In my component's render function I have:
render() {
const items = ['EN', 'IT', 'FR', 'GR', 'RU'].map((item) => {
return (<li onClick={this.onItemClick.bind(this, item)} key={item}>{item}</li>);
});
return (
<div>
...
<ul>
{items}
</ul>
...
</div>
);
}
everything renders fine, however when clicking the <li> element I receive the following error:
Uncaught Error: Invariant Violation: Objects are not valid as a React
child (found: object with keys {dispatchConfig, dispatchMarker,
nativeEvent, target, currentTarget, type, eventPhase, bubbles,
cancelable, timeStamp, defaultPrevented, isTrusted, view, detail,
screenX, screenY, clientX, clientY, ctrlKey, shiftKey, altKey,
metaKey, getModifierState, button, buttons, relatedTarget, pageX,
pageY, isDefaultPrevented, isPropagationStopped, _dispatchListeners,
_dispatchIDs}). If you meant to render a collection of children, use an array instead or wrap the object using createFragment(object) from
the React add-ons. Check the render method of Welcome.
If I change to this.onItemClick.bind(this, item) to (e) => onItemClick(e, item) inside the map function everything works as expected.
If someone could explain what I am doing wrong and explain why do I get this error, would be great
UPDATE 1:
onItemClick function is as follows and removing this.setState results in error disappearing.
onItemClick(e, item) {
this.setState({
lang: item,
});
}
But I cannot remove this line as I need to update state of this component
I was having this error and it turned out to be that I was unintentionally including an Object in my JSX code that I had expected to be a string value:
return (
<BreadcrumbItem href={routeString}>
{breadcrumbElement}
</BreadcrumbItem>
)
breadcrumbElement used to be a string but due to a refactor had become an Object. Unfortunately, React's error message didn't do a good job in pointing me to the line where the problem existed. I had to follow my stack trace all the way back up until I recognized the "props" being passed into a component and then I found the offending code.
You'll need to either reference a property of the object that is a string value or convert the Object to a string representation that is desirable. One option might be JSON.stringify if you actually want to see the contents of the Object.
So I got this error when trying to display the createdAt property which is a Date object. If you concatenate .toString() on the end like this, it will do the conversion and eliminate the error. Just posting this as a possible answer in case anyone else ran into the same problem:
{this.props.task.createdAt.toString()}
I just got the same error but due to a different mistake: I used double braces like:
{{count}}
to insert the value of count instead of the correct:
{count}
which the compiler presumably turned into {{count: count}}, i.e. trying to insert an Object as a React child.
Just thought I would add to this as I had the same problem today, turns out that it was because I was returning just the function, when I wrapped it in a <div> tag it started working, as below
renderGallery() {
const gallerySection = galleries.map((gallery, i) => {
return (
<div>
...
</div>
);
});
return (
{gallerySection}
);
}
The above caused the error. I fixed the problem by changing the return() section to:
return (
<div>
{gallerySection}
</div>
);
...or simply:
return gallerySection
React child(singular) should be type of primitive data type not object or it could be JSX tag(which is not in our case). Use Proptypes package in development to make sure validation happens.
Just a quick code snippet(JSX) comparision to represent you with idea :
Error : With object being passed into child
<div>
{/* item is object with user's name and its other details on it */}
{items.map((item, index) => {
return <div key={index}>
--item object invalid as react child--->>>{item}</div>;
})}
</div>
Without error : With object's property(which should be primitive, i.e. a string value or integer value) being passed into child.
<div>
{/* item is object with user's name and its other details on it */}
{items.map((item, index) => {
return <div key={index}>
--note the name property is primitive--->{item.name}</div>;
})}
</div>
TLDR; (From the source below) : Make sure all of the items you're rendering in JSX are primitives and not objects when using React. This error usually happens because a function involved in dispatching an event has been given an unexpected object type (i.e passing an object when you should be passing a string) or part of the JSX in your component is not referencing a primitive (i.e. this.props vs this.props.name).
Source - codingbismuth.com
Mine had to do with forgetting the curly braces around props being sent to a presentational component:
Before:
const TypeAheadInput = (name, options, onChange, value, error) => {
After
const TypeAheadInput = ({name, options, onChange, value, error}) => {
I too was getting this "Objects are not valid as a React child" error and for me the cause was due to calling an asynchronous function in my JSX. See below.
class App extends React.Component {
showHello = async () => {
const response = await someAPI.get("/api/endpoint");
// Even with response ignored in JSX below, this JSX is not immediately returned,
// causing "Objects are not valid as a React child" error.
return (<div>Hello!</div>);
}
render() {
return (
<div>
{this.showHello()}
</div>
);
}
}
What I learned is that asynchronous rendering is not supported in React. The React team is working on a solution as documented here.
Mine had to do with unnecessarily putting curly braces around a variable holding a HTML element inside the return statement of the render() function. This made React treat it as an object rather than an element.
render() {
let element = (
<div className="some-class">
<span>Some text</span>
</div>
);
return (
{element}
)
}
Once I removed the curly braces from the element, the error was gone, and the element was rendered correctly.
For anybody using Firebase with Android, this only breaks Android. My iOS emulation ignores it.
And as posted by Apoorv Bankey above.
Anything above Firebase V5.0.3, for Android, atm is a bust. Fix:
npm i --save firebase#5.0.3
Confirmed numerous times here
https://github.com/firebase/firebase-js-sdk/issues/871
I also have the same problem but my mistake is so stupid. I was trying to access object directly.
class App extends Component {
state = {
name:'xyz',
age:10
}
render() {
return (
<div className="App">
// this is what I am using which gives the error
<p>I am inside the {state}.</p>
//Correct Way is
<p>I am inside the {this.state.name}.</p>
</div>
);
}
}
Typically this pops up because you don't destructure properly. Take this code for example:
const Button = text => <button>{text}</button>
const SomeForm = () => (
<Button text="Save" />
)
We're declaring it with the = text => param. But really, React is expecting this to be an all-encompassing props object.
So we should really be doing something like this:
const Button = props => <button>{props.text}</button>
const SomeForm = () => (
<Button text="Save" />
)
Notice the difference? The props param here could be named anything (props is just the convention that matches the nomenclature), React is just expecting an object with keys and vals.
With object destructuring you can do, and will frequently see, something like this:
const Button = ({ text }) => <button>{text}</button>
const SomeForm = () => (
<Button text="Save" />
)
...which works.
Chances are, anyone stumbling upon this just accidentally declared their component's props param without destructuring.
Just remove the curly braces in the return statement.
Before:
render() {
var rows = this.props.products.map(product => <tr key={product.id}><td>{product.name}</td><td>{product.price}</td></tr>);
return {rows}; // unnecessary
}
After:
render() {
var rows = this.props.products.map(product => <tr key={product.id}><td>{product.name}</td><td>{product.price}</td></tr>);
return rows; // add this
}
I had the same problem because I didn't put the props in the curly braces.
export default function Hero(children, hero ) {
return (
<header className={hero}>
{children}
</header>
);
}
So if your code is similar to the above one then you will get this error.
To resolve this just put curly braces around the props.
export default function Hero({ children, hero }) {
return (
<header className={hero}>
{children}
</header>
);
}
I got the same error, I changed this
export default withAlert(Alerts)
to this
export default withAlert()(Alerts).
In older versions the former code was ok , but in later versions it throws an error. So use the later code to avoid the errror.
This was my code:
class App extends Component {
constructor(props){
super(props)
this.state = {
value: null,
getDatacall : null
}
this.getData = this.getData.bind(this)
}
getData() {
// if (this.state.getDatacall === false) {
sleep(4000)
returnData("what is the time").then(value => this.setState({value, getDatacall:true}))
// }
}
componentDidMount() {
sleep(4000)
this.getData()
}
render() {
this.getData()
sleep(4000)
console.log(this.state.value)
return (
<p> { this.state.value } </p>
)
}
}
and I was running into this error. I had to change it to
render() {
this.getData()
sleep(4000)
console.log(this.state.value)
return (
<p> { JSON.stringify(this.state.value) } </p>
)
}
Hope this helps someone!
If for some reason you imported firebase. Then try running npm i --save firebase#5.0.3. This is because firebase break react-native, so running this will fix it.
In my case it was i forgot to return a html element frm the render function and i was returning an object . What i did was i just wrapped the {items} with a html element - a simple div like below
<ul>{items}</ul>
Just remove the async keyword in the component.
const Register = () => {
No issues after this.
In my case, I added a async to my child function component and encountered this error. Don't use async with child component.
I got this error any time I was calling async on a renderItem function in my FlatList.
I had to create a new function to set my Firestore collection to my state before calling said state data inside my FlatList.
My case is quite common when using reduce but it was not shared here so I posted it.
Normally, if your array looks like this:
[{ value: 1}, {value: 2}]
And you want to render the sum of value in this array. JSX code looks like this
<div>{array.reduce((acc, curr) => acc.value + curr.value)}</div>
The problem happens when your array has only one item, eg: [{value: 1}].
(Typically, this happens when your array is the response from server so you can not guarantee numbers of items in that array)
The reduce function returns the element itself when array has only one element, in this case it is {value: 1} (an object), it causes the Invariant Violation: Objects are not valid as a React child error.
You were just using the keys of object, instead of the whole object!
More details can be found here: https://github.com/gildata/RAIO/issues/48
import React, { Component } from 'react';
import PropTypes from 'prop-types';
class SCT extends Component {
constructor(props, context) {
super(props, context);
this.state = {
data: this.props.data,
new_data: {}
};
}
componentDidMount() {
let new_data = this.state.data;
console.log(`new_data`, new_data);
this.setState(
{
new_data: Object.assign({}, new_data)
}
)
}
render() {
return (
<div>
this.state.data = {JSON.stringify(this.state.data)}
<hr/>
<div style={{color: 'red'}}>
{this.state.new_data.name}<br />
{this.state.new_data.description}<br />
{this.state.new_data.dependtables}<br />
</div>
</div>
);
}
}
SCT.propTypes = {
test: PropTypes.string,
data: PropTypes.object.isRequired
};
export {SCT};
export default SCT;
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
If you are using Firebase and seeing this error, it's worth to check if you're importing it right. As of version 5.0.4 you have to import it like this:
import firebase from '#firebase/app'
import '#firebase/auth';
import '#firebase/database';
import '#firebase/storage';
Yes, I know. I lost 45 minutes on this, too.
I just put myself through a really silly version of this error, which I may as well share here for posterity.
I had some JSX like this:
...
{
...
<Foo />
...
}
...
I needed to comment this out to debug something. I used the keyboard shortcut in my IDE, which resulted in this:
...
{
...
{ /* <Foo /> */ }
...
}
...
Which is, of course, invalid -- objects are not valid as react children!
I'd like to add another solution to this list.
Specs:
"react": "^16.2.0",
"react-dom": "^16.2.0",
"react-redux": "^5.0.6",
"react-scripts": "^1.0.17",
"redux": "^3.7.2"
I encountered the same error:
Uncaught Error: Objects are not valid as a React child (found: object
with keys {XXXXX}). If you meant to render a collection of children,
use an array instead.
This was my code:
let payload = {
guess: this.userInput.value
};
this.props.dispatch(checkAnswer(payload));
Solution:
// let payload = {
// guess: this.userInput.value
// };
this.props.dispatch(checkAnswer(this.userInput.value));
The problem was occurring because the payload was sending the item as an object. When I removed the payload variable and put the userInput value into the dispatch everything started working as expected.
If in case your using Firebase any of the files within your project.
Then just place that import firebase statement at the end!!
I know this sounds crazy but try it!!
I have the same issue, in my case,
I update the redux state, and new data parameters did not match old parameters, So when I want to access some parameters it through this Error,
Maybe this experience help someone
My issue was simple when i faced the following error:
objects are not valid as a react child (found object with keys {...}
was just that I was passing an object with keys specified in the error while trying to render the object directly in a component using {object} expecting it to be a string
object: {
key1: "key1",
key2: "key2"
}
while rendering on a React Component, I used something like below
render() {
return this.props.object;
}
but it should have been
render() {
return this.props.object.key1;
}
If using stateless components, follow this kind of format:
const Header = ({pageTitle}) => (
<h1>{pageTitle}</h1>
);
export {Header};
This seemed to work for me
Something like this has just happened to me...
I wrote:
{response.isDisplayOptions &&
{element}
}
Placing it inside a div fixed it:
{response.isDisplayOptions &&
<div>
{element}
</div>
}
I am beginner developer and I am working on react (gatsby, TS, styled components) project. I am getting this error:
"React does not recognize the isOpen prop on a DOM element. If you intentionally want it to appear in the DOM as a custom attribute, spell it as lowercase isopen instead. If you accidentally passed it from a parent component, remove it from the DOM element."
export const Navigation = () => {
const [isNavigationOpen, setIsNavigationOpen] = useState(false);
const { isTablet } = useQuery();
const showNavbar = () => {
setIsNavigationOpen((previousState) => !previousState);
};
const renderElement = isTablet ? (
<>
<SvgStyled
src='bars_icon'
isOpen={isNavigationOpen}
onClick={showNavbar}
/>
<MobileNavigation isOpen={isNavigationOpen}>
{NAVIGATION_DATA.map(({ id, url, text }) => (
<LinkMobile key={id} to={url}>
<ExtraSmallParagraph>{text}</ExtraSmallParagraph>
</LinkMobile>
))}
</MobileNavigation>
</>
) : (
<FlexWrapper>
{NAVIGATION_DATA.map(({ id, url, text }) => (
<LinkDekstop key={id} to={url}>
<ExtraSmallParagraph>{text}</ExtraSmallParagraph>
</LinkDekstop>
))}
</FlexWrapper>
);
return renderElement;
};
I am sure that I am missing some fundamental react stuff or something. Maybe someone could help me and explain the reason of this error.
When this happens it is because all props passed to the styled component are then also passed down to the DOM element that you are styling.
You've likely a component that looks like the following:
const SvgStyled = styled(SVG)<{ isOpen: boolean }>`
// your CSS and logic referencing the `isOpen` prop
`;
To resolve this issue you refactor the styled component definition and explicitly pass only the props you want to the element being styled. Use an anonymous function component and destructure the prop you don't want to pass on to the DOM element, and spread the rest of the props. This ensures the className prop that styled-components is creating a CSS class for is passed through.
Example:
interface SvgStyledProps {
className?: string,
isOpen: boolean,
}
const SvgStyled = styled(({ isOpen, ...props}) => (
<Svg {...props} />
))<SvgStyledProps>`
// your CSS and logic referencing the `isOpen` prop
`;
For any other Typescript specifics/caveats with styled-components see docs.
As of styled components v5.1, you can alternatively prevent undesired props from being passed down to your React node by prefixing it with a dollar sign ($) and designating it as a transient prop:
const SvgStyled = styled(SVG)<{ $isOpen: boolean }>`
// your CSS and logic referencing the `$isOpen` prop
`;
// SVG does NOT receive props.$isOpen
docs
I'm trying to create a wrapper component around the react-router-dom NavLink component.
I would like my custom component to accept all of NavLinks props, and proxy them down to NavLink.
However when I do this, I'm getting:
Warning: React does not recognize the staticContext prop on a DOM
element. If you intentionally want it to appear in the DOM as a custom
attribute, spell it as lowercase staticcontext instead. If you
accidentally passed it from a parent component, remove it from the DOM
element.
A working demo of the issue can be found here:
https://codesandbox.io/s/w0n49rw7kw
There is a way to overcome that is using:
const { to, staticContext, ...rest } = this.props;
So your ...rest will never contain staticContext
This is a common problem with a simple solution as documented in the React documentation:
The unknown-prop warning will fire if you attempt to render a DOM
element with a prop that is not recognized by React as a legal DOM
attribute/property. You should ensure that your DOM elements do not
have spurious props floating around.
The spread operator can be used to pull variables off props, and put
the remaining props into a variable.
function MyDiv(props) {
const { layout, ...rest } = props
if (layout === 'horizontal') {
return <div {...rest} style={getHorizontalStyle()} />
} else {
return <div {...rest} style={getVerticalStyle()} />
}
}
You can also assign the props to a new object and delete the keys that
you’re using from the new object. Be sure not to delete the props from
the original this.props object, since that object should be considered
immutable.
function MyDiv(props) {
const divProps = Object.assign({}, props);
delete divProps.layout;
if (props.layout === 'horizontal') {
return <div {...divProps} style={getHorizontalStyle()} />
} else {
return <div {...divProps} style={getVerticalStyle()} />
}
}
This happens because you probably used {...props} somewhere in your component.
Example from React:
function MyDiv(props) {
const { layout, ...rest } = props
if (layout === 'horizontal') {
return <div {...rest} style={getHorizontalStyle()} />
} else {
return <div {...rest} style={getVerticalStyle()} />
}
}
We grab layout separately so that it won't be contained in {...rest}.
The given answer by the React docs was not quite good enough for my situation, so I found/developed one which isn't perfect, but is at least not so much of a hassle.
You can see the Q/A in which it arose here:
What is Reacts function for checking if a property applies?
The gist is, use a function to pick the bad props out for you.
const SPECIAL_PROPS = [
"key",
"children",
"dangerouslySetInnerHTML",
];
const defaultTester = document.createElement("div")
function filterBadProps(props: any, tester: HTMLElement = defaultTester) {
if(process.env.NODE_ENV !== 'development') { return props; }
// filter out any keys which don't exist in reacts special props, or the tester.
const out: any = {};
Object.keys(props).filter((propName) =>
(propName in tester) || (propName.toLowerCase() in tester) || SPECIAL_PROPS.includes(propName)
).forEach((key) => out[key] = props[key]);
return out;
}
Personally, I felt that the warning was completely useless in the first place, so I added a line which skips the check entirely when not in development mode (and warnings are suppressed). If you feel that the warnings have merit, just remove the line:
if(process.env.NODE_ENV !== 'development') { return props; }
You can use it like this:
public render() {
const tooManyProps = this.props;
const justTheRightPropsForDiv = filterBadProps(tooManyProps);
const justTheRightPropsForSpan = filterBadProps(tooManyProps, document.createElement("span"));
return (<div {...justTheRightPropsForDiv}>
<span {...justTheRightPropsForSpan} />
</div>)
}
If someone has this issue with react-admin, check if you don't have a Link as a child of Admin. Like this:
<Admin layout={props => <Layout/>}>
<Link to="/something">something</Link> <-- causing issue
</Admin>
Just move it to another component. For instance, inside the Layout.
I got the same issue when passing data in child component with camelCase property.
Warning: React does not recognize the moreInfo prop on a DOM element.
If you intentionally want it to appear in the DOM as a custom attribute,
spell it as lowercase moreinfo instead. If you accidentally passed it
from a parent component, remove it from the DOM element.
<CenteredModal
moreInfo={viewType}
/>
To fix that error, I used all lowercase letters for property.
<CenteredModal
moreinfo={viewType}
/>