Error while calculating sum of two matrices in c - c

So I'm new to C and was trying to write a program to add two matrices
program 1
#include <stdio.h>
int main(){
int m,n,o,p,i,j;
int mat1[m][n];
int mat2[m][n];
int result[m][n];
printf("enter the number of rows and columns for matrix ");
scanf("%i%i",&m,&n);
printf("enter elements of matrix one :");
for(i=0;i<m;i++){
for(j=0;j<n;j++){
scanf("%i",&mat1[i][j]);
}
}
printf("enter the elements of matrix two:");
for(i=0;i<m;i++){
for(j=0;j<n;j++){
scanf("%i",&mat2[i][j]);
}
}
for(i=0;i<m;i++){
for(j=0;j<n;j++){
result[i][j]=mat1[i][j]+mat2[i][j];
}
}
printf("the sum of the matrices are");
for(i=0;i<m;i++){
for(j=0;j<n;j++){
printf("%i",result[i][j]);
}
}
return 0;
}
this produced no error
method two
when i used a function to enter the values in two the matrix, it produced the following error
25 24 C:\Users\Hp\my-programs\matrix-entry-function.cpp [Error] invalid types 'int[int]' for array subscript
25 35 C:\Users\Hp\my-programs\matrix-entry-function.cpp [Error] invalid types 'int[int]' for array subscript
code:
#include <stdio.h>
int mat_entry(int m,int n)
{
printf("enter the rows and columns of matrix ");
scanf("%i%i",&m,&n);
int mat[m][n];
for(int i=0;i<m;i++)
{
for(int j=0;j<n;j++)
{
printf("\nenter the %i'th element %i'th row :",j+1,i+1);
scanf("%i",&mat[i][j]);
}
}
}
int main()
{
int a,b,c,d,e,f,m,n;
int res[m][n];
int mat1=mat_entry(a,b);
int mat2=mat_entry(c,d);
for(int i=0;i<m;i++)
{
for(int j=0;j<n;j++)
{
res[i][j]=(mat1[i][j]+mat2[i][j]);
}
}
}

Your program 1 happened not to produce error. You are unlucky. You invoked undefined behavior by using values in uninitialized variables having automatic storage duration, which are indeterminate. You must declare mat1, mat2 and result after reading m and n.
int main(){
int m,n,o,p,i,j;
printf("enter the number of rows and columns for matrix ");
scanf("%i%i",&m,&n);
/* move these declaretions after reading number of rows and columns */
int mat1[m][n];
int mat2[m][n];
int result[m][n];
printf("enter elements of matrix one :");
Your program 2 invokes undefined behavior by using return values of functions with no return statements. Also using [] operator with two operands having type int is wrong. E1[E2] is equivalent to (*((E1)+(E2))) (N1570 6.5.2.1 Array subscripting, paragraph 2), so exactly one operand of it must be a pointer (including one converted from arrays).
To return matrixes as return values of functions, consider using structures and allocating memory for elements dinamically.

You have used
int mat1=mat_entry(a,b);
int mat2=mat_entry(c,d);
instead of sending parameters from one function to another, which would work only when the variables you take are pointers, here you have to either use mat1 and mat2 as pointers or you have to make them integer matrices.

There isn't one thing that you are doing wrong my friend.
You are not even using dynamic memory allocation but still trying to declare matrices with values which are not defined yet.Try to run your code,even your first code won't run.
i have corrected your code for you :
#include <stdio.h>
int main(){
int m,n;
printf("enter the number of rows and columns for matrix ");
scanf("%i%i",&m,&n);
int mat1[m][n];
int mat2[m][n];
int result [m][n];
int i,j;
printf("enter elements of matrix one :");
for(i=0;i<m;i++){
for(j=0;j<n;j++){
scanf("%d",&mat1[i][j]);
}
}
printf("enter the elements of matrix two:");
for(i=0;i<m;i++){
for(j=0;j<n;j++){
scanf("%d",&mat2[i][j]);
}
}
for(i=0;i<m;i++){
for(j=0;j<n;j++){
result[i][j]=mat1[i][j]+mat2[i][j];
}
}
printf("the sum of the matrices are");
for(i=0;i<m;i++){
for(j=0;j<n;j++){
printf("%d",result[i][j]);
}
}
return 0;
}
I don't think it would be that difficult to put this functionality into a function . Try it out

It is impossible to write a function that makes a matrix with user-supplied dimensions, unless you use dynamic allocation (which you probably don't want to, at this stage).
Luckily, you don't need that! Since all you want is adding matrices, they should have the same dimensions, and you only want to ask the user once what the dimensions are. Afterwards, fill both matrices, and do the "adding" part.
That is:
int main()
{
int a,b,c,d,e,f,m,n;
printf("enter the rows and columns of matrix ");
scanf("%i%i",&m,&n);
int res[m][n];
int mat1[m][n];
int mat2[m][n];
mat_entry(m, n, mat1); // fill matrix 1
mat_entry(m, n, mat2); // fill matrix 2
for(int i=0;i<m;i++)
{
for(int j=0;j<n;j++)
{
res[i][j]=(mat1[i][j]+mat2[i][j]);
}
}
}
The function mat_entry has no return value (i.e. void), but it receives the matrix to fill by pointer (the details are a bit complicated, but the syntax is straightforward):
void mat_entry(int m,int n, int mat[m][n])
{
...
}
The code inside is the same as you suggested, minus the asking for dimensions:
for(int i=0;i<m;i++)
{
for(int j=0;j<n;j++)
{
printf("\nenter the %i'th element %i'th row :",j+1,i+1);
scanf("%i",&mat[i][j]);
}
}

Related

Reading and Printing a matrix

I tried to read and print a matrix using an external function (from another c file), the thing is that I want to read the matrix dimensions in the function and store them in the main function, how can I do this?
Do I need to return an array with the m and n dimensions of the matrix or can I access the variables that I created in main and change their value within the external function? (I prefer if someone would explain the second) I don't actually know how to use pointers and stuff.
Sorry for my English, I'm not a native speaker, also thanks for your response
The second and the third functions are in an external function.c file
int main(){
int num_of_rows, num_of_columns;
int matrix[10][10];
read_matrix(num_of_rows, num_of_columns, matrix);
print_matrix(num_of_rows, num_of_columns, matrix);
printf("\n Press any key to exit the program: ");
_getch();
return 0;
}
void read_matrix(int num_of_rows, int num_of_columns, int matrix[10][10]){
int i,j;
printf("\nPlease specify the number of rows:");
scanf("%d", &num_of_rows);
printf("\nPlease specify the number of columns: ");
scanf("%d", &num_of_columns);
printf("\nPlease introduce the matrix elements below:\n");
for(i=0; i<num_of_rows; i++){
for(j=0; j<num_of_columns; j++){
printf("matrix[%d][%d]= ", i, j);
scanf("%d", &matrix[i][j]);
}
}
}
void print_matrix(int num_of_rows, int num_of_columns, int matrix[10][10]){
int i,j;
for(i=0; i<num_of_rows; i++){
for(j=0; j<num_of_columns; j++){
printf("matrix[%d][%d]= %d", i, j, matrix[i][j]);
}
}
}
Parameters are passed by value in C.
In read_matrix, the num_of_rows parameter is a local variable. Even if you modify it, the caller won't see anything change. Same for num_of_columns.
You want this:
void read_matrix(int *num_of_rows, int *num_of_columns, int matrix[10][10]) {
// ^ add * ^ add *
...
scanf("%d", num_of_rows); // << remove the &
printf("\nPlease specify the number of columns: ");
scanf("%d", num_of_columns); // << remove the &
...
for (i = 0; i < *num_of_rows; i++) {
// ^add *
for (j = 0; j < *num_of_columns; j++) {
// ^add *
and in main:
read_matrix(&num_of_rows, &num_of_columns, matrix);
// ^ ^ add the &s
This is basic knowledge that is covered in your C learning material. Most likely in the chapter dealing with pointers and the one dealing with function calls.
Here's the catch. I tested your code and it works nicely. The problem is, what you want to achieve is only possible by using dynamic memory allocation. Take a look at the malloc and free functions.
You can read more about it on:
https://www.tutorialspoint.com/what-is-malloc-in-c-language
https://www.tutorialspoint.com/how-do-malloc-and-free-work-in-c-cplusplus
In C language you are responsible for allocation a space in memory for variable length data structures. Pointers just store an address to a specific memory space allocated to the desired data type.
e.g.:
int n, *p;
p = (int*) malloc(n * sizeof(int));
In this example, you are just giving p an address to the first integer from n integers you just allocated.
p will work just like a vector when using for loops because behind the scenes, it's exactly what happens when you traverse your fixed length vectors and matrices, but this time you were in control of it's length in runtime.
#include<stdio.h>
void main()
{
int x[3][3], p, q, max;
printf("Enter the elements of matrix: \n");
for(p=0;p<3;p++)
{
for(q=0;q<3;q++)
scanf("%d", &x[p][q]);
}
max=x[0][0];
printf("The matrix is as follows: \n");
for(p=0;p<3;p++)
{
for(q=0;q<=3;q++)
scanf(" %d", &x[p][q]);
}
for(p=0;p<3;p++)
{
for(q=0;q<3;q++)
{
if(x[p][q]>max)
max=x[p][q];
}
printf("\n");
}
printf("Maximum number in the matrix is: %d", max);
}
Output:
Enter the elements of matrix:
23 65 12
12 23 56
12 10 32
The matrix is as follows:
23 65 12
12 23 56
12 10 32
Maximum number in the matrix is: 65
Matrix Programs
Explore more matrix programs.

Why this program stops working at runtime?

It successfully compiles.
But at running on getting values of matrix it crashes stops working.
#include <stdio.h>
void getmat(int mat[100][100],int m,int n);
void matmul(int mat1[100][100],int mat2[100][100],int m1,int n1,int m2,int
n2,int matmul[100][100]);
void printmat(int matmul[100][100],int m,int n);
int main(void)
{
int m1,n1,m2,n2;
printf("Enter the dimensions of matrix1: ");
scanf("%d %d",&m1,&n1);
printf("Enter the dimensions of matrix2: ");
scanf("%d %d",&m2,&n2);
int mat1[m1][n1];
int mat2[m2][n2];
int matmul1[m1][n2];
int matmul2[m2][n1];
printf("For the values of matrix 1\n");
getmat(mat1,m1,n1);
printf("For the values of matrix 2\n");
getmat(mat2,m2,n2);
if(n1==m2)
{
printf("Mat1 x Mat2 is possible.");
matmul(mat1,mat2,m1,n1,m2,n2,matmul1);
printf("Mat1 x Mat2 :\n");
printmat(matmul1,m1,n2);
}
else
printf("Mat1 x Mat2 is not possible.\n");
if(n2==m1)
{
printf("Mat2 x Mat1 is possible.");
matmul(mat2,mat1,m2,n2,m1,n1,matmul2);
printf("Mat2 x Mat1 :\n");
printmat(matmul2,m2,n1);
}
else
printf("Mat2 x Mat1 is not possible.\n");
return 0;
}
void printmat(int matmul[100][100],int m,int n)
{
int i,j;
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
printf("%3d ",matmul[i][j]);
}
printf("\n");
}
}
void getmat(int mat[100][100],int m,int n)
{
int i,j;
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
printf("Enter element of %dx%d: ",i+1,j+1);
scanf("%d",&mat[i][j]);
}
}
}
void matmul(int mat1[100][100],int mat2[100][100],int m1,int n1,int m2,int
n2,int matmul[100][100])
{
int i,j,k;
for(i=0;i<m1;i++)
{
for(j=0;j<n2;j++)
{
matmul[i][j]=0;
for(k=0;k<m2;k++)
{
matmul[i][j]+=mat1[i][k]*mat2[k][j];
}
}
}
}
Help making any changes or optimizing this code.
Also another way to this.
This error shows up at running a half
Use a Debugger
Also, all your functions are written to take a 100x100 matricies.
But you declare your matricies to have variable sizes:
int mat1[m1][n1];
int mat2[m2][n2];
int matmul1[m1][n2];
int matmul2[m2][n1];
When you pass a 3x3 matrix to a function that is expecting a 100x100 matrix, you will definitely have a bad time.
I see that you are setting up your arrays with variable sizes. You should really set it up as a very large array or use malloc to set up the array properly. When you call the processing routines, pass the arrays as pointers and use the sizes as arguments in order to set up your references. You should note that myarray[i, j] is the equivalent of a single valued array using i*rowsize + j. When you define your array in the subroutines as [100, 100], it will go to [i*100 + j] which is outside the bounds of your actual array.
This causes the program to crash.
Once you actually calculate everything properly, it should work.

summing up rows in c showing garbage numbers in columns

I'm trying to sum columns in C. My code only adds the sum for the firsts columns for example if is a 2x2 array it only add the first column but for the rest it displays weird numbers. this is what i got so far. I haven't made the code for the rows yet. Thanks for your help.
#include <stdio.h>
int main(){
printf("Enter the number of columns");
int i;
scanf("%d", &i);
printf("Enter the number of rows");
int y;
scanf("%d", &y);
int r[i][y];
int a;
int b;
int columntotal[i],rowtotal[y];
for (a=0; a<i; a++){
for (b=0; b<y; b++){
scanf("%d",&r[a][b]);
}
}
//printing
for(a=0;a<i;a++)
{
for(b=0;b<y;b++){
printf("\t%d", r[a][b]);
}
printf("\n");
}
for (a=0;a<i;a++){
for (b=0;b<y;b++){
columntotal[a]=columntotal[a]+r[a][b];
}
}
for (a=0;a<i;a++){
printf("%d\n", columntotal[a]);
}
return(0);
}
As far as I remember dynamic rows,col assign while creating array is not possible in C.So your this statement int columntotal[i],rowtotal[y]; will not work unless i,y is a constant variable i.e #define i,y,etc which is not in your case.
Second you are iterating over a columntotal array which is not properly declared. You can make use of dynamic memory allocation to allocate number of blocks to columntotal array and then fill it with you column sum as you iterate over it.
int *columntotal= malloc(i * sizeof (int));
for (a=0;a<i;a++){
for (b=0;b<y;b++){
columntotal[a]=columntotal[a]+r[a][b]; //r is your 2D array
}
}

Passing arrays into functions, file.exe stopped working

I am a complete beginner in C and I am practicing passing arrays into functions. I wrote a program to take a two dimensional array as input and find sum of the individual columns.
And when I compiled the program I got no errors, but once I run it, I get a dialogue box saying "untitled5.exe stopped working" where untitled5 is the file name.
I got this error quite a few times. I have used both dev c++ and codeblocks to compile my program, so what is the reason for this? Is this a problem with my code or with my compiler or with my laptop?
#include<stdio.h>
void summation (int arr[][5], int size);
int main()
{
int n,arr[n][5],sum,i,j;
printf("enter the number of rows");
scanf("%d",&n);
for (i=0;i<n;i++)
{
for (j=0;j<5;j++)
{
printf("%d,%d th element is",i,j);
scanf("%d",&arr[i][j]);
}
}
summation (arr,5);
return 0;
}
void summation (int arr[][5], int size)
{
int i,j,s=0;
for(j=0;j<5;j++)
{
for (i=0;i<5;i++)
{
s=s+arr[i][j];
}
printf("%d",s);
}
}
In main() you are using i to index the first dimension of the array. In summation() you are using i to index the second dimension of the array. I think that you are going beyond the end of the first dimension inside summation() when main() does not fill up that much of the array (e.g., when you enter 2 for the number of rows).
I think you want
summation (arr,5);
And, inside summation():
for (i=0;i<size;i++)
{
s=s+arr[i][j];
}
#include<stdio.h>
void summation (int arr[][5], int size, int rows);
int main()
{
int n, sum, i, j;
printf("enter the number of rows");
scanf("%d",&n);
int arr[n][5];
for (i=0;i<n;i++)
{
for (j=0;j<5;j++)
{
printf("%d,%d th element is",i,j);
scanf("%d",&arr[i][j]);
}
}
summation (arr, 5, n);
return 0;
}
void summation (int arr[][5], int size, int rows)
{
int i,j,s=0;
for(i=0;i<rows;j++)
{
for (j=0;i<size;i++)
{
s=s+arr[i][j];
}
}
printf("%d",s);
}
So first off I moved your array declaration to after you have initialized n and made it equal to something.
Then your next problem was you were probably going out of bounds in your summation function. You always have 5 columns in your 2darray, but you can have a different amount of rows. Pass the amount of rows, n, into the function summation to make sure you don't go out of bounds.

How to initialize array elements before using it?

I have to write a program which illustrates the usage of pointers with arrays and functions.
#include <stdio.h>
#include <conio.h>
#define ROWS 3
#define COLS 4
void print(int rows, int cols, int *matrix);
void main(void)
{
int a[ROWS*COLS],i;
for(i=0;i<ROWS*COLS;i++)
{
a[i]=i+1;
}
print(ROWS,COLS,a);
getch();
}
void print(int rows, int cols, int *matrix)
{
int i,j,*p=matrix;
for(i=0;i<rows;i++)
{
for(j=0;j<cols;j++)
{
printf("%3d",*(p+(i*cols)+j));
}
printf("\n");
}
}
The above program prints a matrix with the rows and columns predefined. I want to modify the program such that the rows and columns are entered by the user.
#include <stdio.h>
#include <conio.h>
void print(int rows, int cols, int *matrix);
void main(void)
{
int ROWS,COLS,a[ROWS*COLS],i;
printf("Enter the number of rows: ");
scanf("%d",ROWS);
printf("\nEnter the number of columns: ");
scanf("%d",COLS);
for(i=0;i<ROWS*COLS;i++)
{
a[i]=i+1;
}
print(ROWS,COLS,a);
getch();
}
void print(int rows, int cols, int *matrix)
{
int i,j,*p=matrix;
for(i=0;i<rows;i++)
{
for(j=0;j<cols;j++)
{
printf("%3d",*(p+(i*cols)+j));
}
printf("\n");
}
}
This programs is giving an error that the variables ROWS and COLS are being used before they are being declared. How to solve this problem.
One option is to allocate a on the heap:
int main(void)
{
int rows,cols,*a,i;
printf("Enter the number of rows: ");
scanf("%d",&rows);
printf("\nEnter the number of columns: ");
scanf("%d",&cols);
a = malloc(rows*cols*sizeof(int));
for(i=0;i<rows*cols;i++)
{
a[i]=i+1;
}
print(rows,cols,a);
getch();
free(a);
}
Notice also that I've:
Added ampersands that were missing from the scanf() calls;
Changed the return type of main() to int. See What are the valid signatures for C's main() function?
As you why your code didn't work:
Traditionally, C required constant expressions for array bounds. When ROWS and COLS were constants, everything was good with your code. Once you've turned them into variables, a became a variable-length array. The problem was that the size of the array is computed at the point where the array is declared, and at that point the values of ROWS and COLS were not yet known.
In C99, it is possible to fix your code by pushing the declaration of a down:
int main(void)
{
int rows,cols,i;
printf("Enter the number of rows: ");
scanf("%d",&rows);
printf("\nEnter the number of columns: ");
scanf("%d",&cols);
int a[rows*cols];
for(i=0;i<rows*cols;i++)
{
a[i]=i+1;
}
print(rows,cols,a);
getch();
}
printf("Enter the number of rows: ");
scanf("%d",&ROWS);
printf("\nEnter the number of columns: ");
scanf("%d",&COLS);
You should declare the array after you get rows and cols - otherwise it's not make sense.
int rows,cols;
scanf("%d %d",&rows,&cols);
int a[rows*cols];
By the way, main should return int (0 if the program ends successfully)
You need to dynamically allocate the array - use malloc
scanf("%d", &ROWS); - notice the & - scanf requires the address.

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