Changing folder name Batch filepath - batch-file

In my batch file, I first create a Lala file in folder: C:Lala-20160322-othercode and next day it creates the file in Lala-20160323-othercode and so on. In the same batch file, I want to use this created file. Now i do not know what to write after -filepath
Since Lala is in a differnt folder every time.
My batchfile is in folder above Lala-20160322-othercode. How can I do this?
The file itself is always called Lala, but on my computer there are many folder (every day another folder) with Lala.
I am new to batch files. Many thanks!!!!!!!!!!!!!!!!
Code:
#echo off
setlocal
call "C:\folder\NameofPythonProgramm" Pythonfunction -filepath ????? -pythonfunction
First I had %1 where the questionmarks are, but I want this dynamic file path

Save this as Test.bat, and run from its folder in open Cmd Prompt to access the file Lala* in the dir corresponding to your desired month. Let me know if any errors.
#echo off
setlocal enabledelayedexpansion
set "dir=c:\Lala-Months"
set "cur_month=August"
FOR /R "%dir%" %%G in (.) DO (set "mon=%%G"
if not '!mon:%cur_month%=!'=='!mon!' echo %%G )
exit /b

Related

How can I improve a batch file with a conditional who copy a jpg file refferring to a specific extension and to a specific database?

I created a .bat file with the following code in order to copy a random file from a directory A-POOL FOLDER into a directory B-FOLDER (with a fixed file name video.mp4). So, in the directory A there is a pool of .mp4 file, and in the directory B there is the the file video.mp4 (same name, but different video every time I execute my batch-file).
That's a code who do this. It perfectly works.
#echo off
setlocal EnableDelayedExpansion
cd C:\Users\aless\Desktop\example\A-POOL
set n=0
for %%f in (*.*) do (
set /A n+=1
set "file[!n!]=%%f"
)
for /L %%i in (1,1,%time:~-1%) do set "dummy=!random!"
set /A "rand=(n*%random%)/32768+1"
copy "!file[%rand%]!" C:\Users\aless\Desktop\example\B-FOLDER\video.mp4
FOR %%G IN ("!file[%rand%]!") DO >"C:\Users\aless\Desktop\example\B-FOLDER\title.txt" ECHO %%~nG
Now the question (different from last time):
In the directory A-POOL I have a lot of .mp4 files. I changed manually the .mp4 extension of every file with a code who rappresent a food.
For example: Filename.pizza, Filename2.pizza, Filename.pasta, Filename200.pasta, Filename.cheeseburger etc...
I created another folder named "FOOD-DATABASE" (in C:\Users\aless\Desktop\FOOD-DATABASE) who contains a big database of images in .jpg extension of the foods. The file NAMES of the food database are equal to the file EXTENSIONS of the files contained in A-POOL folder
Content of FOOD DATABASE folder:
(pasta.jpg, pizza,jpg, cheeseburger.jpg... etc..).
So I need to add to the code a string/conditional who execute e command who say:
If the picked random File have the extension .pizza COPY pizza.jpg from C:\Users\aless\Desktop\FOOD-DATABASE into C:\Users\aless\Desktop\B-FOLDER\FOOD.JPG (fixed name file)
Actually I don't want to add this strings for every food type... in few word the code strings have to read the extension of the picked random file and copy from C:\Users\aless\Desktop\FOOD-DATABASE to C:\Users\aless\Desktop...B FOLDER\FOOD.JPG (fixed name file) the file with the same name to the extension of the random file.
It's a mess... I know ;) Thanks for your help!
As mentioned in the comments, we know that the extension of the one file is the name of another file. so these variable expansions are important:
%%~nG
%%~xG
The last for loop sets a variable %food% from expanded %%~xG which is the extension of the file and using a random example would be .pizza We just need to get rid of the . and you have pizza. We do this by %food:~1.
#echo off
setlocal EnableDelayedExpansion
pushd "%userprofile%\Desktop\example\A-POOL"
set n=0
for %%f in (*.*) do (
set /A n+=1
set "file[!n!]=%%f"
)
for /L %%i in (1,1,%time:~-1%) do set "dummy=!random!"
set /A "rand=(n*%random%)/32768+1"
copy "!file[%rand%]!" "..\B-FOLDER\video.mp4" /Y
for %%G IN ("!file[%rand%]!") DO (
echo %%~nG > "..\B-FOLDER\title.txt"
set "food=%%~xG"
)
copy "..\FOOD-DATABASE\%food:~1%.jpg" "..\B-FOLDER\food.jpg" /Y
popd
Notes!
I am using pushd instead of cd and using relative path, not full paths as we are working in the same folder structure.
I can make out that you are running this on your own profile, so I replaced C:\users\<username> with %userprofile% in the event someone else wants to run it from a similar folder, their <username> will be different.
popd at the bottom of the script simply changes back to the previous working directory you were in before the last pushd. it is not needed for this particular script, but adding it so you can learn about it compared to pushd
All of the items I modified has some good help topics, you can find help topics on cmd by simply running the command name with an appended /? for instance for /?, set /? etc.

How to rename the folders with batch?

I have a file folder.txt file with a list of folder names on the HDD that have to be renamed with the names from gbv.txt. So the first line from folder.txt should be renamed with the first line from gbv.txt and so on. The folders are in the same directory from where the script will be started.
folder.txt
F-93-B-109
F-93-B-122
F-93-B-148
F-93-B-157
gbv.txt
GBV529357402
GBV52935795X
GBV529360799
GBV529362236
I'm slightly new to batch and don't know how to use rename in this situation in the loop
Essentially to read two files at a time you need to use a FOR /F command to read one file and stream the other file into the FOR /F command block. When you do this, you then can use the SET /P command to capture the line of text from the file being streamed into the command block.
#echo off
setlocal enabledelayedexpansion
< gbv.txt (FOR /F "delims=" %%G IN (folder.txt) DO (
set /p newname=
echo rename "%%G" "!newname!"
)
)
pause
The output on the screen will look like this.
C:\BatchFiles\SO>so.bat
rename "F-93-B-109" "GBV529357402"
rename "F-93-B-122" "GBV52935795X"
rename "F-93-B-148" "GBV529360799"
rename "F-93-B-157" "GBV529362236"
Press any key to continue . . .
When the output looks good, remove the word echo before the rename in the script.

Batch file to run exe with unknown filename as arguments

I have an exe for comparing 2 .csv files. And it works when I open cmd window, drag exe, type space, drag 1st csv file, type space, and drag 2nd file.
Now I want to automate it, and the problem is it is never on the same place, nor uses the same files for comparing...
What I got so far is following in batch:
%~dp0\Komparator.exe BC101.csv BC102.csv
pause
those 2 csv files are going to be in same folder, next to .exe and .bat file... but that "same folder" is not always the same, today its one location, another day is another folder
but I dont know how to automate those 2 arguments for file names, I just want it to recognize two .csv files near .exe and .bat
Thanks in advance!
You can read csv filenames and store them into batch variables using for cycle.
Here's an example, assuming your csv files are in the same directory as the batch file.
compare.cmd
#echo off
set FILE1=
set FILE2=
for /f "delims=" %%a in ('dir /b %~dp0*.csv 2^>nul ^| sort') do (
if defined FILE1 set "FILE2=%%~a" & goto :exit_loop
set "FILE1=%%~a"
)
:exit_loop
if not defined FILE1 echo first csv file not found!& goto :eof
if not defined FILE2 echo second csv file not found!& goto :eof
%~dp0\Komparator.exe "%~dp0%FILE1%" "%~dp0%FILE2%"

Batch file Drag and Drop multiple files from one folder to a new folder Error

So I have the batch file below.
#ECHO OFF
FOR %%I IN (.) DO SET FolderName=%%~nxI
MKDIR "C:\%FolderName%"
for %%i in (%*) do (
move "%%~i" "C:\%FolderName%"
)
So when I drag and drop multiple files into the batch file, it will take the name of the folder that holds the files that I drag and drop and make a new folder at C:\ with the same name and then move the files into the new folder at C:\
Example: The folder that holds the files that I want to move is name Shop. Then the folder Shop is located at
...\ground\bell\tower\Shop
Using the batch file will make a new folder name Shop at C:\
Example
C:\Shop
The batch files works when I drag and drop about 100 files at once. The problem is that when I drag and drop 300 files at once, it returns the Error that says "The filename or extension is too long". I am able to move the files manually so I know that it can not be cause by a filename being too long.
Then I made a new batch file thinking maybe it is a problem with the move command or my for loop. So I wrote the batch file below.
#echo off
FOR %%I IN (.) DO SET FolderName=%%~nxI
MKDIR "C:\%FolderName%"
MOVE "%cd%\*.*" "C:\%FolderName%"
Now the second batch file above works just about the same as the first batch file. Just that with the second batch file, I only need to drag and drop one file from the folder that I want to move and it will move all the files in the first folder to a new folder at C:\ even if the first folder had 1000 files.
My question is why does the first batch file fail if I drag and drop too many files at once. Using the second batch file work, so it can not be because of the move command or is it? Since I am moving all the files from one folder to the other, the second batch file fits my need and was wondering if there will be any problems with the second batch file or a better way of doing this.
When you Drag-n-Drop Files on you Bat File, your Bat is actually called as if you would have called it in your command prompt. So if you drag three files on your Bat i.e.
Testfile.txt
Testfile.md
Testfile.jpg
Then actually your Bat is called like this:
C:\MyBatch.BAT Testfile.txt Testfile.md Testfile.jpg
If you call more it is obviously something like:
C:\MyBatch.BAT Testfile.txt Testfile.md Testfile.jpg Testfile01.txt Testfile01.md Testfile01.jpg Testfile02.txt Testfile02.md Testfile02.jpg Testfile03.txt Testfile03.md Testfile03.jpg Testfile04.txt Testfile04.md Testfile04.jpg Testfile05.txt Testfile05.md Testfile05.jpg etc...
Ah, can you read the rest of the line? Ok, this is not as long as 1000 Files but get the point what the difference is in your scripts. Your command line buffer will not be able to capture that much input.
Actually the size of how many characters you can enter in you command prompt varies a bit from system to system, but there was something like 8k in winXP, i reckon it is still the same.
http://support.microsoft.com/kb/830473 <-- that could help more concerning max.
And since the length of your command prompt is so "short" you have to find different methods for longer file trails - as you did - you could also overcome this, if you output the files you want to copy in a text file and then use that as input for your copy bat.
dir /b >filelist.txt
so now that you have this file list, then you just read the text file line by line:
for /f "delims=" %%i in (filelist.txt) do echo D|xcopy "C:\FolderName\%%i" "c:\temp\%%i" /i /z /y
so this will actually read your file list.txt and will (for each filename in list) press D key and pipes it to the XCopy command.
So piping a filelist to your command is a much better way, where actually in your case, if you really want the whole dir and not just a selection, copying directories is faster than copying file by file.
Hope you Question is answered.
If I am not mistaken, you are trying to create a folder with the parent folder as name. So before you ask again the same question in another post, I will code what you are seeking.
#echo off
setlocal
set "destination=c:\destination"
for %%i in (%~1) do set "parent=%%~pi" &goto:next
:next
for %%i in ("%parent:~0,-1%") do set "parent=%%~nxi"
for %%i in (%*) do (
echo:
if not exist %destination%\%parent%\nul ( mkdir "%destination%\%parent%" )
move "%%~i" "%destination%%parent%"
)
In addition, a command with many arguments is not a problem in the previous code.
For example: Write a batch file with the following code
#echo off
setlocal
set "destination=c:\destination"
for %%i in (%~1) do set "parent=%%~pi" &goto:next
:next
for %%i in ("%parent:~0,-1%") do set "parent=%%~nxi"
for %%i in (%*) do (
echo:
if not exist %destination%\%parent%\nul (echo mkdir "%destination%\%parent%")
echo move "%%~i" "%destination%%parent%"
)
call it test-move.bat and put the following long command-line of 250 parameters in cmd:
test-move.bat TestFile001.txt TestFile002.txt TestFile003.txt TestFile004.txt TestFile005.txt TestFile006.txt TestFile007.txt TestFile008.txt TestFile009.txt TestFile010.txt TestFile011.txt TestFile012.txt TestFile013.txt TestFile014.txt TestFile015.txt TestFile016.txt TestFile017.txt TestFile018.txt TestFile019.txt TestFile020.txt TestFile021.txt TestFile022.txt TestFile023.txt TestFile024.txt TestFile025.txt TestFile026.txt TestFile027.txt TestFile028.txt TestFile029.txt TestFile030.txt TestFile031.txt TestFile032.txt TestFile033.txt TestFile034.txt TestFile035.txt TestFile036.txt TestFile037.txt TestFile038.txt TestFile039.txt TestFile040.txt TestFile041.txt TestFile042.txt TestFile043.txt TestFile044.txt TestFile045.txt TestFile046.txt TestFile047.txt TestFile048.txt TestFile049.txt TestFile050.txt TestFile051.txt TestFile052.txt TestFile053.txt TestFile054.txt TestFile055.txt TestFile056.txt TestFile057.txt TestFile058.txt TestFile059.txt TestFile060.txt TestFile061.txt TestFile062.txt TestFile063.txt TestFile064.txt TestFile065.txt TestFile066.txt TestFile067.txt TestFile068.txt TestFile069.txt TestFile070.txt TestFile071.txt TestFile072.txt TestFile073.txt TestFile074.txt TestFile075.txt TestFile076.txt TestFile077.txt TestFile078.txt TestFile079.txt TestFile080.txt TestFile081.txt TestFile082.txt TestFile083.txt TestFile084.txt TestFile085.txt TestFile086.txt TestFile087.txt TestFile088.txt TestFile089.txt TestFile090.txt TestFile091.txt TestFile092.txt TestFile093.txt TestFile094.txt TestFile095.txt TestFile096.txt TestFile097.txt TestFile098.txt TestFile099.txt TestFile100.txt TestFile101.txt TestFile102.txt TestFile103.txt TestFile104.txt TestFile105.txt TestFile106.txt TestFile107.txt TestFile108.txt TestFile109.txt TestFile110.txt TestFile111.txt TestFile112.txt TestFile113.txt TestFile114.txt TestFile115.txt TestFile116.txt TestFile117.txt TestFile118.txt TestFile119.txt TestFile120.txt TestFile121.txt TestFile122.txt TestFile123.txt TestFile124.txt TestFile125.txt TestFile126.txt TestFile127.txt TestFile128.txt TestFile129.txt TestFile130.txt TestFile131.txt TestFile132.txt TestFile133.txt TestFile134.txt TestFile135.txt TestFile136.txt TestFile137.txt TestFile138.txt TestFile139.txt TestFile140.txt TestFile141.txt TestFile142.txt TestFile143.txt TestFile144.txt TestFile145.txt TestFile146.txt TestFile147.txt TestFile148.txt TestFile149.txt TestFile150.txt TestFile151.txt TestFile152.txt TestFile153.txt TestFile154.txt TestFile155.txt TestFile156.txt TestFile157.txt TestFile158.txt TestFile159.txt TestFile160.txt TestFile161.txt TestFile162.txt TestFile163.txt TestFile164.txt TestFile165.txt TestFile166.txt TestFile167.txt TestFile168.txt TestFile169.txt TestFile170.txt TestFile171.txt TestFile172.txt TestFile173.txt TestFile174.txt TestFile175.txt TestFile176.txt TestFile177.txt TestFile178.txt TestFile179.txt TestFile180.txt TestFile181.txt TestFile182.txt TestFile183.txt TestFile184.txt TestFile185.txt TestFile186.txt TestFile187.txt TestFile188.txt TestFile189.txt TestFile190.txt TestFile191.txt TestFile192.txt TestFile193.txt TestFile194.txt TestFile195.txt TestFile196.txt TestFile197.txt TestFile198.txt TestFile199.txt TestFile200.txt TestFile201.txt TestFile202.txt TestFile203.txt TestFile204.txt TestFile205.txt TestFile206.txt TestFile207.txt TestFile208.txt TestFile209.txt TestFile210.txt TestFile211.txt TestFile212.txt TestFile213.txt TestFile214.txt TestFile215.txt TestFile216.txt TestFile217.txt TestFile218.txt TestFile219.txt TestFile220.txt TestFile221.txt TestFile222.txt TestFile223.txt TestFile224.txt TestFile225.txt TestFile226.txt TestFile227.txt TestFile228.txt TestFile229.txt TestFile230.txt TestFile231.txt TestFile232.txt TestFile233.txt TestFile234.txt TestFile235.txt TestFile236.txt TestFile237.txt TestFile238.txt TestFile239.txt TestFile240.txt TestFile241.txt TestFile242.txt TestFile243.txt TestFile244.txt TestFile245.txt TestFile246.txt TestFile247.txt TestFile248.txt TestFile249.txt TestFile250.txt

Windows batch way to replace all files in subdirectories with singular file (copy, rename all files)

I have a good command over cmd commands, but this may require a variable or a loop which is where I fail in batch commands. Please help if you can!
-- Have about 100 subdirectories each has 1-20 HTML files in it. There are about 100 HTML files in the root directory too.
-- Need to replace all HTML files in the above directories with the same HTML source (copy over existing file and keep the name the same). Basically trying to replace all existing files with a redirect script to a new server for direct bookmarked people. We are running a plain webserver without access to server-side redirects so trying to do this just by renaming the files (locked down corp environment).
Seems pretty simple. I can't get it to work with wildcards by copying the same file over to replace. I only get the first file replaced, but the rest of the files will fail. Any one with any advice?
This should do it from the command prompt. Replace % with %% for use in a batch file.
for /r "c:\base\folder" %a in (*.html) do copy /y "d:\redirect.html" "%a"
Without knowing more precisely how you want to update the file content I suggest the following rough approach.
To re-create your example, I had to create some folders. Run this command to do that:
for /l %i in (1,1,20) do mkdir fold%i
I then used this script to create some example files:
#echo off
set number=0
for /d %%i in (c:\Logs\htmltest\*) do call :makefiles %%i
goto :EOF
:makefiles
set /a number+=1
touch %1\file%number%.txt
echo %number% >%1\file%number%.txt
I then used this script to append the text changed to the file. Not sure if that is what you wanted - probably you need something more sophisticated.
#echo off
set number=0
for /d %%i in (c:\Logs\htmltest\*) do #for %%f in ("%%i\*.txt") do call :changetext %%f
goto :EOF
:changetext
echo changing file contents to ^"changed^" for file: %1
echo changed>>%1

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