How to get popup when url status success in angular js - angularjs

Question

I am doing an event scheduler app using angular js. In calendar when i am clicking the event i am sent the event id to back end to getting event details.Here how to get the pop up on my calendar when the url status is true.
My code is:
$scope.alertOnEventClick = function( date, jsEvent, view){
var event_id=date.id;
$http.post("Youin-api/v2/business/event_information",{"event_id":event_id}).then(function(response) {
if(response.error="true")
{
$scope.eventInformation= response;
}
});
};
My bootstrap model pop up is:
<div class="modal fade" id="AddUsers" ng-model="eventInformation" role="dialog">
<div class="modal-dialog " style="top:80px;">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">User Details</h4>
</div>
<div class="modal-body">
<p><form role="form" ng-submit="AddUsers(addusers)">
<div class="form-group">
<label for="pwd">User Type</label>
<input type="text" class="form-control" id="user_type" ng-model="addusers.user_type" value="{{addusers.user_type}}">
</div>
<div class="form-group">
<label for="pwd">Created By</label>
<input ty{{addusers.user_type}}pe="text" class="form-control" id="created_by" ng-model="addusers.created_by" value="">
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button type="submit" class="btn btn-default">Submit</button>
</div>
</form></p>
</div>
</div>
</div>
</div>
thanks in advance..!!

Answer 1

To manually trigger modal to show from javascript. Use this.
$('#AddUsers').modal('show')
Note: You have to add bootstrap.js and jquery.js to use this functionality.
You can view the complete modal api options here.

Answer 2

Wherever you want to open the modal based on your condition you can achieve the same using following:
angular.element(document.getElementById("AddUsers")).modal();