pivot day of the month from row to column with sum value - sql-server

Question

I have a data with sum value and mapping to the day that matched with this SQL
sample data and code
http://sqlfiddle.com/#!3/ca364/6
but my problem is I can't pivot a date row to column
i need to pivot (query from sqlfiddle above) to shown as this example
Date 1 2 3 4 5 6 7 8 9 to end of the month
TAS0B065B999P999 0 0 0 0 0 4900 9900 0 -96600
TAS1B065B999P999 0 0 0 0 0 0 0 0 0
TAS2B065B999P999 0 0 0 0 0 0 0 0 0
TAS3B065B999P999 0 0 0 0 0 0 0 0 0
TAS4B065B999P999 0 0 0 0 0 0 0 0 0
TAS5B065B999P999 0 0 0 0 0 0 0 0 0
TAS6B065B999P999 0 0 0 0 0 0 0 0 0
TAS7B065B999P999 0 0 0 0 0 0 0 0 0
TAS8B065B999P999 0 0 0 0 0 0 0 0 0
TAS9B065B999P999 0 0 0 0 0 0 0 0 0
TASAB065B999P999 0 0 0 0 0 0 0 0 0
TDS1B065B999P999 0 0 0 0 0 0 0 0 0
TDS2B065B999P999 0 0 0 0 0 0 0 0 0
TDS3B065B999P999 0 0 0 0 0 0 0 0 0
TRS1B065B999P999 0 0 0 0 0 0 0 0 0
TRS2B065B999P999 0 0 0 -72900 0 74900 -74900 90900 0
TRS3B065B999P999 0 0 0 21100 0 0 0 0 0
Sample code
WITH t1
AS (SELECT dt,TERM,
SumCashOUT,
DATEADD(MONTH, DATEDIFF(MONTH, '1900-01-01', dt), '1900-01-01') AS firstInMonth,
DATEADD(DAY, -1, DATEADD(MONTH, DATEDIFF(MONTH, '1900-01-01', dt)+1, '1900-01-01')) AS lastInMonth
FROM
(
SELECT CONVERT( DATE, TA_DATE) AS dt,TERM,
DATENAME(dw, CONVERT( DATE, TA_DATE)) AS dn,
DATEPART(DW, CONVERT( DATE, TA_DATE)) AS dtdw,
OUT1 + OUT2 + OUT3 + OUT4 AS SumCashOUT
FROM CASH1609
GROUP BY TA_DATE,
TERM,
OUT1,
OUT2,
OUT3,
OUT4
) AS st
GROUP BY dt,TERM,
dn,
dtdw,
SumCashOUT),
Calendar
AS (SELECT DISTINCT
DATEADD(Day, c.number, t1.firstInMonth) AS d
FROM t1
JOIN master..spt_values AS c ON type = 'P'
AND DATEADD(DAY, c.number, t1.firstInMonth) BETWEEN t1.firstInMonth AND t1.lastInMonth)
SELECT DATEPART(dd, d) AS Date,TERM,
CASE
WHEN CONVERT( NUMERIC(16, 0), SumCashOUT) IS NULL
THEN 0
ELSE CONVERT(NUMERIC(16, 0), SumCashOUT)
END AS SumCashOUT
FROM calendar AS c
LEFT JOIN t1 ON t1.dt = c.d
LEFT JOIN holiday ON c.d = holiday.HDATE
ORDER BY DAte ASC;

Answer 1

You will have to use PIVOT Command in SQL Server.
This will deliver the desired output:
;WITH tab (TERM, DOM, CASH) AS
(
SELECT TERM,
DAY(CAST(TA_DATE AS DATE)) AS DOM,
OUT1 + OUT2 + OUT3 + OUT4 AS CASH
FROM CASH1609
)
SELECT *
FROM tab
PIVOT
(
SUM (CASH)
FOR DOM IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],
[12],[13],[14],[15],[16],[17],[18],[19],[20],[21],
[22],[23],[24],[25],[26],[27],[28],[29],[30],[31])
) AS pvt
The "tab" CTE prepares the Columns DOM(Day-Of-Month) and CASH.
PIVOT needs an aggregate function (SUM in your case) AND the possible values for the pivot-column.
Note: This will deliver NULL for each non-existing DOM, just replace
SELECT * FROM tab
with
SELECT TERM, COALESCE([1],0), COALESCE([2],0), etc... FROM tab...