Bash associative array with list as value - arrays

Question

I have to work with an output of a Java tool, which returns a map data structure that looks like HashMap<String, ArrayList<String>. I have to work with BASH and i tried to declare it as an associative array, what is very similar to a map. The declaration of the associative array in bash should be in one line, i try to do this as following.
ARRAY=(["sem1"]=("first name" "second name") ["sem2"]=("third name") ["sem3]=OTHER_LITS)
But this creates the following error:
bash: syntax error near unexpected token `('
I can define this line by line, but i want to have it in one line. How can i define a assoviative array in bash in only one line?

Answer 1

BTW, associative array, dictionary or map - all come into the one abstract data type (let's call it a dictionary).
So, here is the solution for storing array as values in the dictionary of Bash (4+ version).
Note, that array in Bash is a space delimited list of strings (so no any spaces inside the element, i.e. string), so we could write a quoted list:
"firstname middlename secondname"
as a value of the s1 key in our X dictionary:
declare -A X=(
['s1']="firstname middlename secondname"
['s2']="surname nickname"
['s3']="other"
)
Now we can get the value of the s1 key as array:
declare -a names=(${X[s1]})
Variable names now contains array:
> echo $names
firstname
> echo ${names[1]}
middlename
> echo ${#names[#]}
3
Finally, your question part where the strings with spaces were shown:
"first name", "second name"
Let's do a trick - represent a space as a special symbol sequence (it could be just one symbol), for example, double underscores:
"first__name", "second__name"
Declare our dictionary again, but with "escaped" spaces inside array elements:
declare -A X=(
['s1']="first__name middle__name second__name"
['s2']="surname nickname"
['s3']="other"
)
In this case after we get the value of the s1 key as array:
declare -a names=(${X[s1]})
We need to post process our array elements to remove __ the space-replacements to the actual space symbols. To do this we simply use replace commands of Bash strings:
> echo ${names/__/ }
first name
> echo ${names[1]/__/ }
middle name
> echo ${#names[#]}
3

Answer 2

In the absence of multi-dimensional array support in BASH, you can use this word-around associative array. Each key in the associative array is string concatenation of map-index,array-list-index:
# use one line declaration
declare -A array=([sem1,0]="first name" [sem1,1]="second name" [sem2,0]="third name" [sem3,0]="foo bar")
# loop thrpugh the map array
for i in "${!array[#]}"; do echo "$i => ${array[$i]}"; done
sem2,0 => third name
sem1,0 => first name
sem1,1 => second name
sem3,0 => foo bar

Answer 3

A more ergonomic solution that doesn't force the manipulation of the keys.
# your data with spaces
array=(1 '2 with space' 3 "4 with space and ' symbol")
declare -p array
# quote it with " and store it, your data can't contain double quote
declare -A associative=([x]=x [array]=$(printf '"%s" ' "${array[#]}"))
declare -p associative
# get your data in another array
eval deserialized_array=(${associative[array]})
declare -p deserialized_array
echo ${deserialized_array[3]}
# or let bash handle everything
# note: array contain data with double quote character
array=(1 '2 with space' 3 "4 with space and ' \" symbol")
declare -A associative=([x]=x [array]=$(declare -p array))
declare -p associative
array=() # make sure data is gone
# get the data in the same array
eval ${associative[array]}
echo ${array[3]}