I'm using regex for validating numbers in angularjs. But my code shows validation error when the number exceeds 9 digits.Could someone please help me to rectify my code such that any digits of number can be entered.
What I have tried is :
ng-pattern="/^\d{0,9}?$/"
Just remove the {0,9}? and use * instead like
/^\d*$/
{0,9} mean is any length between 0 and 9
I suspect the problem is understanding the difference between:
{0,9}
[0-9]
{0,9} means "zero to 9 repetitions of the preceding term", which in this case means "zero to 9 digits".
[0-9] means "a character in the range 0 to 9 (inclusive)", which is the same as \d.
Try:
/^\d+$/
Which means "all numeric input" and excludes blank input.
To allow decimal input too, escape the dot and make the decimal part optional:
/^\d+(\.\d+)?$/
Which means "at least one digit, optionally followed by a dot and at least one digit".
Just change the {0,9} quantifier with the *. And remove the ? -- it's useless:
ng-pattern="/^\d*$/"
For decimal values:
ng-pattern="/^\d*(\.\d+)?$/"
Use :
"/^\d*?$/"
\d{0,9} = match 0 to 9 digits
\d* = match 0 to N digits
\d = digit : 0 or 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9
Related
I have the following piece of code. I want to format numbers with string templates. One variable has 2 decimal places, the other 4 decimal places but they represent the same number 50000 (fifty thousand).
The first number is correctly formatted (German representation) 50.000,00, the other one however is formatted as 5 million 5.000.000,00!
DATA: lv_p2 TYPE p LENGTH 9 DECIMALS 2,
lv_p4 TYPE p LENGTH 14 DECIMALS 4.
START-OF-SELECTION.
lv_p2 = '50000'.
lv_p4 = lv_p2.
SET COUNTRY 'DE'.
"This is correctly formatted as 50.000,00
WRITE |{ lv_p2 NUMBER = ENVIRONMENT CURRENCY = 'EUR' }|.
"This is on the other hand interpreted as five million! 5.000.000,00
WRITE |{ lv_p4 NUMBER = ENVIRONMENT CURRENCY = 'EUR' }|.
Is this documented somewhere? What am I doing wrong here?
EDIT:
It looks like the problem is with the addition CURRENCY. If I don't use it, then the number is correctly formatted.
WRITE |{ lv_p4 NUMBER = ENVIRONMENT }|.
or WRITE |{ lv_p4 NUMBER = ENVIRONMENT DECIMALS = 2 }|.
Anyway looks like some kind of a bug.
I believe this behaviour is documented.
ABAP Documentation - WRITE, format_options - CURRENCY cur
When CURRENCY is added:
"For data objects of type p, the decimal places determined by the
definition of the data type are ignored completely. Independently of
the actual value and without rounding, decimal separators and
thousands separators are inserted between the digits in the places
determined by cur."
Shortly: if CURRENCY is added (by WRITE), the number of decimal places is determined by the currency (in this case EUR has 2 decimal places), so the value 50.000,0000 will be 5.000.000,00. Same length (9 digits) only the number of decimals will be different.
I am trying to create a syntax parser using C-Bison and Flex. In Flex I have a regular expression which matches integers based on the following:
Must start with any digit in range 1-9 and followed by any number of digits in range 0-9. (ex. Correct: 1,12,11024 | Incorrect: 012)
Can be signed (ex. +2,-5)
The number 0 must not be followed by any digit (0-9) and must not signed. (ex. Correct: 0 | Incorrect: 012,+0,-0)
Here is the regex I have created to perform the matching:
[^+-]0[^0-9]|[+-]?[1-9][0-9]*
Here is the expression I am testing:
(1 + 1 + 10)
The matches:
1
1
10)
And here is my question, why does it match '10)'?
The reason I used the above expression, instead of the much simpler one,
(0|[+-]?[1-9][0-9]*) is due to inability of the parser to recognise incorrect expressions such as 012.
The problem seems to occur only when before the ')' precedes the digit '0'. However if the '0' is preceded by two or more digits (ex. 100), then the ')' is not matched.
I know for a fact if I remove [^0-9] from the regex it doesn't match the ')'.
It matches 10( because 1 matches [^+-], 0 matches 0 and ( matches [^0-9].
The reason I used the above expression, instead of the much simpler one, (0|[+-]?[1-9][0-9]*) is due to inability of the parser to recognise incorrect expressions such as 012.
How so? Using the above regex, 012 would be recognized as two tokens: 0 and 12. Would this not cause an error in your parser?
Admittedly, this would not produce a very good error message, so a better approach might be to just use [0-9]+ as the regex and then use the action to check for a leading zero. That way 012 would be a single token and the lexer could produce an error or warning about the leading zero (I'm assuming here that you actually want to disallow leading zeros - not use them for octal literals).
Instead of a check in the action, you could also keep your regex and then add another one for integers with a leading zero (like 0[0-9]+ { warn("Leading zero"); return INT; }), but I'd go with the check in the action since it's an easy check and it keeps the regex short and simple.
PS: If you make - and + part of the integer token, something like 2+3 will be seen as the integer 2, followed by the integer +3, rather than the integers 2 and 3 with a + token in between. Therefore it is generally a better idea to not make the sign a part of the integer token and instead allow prefix + and - operators in the parser.
I have an input of type number, the value in this input will be saved in a column of type number(12,2), so I want to set the max length to 12 (12 digits in total,
2 of which are after the decimal point).
I tried as following :
<input type="number" md-maxlength="12" ng-pattern="/^[0-9]{0,10}([,.][0-9]{0,2})?$/" step="0.01" ..>
Whenver I type something it's invalid, this only occurs when I add the md-maxlength="12" which I use to display the max length under the input field.
As you can see in the picture the input is invalid.
How can I solve this ?
Edit:
ng-maxlength instead of md-maxlength resolves this issue but the x/12 label under the input which indicates the max length is not displayed anymore.
Edit 2:
The regex now indicates that only 10 number are allowed before decimal point (comma or dot) and 2 are optional after, you can see that the regex is working just fine here : https://regex101.com/r/fdDLFP/3, the problem is when I add the md-maxlength.
I have this string:
{"name": "Fancy HaXXor123Name","profession": 1,"race": 2,"map_id": 1052,"world_id": 268435461,"team_color_id": 0,"commander": false,"fov": 0.768}
I want to get an array back which includes the following information (from left to right from the string):
Fancy HaXXor123Name
1
2
1052
268435461
0
false
0.768
I tried to mess with RegExBuddy and got a promissing pattern which looks like this
(\d{1,}).(\d{1,})|(\d{1,})|(?i)"(.*?)"
This is what I got back
name
Fancy HaXXor123Name
profession
1
race
2
map_id
10
2
world_id
2684354
1
team_color_id
0
commander
fov
0
768
So there are large spaces between the informations, torn numbers and the false is missing. I can't fix this problem and I'm completely new to StringRegExp.
I'm using AutoIT which uses the PCRE RegExp-Engine (this is what think).
You may use a regex like the following:
"\s*:\s*(?:"\K[^"]*|\K[^][\s,{}]+)
See the regex demo
Details:
"\s*:\s* - a literal ", 0+ whitespaces, :, 0+ whitespaces
(?:"\K[^"]*|\K[^][\s,{}]+) - A non-capturing group matching 2 alternatives:
"\K[^"]* - a ", then \K zeros the text matched so far, and then matches 0+ chars other than " with [^"]*
\K[^][\s,{}]+ - \K drops the text matched so far, and [^][\s,{}]+ matches 1+ chars other than ], [, whitespace, ,, { and }.
I am making a program which got to split the phone-number apart, each part has been divided by a hyphen (or spaces, or '( )' or empty).
Exp: Input: 0xx-xxxx-xxxx or 0xxxxxxxxxx or (0xx)xxxx-xxxx
Output: code 1: 0xx
code 2: xxxx
code 3: xxxx
But my problem is: sometime "Code 1" is just 0x -> so "Code 2" must be xxxxx (1st part always have hyphen or a parenthesis when 2 digit long)
Anyone can give me a hand, It would be grateful.
According to your comments, the following regex will extract the information you need
^\(?(0\d{1,2})\)?[- ]?(\d{4,5})[- ]?(\d{4})$
Break down:
^\(?(0\d{1,2})\)? matches 0x, 0xx, (0xx) and (0x) at he beggining of the string
[- ]? as parenthesis can only be used for the first group, the only valid separators left are space and the hyphen. ? means 0 or 1 time.
(\d{4,5}) will match the second group. As the length of the 3rd group is fixed (4 digits), the regex will automatically calculate the length of the Group1 and 2.
(\d{4})$ matches the 4 digits at the end of the number.
See it in action
You can the extract data from capture group 1,2 and 3
Note: As mentionned in the comments of the OP, this only extracts data from correctly formed numbers. It will match some ill-formed numbers.