C is there a workaround to allow dynamic function calls? - c

I have read that C does not support dynamic function calls. My program has an ever growing number of test cases implemented as separate functions like -
int testcase1(void);
int testcase2(void);
int testcase3(void);
Each time I add a new test case, I also have have to add the call to my main function like -
int main(int argc, char **argv){
assert(!testcase1());
assert(!testcase2());
assert(!testcase3());
}
I would prefer to call something like assert(!testcase*()) where * matches any string which resolves to a valid function name in my program.
Can you think of a more convenient solution?

If you all your testcases have same signature then you can use an array of function pointers:
void (*func[])() = { testcase1, testcase2 };
for (size_t i = 0; i < sizeof(func)/sizeof(func[0]); i++) {
assert(!func[i]());
}

The best solution is likely to write a few extra lines of code when you add new test cases - it really isn't a big issue. I would recommend something along the lines of the function pointer array, as suggested in another answer.
However, just to show that everything is possible in C if you throw ugly macros at the problem, here is a not recommended alternative:
#include <assert.h>
#include <stdbool.h>
#include <stdio.h>
#define TEST_CASES \ // list of "x macros"
X(testcase1) \
X(testcase2) \
X(testcase3)
#define X(func) bool func (void); // declare function prototypes
TEST_CASES
#undef X
bool (*const test_cases[])(void) = // array of read-only function pointers
{
#define X(func) &func, // point at each function
TEST_CASES
#undef X
};
int main (void)
{
for(size_t i=0; i<sizeof(test_cases)/sizeof(test_cases[0]); i++)
{
assert(test_cases[i]());
}
}
bool testcase1 (void) { puts(__func__); return true; }
bool testcase2 (void) { puts(__func__); return true; }
bool testcase3 (void) { puts(__func__); return false; }
Output:
testcase1
testcase2
testcase3
Assertion failed!
For each new test case, you would only have to write a function definition and then add it to the "x macro" list TEST_CASES. However, you need very good reasons to introduce ugly tricks like these in production code!

You can use function pointers. Read also about closures (but C99 or C11 don't have them) and callbacks.
Many operating systems provide dynamic loading. On POSIX operating systems (such as Linux or MacOSX) you can get a function pointer (actually an address) from its name in some library (or in the program executable) using dlopen & dlsym. Other operating systems may provide similar functionalities.
At last, you should consider having your testing main function be generated by some script (or some program emitting C code), using metaprogramming techniques. So you would write something which generates the C code of your testing main having a long sequence of assert, and improve your build procedure (e.g. your Makefile if using make) to run appropriately that specialized C code generator. Details are of course specific to your code. You might add some conventions (e.g. add some special comment to be parsed by your test generator, etc...).

I decided to follow #Nominal Animal and #Basile Starynkevitch's approach. In mymainprog.c, I added -
int runtests(void){
void *testh;
int (*testp)(void);
char *dlmsg;
int rc;
char funcname[8];
int testnum;
testh = dlopen("libsmtests.so", RTLD_LAZY);
if (!testh){
printf("%s\n", dlerror());
return 1;
}
dlerror();
for (testnum =1; testnum < 1000; testnum++){
sprintf(funcname,"testcase%d", testnum);
*(void **) (&testp) = dlsym(testh, funcname);
dlmsg = dlerror();
if (dlmsg == NULL) {
rc = (*testp)();
printf("%s called, rc=%d\n", funcname, rc);
}
}
dlclose(testh);
return 0;
}
I add my testcases to a separate file (testcases.c) like this -
int testcase1(void){
return [some testcase expression]
}
int testcase2(void){
return [another testcase expression]
}
and then compile it as a shared library with position-independant code (-fPIC) to libsmtests.so. The advantage is slightly less typing since I don't need to code a call to testNNNN() after adding the implementation of a new functionint testcaseNNN(void) to testcases.c

Related

Is it possible to call functions from arrays in C? [duplicate]

This question already has answers here:
How can I use an array of function pointers?
(12 answers)
Closed 4 years ago.
When I was making my terminal i was wondering if I can call a function by array.
(This code is not done yet so please code is a bit messy.)
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <windows.h>
#include <unistd.h>
#include <limits.h>
#define true 1
#define false 0
typedef int bool;
/* Static */
static char Input[CHAR_MAX];
static char CurrentDirectory[CHAR_MAX];
static char *Command;
static char *Argument;
static char *Commands[]={"test","test2"};
/* Functions */
int Check_Command();
int test();
int test2();
/* --------- */
int main(){
printf("#######################\n\tterminal\n\tType \"help\" for the list of commands\n#######################\n");
prompt:
printf(">");
fgets(Input,CHAR_MAX,stdin);
int res=Check_Command();
if(res==0){printf("Unknown Command!\n");}
goto prompt;
}
/* Check_Command() function returns 0 if doesn't suceed and returns 1 of it suceeds */
int Check_Command(){
//Since input variable is static, no need to send in arguments
Input[strcspn(Input,"\r\n")]=0;
Command=strtok(Input," ");
Argument=strtok(NULL," ");
int x=0;
while(x<sizeof(Commands)){
if(strcmp(Command,Commands[x])==0){
Commands[x](); <----- Can I call a function like this?
return 1;
}
x++;
}
return 0;
}
/* Commands */
int test(){
printf("Success!\n");
getchar();
exit(0);
}
int test2(){
print("Success [2] \n");
getchar();
exit(0);
}
If this possible then this would be lit, Im too lazy to make commands into a executable and using if statements for all commands.
if you are too lazy to read the whole code here is a basic concept (UNTESTED):
static *Commands[]={"test","test2"};
int main(){
char *Command="test";
int x=0;
while(x<sizeof(Commands)){
if(strcmp(Command,Commands)==0){
Commands[x]();
}
x++
}
}
int test(){
printf("Hi");
}
int test2(){
printf("hey");
}
Edit:
static char Commands[]={test,test2}; DOES NOT WORK
This also includes the "possible duplicate" answer. (Im using Mingw, Windows 10)
It appears that you want to be able to take in a string such as test2 from the user, and then invoke the function test2(). There are two main ways you can approach this:
Homebrew structure mapping names to function pointers.
Using 'dynamic library loading' and function name resolution.
Array of structures
For the first, you define a structure such as:
struct FuncName
{
const char *name;
int (*function)(void);
};
And you can then define an array of these:
struct FuncName functions[] =
{
{ "test", test },
{ "test2", test2 },
};
enum { NUM_FUNCTIONS = sizeof(functions) / sizeof(functions[0]) };
When you get a name from the user, you can search through the array of names and find the matching function pointer to call.
int invoke_function(const char *name)
{
for (int i = 0; i < NUM_FUNCTIONS; i++)
{
if (strcmp(name, functions[i].name) == 0)
{
return (*functions[i].function)();
// Or just: return functions[i].function();
}
}
return -1; // No match found
}
This works reliably on all systems, but the demerit is that you must create the table of function pointers when you compile the program.
Dynamic library
The alternative is to use functions dlopen() and dlsym() from the <dlsym.h> header on Unix (POSIX) systems, or the equivalent on Windows.
Normally, you expect to find the functions in dynamically loaded libraries loaded with dlopen(), but there's usually a way to search the main executable for the names instead (pass a null pointer as the file name to dlopen() on POSIX systems). You can then call dlsym() to get the function pointer corresponding to the name you specify, which you can call.
void *dlh = dlopen(NULL, RTLD_NOW);
int (*funcptr)(void) = (int (*)(void))dlsym("test", dlh);
return (*funcptr)();
This omits error checking and you need the cast to convert from an object pointer (void *) to a function pointer because the C standard does not require that to be doable, but POSIX does (see the specification of
dlsym() already linked to).
Non-uniform function signatures
With both solutions, life is easy if all the callable functions have the same interface. Life is much messier if the different functions have different interfaces (so some expect no arguments, some expect one, some expect two, and the types of the arguments vary between functions, as do the return types). Expect to use lots of casts and be prepared to bludgeon the compiler into submission — isolate the code from everything else so as to leave the non-portable part well separated from the main code.
Beware: no compiler was consulted about the validity of any of this code!

c how to evaluate function pointer using function name

This is my snippet:
typedef void (*FUNCPT)(void);
void func1();
int main(){
FUNCPT fpt1;
char *s = "func1";
return 0;
}
I can evaluate fpt1 like this :
fpt1 = func1;
But there is some reason that I must use function name to evaluate function pointer, I expect to get same value by something like this:
fpt1 = (FUNCPT)s;
How can I achive this?
The only way to evaluate a function name to a function pointer (without referring to a fixed table of symbols vs. names in your own code) is using shared libraries and dlopen(), dlsym() and the likes in the Linux/Unix world and the appropriate equivalents in the Windows world.
Put the functions you want to resolve into a shared library
Open that shared library from your program using dlopen
Find the symbol by name using dlsym
Cast that returned address into a proper function pointer and call it
This is, however, more an OS than a C question. Without stating your platform, further help is not possible.
I don't think there is any portable way to do that. I think you need to write your own code for that. For instance a look-up table like:
#include <stdio.h>
void func1() {printf("func1\n");}
void func2() {printf("func2\n");}
void func3() {printf("func3\n");}
typedef void (*FUNCPT)(void);
typedef struct lookup
{
FUNCPT f;
char name[32];
} lookup;
lookup lookup_table[] = {
{func1, "func1"},
{func2, "func2"},
{func3, "func3"},
};
FUNCPT getFuncByName(char* str)
{
int i;
for (i=0; i < (sizeof(lookup_table)/sizeof(lookup)); ++i)
{
if (strcmp(str, lookup_table[i].name) == 0) return lookup_table[i].f;
}
return NULL;
}
int main(){
FUNCPT fpt = getFuncByName("func2");
if (fpt) fpt();
return 0;
}

Function mocking in C?

I'm writing a unit-test to check some API calls. I am using check to test. My module is build with CMake (idk if it matters).
My test calls a function (which I need to test) and this function makes a call to another binary.
Simplified version of it looks like this.
/* unitTest.c */
#include "libraryAPI.h"
void letsMakeACall(void)
{
ck_assert_eq(foo("water"), 0);
}
-- Module I am working on---
/*libraryAPI.c*/
#include "legacyLib.h"
void foo(const char *drink )
{
if (checkDrink(drink)!=0)
{
return 1;
}else
{
return 0;
}
}
----LEGACY BINARY---
/*legacyLib.c*/
static const char* expected = "water";
void checkDrink(const char *drink)
{
if(drink == expected)
{
/*There are also a dozen functions being called which depend on legacy module initialisation*/
return 0;
}else{
return 1;
}
}
I'd like to mock response from legacyLib, because otherwise it call dozens of functions and breaks. My initial idea was to add some ifdef conditions when tests are being run, but it is against guidelines.
Because it is basically a call interception I don't know what it a best(or working) solution. What can I use to solve it?
I am also unsure how to solve this generally, I have posted a similar question, but in some cases you can do the following (presuming you are testing individual functions):
Include the .c file instead of the header .h, but after you "rename" your mocked function using a define directive:
#define checkDrink checkDrink_mocked
// preprocessor will now replace all occurrences of "checkDrink"
// with "checkDrink_mocked"
int checkDrink_mocked(const char *drink);
#include "legacyLib.c"
#undef checkDrink
Implement the renamed function:
int checkDrink_mocked(const char *drink)
{
return 15;
}

Is it possible to exchange a C function implementation at run time?

I have implemented a facade pattern that uses C functions underneath and I would like to test it properly.
I do not really have control over these C functions. They are implemented in a header. Right now I #ifdef to use the real headers in production and my mock headers in tests. Is there a way in C to exchange the C functions at runtime by overwriting the C function address or something? I would like to get rid of the #ifdef in my code.
To expand on Bart's answer, consider the following trivial example.
#include <stdio.h>
#include <stdlib.h>
int (*functionPtr)(const char *format, ...);
int myPrintf(const char *fmt, ...)
{
char *tmpFmt = strdup(fmt);
int i;
for (i=0; i<strlen(tmpFmt); i++)
tmpFmt[i] = toupper(tmpFmt[i]);
// notice - we only print an upper case version of the format
// we totally disregard all but the first parameter to the function
printf(tmpFmt);
free(tmpFmt);
}
int main()
{
functionPtr = printf;
functionPtr("Hello world! - %d\n", 2013);
functionPtr = myPrintf;
functionPtr("Hello world! - %d\n", 2013);
return 0;
}
Output
Hello World! - 2013
HELLO WORLD! - %D
It is strange that you even need an ifdef-selected header. The code-to-test and your mocks should have the exact same function signatures in order to be a correct mock of the module-to-test. The only thing that then changes between a production-compilation and a test-compilation would be which .o files you give to the linker.
It is possible With Typemock Isolator++ without creating unnecessary new levels of indirection. It can be done inside the test without altering your production code. Consider the following example:
You have the Sum function in your code:
int Sum(int a, int b)
{
return a+b;
}
And you want to replace it with Sigma for your test:
int Sigma(int a, int b)
{
int sum = 0;
for( ; 0<a ; a--)
{
sum += b;
}
return sum;
}
In your test, mock Sum before using it:
WHEN_CALLED: call the method you want to fake.
ANY_VAL: specify the args values for which the mock will apply. in this case any 2 integers.
*DoStaticOrGlobalInstead: The alternative behavior you want for Sum.
In this example we call Sigma instead.
TEST_CLASS(C_Function_Tests)
{
public:
TEST_METHOD(Exchange_a_C_function_implementation_at_run_time_is_Possible)
{
void* context = NULL; //since Sum global it has no context
WHEN_CALLED(Sum (ANY_VAL(int), ANY_VAL(int))).DoStaticOrGlobalInstead(Sigma, context);
Assert::AreEqual(2, Sum(1,2));
}
};
*DoStaticOrGlobalInstead
It is possible to set other types of behaviors instead of calling an alternative method. You can throw an exception, return a value, ignore the method etc...
For instance:
TEST_METHOD(Alter_C_Function_Return_Value)
{
WHEN_CALLED(Sum (ANY_VAL(int), ANY_VAL(int))).Return(10);
Assert::AreEqual(10, Sum(1,2));
}
I don't think it's a good idea to overwrite functions at runtime. For one thing, the executable segment may be set as read-only and even if it wasn't you could end up stepping on another function's code if your assembly is too large.
I think you should create something like a function pointer collection for the one and the other set of implementations you want to use. Every time you want to call a function, you'll be calling from the selected function pointer collection. Having done that, you may also have proxy functions (that simply call from the selected set) to hide the function pointer syntax.

Generate two functions with C Preprocessor

I have a project, and a case where I have a few often-changed preprocessor #defines that control how it works--ex:
void myfunction(int num, mystruct* content) {
doSomethingTo(content);
//...
#ifdef FEATURE_X
feature_x(content);
#endif
}
This works fine, although it does have to be recompiled each time, so it's in the "stuff that has to be recompiled each time" file. I would like to push it into a [static] library instead. I'm ok with changing how it's called (already have a function pointer for picking myFunction), so I'd like that to turn into
void myfunction(int num, mystruct* content) {
doSomethingTo(content);
//...
}
void myfunction_featureX(int num, mystruct* content) {
doSomethingTo(content);
//...
feature_x(content);
}
I need to do this in a couple places, so using a separate library (one with and one without -D FEATURE_X) for each isn't an acceptable option. I could do it with copy/paste, but that results in code reuse that carries a risk of fixing a bug in one copy but not the other.
Have the featureX versions of functions call the mainline functions. In your example myfunction_featureX would call myfunction and then do its own thing.
Surely, this is the point at which you change the activation of Feature X from a compile time issue into a run-time issue:
void myfunction(int num, mystruct* content)
{
doSomethingTo(content);
//...
if (FeatureX_Enabled())
feature_x(content);
}
The FeatureX_Enabled() test might be a full function, or it might be simply test an appropriately scoped variable that is defined outside the function — a static variable in the file, or an external variable. This avoids having to futz with the function pointers; it's the same function called as now. Changing a table of function pointers is equivalent to changing a single variable — it involves changing the value of something stored outside the function to change the behaviour of the function.
Would it help if you put myfeature_x in a function table instead?
#include <stdio.h>
#include <string.h>
typedef struct {
int x,y;
} mystruct;
typedef void (*fn_ptr)(mystruct* content);
fn_ptr vtable[10];
#define FEATURE_X_INDEX 0
void feature_x(mystruct *content)
{
printf("y: %d\n", content->y);
}
void myfunction(int num, mystruct* content) {
printf("x: %d\n", content->x);
//...
if (vtable[FEATURE_X_INDEX]) {
vtable[FEATURE_X_INDEX](content);
}
}
int main(void)
{
bzero(vtable, sizeof(vtable));
mystruct s;
s.x = 1;
s.y = 2;
myfunction(0, &s);
if (1) {
//Of course you'd use a more sensible condition.
vtable[FEATURE_X_INDEX] = feature_x;
}
myfunction(0, &s);
return 0;
}
Output:
x: 1
x: 1
y: 2
Then all you need to do is populate the virtual function table with NULLs if that feature is not to be used, and with function pointers if it is to be used. This you can do from wherever you want - your static library for example.. or you can compile feature_x into a dynamic library, load it at runtime and if the loading succeeded populate the function table, and clear the table when the dynamically linked library is unloaded.
I think the only benefit this really gives you over Jonathan Leffler's method is that the code for feature_x doesn't actually need to be linked into the same binary as your other code. If all you need is a runtime switch to turn the feature on or off, a simple if statement should do the trick, as Jonathan Leffler suggested. (Incidentally, there's an if here, too - it checks the function table's content :) )

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