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So I need to calculate the determinant matrix on 2x2 matrix, simple one..
If you can, please write the code, because i don't understand like in the other thread, it's like i'm reading an English Literature + Code..
#include<stdio.h>
int main(){
int x[2][2]={{1,2},{3,4}};
int i,j,d;
for(i=0;i<=1;i++){
for(j=0;j<=1;j++){
printf(" %d ", x[i][j]);
}
printf(" \n");
}
return 0;
}
Thank You!
You don't need a loop to calculate the determinant of a 2x2 matrix, simply use:
int result = (x[0][0] * x[1][1]) - (x[0][1] * x[1][0]);
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Which could be a good method to compute the distance between a cluster and a point to decide if the point can be assigned to the cluster?
I read about Mahalanobis distance that I have implemented in this way:
float mahalanobis(float *cluster, float *point, const float *variance, int d) {
float distance=0;
for (int i = 1; i < d; ++i) {
distance+=pow((point[i] - cluster[i])/variance[i-1], 2);
}
return sqrt(distance);
}
but it seems that the result isn't good. Maybe I'm wrong about the implementation
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#include<stdio.h>
int main(){
int a,b[101],i,j,sum=0;
scanf("%d",&a);
for(i=0;i<a;i++){
for(j=0;j<3;j++){
scanf("%d",&b[j]);
sum=sum+b[j];
}
}
if(sum==0) printf("YES\n");
else printf("NO\n");
return 0;
}
outputs are showed perfectly but online judge didn't accept.
online judge message"wrong answer on test 81".
link of problem"http://codeforces.com/problemset/problem/69/A"
The problem is asking to check if the sum of all vectors is zero.
Sum of vectors is element-wise addition of vectors, not simple summation of all elements.
Your program will fail in, for example, this case:
1
1 0 -1
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This code prints the array elements, but I can't understand how does k[x-1] gives the array elements.
#include<stdio.h>
int main()
{
int x[]={2,4,6,8,10},k=1;
while (k<=5)
{
printf ("%3d",k[x-1]);
k++;
}
return 0;
}
Array indexes start at 0 in C. An array like int x[]={2,4,6,8,10} will have a value x[0]=2 and so forth. Typically, when iterating through an array, a convention like this is used:
for (int i = 0; i < length; i++)
printf("%3d",x[i]);
Since the code you provided begins the indexing at 1, you have to subtract one to fetch the proper element.
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1.2^2+2.3^2+3.4^2+4.5^2+ need to calculate the sum up-to nth number with C programming.
But I can't find any way to solve the program.
When the user in put 4 as the value of n, the sum will be the total of 1.2^2+2.3^2+3.4^2+4.5^2.
Can anyone help me get the algorithm?
A simple for loop would do it:
int compute(int n) {
int i, sum=0;
for(i=1; i<=n; i++) {
int val = i*(i+1)*(i+1);
sum += val;
}
return sum;
}
for(int i=0; i<n; i++). This is a for loop.
Inside the loop, store the loop iterator i in a double variable.
Add 1.2 to it.
Multiply it by itself.
Do something with the result: print it, and/or add it to a sum variable etc.
Do not use the xor operator ^ for this.
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Following is the code to obtain matrix like 11 12 13 etc... I am not getting desired results since long. Help me with the solution.
#include<stdio.h>
int main() {
int i,j;
for(i=1;i<5;i++){
for(j=1;j<5;j++){
printf("%d %d",i,j);
}
printf("\n");
}
fgetc(stdin);
}
Probably because you have a space between the digits:
printf("%d %d",i,j);
Shouldn't it be:
printf("%d%d ",i,j);
for your desired output?
Shouldn't printf("%d %d",i,j); actually be printf("%d%d ",i,j);?