Using SQL Server 2012 I need to get the datediff of all dates in a Log table which has the same column, for example:
ID | Version | Status | Date
-----------------------------------------------------
12345 | 1 | new | 2014-05-01 00:00:00.000
12345 | 2 | up | 2014-05-02 00:00:00.000
12345 | 3 | appr | 2014-05-03 00:00:00.000
67890 | 1 | new | 2014-05-04 00:00:00.000
67890 | 2 | up | 2014-05-08 00:00:00.000
67890 | 3 | rej | 2014-05-13 00:00:00.000
I need to get the date diff of all sequential dates (date between 1, 2 and date between 2, 3)
I have tried creating a while but with no luck!
Your help is really appreciated!
This Calculates DateDiff as per your query "date diff of all sequential dates",if not sequential,it will just show same date.Further please don't use Reserved Keywords as Column names
SELECT ID,
[VERSION],
[STATUS],
[DATE],
CASE WHEN LEAD([DATE]) OVER (PARTITION BY ID ORDER BY [VERSION])=DATEADD(DAY,1,[DATE])
THEN CAST(DATEDIFF(DAY,[DATE],LEAD([DATE]) OVER (PARTITION BY ID ORDER BY VERSION)) AS VARCHAR(5))
ELSE [DATE] END AS DATEDIFFF
FROM
#TEMP
Another way with OUTER APPLY (get the previous value) :
SELECT t.*,
DATEDIFF(day,p.[Date],t.[Date]) as dd
FROM YourTable t
OUTER APPLY (
SELECT TOP 1 *
FROM YourTable
WHERE ID = t.ID AND [DATE] < t.[Date] AND [Version] < t.[Version]
ORDER BY [Date] DESC
) as p
Output:
ID Version Status Date dd
12345 1 new 2014-05-01 00:00:00.000 NULL
12345 2 up 2014-05-02 00:00:00.000 1
12345 3 appr 2014-05-03 00:00:00.000 1
67890 1 new 2014-05-04 00:00:00.000 NULL
67890 2 up 2014-05-08 00:00:00.000 4
67890 3 rej 2014-05-13 00:00:00.000 5
Note: If you are using SQL Server 2012 then better use LEAD and LAG functions.
Related
I need to sum up values from Money column for each WeekNumber.
Now I have view:
WeekNumber | DayTime | Money
---------------------------------------
1 | 2012-01-01 | 20.4
1 | 2012-01-02 | 30.5
1 | 2012-01-03 | 55.1
2 | 2012-02-01 | 67.3
2 | 2012-02-02 | 33.4
3 | 2012-03-01 | 11.8
3 | 2012-03-04 | 23.9
3 | 2012-03-05 | 34.3
4 | 2012-04-01 | 76.6
4 | 2012-04-02 | 90.3
Tsql:
SELECT datepart(week,DayTime) AS WeekNumber, DayTime, Money FROM dbo.Transactions
In conclusion, I would like to get something like this:
WeekNumber | DayTime | Sum
---------------------------------------
1 | 2012-01-01 | 106
2 | 2012-02-02 | 100.7
3 | 2012-03-03 | 470
4 | 2012-04-01 | 166.9
DayTime should be random for each Week Number but exists in column DayTime from view above.
Please, be free to write your ideas. Thanks.
SELECT datepart(week,DayTime) AS WeekNumber
, MIN(DayTime) DayTime --<-- Instead of random get first date from your data in that week
, SUM(Money) AS [Sum]
FROM dbo.Transactions
GROUP BY datepart(week,DayTime)
Try this
SELECT datepart(week,DayTime) AS WeekNumber, SUM(Money) FROM dbo.Transactions GROUP BY WeekNumber
As you will have number of rows for each week you cannot get DayTime with the same table. There are other ways to add that too like JOIN
Change your SQL to sum the money column. Like this
SELECT
datepart(week,DayTime) AS WeekNumber,
DayTime, Money = SUM(Money)
FROM dbo.Transactions
GROUP BY datepart(week,DayTime),DayTime
SELECT datepart(week, DayTime) AS WeekNumber
,MIN(DayTime)
,SUM(MONEY)
FROM dbo.Transactions
GROUP BY datepart(week, DayTime)
Using T-SQL, I want a new column that will show me the first day of each month, for the current year of getdate().
After that I need to count the rows on this specific date. Should I do it with CTE or a temp table?
If 2012+, you can use DateFromParts()
To Get a List of Dates
Select D = DateFromParts(Year(GetDate()),N,1)
From (values (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12)) N(N)
Returns
D
2017-01-01
2017-02-01
2017-03-01
2017-04-01
2017-05-01
2017-06-01
2017-07-01
2017-08-01
2017-09-01
2017-10-01
2017-11-01
2017-12-01
Edit For Trans Count
To get Transactions (assuming by month). It becomes a small matter of a left join to created Dates
-- This is Just a Sample Table Variable for Demonstration.
-- Remove this and Use your actual Transaction Table
--------------------------------------------------------------
Declare #Transactions table (TransDate date,MoreFields int)
Insert Into #Transactions values
('2017-02-18',6)
,('2017-02-19',9)
,('2017-03-05',5)
Select TransMonth = A.MthBeg
,TransCount = count(B.TransDate)
From (
Select MthBeg = DateFromParts(Year(GetDate()),N,1)
,MthEnd = EOMonth(DateFromParts(Year(GetDate()),N,1))
From (values (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12)) N(N)
) A
Left Join #Transactions B on TransDate between MthBeg and MthEnd
Group By A.MthBeg
Returns
TransMonth TransCount
2017-01-01 0
2017-02-01 2
2017-03-01 1
2017-04-01 0
2017-05-01 0
2017-06-01 0
2017-07-01 0
2017-08-01 0
2017-09-01 0
2017-10-01 0
2017-11-01 0
2017-12-01 0
For an adhoc table of months for a given year:
declare #year date = dateadd(year,datediff(year,0,getdate() ),0)
;with Months as (
select
MonthStart=dateadd(month,n,#year)
from (values(0),(1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11)) t(n)
)
select MonthStart
from Months
rextester demo: http://rextester.com/POKPM51023
returns:
+------------+
| MonthStart |
+------------+
| 2017-01-01 |
| 2017-02-01 |
| 2017-03-01 |
| 2017-04-01 |
| 2017-05-01 |
| 2017-06-01 |
| 2017-07-01 |
| 2017-08-01 |
| 2017-09-01 |
| 2017-10-01 |
| 2017-11-01 |
| 2017-12-01 |
+------------+
The first part: dateadd(year,datediff(year,0,getdate() ),0) adds the number of years since 1900-01-01 to the date 1900-01-01. So it will return the first date of the year. You can also swap year for other levels of truncation: year, quarter, month, day, hour, minute, second, et cetera.
The second part uses a common table expression and the table value constructor (values (...),(...)) to source numbers 0-11, which are added as months to the start of the year.
Not sure why you require recursive... But for first day of month you can try query like below:
Select Dateadd(day,1,eomonth(Dateadd(month, -1,getdate())))
declare #year date = dateadd(year,datediff(year,0,getdate() ),0)
;WITH months(MonthNumber) AS
(
SELECT 0
UNION ALL
SELECT MonthNumber+1
FROM months
WHERE MonthNumber < 11
)
select dateadd(month,MonthNumber,#year)
from months
I have a table similar to the one represented below.
myID | some data | start_date | end_date
1 Tom 2016-01-01 2016-05-09
2 Mike 2015-03-01 2017-03-09
...
I have a function that when provided with start_date, end_date, interval (for example weeks)
returns me data as below. (splits the start and end dates to week intervals)
select * from my_function('2016-01-01','2016-01-12', 'ww')
2015-12-28 00:00:00.000 | 2016-01-03 00:00:00.000 15W53
2016-01-04 00:00:00.000 | 2016-01-10 00:00:00.000 16W1
2016-01-11 00:00:00.000 | 2016-01-17 00:00:00.000 16W2
I would like to be able to write a query that returns all of the values from the 1 table, but splits Start date and end date in to multiple rows using the function.
myID | some data | Week_start_date | Week_end_date | (optional)week_num
1 Tom 2015-12-28 2016-01-03 15W53
1 Tom 2016-01-04 2016-01-10 16W1
1 Tom 2016-01-11 2016-01-17 16W2
...
2 Mike etc....
Could someone please help me with creating such a query ?
select myID,some_data,b.Week_start_date,b.Week_end_date,b.(optional)week_num from #a cross apply
(select * from my_function('2016-01-01','2016-01-12', 'ww'))b
like sample data i tried
create table #a
(
myID int, some_data varchar(50) , start_date date, end_date date)
insert into #a values
(1,'Tom','2016-01-01','2016-05-09'),
(2,'Mike','2015-03-01','2017-03-09')
here iam keeping function result into one temp table
create table #b
(
a datetime,b datetime, c varchar(50)
)
insert into #b values
('2015-12-28 00:00:00.000','2016-01-03 00:00:00.000','15W53'),
('2016-01-04 00:00:00.000','2016-01-10 00:00:00.000','16W1 '),
('2016-01-11 00:00:00.000','2016-01-17 00:00:00.000','16W2 ')
select myID,some_data,b.a,b.b,b.c from #a cross apply
(select * from #b)b
output like this
myID some_data a b c
1 Tom 2015-12-28 00:00:00.000 2016-01-03 00:00:00.000 15W53
1 Tom 2016-01-04 00:00:00.000 2016-01-10 00:00:00.000 16W1
1 Tom 2016-01-11 00:00:00.000 2016-01-17 00:00:00.000 16W2
2 Mike 2015-12-28 00:00:00.000 2016-01-03 00:00:00.000 15W53
2 Mike 2016-01-04 00:00:00.000 2016-01-10 00:00:00.000 16W1
2 Mike 2016-01-11 00:00:00.000 2016-01-17 00:00:00.000 16W2
Based on your current result and expected result,the only difference ,i see is myID
so you will need to frame your query like this..
;with cte
as
(
select * from my_function('2016-01-01','2016-01-12', 'ww')
)
select dense_rank() over (order by somedata) as col,
* from cte
Dense Rank assigns same values for the same partition and assigs the sequential value to next partition ,unlike Rank
Look here for more info:
https://stackoverflow.com/a/7747342/2975396
I have a dataset (DATASET1) that lists all employees with their Dept IDs, the date they started and the date they were terminated.
I'd like my query to return a dataset in which every row represents a day for each employee stayed employed, with number of days worked (Start-to-Date).
How do I this query? Thanks for your help, in advance.
DATASET1
DeptID EmployeeID StartDate EndDate
--------------------------------------------
001 123 20100101 20120101
001 124 20100505 20130101
DATASET2
DeptID EmployeeID Date #ofDaysWorked
--------------------------------------------
001 123 20100101 1
001 123 20100102 2
001 123 20100103 3
001 123 20100104 4
.... .... ........ ...
EIDT: My goal is to build a fact table which would be used to derive measures in SSAS. The measure I am building is 'average length of employment'. The measure will be deployed in a dashboard and the users will have the ability to select a calendar period and drill-down into month, week and days. That's why I need to start with such a large dataset. Maybe I can accomplish this goal by using MDX queries but how?
You can use a recursive CTE to perform this:
;with data (deptid, employeeid, inc_date, enddate) as
(
select deptid, employeeid, startdate, enddate
from yourtable
union all
select deptid, employeeid,
dateadd(d, 1, inc_date),
enddate
from data
where dateadd(d, 1, inc_date) <= enddate
)
select deptid,
employeeid,
inc_date,
rn NoOfDaysWorked
from
(
select deptid, employeeid,
inc_date,
row_number() over(partition by deptid, employeeid
order by inc_date) rn
from data
) src
OPTION(MAXRECURSION 0)
See SQL Fiddle with Demo
The result is similar to this:
| DEPTID | EMPLOYEEID | DATE | NOOFDAYSWORKED |
-----------------------------------------------------
| 1 | 123 | 2010-01-01 | 1 |
| 1 | 123 | 2010-01-02 | 2 |
| 1 | 123 | 2010-01-03 | 3 |
| 1 | 123 | 2010-01-04 | 4 |
| 1 | 123 | 2010-01-05 | 5 |
| 1 | 123 | 2010-01-06 | 6 |
| 1 | 123 | 2010-01-07 | 7 |
| 1 | 123 | 2010-01-08 | 8 |
| 1 | 123 | 2010-01-09 | 9 |
| 1 | 123 | 2010-01-10 | 10 |
| 1 | 123 | 2010-01-11 | 11 |
| 1 | 123 | 2010-01-12 | 12 |
SELECT DeptID, EmployeeID, Date, DATEDIFF(DAY, StartDate, '3/1/2011') AS ofDaysWorked
FROM DATASET1
See if that worked!
A table exists in Microsoft SQL Server with record ID, Start Date, End Date and Quantity.
The idea is that for each record, the quantity/total days in range = daily quantity.
Given that a table containing all possible dates exists, how can I generate a result set in SQL Server to look like the following example?
EX:
RecordID | Start Date | End Date | Quantity
1 | 1/1/2010 | 1/5/2010 | 30000
2 | 1/3/2010 | 1/9/2010 | 20000
3 | 1/1/2010 | 1/7/2010 | 10000
Results as
1 | 1/1/2010 | QTY (I can do the math easy, just need the dates view)
1 | 1/2/2010 |
1 | 1/3/2010 |
1 | 1/4/2010 |
1 | 1/3/2010 |
2 | 1/4/2010 |
2 | 1/5/2010 |
2 | 1/6/2010 |
2 | 1/7/2010 |
2 | 1/8/2010 |
2 | 1/9/2010 |
3 | 1/1/2010 |
3 | 1/2/2010 |
3 | 1/3/2010 |
3 | 1/4/2010 |
3 | 1/5/2010 |
3 | 1/6/2010 |
3 | 1/7/2010 |
Grouping on dates I could get then get the sum of quantity on that day however the final result set can't be aggregate due to user provided filters that may exclude some of these records down the road.
EDIT
To clarify, this is just a sample. The filters are irrelevant as I can join to the side to pull in details related to the record ID in the results.
The real data contains N records which increases weekly, the dates are never the same. There could be 2000 records with different start and end dates... That is what I want to generate a view for. I can right join onto the data to do the rest of what I need
I should also mention this is for past, present and future data. I would love to get rid of a temporary table of dates. I was using a recursive query to get all dates that exist within a 50 year span but this exceeds MAXRECURSION limits for a view, that I cannot use.
Answer
select RecordId,d.[Date], Qty/ COUNT(*) OVER (PARTITION BY RecordId) AS Qty
from EX join Dates d on d.Date between [Start Date] and [End Date]
ORDER BY RecordId,[Date]
NB: The below demo CTEs use the date datatype which is SQL Server 2008 the general approach should work for SQL2005 as well though.
Test Case
/*CTEs for testing purposes only*/
WITH EX AS
(
SELECT 1 AS RecordId,
cast('1/1/2010' as date) as [Start Date],
cast('1/5/2010' as date) as [End Date],
30000 AS Qty
union all
SELECT 2 AS RecordId,
cast('1/3/2010' as date) as [Start Date],
cast('1/9/2010' as date) as [End Date],
20000 AS Qty
),Dates AS /*Dates Table now adjusted to do greater range*/
(
SELECT DATEADD(day,s1.number + 2048*s2.number,'1990-01-01') AS [Date]
FROM master.dbo.spt_values s1 CROSS JOIN master.dbo.spt_values s2
where s1.type='P' AND s2.type='P' and s2.number <= 8
order by [Date]
)
select RecordId,d.[Date], Qty/ COUNT(*) OVER (PARTITION BY RecordId) AS Qty
from EX join Dates d on d.Date between [Start Date] and [End Date]
ORDER BY RecordId,[Date]
Results
RecordId Date Qty
----------- ---------- -----------
1 2010-01-01 6000
1 2010-01-02 6000
1 2010-01-03 6000
1 2010-01-04 6000
1 2010-01-05 6000
2 2010-01-03 2857
2 2010-01-04 2857
2 2010-01-05 2857
2 2010-01-06 2857
2 2010-01-07 2857
2 2010-01-08 2857
2 2010-01-09 2857
I think you can try this.
SELECT [Quantities].[RecordID], [Dates].[Date], SUM([Quantity])
FROM [Dates]
JOIN [Quantities] on [Dates].[Date] between [Quantities].[Start Date] and [End Date]
GROUP BY [Quantities].[RecordID], [Dates].[Date]
ORDER BY [Quantities].[RecordID], [Dates].[Date]