Decode bits in C - c

Question

I'm trying to decode binary that was encoded (most significant byte first) with the following loop.
int ch; // Has a value of, for example, 97 (which evaluates to 'a' with putchar(ch))
for (int i = 0; i < CHAR_BIT; i++) {
printf("%d", !!((ch << i) & 0x80));
}
So far I have tried:
unsigned int byte[CHAR_BIT]; // Filled elsewhere
unsigned char result = 0;
for (int i = 0; i < CHAR_BIT; i++) {
result |= (byte[i] == '1') << ((CHAR_BIT - 1) - i);
}
putchar(result);
But the output is wrong, it seems as if the characters were shifted the wrong amount. Assuming the first block of code is in a file called prog1 and the second is in prog2, the output of this shell command should be abc but it is `bb (literal back tick followed by bb).
echo "abc" | ./prog1 | ./prog2

Answer 1

This works for me:
prog1.c
#include <stdio.h>
#define CHAR_BIT 8
void encode(int c) {
for (int i = 0; i < CHAR_BIT; i++) {
printf("%d", !!((c << i) & 0x80));
}
}
int main() {
int c;
while ((c = getchar()) != EOF) {
encode(c);
}
printf("\n");
return 0;
}
prog2.c
#include <stdio.h>
#include <string.h>
#define CHAR_BIT 8
void decode(char *byte) {
int c = 0;
for (int i = 0; i < CHAR_BIT; i++) {
c |= (byte[i] == '1') << ((CHAR_BIT - 1) - i);
}
putchar(c);
}
int main() {
char byte[CHAR_BIT + 1];
while (scanf("%8s", byte) == 1) {
decode(byte);
}
return 0;
}
EXAMPLE
> echo "abc" | ./prog1
01100001011000100110001100001010
> echo "abc" | ./prog1 | ./prog2
abc
>
If the encode/decode logic is the same as yours, then this line is suspect:
unsigned int byte[CHAR_BIT]; // Filled elsewhere
and knowing what transpired elsewhere might help to explain what went wrong.