I stil wanna load all data (for filtering, sort, etc), just don't wanna show all by default.
I'm looking at documentation and do some search, but don't find the proper way to do it.
Edit: I already see the pagination options (the default solution provided by documentation), but in my case, at least for now I don't want pagination. Just wanna render the X first rows (the extra will be ommited in table, but have to be loaded in UI, if not, I could use autoHeight).
Thanks in advance.
I'm assuming you are using the Client Side Row Model and not loading data from a Server. In which case, the easiest way to achieve this would be to show the 10 rows, and add more rows (depending on when you want to load them) via Transaction Updates, please see the documentation on this here
you can use pagination:
documentation reference
I'm new to creating Layouts in Filemaker (I'm not using the latest version; am using Filemaker 14 Advanced instead), and I need to know: How can I conditionally/programmatically hide and show drop-down menus on the Layout, based on a selection in another drop-down menu? For instance: Let's say I have a drop-down menu called "Race," and it has three selections: "Human, Vampire, Werewolf." If I choose "Human," I want another drop-down menu called "Class" to appear; if I choose "Vampire," I want a different drop-down menu, called "Clans," to appear instead; if I choose Werewolf, then I want a drop-down menu called "Tribes" to appear. How can I engineer this using Filemaker's built-in language, or is there some other way to do it? Step-by-step instructions and/or code, please; like I said, I'm really, really new to this and to databases in general. Thanks!
You can conditionally hide layout objects by putting a calculation in the Hide Object When blank in the Behavior section of the Data tab on the Inspector palette.
That said, there are relational ways to have your dropdowns change their contents based selections in other fields. That is a lot more flexible, but (of course) more complex. What you want to set up is called a Dynamic Value list and is based on the values in a related table, filtered by the choices you made in the previous fields.
The calculation basically boiled down to just a single "equals" statement, or a bunch of them, simply singling out the value that would need to be selected in order to hide the layout objects I wanted hidden. Thanks for the help, guys! :-)
In my case, I wanted the new dropdown menus to stay shown even if many options were chosen in the first menu. I used the Pattern Count function (https://fmhelp.filemaker.com/help/10/fmp/en/html/func_ref3.33.73.html) to specify that if the answer to the last dropdown menu contained this optioned checked, the new menu would be shown by writing the following : Not PatternCount(table::variable;"text in one of the options")
I have a dropdown containing 100+ options in it. Can it be paginated so that when user selects the dropdown it shows only 10 options with pager.Is there any angular plugin to do so.Thanks
I've personally never seen such a widget and i think it's a bit weird to be honest. The user wouldn't expect that behaviour from a dropdown which harm the usability quite a bit.
I would recomment to simply use a normal dropdown instead - if you think of a standard country-dropdown for example (Germany, France, Italy etc.) it holds around 100 entries as well but doesn't do some unexpected behaviour like pagination in it.
The standard select doesn't support this behaviour for sure and i'm not aware of any public widget that does.
So if you really want to do this you will probably have to implement it on your own.
Yes it can, but the pagination should happen a little bit special way. There is a plugin, called ngInfiniteScroll which does the pagination based on where additional content for a web page is appended dynamically to the bottom of the page as the user approaches the end of the content.
You may try to use this, but then you have to have your custom dropdown built. In this way you can achieve a convenient usage of a dropdown without showing 100+ hits on start.
ngInfiniteScroll website: https://sroze.github.io/ngInfiniteScroll/
Another question for you Filemaker Pro experts. The database I am developing starts with a Main layout with a number of buttons (e.g. insert new item, show all items, etc.). Each button is associated to a script, which takes the user to the relevant layout. In each of these layouts I show the buttons in a row, and highlight the current layout with inverse colour.
My problem is that some of the buttons lead to the same layout, viewed in different modes, and I don't know how to conditionally highlight the right button.
For instance, Insert new item and Show all items take to the same layout, however in the first case the script views the layout as a form and inserts a new record, while in the second I view as a list and show all records. The layout is the same, though, so I'd need to enact a conditional formatting based on something. How do I do that, and what should I check against?
Thanks in advance for any help.
Regards.
Presumably you are currently using the formula: Get (LayoutName) to decide on your conditional formula, why not try additionally using formulas: Get(WindowMode) and Get(LayoutViewState)?
You could conditionally format the button if (which sends user to MyLayout in browse mode):
Get(WindowMode)=0 and Get(LayoutName)="MyLayout"
Or (which sends user to MyLayout in form view):
Get(LayoutViewState)=0 and Get(LayoutName)="MyLayout"
.
Other functions which may help could be Get(FoundCount) and Get(TotalRecordCount). You can see the entire list of Get functions here.
I'm new to Drupal but I've found my way around it pretty easily. There's just one thing I haven't found out how to do, and it's so simple it has to be possible.
I created a template for the site's homepage as it will have a different layout (did it creating page--front.tpl-php). This page will display only the main menu, an image and a text of the company's mission statement. I've done everything but the mission text and I have no idea how to do just that: simply put a block of text there.
I know I can hard-code it on the HTML but I want my client to be able to change it eventually if he wants to, in a graphic way. I tried creating a content type but I can't remove the title field and some submitted info; I thought of using Views but it seems too complicated for what I need, isn't it?
The image I used is hard-coded on he HTML as I know it won't change, but maybe I should have created a view with both the image and the text? But then how would I get rid of the title field and submission info?
Can someone please suggest the best way, if possible, to do this? Perhaps I'm over-complicating.
Thank you.
The easiest way would be to create a region in your theme and then put a block into that region only on the home page.
In mytheme.info:
...
regions[front] = Front Page Text
...
In page--front.tpl.php:
echo render($page['front']);
Then in your blocks administration page create a block and assign it to the "Front Page Text" region with the content you want to output. You could also limit the block's visibility to <front> if you want to be sure, although if you don't output that region in any other template file it shouldn't make a difference.