How can I calculate the number of work days between two dates in SQL Server?
Monday to Friday and it must be T-SQL.
For workdays, Monday to Friday, you can do it with a single SELECT, like this:
DECLARE #StartDate DATETIME
DECLARE #EndDate DATETIME
SET #StartDate = '2008/10/01'
SET #EndDate = '2008/10/31'
SELECT
(DATEDIFF(dd, #StartDate, #EndDate) + 1)
-(DATEDIFF(wk, #StartDate, #EndDate) * 2)
-(CASE WHEN DATENAME(dw, #StartDate) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, #EndDate) = 'Saturday' THEN 1 ELSE 0 END)
If you want to include holidays, you have to work it out a bit...
In Calculating Work Days you can find a good article about this subject, but as you can see it is not that advanced.
--Changing current database to the Master database allows function to be shared by everyone.
USE MASTER
GO
--If the function already exists, drop it.
IF EXISTS
(
SELECT *
FROM dbo.SYSOBJECTS
WHERE ID = OBJECT_ID(N'[dbo].[fn_WorkDays]')
AND XType IN (N'FN', N'IF', N'TF')
)
DROP FUNCTION [dbo].[fn_WorkDays]
GO
CREATE FUNCTION dbo.fn_WorkDays
--Presets
--Define the input parameters (OK if reversed by mistake).
(
#StartDate DATETIME,
#EndDate DATETIME = NULL --#EndDate replaced by #StartDate when DEFAULTed
)
--Define the output data type.
RETURNS INT
AS
--Calculate the RETURN of the function.
BEGIN
--Declare local variables
--Temporarily holds #EndDate during date reversal.
DECLARE #Swap DATETIME
--If the Start Date is null, return a NULL and exit.
IF #StartDate IS NULL
RETURN NULL
--If the End Date is null, populate with Start Date value so will have two dates (required by DATEDIFF below).
IF #EndDate IS NULL
SELECT #EndDate = #StartDate
--Strip the time element from both dates (just to be safe) by converting to whole days and back to a date.
--Usually faster than CONVERT.
--0 is a date (01/01/1900 00:00:00.000)
SELECT #StartDate = DATEADD(dd,DATEDIFF(dd,0,#StartDate), 0),
#EndDate = DATEADD(dd,DATEDIFF(dd,0,#EndDate) , 0)
--If the inputs are in the wrong order, reverse them.
IF #StartDate > #EndDate
SELECT #Swap = #EndDate,
#EndDate = #StartDate,
#StartDate = #Swap
--Calculate and return the number of workdays using the input parameters.
--This is the meat of the function.
--This is really just one formula with a couple of parts that are listed on separate lines for documentation purposes.
RETURN (
SELECT
--Start with total number of days including weekends
(DATEDIFF(dd,#StartDate, #EndDate)+1)
--Subtact 2 days for each full weekend
-(DATEDIFF(wk,#StartDate, #EndDate)*2)
--If StartDate is a Sunday, Subtract 1
-(CASE WHEN DATENAME(dw, #StartDate) = 'Sunday'
THEN 1
ELSE 0
END)
--If EndDate is a Saturday, Subtract 1
-(CASE WHEN DATENAME(dw, #EndDate) = 'Saturday'
THEN 1
ELSE 0
END)
)
END
GO
If you need to use a custom calendar, you might need to add some checks and some parameters. Hopefully it will provide a good starting point.
All Credit to Bogdan Maxim & Peter Mortensen. This is their post, I just added holidays to the function (This assumes you have a table "tblHolidays" with a datetime field "HolDate".
--Changing current database to the Master database allows function to be shared by everyone.
USE MASTER
GO
--If the function already exists, drop it.
IF EXISTS
(
SELECT *
FROM dbo.SYSOBJECTS
WHERE ID = OBJECT_ID(N'[dbo].[fn_WorkDays]')
AND XType IN (N'FN', N'IF', N'TF')
)
DROP FUNCTION [dbo].[fn_WorkDays]
GO
CREATE FUNCTION dbo.fn_WorkDays
--Presets
--Define the input parameters (OK if reversed by mistake).
(
#StartDate DATETIME,
#EndDate DATETIME = NULL --#EndDate replaced by #StartDate when DEFAULTed
)
--Define the output data type.
RETURNS INT
AS
--Calculate the RETURN of the function.
BEGIN
--Declare local variables
--Temporarily holds #EndDate during date reversal.
DECLARE #Swap DATETIME
--If the Start Date is null, return a NULL and exit.
IF #StartDate IS NULL
RETURN NULL
--If the End Date is null, populate with Start Date value so will have two dates (required by DATEDIFF below).
IF #EndDate IS NULL
SELECT #EndDate = #StartDate
--Strip the time element from both dates (just to be safe) by converting to whole days and back to a date.
--Usually faster than CONVERT.
--0 is a date (01/01/1900 00:00:00.000)
SELECT #StartDate = DATEADD(dd,DATEDIFF(dd,0,#StartDate), 0),
#EndDate = DATEADD(dd,DATEDIFF(dd,0,#EndDate) , 0)
--If the inputs are in the wrong order, reverse them.
IF #StartDate > #EndDate
SELECT #Swap = #EndDate,
#EndDate = #StartDate,
#StartDate = #Swap
--Calculate and return the number of workdays using the input parameters.
--This is the meat of the function.
--This is really just one formula with a couple of parts that are listed on separate lines for documentation purposes.
RETURN (
SELECT
--Start with total number of days including weekends
(DATEDIFF(dd,#StartDate, #EndDate)+1)
--Subtact 2 days for each full weekend
-(DATEDIFF(wk,#StartDate, #EndDate)*2)
--If StartDate is a Sunday, Subtract 1
-(CASE WHEN DATENAME(dw, #StartDate) = 'Sunday'
THEN 1
ELSE 0
END)
--If EndDate is a Saturday, Subtract 1
-(CASE WHEN DATENAME(dw, #EndDate) = 'Saturday'
THEN 1
ELSE 0
END)
--Subtract all holidays
-(Select Count(*) from [DB04\DB04].[Gateway].[dbo].[tblHolidays]
where [HolDate] between #StartDate and #EndDate )
)
END
GO
-- Test Script
/*
declare #EndDate datetime= dateadd(m,2,getdate())
print #EndDate
select [Master].[dbo].[fn_WorkDays] (getdate(), #EndDate)
*/
My version of the accepted answer as a function using DATEPART, so I don't have to do a string comparison on the line with
DATENAME(dw, #StartDate) = 'Sunday'
Anyway, here's my business datediff function
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION BDATEDIFF
(
#startdate as DATETIME,
#enddate as DATETIME
)
RETURNS INT
AS
BEGIN
DECLARE #res int
SET #res = (DATEDIFF(dd, #startdate, #enddate) + 1)
-(DATEDIFF(wk, #startdate, #enddate) * 2)
-(CASE WHEN DATEPART(dw, #startdate) = 1 THEN 1 ELSE 0 END)
-(CASE WHEN DATEPART(dw, #enddate) = 7 THEN 1 ELSE 0 END)
RETURN #res
END
GO
Another approach to calculating working days is to use a WHILE loop which basically iterates through a date range and increment it by 1 whenever days are found to be within Monday – Friday. The complete script for calculating working days using the WHILE loop is shown below:
CREATE FUNCTION [dbo].[fn_GetTotalWorkingDaysUsingLoop]
(#DateFrom DATE,
#DateTo DATE
)
RETURNS INT
AS
BEGIN
DECLARE #TotWorkingDays INT= 0;
WHILE #DateFrom <= #DateTo
BEGIN
IF DATENAME(WEEKDAY, #DateFrom) IN('Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday')
BEGIN
SET #TotWorkingDays = #TotWorkingDays + 1;
END;
SET #DateFrom = DATEADD(DAY, 1, #DateFrom);
END;
RETURN #TotWorkingDays;
END;
GO
Although the WHILE loop option is cleaner and uses less lines of code, it has the potential of being a performance bottleneck in your environment particularly when your date range spans across several years.
You can see more methods on how to calculate work days and hours in this article:
https://www.sqlshack.com/how-to-calculate-work-days-and-hours-in-sql-server/
DECLARE #TotalDays INT,#WorkDays INT
DECLARE #ReducedDayswithEndDate INT
DECLARE #WeekPart INT
DECLARE #DatePart INT
SET #TotalDays= DATEDIFF(day, #StartDate, #EndDate) +1
SELECT #ReducedDayswithEndDate = CASE DATENAME(weekday, #EndDate)
WHEN 'Saturday' THEN 1
WHEN 'Sunday' THEN 2
ELSE 0 END
SET #TotalDays=#TotalDays-#ReducedDayswithEndDate
SET #WeekPart=#TotalDays/7;
SET #DatePart=#TotalDays%7;
SET #WorkDays=(#WeekPart*5)+#DatePart
RETURN #WorkDays
(I'm a few points shy of commenting privileges)
If you decide to forgo the +1 day in CMS's elegant solution, note that if your start date and end date are in the same weekend, you get a negative answer. Ie., 2008/10/26 to 2008/10/26 returns -1.
my rather simplistic solution:
select #Result = (..CMS's answer..)
if (#Result < 0)
select #Result = 0
RETURN #Result
.. which also sets all erroneous posts with start date after end date to zero. Something you may or may not be looking for.
For difference between dates including holidays I went this way:
1) Table with Holidays:
CREATE TABLE [dbo].[Holiday](
[Id] [int] IDENTITY(1,1) NOT NULL,
[Name] [nvarchar](50) NULL,
[Date] [datetime] NOT NULL)
2) I had my plannings Table like this and wanted to fill column Work_Days which was empty:
CREATE TABLE [dbo].[Plan_Phase](
[Id] [int] IDENTITY(1,1) NOT NULL,
[Id_Plan] [int] NOT NULL,
[Id_Phase] [int] NOT NULL,
[Start_Date] [datetime] NULL,
[End_Date] [datetime] NULL,
[Work_Days] [int] NULL)
3) So in order to get "Work_Days" to later fill in my column just had to:
SELECT Start_Date, End_Date,
(DATEDIFF(dd, Start_Date, End_Date) + 1)
-(DATEDIFF(wk, Start_Date, End_Date) * 2)
-(SELECT COUNT(*) From Holiday Where Date >= Start_Date AND Date <= End_Date)
-(CASE WHEN DATENAME(dw, Start_Date) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, End_Date) = 'Saturday' THEN 1 ELSE 0 END)
-(CASE WHEN (SELECT COUNT(*) From Holiday Where Start_Date = Date) > 0 THEN 1 ELSE 0 END)
-(CASE WHEN (SELECT COUNT(*) From Holiday Where End_Date = Date) > 0 THEN 1 ELSE 0 END) AS Work_Days
from Plan_Phase
Hope that I could help.
Cheers
Here is a version that works well (I think). Holiday table contains Holiday_date columns that contains holidays your company observe.
DECLARE #RAWDAYS INT
SELECT #RAWDAYS = DATEDIFF(day, #StartDate, #EndDate )--+1
-( 2 * DATEDIFF( week, #StartDate, #EndDate ) )
+ CASE WHEN DATENAME(dw, #StartDate) = 'Saturday' THEN 1 ELSE 0 END
- CASE WHEN DATENAME(dw, #EndDate) = 'Saturday' THEN 1 ELSE 0 END
SELECT #RAWDAYS - COUNT(*)
FROM HOLIDAY NumberOfBusinessDays
WHERE [Holiday_Date] BETWEEN #StartDate+1 AND #EndDate
I know this is an old question but I needed a formula for workdays excluding the start date since I have several items and need the days to accumulate correctly.
None of the non-iterative answers worked for me.
I used a defintion like
Number of times midnight to monday, tuesday, wednesday, thursday and friday is passed
(others might count midnight to saturday instead of monday)
I ended up with this formula
SELECT DATEDIFF(day, #StartDate, #EndDate) /* all midnights passed */
- DATEDIFF(week, #StartDate, #EndDate) /* remove sunday midnights */
- DATEDIFF(week, DATEADD(day, 1, #StartDate), DATEADD(day, 1, #EndDate)) /* remove saturday midnights */
This is basically CMS's answer without the reliance on a particular language setting. And since we're shooting for generic, that means it should work for all ##datefirst settings as well.
datediff(day, <start>, <end>) + 1 - datediff(week, <start>, <end>) * 2
/* if start is a Sunday, adjust by -1 */
+ case when datepart(weekday, <start>) = 8 - ##datefirst then -1 else 0 end
/* if end is a Saturday, adjust by -1 */
+ case when datepart(weekday, <end>) = (13 - ##datefirst) % 7 + 1 then -1 else 0 end
datediff(week, ...) always uses a Saturday-to-Sunday boundary for weeks, so that expression is deterministic and doesn't need to be modified (as long as our definition of weekdays is consistently Monday through Friday.) Day numbering does vary according to the ##datefirst setting and the modified calculations handle this correction with the small complication of some modular arithmetic.
A cleaner way to deal with the Saturday/Sunday thing is to translate the dates prior to extracting a day of week value. After shifting, the values will be back in line with a fixed (and probably more familiar) numbering that starts with 1 on Sunday and ends with 7 on Saturday.
datediff(day, <start>, <end>) + 1 - datediff(week, <start>, <end>) * 2
+ case when datepart(weekday, dateadd(day, ##datefirst, <start>)) = 1 then -1 else 0 end
+ case when datepart(weekday, dateadd(day, ##datefirst, <end>)) = 7 then -1 else 0 end
I've tracked this form of the solution back at least as far as 2002 and an Itzik Ben-Gan article. (https://technet.microsoft.com/en-us/library/aa175781(v=sql.80).aspx) Though it needed a small tweak since newer date types don't allow date arithmetic, it is otherwise identical.
EDIT:
I added back the +1 that had somehow been left off. It's also worth noting that this method always counts the start and end days. It also assumes that the end date is on or after the start date.
None of the functions above work for the same week or deal with holidays. I wrote this:
create FUNCTION [dbo].[ShiftHolidayToWorkday](#date date)
RETURNS date
AS
BEGIN
IF DATENAME( dw, #Date ) = 'Saturday'
SET #Date = DATEADD(day, - 1, #Date)
ELSE IF DATENAME( dw, #Date ) = 'Sunday'
SET #Date = DATEADD(day, 1, #Date)
RETURN #date
END
GO
create FUNCTION [dbo].[GetHoliday](#date date)
RETURNS varchar(50)
AS
BEGIN
declare #s varchar(50)
SELECT #s = CASE
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-01-01') = #date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]+1) + '-01-01') = #date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-07-04') = #date THEN 'Independence Day'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-12-25') = #date THEN 'Christmas Day'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-12-31') = #date THEN 'New Years Eve'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-11-11') = #date THEN 'Veteran''s Day'
WHEN [Month] = 1 AND [DayOfMonth] BETWEEN 15 AND 21 AND [DayName] = 'Monday' THEN 'Martin Luther King Day'
WHEN [Month] = 5 AND [DayOfMonth] >= 25 AND [DayName] = 'Monday' THEN 'Memorial Day'
WHEN [Month] = 9 AND [DayOfMonth] <= 7 AND [DayName] = 'Monday' THEN 'Labor Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 22 AND 28 AND [DayName] = 'Thursday' THEN 'Thanksgiving Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 23 AND 29 AND [DayName] = 'Friday' THEN 'Day After Thanksgiving'
ELSE NULL END
FROM (
SELECT
[Year] = YEAR(#date),
[Month] = MONTH(#date),
[DayOfMonth] = DAY(#date),
[DayName] = DATENAME(weekday,#date)
) c
RETURN #s
END
GO
create FUNCTION [dbo].GetHolidays(#year int)
RETURNS TABLE
AS
RETURN (
select dt, dbo.GetHoliday(dt) as Holiday
from (
select dateadd(day, number, convert(varchar,#year) + '-01-01') dt
from master..spt_values
where type='p'
) d
where year(dt) = #year and dbo.GetHoliday(dt) is not null
)
create proc UpdateHolidaysTable
as
if not exists(select TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_NAME = 'Holidays')
create table Holidays(dt date primary key clustered, Holiday varchar(50))
declare #year int
set #year = 1990
while #year < year(GetDate()) + 20
begin
insert into Holidays(dt, Holiday)
select a.dt, a.Holiday
from dbo.GetHolidays(#year) a
left join Holidays b on b.dt = a.dt
where b.dt is null
set #year = #year + 1
end
create FUNCTION [dbo].[GetWorkDays](#StartDate DATE = NULL, #EndDate DATE = NULL)
RETURNS INT
AS
BEGIN
IF #StartDate IS NULL OR #EndDate IS NULL
RETURN 0
IF #StartDate >= #EndDate
RETURN 0
DECLARE #Days int
SET #Days = 0
IF year(#StartDate) * 100 + datepart(week, #StartDate) = year(#EndDate) * 100 + datepart(week, #EndDate)
--same week
select #Days = (DATEDIFF(dd, #StartDate, #EndDate))
- (CASE WHEN DATENAME(dw, #StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, #EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between #StartDate and #EndDate)
ELSE
--diff weeks
select #Days = (DATEDIFF(dd, #StartDate, #EndDate) + 1)
- (DATEDIFF(wk, #StartDate, #EndDate) * 2)
- (CASE WHEN DATENAME(dw, #StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, #EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between #StartDate and #EndDate)
RETURN #Days
END
Using a date table:
DECLARE
#StartDate date = '2014-01-01',
#EndDate date = '2014-01-31';
SELECT
COUNT(*) As NumberOfWeekDays
FROM dbo.Calendar
WHERE CalendarDate BETWEEN #StartDate AND #EndDate
AND IsWorkDay = 1;
If you don't have that, you can use a numbers table:
DECLARE
#StartDate datetime = '2014-01-01',
#EndDate datetime = '2014-01-31';
SELECT
SUM(CASE WHEN DATEPART(dw, DATEADD(dd, Number-1, #StartDate)) BETWEEN 2 AND 6 THEN 1 ELSE 0 END) As NumberOfWeekDays
FROM dbo.Numbers
WHERE Number <= DATEDIFF(dd, #StartDate, #EndDate) + 1 -- Number table starts at 1, we want a 0 base
They should both be fast and it takes out the ambiguity/complexity. The first option is the best but if you don't have a calendar table you can allways create a numbers table with a CTE.
DECLARE #StartDate datetime,#EndDate datetime
select #StartDate='3/2/2010', #EndDate='3/7/2010'
DECLARE #TotalDays INT,#WorkDays INT
DECLARE #ReducedDayswithEndDate INT
DECLARE #WeekPart INT
DECLARE #DatePart INT
SET #TotalDays= DATEDIFF(day, #StartDate, #EndDate) +1
SELECT #ReducedDayswithEndDate = CASE DATENAME(weekday, #EndDate)
WHEN 'Saturday' THEN 1
WHEN 'Sunday' THEN 2
ELSE 0 END
SET #TotalDays=#TotalDays-#ReducedDayswithEndDate
SET #WeekPart=#TotalDays/7;
SET #DatePart=#TotalDays%7;
SET #WorkDays=(#WeekPart*5)+#DatePart
SELECT #WorkDays
CREATE FUNCTION x
(
#StartDate DATETIME,
#EndDate DATETIME
)
RETURNS INT
AS
BEGIN
DECLARE #Teller INT
SET #StartDate = DATEADD(dd,1,#StartDate)
SET #Teller = 0
IF DATEDIFF(dd,#StartDate,#EndDate) <= 0
BEGIN
SET #Teller = 0
END
ELSE
BEGIN
WHILE
DATEDIFF(dd,#StartDate,#EndDate) >= 0
BEGIN
IF DATEPART(dw,#StartDate) < 6
BEGIN
SET #Teller = #Teller + 1
END
SET #StartDate = DATEADD(dd,1,#StartDate)
END
END
RETURN #Teller
END
I took the various examples here, but in my particular situation we have a #PromisedDate for delivery and a #ReceivedDate for the actual receipt of the item. When an item was received before the "PromisedDate" the calculations were not totaling correctly unless I ordered the dates passed into the function by calendar order. Not wanting to check the dates every time, I changed the function to handle this for me.
Create FUNCTION [dbo].[fnGetBusinessDays]
(
#PromiseDate date,
#ReceivedDate date
)
RETURNS integer
AS
BEGIN
DECLARE #days integer
SELECT #days =
Case when #PromiseDate > #ReceivedDate Then
DATEDIFF(d,#PromiseDate,#ReceivedDate) +
ABS(DATEDIFF(wk,#PromiseDate,#ReceivedDate)) * 2 +
CASE
WHEN DATENAME(dw, #PromiseDate) <> 'Saturday' AND DATENAME(dw, #ReceivedDate) = 'Saturday' THEN 1
WHEN DATENAME(dw, #PromiseDate) = 'Saturday' AND DATENAME(dw, #ReceivedDate) <> 'Saturday' THEN -1
ELSE 0
END +
(Select COUNT(*) FROM CompanyHolidays
WHERE HolidayDate BETWEEN #ReceivedDate AND #PromiseDate
AND DATENAME(dw, HolidayDate) <> 'Saturday' AND DATENAME(dw, HolidayDate) <> 'Sunday')
Else
DATEDIFF(d,#PromiseDate,#ReceivedDate) -
ABS(DATEDIFF(wk,#PromiseDate,#ReceivedDate)) * 2 -
CASE
WHEN DATENAME(dw, #PromiseDate) <> 'Saturday' AND DATENAME(dw, #ReceivedDate) = 'Saturday' THEN 1
WHEN DATENAME(dw, #PromiseDate) = 'Saturday' AND DATENAME(dw, #ReceivedDate) <> 'Saturday' THEN -1
ELSE 0
END -
(Select COUNT(*) FROM CompanyHolidays
WHERE HolidayDate BETWEEN #PromiseDate and #ReceivedDate
AND DATENAME(dw, HolidayDate) <> 'Saturday' AND DATENAME(dw, HolidayDate) <> 'Sunday')
End
RETURN (#days)
END
If you need to add work days to a given date, you can create a function that depends on a calendar table, described below:
CREATE TABLE Calendar
(
dt SMALLDATETIME PRIMARY KEY,
IsWorkDay BIT
);
--fill the rows with normal days, weekends and holidays.
create function AddWorkingDays (#initialDate smalldatetime, #numberOfDays int)
returns smalldatetime as
begin
declare #result smalldatetime
set #result =
(
select t.dt from
(
select dt, ROW_NUMBER() over (order by dt) as daysAhead from calendar
where dt > #initialDate
and IsWorkDay = 1
) t
where t.daysAhead = #numberOfDays
)
return #result
end
As with DATEDIFF, I do not consider the end date to be part of the interval.
The number of (for example) Sundays between #StartDate and #EndDate is the number of Sundays between an "initial" Monday and the #EndDate minus the number of Sundays between this "initial" Monday and the #StartDate. Knowing this, we can calculate the number of workdays as follows:
DECLARE #StartDate DATETIME
DECLARE #EndDate DATETIME
SET #StartDate = '2018/01/01'
SET #EndDate = '2019/01/01'
SELECT DATEDIFF(Day, #StartDate, #EndDate) -- Total Days
- (DATEDIFF(Day, 0, #EndDate)/7 - DATEDIFF(Day, 0, #StartDate)/7) -- Sundays
- (DATEDIFF(Day, -1, #EndDate)/7 - DATEDIFF(Day, -1, #StartDate)/7) -- Saturdays
Best regards!
I borrowed some ideas from others to create my solution. I use inline code to ignore weekends and U.S. federal holidays. In my environment, EndDate may be null, but it will never precede StartDate.
CREATE FUNCTION dbo.ufn_CalculateBusinessDays(
#StartDate DATE,
#EndDate DATE = NULL)
RETURNS INT
AS
BEGIN
DECLARE #TotalBusinessDays INT = 0;
DECLARE #TestDate DATE = #StartDate;
IF #EndDate IS NULL
RETURN NULL;
WHILE #TestDate < #EndDate
BEGIN
DECLARE #Month INT = DATEPART(MM, #TestDate);
DECLARE #Day INT = DATEPART(DD, #TestDate);
DECLARE #DayOfWeek INT = DATEPART(WEEKDAY, #TestDate) - 1; --Monday = 1, Tuesday = 2, etc.
DECLARE #DayOccurrence INT = (#Day - 1) / 7 + 1; --Nth day of month (3rd Monday, for example)
--Increment business day counter if not a weekend or holiday
SELECT #TotalBusinessDays += (
SELECT CASE
--Saturday OR Sunday
WHEN #DayOfWeek IN (6,7) THEN 0
--New Year's Day
WHEN #Month = 1 AND #Day = 1 THEN 0
--MLK Jr. Day
WHEN #Month = 1 AND #DayOfWeek = 1 AND #DayOccurrence = 3 THEN 0
--G. Washington's Birthday
WHEN #Month = 2 AND #DayOfWeek = 1 AND #DayOccurrence = 3 THEN 0
--Memorial Day
WHEN #Month = 5 AND #DayOfWeek = 1 AND #Day BETWEEN 25 AND 31 THEN 0
--Independence Day
WHEN #Month = 7 AND #Day = 4 THEN 0
--Labor Day
WHEN #Month = 9 AND #DayOfWeek = 1 AND #DayOccurrence = 1 THEN 0
--Columbus Day
WHEN #Month = 10 AND #DayOfWeek = 1 AND #DayOccurrence = 2 THEN 0
--Veterans Day
WHEN #Month = 11 AND #Day = 11 THEN 0
--Thanksgiving
WHEN #Month = 11 AND #DayOfWeek = 4 AND #DayOccurrence = 4 THEN 0
--Christmas
WHEN #Month = 12 AND #Day = 25 THEN 0
ELSE 1
END AS Result);
SET #TestDate = DATEADD(dd, 1, #TestDate);
END
RETURN #TotalBusinessDays;
END
That's working for me, in my country on Saturday and Sunday are non-working days.
For me is important the time of #StartDate and #EndDate.
CREATE FUNCTION [dbo].[fnGetCountWorkingBusinessDays]
(
#StartDate as DATETIME,
#EndDate as DATETIME
)
RETURNS INT
AS
BEGIN
DECLARE #res int
SET #StartDate = CASE
WHEN DATENAME(dw, #StartDate) = 'Saturday' THEN DATEADD(dd, 2, DATEDIFF(dd, 0, #StartDate))
WHEN DATENAME(dw, #StartDate) = 'Sunday' THEN DATEADD(dd, 1, DATEDIFF(dd, 0, #StartDate))
ELSE #StartDate END
SET #EndDate = CASE
WHEN DATENAME(dw, #EndDate) = 'Saturday' THEN DATEADD(dd, 0, DATEDIFF(dd, 0, #EndDate))
WHEN DATENAME(dw, #EndDate) = 'Sunday' THEN DATEADD(dd, -1, DATEDIFF(dd, 0, #EndDate))
ELSE #EndDate END
SET #res =
(DATEDIFF(hour, #StartDate, #EndDate) / 24)
- (DATEDIFF(wk, #StartDate, #EndDate) * 2)
SET #res = CASE WHEN #res < 0 THEN 0 ELSE #res END
RETURN #res
END
GO
Create function like:
CREATE FUNCTION dbo.fn_WorkDays(#StartDate DATETIME, #EndDate DATETIME= NULL )
RETURNS INT
AS
BEGIN
DECLARE #Days int
SET #Days = 0
IF #EndDate = NULL
SET #EndDate = EOMONTH(#StartDate) --last date of the month
WHILE DATEDIFF(dd,#StartDate,#EndDate) >= 0
BEGIN
IF DATENAME(dw, #StartDate) <> 'Saturday'
and DATENAME(dw, #StartDate) <> 'Sunday'
and Not ((Day(#StartDate) = 1 And Month(#StartDate) = 1)) --New Year's Day.
and Not ((Day(#StartDate) = 4 And Month(#StartDate) = 7)) --Independence Day.
BEGIN
SET #Days = #Days + 1
END
SET #StartDate = DATEADD(dd,1,#StartDate)
END
RETURN #Days
END
You can call the function like:
select dbo.fn_WorkDays('1/1/2016', '9/25/2016')
Or like:
select dbo.fn_WorkDays(StartDate, EndDate)
from table1
Create Function dbo.DateDiff_WeekDays
(
#StartDate DateTime,
#EndDate DateTime
)
Returns Int
As
Begin
Declare #Result Int = 0
While #StartDate <= #EndDate
Begin
If DateName(DW, #StartDate) not in ('Saturday','Sunday')
Begin
Set #Result = #Result +1
End
Set #StartDate = DateAdd(Day, +1, #StartDate)
End
Return #Result
End
I found the below TSQL a fairly elegant solution (I don't have permissions to run functions). I found the DATEDIFF ignores DATEFIRST and I wanted my first day of the week to be a Monday. I also wanted the first working day to be set a zero and if it falls on a weekend Monday will be a zero. This may help someone who has a slightly different requirement :)
It does not handle bank holidays
SET DATEFIRST 1
SELECT
,(DATEDIFF(DD, [StartDate], [EndDate]))
-(DATEDIFF(wk, [StartDate], [EndDate]))
-(DATEDIFF(wk, DATEADD(dd,-##DATEFIRST,[StartDate]), DATEADD(dd,-##DATEFIRST,[EndDate]))) AS [WorkingDays]
FROM /*Your Table*/
One approach is to 'walk the dates' from start to finish in conjunction with a case expression which checks if the day is not a Saturday or a Sunday and flagging it(1 for weekday, 0 for weekend). And in the end just sum flags(it would be equal to the count of 1-flags as the other flag is 0) to give you the number of weekdays.
You can use a GetNums(startNumber,endNumber) type of utility function which generates a series of numbers for 'looping' from start date to end date. Refer http://tsql.solidq.com/SourceCodes/GetNums.txt for an implementation. The logic can also be extended to cater for holidays(say if you have a holidays table)
declare #date1 as datetime = '19900101'
declare #date2 as datetime = '19900120'
select sum(case when DATENAME(DW,currentDate) not in ('Saturday', 'Sunday') then 1 else 0 end) as noOfWorkDays
from dbo.GetNums(0,DATEDIFF(day,#date1, #date2)-1) as Num
cross apply (select DATEADD(day,n,#date1)) as Dates(currentDate)
I have report, which takes YEAR as one parameter and I wanted to calculate the start and end of the financial year. Here is how I'm trying:
CREATE PROCEDURE [dbo].[sp_name]
#StartDate as datetime,
#Enddate as datetime,
#year as varchar(10)
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
SET NOCOUNT ON;
#StartDate = year(dateadd(q, -1, cast(cast(#year AS char) + '/01/' + cast(#year AS char) AS datetime))) = #year
Is this the correct way to do this?
I need financial start date as 1-July-2014 to 30-June-2015, if year entered as 2015.Please note that, this I need internally to be calculated in script. If I'm doing something wrong, how can I correct this to get desired results?
Using DATEADD and DATEDIFF you can computer for your fiscal years:
DECLARE #year INT = 2015
SELECT
start_date = DATEADD(MONTH, 6, DATEADD(YEAR, DATEDIFF(YEAR, 0, DATEADD(YEAR, #year - 1900, 0)) - 1, 0)),
end_date = DATEADD(DAY, -1, DATEADD(MONTH, 6, DATEADD(YEAR, DATEDIFF(YEAR, 0, DATEADD(YEAR, #year - 1900, 0)), 0)))
Read here for more common date routines.
To use this in a stored procedure:
CREATE PROCEDURE procedure_name
#year AS INT
AS
BEGIN
SET NOCOUNT ON
SELECT
start_date = DATEADD(MONTH, 6, DATEADD(YEAR, DATEDIFF(YEAR, 0, DATEADD(YEAR, #year - 1900, 0)) - 1, 0)),
end_date = DATEADD(DAY, -1, DATEADD(MONTH, 6, DATEADD(YEAR, DATEDIFF(YEAR, 0, DATEADD(YEAR, #year - 1900, 0)), 0)))
END
For SQL server 2012+ versions, you can use DATEFROMPARTS
https://msdn.microsoft.com/en-IN/library/hh213228.aspx
CREATE PROCEDURE [dbo].[usp_name]
#StartDate as datetime,
#Enddate as datetime,
#year as int
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
SET NOCOUNT ON;
SELECT #StartDate = DATEFROMPARTS(#year-1,7,1), #EndDate=DATEFROMPARTS(#year,6,30)
END
Perhaps this will help and also works when the financial year has changed or you move to a new company.
CREATE PROCEDURE [dbo].[usp_yeardates] /* or your sp name */
#year AS SMALLINT,
#monthoffset AS TINYINT = 0, /* if you wish your year to start at a month other than jan then set number of months to offset, e.g. to start April, move three forward #monthoffset = 3 */
#startdate AS SMALLDATETIME OUTPUT, /* NB 2008r2+ use DATE instead of SMALLDATETIME */
#enddate AS SMALLDATETIME OUTPUT
AS
/* Created by Darren Edward Comeau - 26/08/2015 */
BEGIN
/* check inputs */
IF #year < 1900 or #year > 2078
RAISERROR ('year out of bounds',16,1)
ELSE IF #monthoffset > 11
RAISERROR ('monthoffset out of bounds',16,2)
ELSE
SELECT
/* logic to establish start / end date */
#startdate =
dateadd(month,#monthoffset,
dateadd(year,#year-1900,'19000101')
),
#enddate =
dateadd(day,-1,
dateadd(month,#monthoffset,
dateadd(year,#year-1899,'19000101')
)
);
END;
GO
You would use the procedure as follows;
/* usage */
DECLARE
#startdate SMALLDATETIME,
#enddate SMALLDATETIME,
#year SMALLINT,
#monthoffset TINYINT,
#rc INT;
EXEC #rc = usp_yeardates
#year = 2011,
#monthoffset = 6, /* 6 months offset equalls July - June year */
#startdate = #startdate OUTPUT,
#enddate = #enddate OUTPUT;
SELECT
#rc AS [ReturnCode],
#startdate AS [StartDate],
#enddate AS [EndDate];
This will give you financial year's as well start and end date
DECLARE #DateFrom datetime, #DateTo datetime
SET #DateFrom = '2012-03-30'
SET #DateTo = '2021-03-31'
DECLARE #Output TABLE ( Item NVARCHAR(1000),startdate Datetime,enddate Datetime )
DECLARE #Year INT
DECLARE #EndYear INT
DECLARE #Month INT
DECLARE #FinacialYearValue INT
SET #Month = CAST(MONTH(#DateFrom) AS INT)
SET #Year = CAST(YEAR(#DateFrom) AS INT)
SET #EndYear= CAST(YEAR(#DateTo) AS INT)
SET #FinacialYearValue = (CASE WHEN #Month <=3 THEN #Year - 1 ELSE #Year END)
WHILE #EndYear >= #FinacialYearValue
BEGIN
INSERT INTO #Output (Item,startdate,enddate )
SELECT CAST(#FinacialYearValue AS varchar(4)) + '-' + CAST((#FinacialYearValue +1 ) AS varchar(4)) ,
start_date = DATEADD(MONTH, 3, DATEADD(YEAR, DATEDIFF(YEAR, 0, DATEADD(YEAR, #FinacialYearValue+1 - 1900, 0)) - 1, 0)),
end_date = DATEADD(DAY, -1, DATEADD(MONTH, 3, DATEADD(YEAR, DATEDIFF(YEAR, 0, DATEADD(YEAR, #FinacialYearValue+1 - 1900, 0)), 0)))
SET #FinacialYearValue += 1
END
SELECT * FROM #Output
Declare #BillDate smalldatetime, #FYStartDate smalldatetime, #FYEndDate smalldatetime
Select #BillDate ='10-JAN-2019'
Select #FYStartDate = case when MONTH(#BillDate) <=3 Then '01-Apr-' + CAST(YEAR(#BillDate) - 1 AS varchar(4)) Else '01-Apr-' + CAST(YEAR(#BillDate) AS varchar(4)) End,
#FYEndDate = case when MONTH(#BillDate) <=3 Then '31-Mar-' + CAST(YEAR(#BillDate) AS varchar(4)) Else '31-Mar-' + CAST(YEAR(#BillDate) + 1 AS varchar(4)) End
The below code would well in both Azure SQL DB and On-premises. Change your Time Zone as per your need/wish. (Unit Tested)
If we given the current date or whatever date we wish to give, the below code would help us to give us both the financial year start and end date as result sets.
Also want to mention that the logic for financial year is not works well on year alone.please check below 2 cases.
Year- 2019 --> it may be either March 31 or April 1. if we dont specify date, we willl end up with errors.
Date -
20190331 --> financial start date is 20180401 and financial end date - 20190331.
20190401 --> financial start date is 20190401 and financial end date - 20200331.
DECLARE #Current_DateTime DATETIME= SYSDATETIMEOFFSET() AT TIME ZONE 'India Standard Time'; -- GETDATE()
-- SET #Current_DateTime='20200312'; -- uncomment this line to test with your desired date.
SELECT DATEFROMPARTS(Yr, 4, 1) AS FinancialYear_StartDate,
DATEFROMPARTS(Yr + 1, 3, 31) AS FinancialYear_EndDate,
CONCAT(Yr,'-',Yr+1) AS FinancialYear
FROM
(SELECT CASE WHEN DATEPART(MONTH, #Current_DateTime ) < 4
THEN DATEPART(YEAR, #Current_DateTime ) - 1 ELSE DATEPART(YEAR, #Current_DateTime ) END Yr) a;
CREATE PROC udp_financial_year
AS
BEGIN
SELECT DISTINCT
CASE
WHEN DATEPART(MONTH,creationdate) <10 then
CONVERT(VARCHAR,DATEPART(YEAR,creationdate)-1)+'-'+
CONVERT(VARCHAR,DATEPART(YEAR,creationdate))
ELSE
CONVERT(VARCHAR,DATEPART(YEAR,creationdate))+'-'+
CONVERT(VARCHAR,DATEPART(YEAR,creationdate)+1)
END
financialyr
FROM testing
ORDER BY financialyrDESC
END
This will provide starting date of an Indian financial year. i.g. April to March.
SELECT CAST(DATEFROMPARTS(YEAR(DATEADD(M, (MONTH(DATEADD(MONTH, -4, GETDATE()) - 1) * -1), GETDATE())), MONTH('04-01-2020'), DAY('04-01-2020')) AS date)
Declare #Date date = Getdate() ---Paste your date here
Declare #Fyear varchar(4)
Declare #FyearStartDate Date
Declare #FyearEnd varchar(4)
Declare #FyearEndDate Date
If Month(#Date) >= 4
Set #Fyear = year(#Date)
Else
Set #Fyear = year(#Date)-1
Set #FyearStartDate = '04' +'-'+ '01-' + #Fyear
Set #FyearEnd = #Fyear+1
Set #FyearEndDate = '03' +'-'+ '31-' + #FyearEnd
Select #FyearStartDate FYSTARTDT, #FyearEndDate FYENDDT