Select top 2 distinct for each id and date - sql-server

Question

I have a table like this :
Table1:
[Id] [TDate] [Score]
1 1.1.00 50
1 1.1.00 60
2 1.1.01 50
2 1.1.01 70
2 1.3.01 40
3 1.1.00 80
3 1.1.00 30
3 1.2.00 40
My desired output should be like this:
[ID] [TDate] [Score]
1 1.1.00 60
2 1.1.01 70
2 1.3.01 40
3 1.1.00 80
3 1.2.00 40
So fare, I have written this:
SELECT DISTINCT TOP 2 Id, TDate, Score
FROM
( SELECT Id, TDate, Score, ROW_NUMBER() over(partition by TDate order by Score) Od
FROM Table1
) A
WHERE A.Od = 1
ORDER BY Score
But it gives me :
[ID] [TDate] [Score]
2 1.1.01 70
3 1.1.00 80
of course I can do this:
"select top 2 ...where ID = 1"
and then:
union
`"Select top 2 ... where ID = 2"`
etc..
but I have a 100,000 of this..
Any way to generalize it to any Id?
Thank you.

Answer 1

WITH TOPTWO AS (
SELECT Id, TDate, Score, ROW_NUMBER()
over (
PARTITION BY TDate
order by SCORE
) AS RowNo
FROM [table_name]
)
SELECT * FROM TOPTWO WHERE RowNo <= 2

Answer 2

Your output doesn't make sense. Let me assume you want two rows per id. Then the query would look like:
SELECT TOP 2 Id, TDate, Score
FROM (SELECT Id, TDate, Score,
ROW_NUMBER() over (partition by id order by Score DESC) as seqnum
FROM Table1
) t
WHERE seqnum <= 2
ORDER BY Score;
Notes:
This assumes that you want two rows per id. Hence, id is in the PARTITION BY.
The WHERE now selects two rows per group in the PARTITION BY.
There is no need for SELECT DISTINCT in the outer query -- at least for this question.

Answer 3

Try this : Make partition by ID and TDate and sort by score in descending order
ROW_NUMBER() over(partition by ID,TDate order by Score DESC) Od
Complete script
WITH CTE AS(
SELECT *,
ROW_NUMBER() over(partition by ID,TDate order by Score DESC) RN
FROM TableName
)
SELECT *
FROM CTE
WHERE RN = 1

Answer 4

Unless I am missing something this can be done with a simple group by
First I prepare a temp table for testing :
declare #table table (ID int, TDate varchar(10), Score int)
insert into #Table values(1, '1.1.00', 50)
insert into #Table values(1, '1.1.00', 60)
insert into #Table values(2, '1.1.01', 50)
insert into #Table values(2, '1.1.01', 70)
insert into #Table values(2, '1.3.01', 40)
insert into #Table values(3, '1.1.00', 80)
insert into #Table values(3, '1.1.00', 30)
insert into #Table values(3, '1.2.00', 40)
Now lets do a select on this table
select ID, TDate, max(Score) as Score
from #table
group by ID, TDate
order by ID, TDate
The result is this :
ID TDate Score
1 1.1.00 60
2 1.1.01 70
2 1.3.01 40
3 1.1.00 80
3 1.2.00 40
So all you need to do is change #table to your table name and you are done