SQL Server and XML Utilization - sql-server

Question

I'm trying to utilize XML with SQL Server. All I'm trying to do is print out all three guests. When I run my code, it only shows the prints the first guest's information, and I need all three guest's information to be printed. What am I doing wrong?
SELECT Guest.GuestID, GuestFirst, GuestLast, CheckinDate, Nights
FROM GUEST
JOIN FOLIO
ON Guest.GuestID = Folio.GuestID
FOR XML RAW
Declare #idoc int
Declare #xmldoc nvarchar(4000)
Set #xmldoc = '
<ROOT>
<GUEST>
<GuestID>4431</GuestID>
<GuestFirst>Lacey</GuestFirst>
<GuestLast>Byington</GuestLast>
<RESERVATIONDETAIL>
<CheckInDate>2016-08-02</CheckInDate>
<Nights>2</Nights>
</RESERVATIONDETAIL>
</GUEST>
<GUEST>
<GuestID>5563</GuestID>
<GuestFirst>Jonathan</GuestFirst>
<GuestLast>Langford</GuestLast>
<RESERVATIONDETAIL>
<CheckInDate>2016-08-05</CheckInDate>
<Nights>2</Nights>
</RESERVATIONDETAIL>
</GUEST>
<GUEST>
<GuestID>6680</GuestID>
<GuestFirst>Tanner</GuestFirst>
<GuestLast>Olson</GuestLast>
<RESERVATIONDETAIL>
<CheckInDate>2015-09-11</CheckInDate>
<Nights>3</Nights>
</RESERVATIONDETAIL>
</GUEST>
</ROOT>'
EXEC sp_xml_preparedocument #idoc OUTPUT, #xmldoc
SELECT * FROM OPENXML (#idoc, '/ROOT', 3)
WITH
(
GuestID smallint 'GUEST/GuestID',
GuestFirst varchar(30) 'GUEST/GuestFirst',
GuestLast varchar(30) 'GUEST/GuestLast',
CheckinDate smalldatetime 'GUEST/RESERVATIONDETAIL/CheckInDate',
Nights tinyint 'GUEST/RESERVATIONDETAIL/Nights'
)
EXEC sp_xml_removedocument #idoc
GO

Answer 1

Instead xml document try it with xquery,
DECLARE #xmldoc XML
Set #xmldoc = '
<ROOT>
<GUEST>
<GuestID>4431</GuestID>
<GuestFirst>Lacey</GuestFirst>
<GuestLast>Byington</GuestLast>
<RESERVATIONDETAIL>
<CheckInDate>2016-08-02</CheckInDate>
<Nights>2</Nights>
</RESERVATIONDETAIL>
</GUEST>
<GUEST>
<GuestID>5563</GuestID>
<GuestFirst>Jonathan</GuestFirst>
<GuestLast>Langford</GuestLast>
<RESERVATIONDETAIL>
<CheckInDate>2016-08-05</CheckInDate>
<Nights>2</Nights>
</RESERVATIONDETAIL>
</GUEST>
<GUEST>
<GuestID>6680</GuestID>
<GuestFirst>Tanner</GuestFirst>
<GuestLast>Olson</GuestLast>
<RESERVATIONDETAIL>
<CheckInDate>2015-09-11</CheckInDate>
<Nights>3</Nights>
</RESERVATIONDETAIL>
</GUEST>
</ROOT>'
SELECT
a.b.value('GuestID[1]','smallint') AS GuestID,
a.b.value('GuestFirst[1]','varchar(30)') AS GuestFirst,
a.b.value('GuestLast[1]','varchar(30)') AS GuestLast,
a.b.value('RESERVATIONDETAIL[1]/CheckInDate[1]','smalldatetime') AS CheckInDate,
a.b.value('RESERVATIONDETAIL[1]/Nights[1]','tinyint') AS Nights
FROM #xmldoc.nodes('ROOT/GUEST') AS a(b)
GO
btw, the select query you have given on the top will not produce the same xml which you have given below.

Answer 2

#Jatin answer is good, you can use xquery. You can also use OPENXML like this:
EXEC sp_xml_preparedocument #idoc OUTPUT, #xmldoc
SELECT * FROM OPENXML (#idoc, '/ROOT/GUEST', 3)
WITH
(
GuestID smallint './GuestID',
GuestFirst varchar(30) './GuestFirst',
GuestLast varchar(30) './GuestLast',
CheckinDate smalldatetime './RESERVATIONDETAIL/CheckInDate',
Nights tinyint './RESERVATIONDETAIL/Nights'
)
EXEC sp_xml_removedocument #idoc

Answer 3

You are almost there. You just need to make this small change:
SELECT * FROM OPENXML (#idoc, '/ROOT/*', 3)
WITH
(
GuestID smallint 'GuestID',
GuestFirst varchar(30) 'GuestFirst',
GuestLast varchar(30) 'GuestLast',
CheckinDate smalldatetime 'RESERVATIONDETAIL/CheckInDate',
Nights tinyint 'RESERVATIONDETAIL/Nights'
)