Create multiple generations of children process - c

So I'm trying to understand the concept of grandchildren.
I'm able to create a given number of sons (i.e brothers) but I don't know how to create multiple generations .
This is what I did to create one grandson :
int main ()
{
//Displaying the father
printf("Initial : Father = %d\n\n", getpid());
/****** FORK *******/
pid_t varFork, varFork2;
varFork = fork();
if(varFork == -1) //If we have an error, we close the process
{
printf("ERROR\n");
exit(-1);
}
else if (varFork == 0) //if we have a son, we display it's ID and it's father's
{
printf("SON 1\n");
printf(" ID = %d, Father's ID = %d\n", getpid(), getppid());
varFork2 = fork();//creation of the second fork
if(varFork2 == -1) //If we have an error, we close the process
{
printf("ERROR\n");
exit(-1);
}
else if (varFork2 == 0) //now we have the son of the first son, so the grandson of the father
{
printf("\nGRANDSON 1\n");
printf(" ID = %d, Father's ID = %d\n", getpid(), getppid());
}
else sleep(0.1);/*we wait 0.1sec so that the father doesn't die before we can
display it's id (and before the son process gets adopted by a user process descending from the initial process)*/
}
else //in the other case, we have a father
{
sleep(0.1);//again we put the father asleep to avoid adoption
}
return 0;
}
How can I create X generations of grandsons, X being a global variable (1son, 1 grandson, 1 great-grandson, etc.) ?

How can I create X generations
Before forking, decrement X and continue forking inside the child until X is 0.
Or inside the child decrement X and only continue forking if after decrementing it X still is greater 0.
The code might look like this:
#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <errno.h>
void logmsg(const char *, int);
#define MAX_GENERATIONS (4)
int main(void)
{
pid_t pid = 0;
for (size_t g = 0; g < MAX_GENERATIONS; ++g)
{
logmsg("About to fork.", 0);
switch (pid = fork())
{
case -1:
{
logmsg("fork() failed", errno);
break;
}
case 0:
{
logmsg("Hello world. I am the new child.", 0);
break;
}
default:
{
char s[1024];
snprintf(s, sizeof s, "Successfully created child carrying PID %d.", (int) pid);
logmsg(s, 0);
g = MAX_GENERATIONS; /* Child forked, so we are done, set g to end looping. */
break;
}
}
}
logmsg("Sleeping for 3s.", 0);
sleep(3);
if (0 != pid) /* In case we forked a child ... */
{
logmsg("Waiting for child to end.", 0);
if (-1 == wait(NULL)) /* ... wait for the child to terminate. */
{
logmsg("wait() failed", errno);
}
}
logmsg("Child ended, terminating as well.", 0);
return EXIT_SUCCESS;
}
void logmsg(const char * msg, int error)
{
char s[1024];
snprintf(s, sizeof s, "PID %d: %s", (int) getpid(), msg);
if (error)
{
errno = error;
perror(s);
exit(EXIT_FAILURE);
}
puts(s);
}
The output should look similar to this:
PID 4887: About to fork.
PID 4887: Successfully created child carrying PID 4888.
PID 4887: Sleeping for 3s.
PID 4888: Hello world. I am the new child.
PID 4888: About to fork.
PID 4888: Successfully created child carrying PID 4889.
PID 4888: Sleeping for 3s.
PID 4889: Hello world. I am the new child.
PID 4889: About to fork.
PID 4889: Successfully created child carrying PID 4890.
PID 4890: Hello world. I am the new child.
PID 4890: About to fork.
PID 4889: Sleeping for 3s.
PID 4890: Successfully created child carrying PID 4891.
PID 4890: Sleeping for 3s.
PID 4891: Hello world. I am the new child.
PID 4891: Sleeping for 3s.
PID 4888: Waiting for child to end.
PID 4890: Waiting for child to end.
PID 4891: Child ended, terminating as well.
PID 4890: Child ended, terminating as well.
PID 4887: Waiting for child to end.
PID 4889: Waiting for child to end.
PID 4889: Child ended, terminating as well.
PID 4888: Child ended, terminating as well.
PID 4887: Child ended, terminating as well.
The difference with my code above compared to the proposal I made is that it counts upwards to X.

Related

Parent/Child process print

I'm writing a C program that creates a child process. After creating the child process, the parent process should ouput two messages: "I am the parent" then it should print "The parent is done". Same for child process "I am child" and "The child is done". However I want to make sure, the second message of the child is always done before the second message of the parent. How can I achieve to print "The child is done" and "The parent is done" rather than printing their pid?
#include <unistd.h>
#include <stdio.h>
main()
{
int pid, stat_loc;
printf("\nmy pid = %d\n", getpid());
pid = fork();
if (pid == -1)
perror("error in fork");
else if (pid ==0 )
{
printf("\nI am the child process, my pid = %d\n\n", getpid());
}
else
{
printf("\nI am the parent process, my pid = %d\n\n", getpid());
sleep(2);
}
printf("\nThe %d is done\n\n", getpid());
}
You could have a flag variable, that is set in the parent, but then the child clears it. Then simply check for that for the last output.
Something like
int is_parent = 1; // Important to create and initialize before the fork
pid = fork();
if (pid == -1) { ... }
if (pid == 0)
{
printf("\nI am the child process, my pid = %d\n\n", getpid());
in_parent = 0; // We're not in the parent anymore
}
else { ... }
printf("\nThe %s is done\n\n", is_parent ? "parent" : child");
Call wait(2) in the parent process for the child to complete.
else
{
wait(0);
printf("\nI am the parent process, my pid = %d\n\n", getpid());
}
You should check if wait() succeeds and main()'s return type should be int.

Fork() function in C

Below is an example of the Fork function in action. Below is also the output. My main question has to to do with the a fork is called how values are changed. So pid1,2 and 3 start off at 0 and get changed as the forks happen. Is this because each time a fork happens the values are copied to the child and the specific value gets changed in the parent? Basically how do values change with fork functions?
#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
int main() {
pid_t pid1, pid2, pid3;
pid1=0, pid2=0, pid3=0;
pid1= fork(); /* A */
if(pid1==0){
pid2=fork(); /* B */
pid3=fork(); /* C */
} else {
pid3=fork(); /* D */
if(pid3==0) {
pid2=fork(); /* E */
}
if((pid1 == 0)&&(pid2 == 0))
printf("Level 1\n");
if(pid1 !=0)
printf("Level 2\n");
if(pid2 !=0)
printf("Level 3\n");
if(pid3 !=0)
printf("Level 4\n");
return 0;
}
}
Then this is the execution.
----A----D--------- (pid1!=0, pid2==0(as initialized), pid3!=0, print "Level 2" and "Level 4")
| |
| +----E---- (pid1!=0, pid2!=0, pid3==0, print "Level 2" and "Level 3")
| |
| +---- (pid1!=0, pid2==0, pid3==0, print "Level 2")
|
+----B----C---- (pid1==0, pid2!=0, pid3!=0, print nothing)
| |
| +---- (pid1==0, pid2==0, pid3==0, print nothing)
|
+----C---- (pid1==0, pid2==0, pid3!=0, print nothing)
|
+---- (pid1==0, pid2==0, pid3==0, print nothing)
Ideally below is how I would like to see it explained as this way makes sense to me. The * are where my main confusion lies. When the child forks for example pid1 = fork(); that creates a process with all the values of the parent, but does it then pass up a value like lets say 1 to the parents pid1? Meaning the child would have pid 1=0, pid2=0 and pid3=0 and the parent then as pid1=2 and pid2 and 3 equal to 0?
System call fork() is used to create processes. It takes no arguments and returns a process ID. The purpose of fork() is to create a new process, which becomes the child process of the caller. After a new child process is created, both processes will execute the next instruction following the fork() system call. Therefore, we have to distinguish the parent from the child. This can be done by testing the returned value of fork()
Fork is a system call and you shouldnt think of it as a normal C function. When a fork() occurs you effectively create two new processes with their own address space.Variable that are initialized before the fork() call store the same values in both the address space. However values modified within the address space of either of the process remain unaffected in other process one of which is parent and the other is child.
So if,
pid=fork();
If in the subsequent blocks of code you check the value of pid.Both processes run for the entire length of your code. So how do we distinguish them.
Again Fork is a system call and here is difference.Inside the newly created child process pid will store 0 while in the parent process it would store a positive value.A negative value inside pid indicates a fork error.
When we test the value of pid
to find whether it is equal to zero or greater than it we are effectively finding out whether we are in the child process or the parent process.
Read more about Fork
int a = fork();
Creates a duplicate process "clone?", which shares the execution stack. The difference between the parent and the child is the return value of the function.
The child getting 0 returned, and the parent getting the new pid.
Each time the addresses and the values of the stack variables are copied. The execution continues at the point it already got to in the code.
At each fork, only one value is modified - the return value from fork.
First a link to some documentation of fork()
http://pubs.opengroup.org/onlinepubs/009695399/functions/fork.html
The pid is provided by the kernel. Every time the kernel create a new process it will increase the internal pid counter and assign the new process this new unique pid and also make sure there are no duplicates. Once the pid reaches some high number it will wrap and start over again.
So you never know what pid you will get from fork(), only that the parent will keep it's unique pid and that fork will make sure that the child process will have a new unique pid. This is stated in the documentation provided above.
If you continue reading the documentation you will see that fork() return 0 for the child process and the new unique pid of the child will be returned to the parent. If the child want to know it's own new pid you will have to query for it using getpid().
pid_t pid = fork()
if(pid == 0) {
printf("this is a child: my new unique pid is %d\n", getpid());
} else {
printf("this is the parent: my pid is %d and I have a child with pid %d \n", getpid(), pid);
}
and below is some inline comments on your code
#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
int main() {
pid_t pid1, pid2, pid3;
pid1=0, pid2=0, pid3=0;
pid1= fork(); /* A */
if(pid1 == 0){
/* This is child A */
pid2=fork(); /* B */
pid3=fork(); /* C */
} else {
/* This is parent A */
/* Child B and C will never reach this code */
pid3=fork(); /* D */
if(pid3==0) {
/* This is child D fork'ed from parent A */
pid2=fork(); /* E */
}
if((pid1 == 0)&&(pid2 == 0)) {
/* pid1 will never be 0 here so this is dead code */
printf("Level 1\n");
}
if(pid1 !=0) {
/* This is always true for both parent and child E */
printf("Level 2\n");
}
if(pid2 !=0) {
/* This is parent E (same as parent A) */
printf("Level 3\n");
}
if(pid3 !=0) {
/* This is parent D (same as parent A) */
printf("Level 4\n");
}
}
return 0;
}
I think every process you make start executing the line you create so something like this...
pid=fork() at line 6. fork function returns 2 values
you have 2 pids, first pid=0 for child and pid>0 for parent
so you can use if to separate
.
/*
sleep(int time) to see clearly
<0 fail
=0 child
>0 parent
*/
int main(int argc, char** argv) {
pid_t childpid1, childpid2;
printf("pid = process identification\n");
printf("ppid = parent process identification\n");
childpid1 = fork();
if (childpid1 == -1) {
printf("Fork error !\n");
}
if (childpid1 == 0) {
sleep(1);
printf("child[1] --> pid = %d and ppid = %d\n",
getpid(), getppid());
} else {
childpid2 = fork();
if (childpid2 == 0) {
sleep(2);
printf("child[2] --> pid = %d and ppid = %d\n",
getpid(), getppid());
} else {
sleep(3);
printf("parent --> pid = %d\n", getpid());
}
}
return 0;
}
//pid = process identification
//ppid = parent process identification
//child[1] --> pid = 2399 and ppid = 2398
//child[2] --> pid = 2400 and ppid = 2398
//parent --> pid = 2398
linux.die.net
some uni stuff

Create multiple child processes in UNIX

I want to write an UNIX program that creates N child processes, so that the first process creates one child process, then this child creates only one process that is its child, then the child of the child creates another child etc.
Here's my code:
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
int main()
{
int N=3;
int i=0;
printf("Creating %d children\n", N);
printf("PARENT PROCESS\nMy pid is:%d \n",getpid() );
for(i=0;i<N;i++)
{
pid_t pid=fork();
if(pid < 0)
{
perror("Fork error\n");
return 1;
}
else if (pid==0) /* child */
{
printf("CHILD My pid is:%d my parent pid is %d\n",getpid(), getppid() );
}
else /* parrent */
{
exit(0);
}
}
return 0;
}
The output that I expect is in the form:
Creating 3 children
PARENT PROCESS
My pid is 1234
CHILD My pid is 4567 my parent pid is 1234
CHILD My pid is 3528 my parent pid is 4567
CHILD My pid is 5735 my parent pid is 3528
The output I get in the terminal is
Creating 3 children
PARENT PROCESS
My pid is:564
CHILD My pid is:5036 my parent pid is 564
User#User-PC ~
$ CHILD My pid is:4804 my parent pid is 1
CHILD My pid is:6412 my parent pid is 4804
The problem is that the program doesn't seem to terminate. I should use Ctrl+C to get out of the terminal, which is not normal. Can you help me to fix this issue?
The children die when the parent dies.
In your case the parent exits before all the children have been created.
Try waiting for the children before exiting:
else /* parrent */
{
int returnStatus;
waitpid(pid, &returnStatus, 0); // Parent process waits for child to terminate.
exit(0);
}
try to wait the process with wait(NULL);
pid_t child = fork();
if (child == -1)
{
puts("error");
exit(0);
}
else if (child == 0)
{
// your action
}
else
{
wait(&child);
exit(0);
}
so your father will wait the child process to exit
The proposed cure is correct, but the reason stated is wrong. Children do not die with the parent. The line
CHILD My pid is:4804 my parent pid is 1
clearly indicates that by the time child called getppid() its parent is already dead, and the child has been reparented to init (pid 1).
The real problem is that after the child prints its message, it continues to execute the loop, producing more children, making your program into a fork bomb.

Create new process in separate function [c]

I wanna create spare process (child?) in specific function called eg. void process(). I want just to create that child process and do nothing with it. I just wanna it alive and do nothing while main() of my app will be working as I want.
In some point of my app's main() I will be killing child process and then respawn it again. Any ideas how to do that ?
I have something like that but when I'm using this function to create process I get everything twice. Its like after initiation of process() every statement is done twice and i dont want it. After adding sleep(100) after getpid() in child section seems working fine but I cannot kill it.
int process(int case){
if(case==1){
status=1;
childpid = fork();
if (childpid >= 0) /* fork succeeded */
{
if (childpid == 0) /* fork() returns 0 to the child process */
{
printf("CHILD PID: %d\n", getpid());
}
/* fork() returns new pid to the parent process *//* else
{
}*/
}
else
{
perror("fork");
exit(0);
}
}
else{
if(status!=0){
status=0;
//kill!!!!
system(a); //getting kill -9 PID ; but PID is equal 0 here...
printf("\nkilling child");
}
}
}
how to just spawn new child process and let it just exist, like some sort of worker in C#?
Assuming you are in Linux, here's an example that might clarify your view: parent process spawns a child, the child calls pause() which suspends it until a signal is delivered, and finally parent process kill's the child with SIGKILL.
#include <unistd.h>
#include <signal.h>
#include <stdio.h>
int main()
{
pid_t pid;
pid = fork();
if (pid < 0) { perror("fork"); exit(0); }
if (pid == 0) {
printf("Child process created and will now wait for signal...\n");
pause(); //waits for signal
}
else {
//do some other work in parent process here
printf("Killing child (%ld) from parent process!", (long) pid);
kill(pid, SIGKILL);
}
return 0;
}
Please note that fork() returns:
<0 on failure
0 in child process
the child's pid in parent process.

How to use Fork() to create only 2 child processes?

I'm starting to learn some C and while studying the fork, wait functions I got to a unexpected output. At least for me.
Is there any way to create only 2 child processes from the parent?
Here my code:
#include <sys/types.h>
#include <stdio.h>
#include <unistd.h>
#include <sys/wait.h>
int main ()
{
/* Create the pipe */
int fd [2];
pipe(fd);
pid_t pid;
pid_t pidb;
pid = fork ();
pidb = fork ();
if (pid < 0)
{
printf ("Fork Failed\n");
return -1;
}
else if (pid == 0)
{
//printf("I'm the child\n");
}
else
{
//printf("I'm the parent\n");
}
printf("I'm pid %d\n",getpid());
return 0;
}
And Here is my output:
I'm pid 6763
I'm pid 6765
I'm pid 6764
I'm pid 6766
Please, ignore the pipe part, I haven't gotten that far yet. I'm just trying to create only 2 child processes so I expect 3 "I'm pid ..." outputs only 1 for the parent which I will make wait and 2 child processes that will communicate through a pipe.
Let me know if you see where my error is.
pid = fork (); #1
pidb = fork (); #2
Let us assume the parent process id is 100, the first fork creates another process 101. Now both 100 & 101 continue execution after #1, so they execute second fork. pid 100 reaches #2 creating another process 102. pid 101 reaches #2 creating another process 103. So we end up with 4 processes.
What you should do is something like this.
if(fork()) # parent
if(fork()) #parent
else # child2
else #child1
After you create process , you should check the return value. if you don't , the seconde fork() will be executed by both the parent process and the child process, so you have four processes.
if you want to create 2 child processes , just :
if (pid = fork()) {
if (pid = fork()) {
;
}
}
You can create n child processes like this:
for (i = 0; i < n; ++i) {
pid = fork();
if (pid > 0) { /* I am the parent, create more children */
continue;
} else if (pid == 0) { /* I am a child, get to work */
break;
} else {
printf("fork error\n");
exit(1);
}
}
When a fork statement is executed by the parent, a child process is created as you'd expect. You could say that the child process also executes the fork statement but returns a 0, the parent, however, returns the pid.
All code after the fork statement is executed by both, the parent and the child.
In your case what was happening was that the first fork statement created a child process. So presently there's one parent, P1, and one child, C1.
Now both P1 and C1 encounter the second fork statement. The parent creates another child (c2) as you'd expect, but even the child, c1 creates a child process (c3). So in effect you have P1, C1, C2 and C3, which is why you got 4 print statement outputs.
A good way to think about this is using trees, with each node representing a process, and the root node is the topmost parent.
you can check the value as
if ( pid < 0 )
process creation unsuccessful
this tells if the child process creation was unsuccessful..
fork returns the process id of the child process if getpid() is used from parent process..
You can create a child process within a child process. This way you can have 2 copies of the original parent process.
int main (void) {
pid_t pid, pid2;
int status;
pid = fork();
if (pid == 0) { //child process
pid2 = fork();
int status2;
if (pid2 == 0) { //child of child process
printf("friends!\n");
}
else {
printf("my ");
fflush(stdout);
wait(&status2);
}
}
else { //parent process
printf("Hello ");
fflush(stdout);
wait(&status);
}
return 0;
}
This prints the following:
Hello my friends!

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