Good Day! I am working on a chart where I need to display all the days of the current week to show the sales per Week. So far, I am able to display all the days of the current week, I'm just having a trouble in displaying the sales for each day of the week.Since there are no records in the database for the days of the week, it the TOTAL_SALES column should all return a Null value. Instead, it returns the total sales recorded in the database. Here is my Stored Procedure query so far.
WITH DAYSOFTHEWEEK AS
(
SELECT 0 DAY
UNION ALL
SELECT DAY + 1 FROM DAYSOFTHEWEEK WHERE DAY < 6
)
SELECT DATEADD(DAY, DAY, DATEADD(DAY, 2-DATEPART(WEEKDAY, CONVERT (date, GETDATE())), CONVERT (date, GETDATE()))) AS DAY_OF_THE_WEEK,
SUM([ORDER].NET_AMOUNT) AS TOTAL_SALES
FROM DAYSOFTHEWEEK, [ORDER]
GROUP BY DAYSOFTHEWEEK.DAY
I tried adding this condition statement,
WHERE DAYSOFTHEWEEK.DAY IN ([ORDER].ORDER_DATE)
But it returns this error
Operand type clash: date is incompatible with int
Can someone help me out on this?Is there a work around with the code that I already have? Thanks in advance!
What I think you're after is a SUM of each day's sales for the current week with NULL if there are no sales. The secret is to left join your date list onto your data:
-- Setup some fake sales data
WITH TestData(N, Order_Date, Net_Amount) AS (
SELECT 1 N, CAST(GETDATE() AS DATE) Order_Date, RAND() * 100 Net_Amount
UNION ALL
SELECT N+1 N, CAST(GETDATE()-N/5 AS DATE) Order_Date, RAND(CHECKSUM(NEWID())) * 100 Net_Amount FROM TestData
WHERE N < 20
)
SELECT TestData.Order_Date, TestData.Net_Amount INTO #Order FROM TestData
--Set the first day of the week (if required)
SET DATEFIRST 7 --Sunday
;WITH Days(N,DayOfTheWeek) AS (
SELECT 1 N, DATEADD(DAY, 1-DATEPART(WEEKDAY, GETDATE()), CONVERT(DATE,GETDATE())) DayOfTheWeek
UNION ALL
SELECT N+1 N,DATEADD(DAY, 1, DayOfTheWeek) DayOfTheWeek FROM Days
WHERE N < 7
)
SELECT d.DayOfTheWeek, SUM(Net_Amount) TotalAmount
FROM Days d
LEFT JOIN #Order ON d.DayOfTheWeek = Order_Date
GROUP BY d.DayOfTheWeek
DayOfTheWeek TotalAmount
------------ ----------------------
2016-08-07 219.036784917497
2016-08-08 273.319570812461
2016-08-09 271.148114731087
2016-08-10 194.780039228967
2016-08-11 NULL
2016-08-12 NULL
2016-08-13 NULL
Here is every day this week, starting at your datefirst date, which can be temporarily varied for the query with SET DATEFIRST if you need to have some other week start date
I think you have some sales table there that you haven't shown us, you need to join to that on date, then group by
WITH DAYSOFTHEWEEK AS
(
SELECT cast(dateadd(
day,
-datepart(weekday,getdate()) + 1 ,
GETDATE()
)
as date) [DAY], 0 as cnt
UNION ALL
SELECT dateadd(day,1,[DAY]), cnt + 1 FROM DAYSOFTHEWEEK WHERE cnt < 6
)
select DAYSOFTHEWEEK.[day], SUM([ORDER].NET_AMOUNT) AS TOTAL_SALES from daysoftheweek
JOIN
SalesTable on
CAST(SalesTable.SalesDate date) = DAYSOFTHEWEEK.[day]
GROUP BY DAYSOFTHEWEEK.[day]
A little over complicated for me:
To get name of the week use, for example
SELECT DATENAME(dw,getdate())
But you really need something like this:
SELECT ProductName,Sum(Sales) From NameOfTable GROUP BY
DATENAME(ww,salesDate)
Related
I need list of those employees who are absent one day before and one day after weekend in a week......like if some is absent in Friday and present on Monday should not be included in the list
Use datepart(weekday, ) to fetch all records relative to monday and friday.
Have a look at SET DATEFIRST function too.
select *
from your_table
where datepart(weekday, Date) = 5
or datepart(weekday, Date) = 1;
This will list all employee id that are absent on a Friday and the following Monday (+1 week). I set-up a calendar week from mininum date to maximum date from the table and get only Friday and Monday. Then get all empid that has no attendance in any of those dates.
with caldte as (
SELECT dateadd(day, rn - 1, t.mindte) as dates,
datepart(weekday, dateadd(day, rn - 1, t.mindte)) as weekday,
datepart(wk, dateadd(day, rn - 1, t.mindte)) as weeknum
FROM (
select row_number() OVER ( order by c.object_id ) AS rn
FROM sys.columns c) rns,
(select min(dte) as mindte, max(dte) as maxdte
from tbl) t
WHERE rn - 1 <= datediff(day, t.mindte, t.maxdte)
and datepart(weekday, dateadd(day, rn - 1, t.mindte)) in (2, 6)
)
select distinct empid
from tbl
where empid not in (
select t.empid
from caldte c, tbl t
where c.dates = t.dte)
order by empid
How to get 8th Business day, start checking to see if the data exists. If it does exist Set and represents more than 50% of the loans - Set the Verified Date to that Day
Thank You Regards Shehroz
Declare #D date = '2012-12-01' -- Supply 1st of Month
Select D=max(D)
From (
Select Top 8 D=DateAdd(DD,N,#D)
From (Select N From (Values(0),(1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12),(13)) N(N) ) A
Where DatePart(DW,DateAdd(DD,N,#D)) between 2 and 6
) A
Returns
2012-12-12
This will give you the result, however my answer lists all 8th business days from specific date.
It does not consider holidays though. With small changes you can consider holidays too.
You can use top 1 on the last select to get only one date.
DECLARE #start date
SELECT #start = '20160101'
;WITH n AS (
SELECT n = ROW_NUMBER() OVER (ORDER BY [object_id])
FROM sys.all_objects
), dates AS (
SELECT DATEADD(DAY, n - 1, #start) Dt
FROM n
), dayNum AS (
SELECT Dt, DATENAME(WEEKDAY, Dt) WeekDayName
, ROW_NUMBER() OVER (ORDER BY Dt) DayNumber
FROM dates
WHERE DATENAME(WEEKDAY, Dt) NOT IN ('Saturday', 'Sunday')
)
SELECT Dt, DATENAME(WEEKDAY, Dt) WeekDayName
FROM dayNum
WHERE DayNumber % 8 = 0
ORDER BY Dt
I am fairly new to SSIS, and now I have this requirement to exclude weekends in order to do a performance management. Now I have created a calendar and marked the weekends; what I am trying to do, using SSIS, is get the start and end date of every status and count how many weekends are there. I am kind of struggling to know which component to use to achieve this task.
So I have mainly two tables:
1- Table Calendar
2- Table History-Log
Calendar has the following columns:
1- ID
2- date
3- year
4- month
5- day of week
6- isweekend
History-Log has the following:
1- ID
2- Status
3- startdate
4- enddate
Your help is really appreciated.
I'm not an SSIS user, so apologies if this answer does not help, but if I wanted to get the result you describe, based on some test data:
DECLARE #Calendar TABLE (
ID INT,
[Date] DATETIME,
[Year] INT,
[Month] INT,
[DayOfWeek] VARCHAR(10),
IsWeekend BIT
)
DECLARE #HistoryLog TABLE (
ID INT,
[Status] INT,
StartDate DATETIME,
EndDate DATETIME
)
DECLARE #StartDate DATE = '20100101', #NumberOfYears INT = 10
DECLARE #CutoffDate DATE = DATEADD(YEAR, #NumberOfYears, #StartDate);
INSERT INTO #Calendar
SELECT ROW_NUMBER() OVER (ORDER BY d) AS ID,
d AS [Date],
DATEPART(YEAR,d) AS [Year],
DATEPART(MONTH,d) AS [Month],
DATENAME(WEEKDAY,d) AS [DayOfWeek],
CASE WHEN DATENAME(WEEKDAY,d) IN ('Saturday','Sunday') THEN 1 ELSE 0 END AS IsWeekend
FROM
(
SELECT d = DATEADD(DAY, rn - 1, #StartDate)
FROM
(
SELECT TOP (DATEDIFF(DAY, #StartDate, #CutoffDate))
rn = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM sys.all_objects AS s1
CROSS JOIN sys.all_objects AS s2
ORDER BY s1.[object_id]
) AS x
) AS y;
INSERT INTO #HistoryLog
SELECT 1, 3, '2016-01-05', '2016-01-20'
UNION
SELECT 2, 7, '2016-01-08', '2016-01-25'
UNION
SELECT 3, 4, '2016-01-01', '2016-02-03'
UNION
SELECT 4, 3, '2016-02-09', '2016-02-10'
I would use a query like this to return all of the HistoryLog records with a count of the number of weekend days between their StartDate and EndDate:
SELECT h.ID,
h.[Status],
h.StartDate,
h.EndDate,
COUNT(c.ID) AS WeekendDays
FROM #HistoryLog h
LEFT JOIN #Calendar c ON c.[Date] >= h.StartDate AND c.[Date] <= h.EndDate AND c.IsWeekend = 1
GROUP BY h.ID, h.[Status], h.StartDate, h.EndDate
ORDER BY 1
If you wanted to know the number of weekends, rather than the number of weekend days, we'd need to slightly amend this logic (and define how a range containing only one weekend day - or one starting on a Sunday and ending on a Saturday inclusive - should be handled). Assuming you just want to know how many distinct weekends are at least partially within the date range, you could do:
SELECT h.ID,
h.[Status],
h.StartDate,
h.EndDate,
COUNT(weekends.ID) AS Weekends
FROM #HistoryLog h
LEFT JOIN
(
SELECT c.ID,
c.[Date] AS SatDate,
DATEADD(DAY,1,c.[Date]) AS SunDate
FROM #Calendar c
WHERE c.[DayOfWeek] = 'Saturday'
) weekends ON h.StartDate BETWEEN weekends.SatDate AND weekends.SunDate
OR h.EndDate BETWEEN weekends.SatDate AND weekends.SunDate
OR (h.StartDate <= weekends.SatDate AND h.EndDate >= weekends.SunDate)
GROUP BY h.ID, h.[Status], h.StartDate, h.EndDate
I'm trying to get all months in which no transaction is placed for the same year (If different years is not possible)
This is my query to get transactions between 2 dates, but don't know how can I select only months for which transaction in database is missing
SELECT *
FROM Installment
WHERE OrderId = 1
AND InstallmentDate
BETWEEN cast('8/02/2014' as date)
AND cast('12/25/2014' as date)
InstallmentId OrderId CustomerKey InstallmentAmount InstallmentDate
18 1 INS-1 3000 2014-09-03
92 1 INS-1 3000 2014-10-13
137 1 INS-1 3000 2014-11-05
in this case record for the 12th month and 8th month is missing, how can I get this with SQL Server Query ?
Update
select yymm.yy, yymm.mm
from (select distinct year(InstallmentDate) as yy, month(InstallmentDate) as mm
from Installment
where InstallmentDate BETWEEN '2014-09-02' and '2015-01-15'
) yymm left join
Installment i
on i.OrderId = 1 and
year(i.InstallmentDate) = yymm.yy and
month(i.InstallmentDate) = yymm.mm
where i.OrderId is not null;
Gordon's query is returning all the years and months from table between 2 dates, just by changing i.OrderId is null to i.OrderId is not null here is the out of his query
yy mm
2014 9
2014 10
2014 11
Expected Output (if possible)
yy mm
2014 12
2015 1
Using the following recursive CTE:
DECLARE #start DATE = '2014-09-02'
DECLARE #end DATE = '2015-01-15'
;WITH IntervalDates (date)
AS
(
SELECT #start
UNION ALL
SELECT DATEADD(MONTH, 1, date)
FROM IntervalDates
WHERE DATEADD(MONTH, 1, date)<=#end
)
SELECT YEAR(date) AS Year, MONTH(date) AS Month
FROM IntervalDates
you can get a list of all Years/Months between the two dates of interest:
Year Month
==============
2014 9
2014 10
2014 11
2014 12
2015 1
Using EXCEPT on the above CTE:
;WITH IntervalDates (date)
AS
(
SELECT #start
UNION ALL
SELECT DATEADD(MONTH, 1, date)
FROM IntervalDates
WHERE DATEADD(MONTH, 1, date)<=#end
)
SELECT YEAR(date) AS Year, MONTH(date) AS Month
FROM IntervalDates
EXCEPT
SELECT DISTINCT YEAR(InstallmentDate) AS yy, MONTH(InstallmentDate) AS mm
FROM Installment
WHERE OrderId = 1 AND InstallmentDate BETWEEN #start AND #end
yields the required result set:
Year Month
=============
2014 12
2015 1
To do this in SQL, you need to start with a list of months. Assuming you have at least one record for each month in the table, you can then get the missing dates easily using a subquery. The rest of the query is just a left join and checking for non-matches:
select yymm.yy, yymm.mm
from (select distinct year(InstallmentDate) as yy, month(InstallmentDate) as mm
from Installment
where InstallmentDate BETWEEN '2014-09-02' and '2015-01-15'
) yymm left join
Installment i
on i.OrderId = 1 and
year(i.InstallmentDate) = yymm.yy and
month(i.InstallmentDate) = yymm.mm
where i.OrderId is null;
Simplest way I can think of is to have a date dimension table that contains (at least) date, and 1st of month then. For creating one take a look at something like https://dba.stackexchange.com/questions/74957/best-approach-for-populating-date-dimension-table , although that one doesn't have firstOfMonthDate in it as my example show but the idea is the same.
then your query becomes
SELECT DISTINCT
firstOfMonthDate
FROM
dateRef dr
LEFT OUTER JOIN
InstallmentDate i ON dr.date = i.InstallmentDate AND i.OrderId = 1
WHERE
i.InstallmentDate IS NULL
AND
dr.date BETWEEN #startDate and #endDate
change firstOfMonthDate for fiscal month etc. as required. This would work across any range of dates you have in your table so different years wouldn't be an issue.
Try the below script. I retrieve all dates between the specified dates and use a LEFT JOIN to get those which are not present in your table:
DECLARE #startDate AS DATETIME, #endDate AS DATETIME
DECLARE #dates AS TABLE (CurrentDate DATETIME)
SET #startDate = '2014-01-01'
SET #endDate = '2014-01-31';
with GetDates AS
(
SELECT #startDate AS TheDate
UNION ALL
SELECT DATEADD("DD", 1, TheDate) FROM GetDates
WHERE TheDate < #endDate
) INSERT INTO #dates SELECT TheDate FROM GetDates
OPTION (MAXRECURSION 0)
SELECT DISTINCT YEAR(d.CurrentDate), MONTH(d.CurrentDate) FROM #dates d
LEFT JOIN InstallmentDate i ON i.InstallmentDate BETWEEN #startDate AND #endDate AND OrderId = 1
WHERE i.InstallmentDate IS NULL
Hope this helps...
Within a SQL Server 2012 database, I have a table with two columns customerid and date. I am interested in getting by year-month, a count of customers that have purchased in current month but not in prior 13 months. The table is extremely large so something efficient would be highly appreciated. Results table is shown after the input data. In essence, it is a count of customers that purchased in current month but not in prior 13 months (by year and month).
---input table-----
declare #Sales as Table ( customerid Int, date Date );
insert into #Sales ( customerid, date) values
( 1, '01/01/2012' ),
( 1, '04/01/2013' ),
( 1, '01/01/2014' ),
( 1, '01/01/2014' ),
( 1, '04/06/2014' ),
( 2, '04/01/2014' ),
( 3, '01/03/2012' ),
( 3, '01/03/2014' ),
( 4, '01/04/2012' ),
( 4, '04/04/2013' ),
( 5, '02/01/2010' ),
( 5, '02/01/2013' ),
( 5, '04/01/2014' )
select customerid, date
from #Sales;
---desired results ----
yearmth monthpurchasers monthpurchasernot13m
201002 1 1
201201 3 3
201302 1 1
201304 2 2
201401 2 1
201404 3 2
Thanks very much for looking at this!
Dev
You didn't provide the expected result, but I believe this is pretty close (at least logically):
;with g as (
select customerid, year(date)*100 + month(date) as mon
from #Sales
group by customerid, year(date)*100 + month(date)
),
x as (
select *,
count(*) over(partition by customerid order by mon
rows between 13 preceding and 1 preceding) as cnt
from g
),
y as (
select mon, count(*) as cnt from x
where cnt = 0
group by mon
)
select g.mon,
count(distinct(g.customerid)) as monthpurchasers,
isnull(y.cnt, 0) as cnt
from g
left join y on g.mon = y.mon
group by g.mon, y.cnt
order by g.mon
Tell me if this query helps. It extracts all the rows which meet your condition into a Table variable. Then, I use your query and join to this table.
declare #startDate datetime
declare #todayDate datetime
declare #tbl_Custs as Table(customerid int)
set #startDate = '04/01/2014' -- mm/dd/yyyy
set #todayDate = GETDATE()
insert into #tbl_Custs
-- purchased only this month
select customerid
from Sales
where ([date] >= #startDate and [date] <= #todayDate)
and customerid NOT in
(
-- purchased in past 13 months
select distinct customerid
from Sales
where ([date] >= DATEADD(MONTH,-13,[date])
and [date] < #startDate)
)
-- your query goes here
select year(date) as year
,month(date) as month
,count(distinct(c.customerid)) as monthpurchasers
from #tbl_Custs as c right join
Sales as s
on c.customerid = s.customerid
group by year(date) , month(date)
order by year(date) , month(date)
Below query will produce what you are looking for. I am not sure how performance will be on a big table (how big is your table?) but it is pretty straight forward so I think it will be ok. I simply calculate the 13 months earlier on CTE to find my sale window. Than join to the Sales table within that window / customer id and grouping records based on the unmatched records. You don't actually need 2 CTE's here you can do the DATEADD(mm,-13,date) on the join part of the second CTE but I thought it might be more clear this way.
P.S. If you need to change the time frame from 13 months to something else all you have to change is the DATEADD(mm,-13,date) this simply substracts 13 months from the date value.
Hope this helps or at least leads to a better solution
;WITH PurchaseWindow AS (
select customerid, date, DATEADD(mm,-13,date) minsaledate
FROM #Sales
), JoinBySaleWindow AS (
SELECT a.customerid, a.date,a.minsaledate,b.date earliersaledate
FROM PurchaseWindow a
LEFT JOIN #sales b ON a.customerid =b.customerid
--Find the sales for the customer within the last 13 months of original sale
AND b.date BETWEEN a.date AND a.minsaledate
)
SELECT DATEPART(yy,date) AS [year], DATEPART(mm, date) AS [month], COUNT(DISTINCT customerid) monthpurchases
FROM JoinBySaleWindow
--Exclude records where a sale within last 13 months occured
WHERE earliersaledate IS NULL
GROUP BY DATEPART(mm, date), DATEPART(yy,date)
Sorry about the typos they are fixed now.