SSIS for each loops - how are part copied files handled? - sql-server

I'm writing an SSIS package that runs on a schedule to poll a folder location.
The files will be picked up by a foreach loop, however these files are quite large and therefore take time to be copied into the directory.
I'd like to know how SSIS behaves when a foreach file loop is run on a directory with a file that is still being copied, will it skip over the file as it's not complete? Is there a danger that SSIS will attempt to load a part copied file?

Nope there is no danger to the File. Nor will it be copied partially [Unless you are removing it after the copying of files is done.] That would be a disaster. ;)
It has nothing to do with the Loop being in place. The File System Task is the one you need to consider. It will act as if you are manual copying a file. What would happen if you did that? Also what else are you doing after you are done with the coping of the file from Source to the Destination folder matters like [Are you removing?]
In short "NOTHING WOULD HAPPEN". No partial files will be copied.

Related

Update file across multiple folder locations?

I need something that can copy a specified file any and everywhere on my drive (or computer) where that file already exists; i.e. update a file. I tried to search this site, in case I'm not the first, and found this:
CMD command line: copy file to multiple locations at the same time
But not quite the same.
Example:
Say I have a file called CurrentList.txt, and I have copies of it all over my hard drive.  But then I change it and I want all the copies to update.  So I want to copy the newer one over all the others.  It could 'copy if newer', but generally I know it's newer, so it could also just find every instance and copy over it.
I was originally going to use some kind of .bat file that would have to iterate over every folder seeking the file in question, but my batch file programming is limited/rusty.  Then I looked to see if xcopy could do it, but I don't think so...
For how I will use it most, I generally know where those files are going to be, so it actually might be as good or better if I could specify it to (using example), "copy CurrentList.txt, overwriting all other copies wherever found in the C:\Lists folder and all subfolders".
I would really like to be able to have it in a context menu, so I could (from a file explorer) right click on a file or selected files and choose the option to distribute it.
Thanks in advance for any ideas.
Use the "replace" command...
replace CurrentList.txt C:\Lists /s

Rename code in c have a error

i want to move a file from a directory to anther directory with C Coding.
I search and find rename(); function , but when working it doesnt work and have a error:
my code:
#include <stdio.h>
int main() {
if(rename("/root/tmpfile.php", "/home/check-tmp.php"))
perror( NULL );
}
the code well compiled but when running this code showing this error:
Invalid cross-device link
How to move a file from a directory to anther directory without using System for fopen?
Aslo , i finded many codes and ways to do it but doesnt working all codes.
Please say me a way and make sure it will work
Thanks.
Many aspects of the behavior of `rename' are inherently platform-dependent: The rename operation might not be able to move a file from one file system to another , it might not be atomic, and it might not succeed if a file with the destination abstract pathname already exists.
In other words, your system does not support rename files cross different partitions (your root partition and your home partition are different.)
So the solution is when it fails, copy the file to the destination and delete the original.
The rename call can only rename and move files within a single disk partition. The error "cross-device link" indicates that you attempted to move a file from one partition to another. (If you were on a Windows system, you can imagine if you tried to rename a file from C: to D:.)
When you use the Unix mv command to move files, it first tries a rename, but if it fails in this way, it falls back and makes a new copy of the file in the new location, then deletes the original. That's what you would have to have your code do in this situation, too.
(Copying a file is easy enough, but there are plenty of library functions out there that will do it for you, and also take care of things like preserving the last-modified time and other file attributes.)

How to modify a single file inside a very large zip without re-writing the entire zip?

I have large zip files that contain huge files. There are "metadata" text files within the zip archives that need to be modified. However, it is not possible to extract the entire zip and re-compress it. I need to locate the target text file inside the zip, edit it, and possibly append the change to the zip file. The file name of the text file is always the same, so it can be hard-coded. Is this possible? Is there a better way?
There are two approaches. First, if you're just trying to avoid recompression of the entire zip file, you can use any existing zip utility to update a single file in the archive. This will entail effectively copying the entire archive and creating a new one with the replaced entry, then deleting the old zip file. This will not recompress the data not being replaced, so it should be relatively fast. At least, about the same time required to copy the zip archive.
If you want to avoid copying the entire zip file, then you can effectively delete the entry you want to replace by changing the name within the local and central headers in the zip file (keeping the name the same length) to a name that you won't use otherwise and that indicates that the file should be ignored. E.g. replacing the first character of the name with a tilde. Then you can append a new entry with the updated text file. This requires rewriting the central directory at the end of the zip file, which is pretty small.
(A suggestion in another answer to not refer to the unwanted entry in the central directory will not necessarily work, depending on the utility being used to read the zip file. Some utilities will read the local headers for the zip file entry information, and ignore the central directory. Other utilities will do the opposite. So the local and central entry information should be kept in sync.)
There are "metadata" text files within the zip archives that need to be modified.
However, it is not possible to extract the entire zip and re-compress it.
This is a good lesson why, when dealing with huge datasets, keeping the metadata in the same place with the data is a bad idea.
The .zip file format isn't particularly complicated, and it is definitely possible to replace something inside it. The problem is that the size of the new data might increase, and not fit anymore into the location of the old data. Thus there is no standard routine or tool to accomplish that.
If you are skilled enough, theoretically, you can create your own zip handling functions, to provide the "file replace" routine. If it is about the (smallish) metadata, you do not even need to compress them. The .zip's "central directory" is located in the end of the file, after the compressed data (the format was optimized for appending new files). General concept is: read the "central directory" into the memory, append the new modified file after the compressed data, update the central directory in memory with the new file offset of the modified file, and write the central directory back after the modified file. (The old file would be still sitting somewhere inside the .zip, but not referenced anymore by the "central directory".) All the operations would be happening at the end of the file, without touching the rest of the archive's content.
But practically speaking, I would recommend to simply keep the data and the metadata separately.

Connect Direct Multiple files, one Node.

I'm working on a project that requires sending multiple files to the same node. The files are available for sending at the same time and I created a simple C.D shell script to send the files. I looped the call to this script to send all the files (about 20) at the same time.
In my script I'm intending to delete the files within the loop and after the CD script is called. However,.. some one at work , a colleague, told me that the files may not be sent on the spot but rather put in a queue for transmission at a later stage if the C.D node is busy and hence deleting the files would cause errors.
Can someone advise if this is the case? Are the files not fiscally copied even if put in a queue?
I find it weird that the CD script would complete with a successful return code and give me the process number and I still cannot delete the file?
Thanks,
Sergio
You can use the if statement for each file, if the exit code for the file is 0, only the file is deleted and CD moves to the next step for copying the next file.
if (step01=0) then
run task (Do something)
sysopts="rm filename"

Copying multiple files to a Winscp directory via Script

I have a problem when trying to upload multiple files to one WinSCP directory, i can manage to copy just one single file, but the problem is that i need to upload many files that are generated by a software, the names are not fixed ones, so i need to make use of wildcards in roder to copy all of them, i have tried many variants on the code, but it all was unsuccessful, the code i am using is:
open "sftp://myserver:MyPass#sfts.us.myserver.com" -hostkey="hostkey"
put "C:\from*.*" "/Myserverfolder/Subfolder/"
exit
This code does actually copy the first alphabetically named file, but it ignores the rest of the files.
Any help with it would be much appreciated
Try this in script
Lcd C:\from
Cd Myserverfolder/Subfolder
Put *
Try and do all manually first so you can see what's going on.

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