I am trying to split a block of text into a 2d array. I know how to split a line into an array of words, and I know how to split multiple lines into an array of lines, but I would like to do both simultaneously.
For example, I want this :
Tim is nice
Jim is mean
would become
((Tim,is,nice),(Jim,is,mean))
So Far, I have been able to use
Str1.Split(new String() {Environment.NewLine}, StringSplitOptions.None)
To make the example string into:
(Tim is nice,Jim is mean)
And I've used Str1.Split to convert "Tim is nice" into
(Tim,is,nice)
Also, if any of my code is bad syntax or anything like that let me know, I'm a Python programmer primarily.
This isnt a 2D array:
((Tim,is,nice),(Jim,is,mean))
That is a jagged array or an array of arrays. Since each line/sentence may not have the same number of words, it is a better choice. For your example, you will have an array of 2 to hold each "line", then each of those will hold an array of however many words there are.
Dim original = "Tim is nice" & Environment.NewLine & "Jim is very mean"
Dim lines = original.Split(New String() {Environment.NewLine.ToString},
StringSplitOptions.RemoveEmptyEntries)
Dim results(lines.Count - 1)() As String
For n As Int32 = 0 To lines.Count - 1
' store array of words to results(n)
results(n) = lines(n).Split(" "c)
Next
' glue a line back together and show it
Console.WriteLine(String.Join(" ", results(1)))
results(0) will hold the Tim words, results(1) will hold the Jim words. Results (of the writeline):
Jim is very mean
Related
I am doing a loop for each string in an array such that
filename = Array(file1,file2.....file600)
However VBA gets a compile error that is due to the array taking up 8 lines. As far as I am aware it only allows 1 line
(error says expected list or separator)
I am new to VBA sorry
You can escape new lines in VBA with _.
so your solution might look like
filename = Array("file1", _
"file2", _
"file3")
See How to break long string to multiple lines and If Statement With Multiple Lines
If you have 100's of names, however, you might be better off storing them in a worksheet and reading them in, rather than hard-coding them.
Should you strings in the array be actually "buildable" following a pattern (like per your examples: "file1", "file2", ...,"file600") then you could have a Function define them for you, like follows:
Function GetFileNames(nFiles As Long) As String()
Dim iFile As Long
ReDim filenames(1 To nFiles) As String
For iFile = 1 To nFiles
filenames(iFile) = "file" & iFile
Next
GetFileNames = filenames
End Function
which you'd call in your "main" code as follows
Sub main()
Dim filenames() As String
filenames = GetFileNames(600) '<--| this way'filenames' array gets filled with 600 hundred values like "file1", "file2" and so on
End Sub
The amount of code that can be loaded into a form, class, or standard module is limited to 65,534 lines. A single line of code can consist of up to 1023 bytes. Up to 256 blank spaces can precede the actual text on a single line, and no more than twenty-four line-continuation characters ( _) can be included in a single logical line.
From VB6's Help.
when programming, you don't build an array this big mannually, never.
either you store each multiline-string inside a Cell, and at the end you buid the array like this :
option Explicit
Sub ArrayBuild ()
Dim Filenames() 'as variant , and yes i presume when using multi files, the variable name should have an "s"
With Thisworkbook.sheets("temp") 'or other name of sheet
Max = .cells(.rows.count,1).end(xlup).row '=max number of rows in column 1
Filenames = .range( .cells(1,1) , .cells(Max,1)).value2 ' this example uses a one column range from a1 to a[max] , but you could also use a multi column by changing the second .cells to `.cells(Max, ColMax)`
end with
'do stuff
erase Filenames 'free memory
End Sub
An other way is to build an array like you build a house by adding one brick at a time, like this :
Dim Filenames() as string 'this time you can declare as string, but not in the previous example
Dim i& 'counter
For i=1 to Max 'same max as in previous example, adapt code plz...
redim Preserve Filenames (1 to ubound(filenames)+1) 'this is an example for unknown size array wich grows, but in your case you know the size (here Max, so you could declare it `Dim Filenames (1 to Max)` from the start, just wanted to show every option here.
Filenames(i) = Cells (i,1).value2 'for example, but can be anything else. Also i'm beeing lazy and did not reference the cell to its sheet, wich i'd never do in actual coding...
next i
EDIT i did re-read your Question, and it is even easier (basically because you ommited the bracets in your post and corrected it as comment...), use
user3598756 's code plz. I thought File1 is a variable, when it should be written as "File1" .
EDIT 2 why bother build and array where Filename(x)="Filex" anyway? you know the result beforehand
I am opening a text file which contains text like this
asdf,zxcv,asdwqe,asdh,we5,dvsew,safhc
asdf8,asdf3,asdf4,asdf5,asdf6,asdf7,asdf2
....
I am trying to put this all into a 2d array, the only way I have been able to do anything with this so far is to read the file line by line and split that line with a comma into a 1D array and use the information that way. But I have no idea how I'm supposed to do this with a 2D array, I have googled and have found nothing that is helpful.
is there a way I can put my 1d array into a 2d array or something?
Also I do not know how many strings there are per line(but all lines will have the same amount) nor how many lines there are in the file.
EDIT: To clarify, how I want it to work is for example if I do MsgBox myArray(1,3) I want "asdf5" to be displayed in that message box.
This should work :
Sub arrayTest()
Dim arrData
Dim wbtemp As Workbook
'/ 2 = Comma (format parameter)
Set wbtemp = Workbooks.Open("C:\temp\test.txt", False, True, 2)
'/ Read in Array. range array is always 2D
arrData = wbtemp.Worksheets(1).UsedRange
wbtemp.Close (0)
'/ Range array will always start from 1. No 0 base,
'/ but given how less code one needs to write, its a fair trade off.
MsgBox arrData(2, 4)
End Sub
So as the title already suggests I simply want to know if it is possible to sort elements that are in a string array via the numbers that are also contained within those strings.
In my program I have been able to read the contents of a file which are laid out like this:
Adele got 2,Jack got 8
I have then been able to split this file via the comma into a string array called names:
Dim fileReader As System.IO.StreamReader
Dim line As String
fileReader = My.Computer.FileSystem.OpenTextFileReader(ClassA)
line = fileReader.ReadLine
names = line.Split(",")
For Each element As String In names
Array.Sort(names)
Console.WriteLine(element)
Next
I was also able to sort the file alphabetically giving an output of:
Adele got 2
Jack got 8
However what I want to know is whether it is or isn't possible to sort these strings based on the number so the output would look like:
Jack got 8
Adele got 2
I also considered using regex to extract the numbers, parse them as integer, save them to a variable and then add them to an array and compare the arrays but their has to be a simpler way D:
Any help is much appreciated guys :)
Linq to the rescue. I added to the data to be sure it would handle 2 digit numerals and because 2 elements is a feeble test:
Dim phrases As String() = {"Adele got 2", "Zalgo got 9", "Jack got 8", "Ziggy got 11"}
phrases = phrases.OrderByDescending(Function(q) Int32.Parse(q.Split(" ").Last)).ToArray()
For Each s In phrases
Console.WriteLine(s)
Next
Result:
Ziggy got 11
Zalgo got 9
Adele got 8
Jack got 2
Yes, it's possible. Add a comparer function, and then sort using it. This is the comparer:
Private Shared Function WhoGotComparer(ByVal x As String, ByVal y As String) As Integer
Dim parseX() As String = Split(x, " got ")
Dim parseY() As String = Split(y, " got ")
If parseX.Length <> 2 Or parseY.Length <> 2 Then Return 0
Return CInt(parseY(1)).CompareTo(CInt(parseX(1))) 'Performs an integer comparison.
End Function
Add it to your code. You can make use of it like this:
names.Sort(AddressOf WhoGotComparer)
This should result in the array being sorted in descending order. I think that is what you wanted based on the example. If you want to change the order to ascending you can reverse the roles of they x and y parameters in the comparer function, or you can negate the results of the Compare.
I have one 2D array that I'm wanting to populate into another. I got a bit mixed up between lists, dictionaries and simple arrays, so I'm thinking I have two different types or array. The edited code with some attempts and resulting errors:
Dim _inifile As String = "C:\Users\Steve\Scripts\Projects\IniRecEdit\Tests\insrow.ini"
Public IniLines() As String = File.ReadAllLines(_inifile)
Public _ini(IniLines.Length - 1)() As String
For I As Integer = 0 To IniLines.Length - 1
_ini(I) = IniLines(I).Split("="c)
Next
'.....code
Dim _tempini(Lines.Length - 1, SQSIZE - 1) As String
Dim tagrow As Integer
Dim tagcol As Integer
Dim taglist() As String
Dim RowSel As Integer = 1
Dim cControl As Control
For Each cControl In Me.Panel1.Controls
If cControl.Tag <> Nothing Then
taglist = Split(cControl.Tag, ","c)
If taglist(0) = "Cell" Then
tagcol = Val(taglist(1))
tagrow = Val(taglist(2))
If tagrow <= RowSel Then
If tagcol = 0 Then
_tempini(tagrow, tagcol) = _ini(tagrow)(tagcol)
Debug.WriteLine("Lower or equal then Selected row. 1st Column. From ini to row:" & tagrow)
' EDIT etc etc... more code here
Next cControl
' DIFFERENT CODE TRIED AT THIS STAGE to transfer from one array to the other:
ReDim _ini(Lines.Length - 1)
For countrow As Integer = 0 To _tempini.GetLength(0) - 1
For countcol As Integer = 0 To _tempini.GetLength(1) - 1
_ini(countrow) = _tempini(countrow)._tempini(countcol)
Next
Next
' Produces: Error 2 Number of indices is less than the number of dimensions of the indexed array.
ReDim _ini(Lines.Length - 1)
For countrow As Integer = 0 To _tempini.GetLength(0) - 1
For countcol As Integer = 0 To _tempini.GetLength(1) - 1
_ini(countrow)(countcol) = _tempini(countrow, countcol)
Next
Next
'Produces: Additional information: Object reference not set to an instance of an object.
As I say, I'm not even sure whether I'm using lists of not for "_ini" The Locals Window on Visual Studio shows the vars as:
_ini is "String()()"
_tempini is "String(,)"
I'm increasingly aware I need to go back to basics with vb and learn all of the concepts involved. However, a quick assist would let me try and complete this thing I'm knocking together with blu-tack and string :)
You are actually using arrays. The declaration of a list would look like this:
Dim myList As New List(Of String)()
A list has always one dimension and the initial size of a list is 0 (unless you pass an enumeration to the constructor). You have to add items one by one using the Add method. This makes the list grow dynamically.
I assume that your ini-file looks like this
key1 = value1
key2 = value2
key3 = value3
Also I assume that the value does not contain an equal sign, otherwise I would look for the first instance of an equal sign an split the string there "manually".
Using a two dimensional array seems not appropriate in order to store key-value-pairs. There is a handy struct KeyValuePair(Of TKey, TValue) you could use if you need a string or a list. Using an array of KeyValuePairs has the advantage that you will not have to deal with two-dimensional arrays.
However, if you want to look up values for given keys, the Dictionary(Of TKey, TValue) is more appropriate, as it is optimized for a very fast lookup.
Dim dict As New Dictionary(Of String, String)
For i As Integer = 0 To IniLines.Length - 1
Dim parts = IniLines(i).Split("="c)
dict.Add(parts(0).Trim(), parts(1).Trim())
Next
Then you can retrive a value like this
Dim value As String
If dict.TryGetValue("some key", value) Then
' Use the value
Else
' Sorry, key does not exist
End If
Or if you are sure that the key you are looking for really exists, you can simply write
value = dict("some key")
TLDR
(1) Working with Arrays...
(2) Why are you getting "Object reference
not set to an instance of an object."
(3) Multidimensional Arrays
and Arrays of Arrays
(4) Why are you getting "Number of indices is
less than the number of dimens..."
(5) What I would do if I were
you...
Working with Arrays : Declaration(1) and Instanciation(2)
(1) declaration is when you write the name of a variable and its type. You can then access the object reffered by this variable in your code.
(2) we can talk about (variable/object) instanciation when an actual object has been created and registered somewhere in the memory. You can then manipulate that object via something that points to that object : the variable.
A declaration doesn't always mean the actual object is created. (I won't dig in ValueType and ReferenceType, sorry guys, I'm just cutting corners while explaining things without the complex verbose of strict dotNet)
Arrays declaration is different from instanciation :
Dim myArray As String()
This is just a declaration. Your Array is Nothing at this time and therefore contains nothing. Calling something like myStringVariable = myArray(0) will throw an Exception (Object reference not set to an instance of an object) meaning your array declaration points to nowhere because you haven't created an object of type String() and made your Array declaration points to that object.
Dim myArray() As String
This is the same declaration as above. Which one is correct ? I don't know and it's a matter of taste. VB is known for letting you do things the way you want. If you're good, you'll be able to use the one or the other like breathing. In fact, I really don't care.
Dim myArray As String() = new String() {}
This is just an instanciation of your array. Your array is registered in memory, but is of length 0 (zero) and contains no single item (Length = 0).
Remeber the declaration above ? (myArray() As String or myArray As String()) In fact, there is a difference in the two syntax when you talk about instanciation :
you can write : Dim myArray(3) As String
but you can't write : Dim myArray As String(3)
The later throws an exception. The variable type (String) cannot have indexes delimiters.
Dim myArray(3) As String '...
... also declares an Array and instanciate it with 4 predefined items like below.
Dim myArray As String() ' this is a declaration.
Redim myArray(3) ' this is an instanciation with a defined size.
This is one another way to define the number of items in your array using the Redim keyword. You have 4 "slots" in that Array from index [0] to index [3]. Your array looks like this :
[0][""]
[1][""]
[2][""]
[3][""]
.
Dim myArray As String = New String(3) {}
This is the same as above, but in one line : you're declaring and instanciating an Array of String that contains 4 items of type String which are all empty string (they are not Nothing)
Dim myArray() As String = { "One", "Two", "Three", "Four" }
This is a one line declaration, instanciation and items-setting :
[0]["One"]
[1]["Two"]
[2]["Three"]
[3]["Four"]
Redim
Redim is used to redifine the number of items in an Array. One dimensional arrays just behaves the way they are supposed to.
Suppose you have defined your array as :
Dim myArray() As String = { "One", "Two", "Three", "Four" }
Obviously, you have four String. Then use Redim :
Redim myArray(6) ' to get 7 items ..!
This is what you get :
[0][""]
[1][""]
[2][""]
[3][""]
[4][""]
[5][""]
[6][""]
You can resize an Array, but to keep the items inside, you'll have to use a keyword : Preserve
Redim Preserve myArray(6)
myArray(4) = "Five"
'myArray(5) = "Six"
myArray(6) = "Seven"
Because I've commented out the setting of the sixth item, the array will look like this :
[0]["One"]
[1]["Two"]
[2]["Three"]
[3]["Four"]
[4]["Five"]
[5][""] ' Empty String.
[6]["Seven"]
What happens if you Redim Preserve the Array above twice while killing some items ?
Redim Preserve myArray(2)
Redim Preserve myArray(6)
' You get :
[0]["One"]
[1]["Two"]
[2]["Three"]
[3][""]
[4][""]
[5][""]
[6][""]
You've lost items 3..6 ! Don't expect to get them back.
Public _ini(IniLines.Length - 1)() As String
What this code does ? Writing Dim myArray(3)() As String ("3" could be any positive or null integer) results in the following Array structure :
[0][Nothing]
[1][Nothing]
[2][Nothing]
[3][Nothing]
Why are you getting Nothing but not a bidimensional array ? Not even empty strings ?
It's because the declaration above creates a ONE dimensional Array of Array (of the type defined, String here)
VB.net allows you to declare an Array of Array this way (I don't know yet if C# can - but I really don't care : I never, and will never use this type of syntax) This is not a bidimensional Array. To define the values, you'll have to create each instance of the contained Array per item (or line) and assign it to your Array.
In the declaration above, while you have explicitely initialized your Array, its contents [0..3] are still simple declarations that points to no instance of anything, thus, explaining the "Nothing" thing.
Then upon getting datas from your file, your _ini variable could look like this, depending on the content of your file (that's why I asked you to provide a sample of the content of your file) :
[0][ ["Key0" | "Value0"] ]
[1][ ["Key1" | ""] ]
[2][ [""] ]
[3][ ["Key3" | "Value3" | "OtherData" | "MoreData" | "EvenMoreData"] ]
...
Reading a (String) value can be done like follows :
Dim myStringVariable As String = _ini(0)(1) ' Gets "Value0"
=> Be carefull when you use Array or Arrays along with
multidimentional arrays. They are not the same !
Let's pick the code below :
ReDim _ini(Lines.Length - 1)
For countrow As Integer = 0 To _tempini.GetLength(0) - 1
For countcol As Integer = 0 To _tempini.GetLength(1) - 1
_ini(countrow)(countcol) = _tempini(countrow, countcol)
Next
Next
Your _tempini is a bidimentional array of String.
Your _ini is an one dimensions array of array of String.
Scan this line :
_ini(countrow)(countcol) = _tempini(countrow, countcol)
1) _ini(countrow) contains Nothing (whatever the value of countrow) = contains NO Array (of String) because you've just called ReDim _ini(Lines.Length - 1) right before the For loop.
2) Therefore your assignation _ini(countrow)(countcol) = ... is the same as running the following at runtime :
Nothing(countcol) = _tempini(countrow, countcol)
Nothing is not an Array, so the (countcol) indexing has no meaning : you're indexing an item value to an object expected to be an Array that doesn't even exist.
That's why you get the Exception Object reference not set to an instance of an object.
Multidimensional Arrays / Redim / Preserve
The declaration and instanciation above still apply !
Public myBiDiArray(,) As String ' Declaration ONLY : bi dimensional array
Public myBiDiArray(2,1) As String ' Declaration AND Instanciation
Public myBiDiArray(,) As String = New String(2, 1) {} ' Dec. + Inst.
Public myBiDiArray(,) As String = _
{ {"One", "Un"}, {"Two", "Deux"}, {"Three", "Trois"} }
' ^^ Declaration + Instanciation + Item Setter
Public myBiDiArray(,) As String = _
New String(,) { {"One", "Un"}, {"Two", "Deux"}, {"Three", "Trois"} }
' ^^ Declaration + Instanciation + Item Setter
Let's have a Bidimensional Array of String with rows and columns...
Dim myArray(2, 1) As String ' 3 lines, two columns
This array contains the following items :
Line 0 = [""][""]
Line 1 = [""][""]
Line 2 = [""][""]
Now you want to resize the Array and use the Redim (only) Keyword...
Redim myArray(5, 3) ' ...
...which would set the lines to 6 and columns to 4 :
' Array Size = 6, 4
Line 0 = [""][""][""][""]
Line 1 = [""][""][""][""]
Line 2 = [""][""][""][""]
Line 3 = [""][""][""][""]
Line 4 = [""][""][""][""]
Line 5 = [""][""][""][""]
That's great !
Now let's set a value in Row(0) and Column(0)
myArray(0, 0) = "Cell,0,0"
' You get :
Line 0 = ["Cell,0,0"][""][""][""]
Line 1 = [""] [""][""][""]
Line 2 = [""] [""][""][""]
Line 3 = [""] [""][""][""]
Line 4 = [""] [""][""][""]
Line 5 = [""] [""][""][""]
But what happens with the Preserve Keyword ?
Redim Preserve myArray(3, 2) ' 4 lines and 3 columns
You get an exception : 'ReDim' can only change the rightmost dimension.
But you must know that this Exception is not handled by the debugger unless you explicitly write a Try/Catch routine that encapsulates the Redim Preserve Code. Otherwise, the application just exit the method/function containing that piece of code without any warning and your Array remains untouched !
To redim a multidimensional array (not only the last dimension) while preserving its content, you must create a new array of the desired size and copy the content of the former one to this new array, then make your former array point to that new one...
_ini(countrow) = _tempini(countrow)._tempini(countcol)
I'm not aware of such syntax in VB.Net. Perhaps you got this from another language or a Reference that adds extensions to Arrays (like System.Linq) which extends (?) the members of an Array to itself for some purpose.., but I'm not aware of that.
It looks to me like a simple syntax error. That's why you get the Exception Number of indices is less than the number of dimensions of the indexed array.
To get the (string) value of a bidimensional array, just write :
myStringValue = _tempini(countrow, countcol)
The error warning is not pointing to the systax error though : the debugger stopped at the closing backet and discarded the remaining piece of text :
_ini(countrow) = _tempini(countrow ... ' <- compiler expects a comma here.
Writing this will produce the following error :
myStringValue = _tempini(countrow, countcol)._tempini(countcol)
Compiler Error : 'tempini' is not a member of 'String'.
Again, don't mess with bidimentional arrays and arrays of arrays : Writing...
_ini(countrow) = _tempini(countrow, countcol) ' ...
... has no meaning ! Even if the syntax looks correct, the above code actually tries to assign a String value to an Array(Of String) variable, which will throw an InvalidCastException.
I'll be honest : Arrays are a great bit of fun with fixed/predefined size/dimensions. From the moment I'm working with unknown number of elements/items at runtime, I leave Arrays behind.
What I would do ?
Oh! just the same Olivier Jacot-Descombes advised you to do :) No surprise, a Dictionary is very handy in your situation.
I would also enable those two :
Option Strict On
Option Explicit On
and disable this one : Option Infer Off.
Another PERSONAL advice is to avoid using the Tag property of a control. This tag is of type Object.
some Casting should be done to get a cleaner code.
Controls are usual components you'll use anywhere. One day, I've imagined I have tied an object of type 'String' to a specific control while it actually contained a Date or even Nothing. Why ? Because I confounded two different projects and lost track of the whole thing.
pass your code to a colleague or a friend, and be sure he/she'll ask you to document it about what you've done with the Tag Property... that simply means no one want to discover the obscure underlying logic of a code involving Objects. People like to deal with strongly typed variables, easy to debug and fast performing at runtime.
Also avoid the use of Val(). Val() is very handy because it can almost convert anything. However, because of this nice feature, it adds a workload on the CPU. Again, if you know you're dealing with Int32 or Double, then use Int32.Parse() or Double.Parse() but not Val(). Most misuse of Val() on the web are related to type inference and implicit casting. Debugging such kind of glitches are a real pain. Use Val only when you have no alternative.
I think you now have almost everything you need to get your code working with little changes. I have not provided the code for the changes though :
I don't understand where your samples of code lands in your application logic
I don't know what kind of datas you're manipulating
I don't even know what's the purpose of the code.
^^ So I just addressed two things :
why you're getting errors...
since you're new to VB, I just provided a custom explanation of Arrays.
Was that the (not so) quick assist you were looking for ? I don't know. That's the best I could give right now.
OK. People have been really helpful, but not really up to totally recoding at this stage. I did find a work around, however. It aint pretty and probably is really bad practice! However, got it up and running with the code I've got.
Essentially, I just did the process in reverse, constructed a line from the components in _tempini, delimited by a "=" and then just re-ran the original procedure for populating the _ini array in the first place. A total work-around, but hope will help any other amateurs like me getting stuck in these early stages.
However, I would say follow these fellas advice! Look into list, dictionaries etc before starting your code.
The fix:
ReDim _ini(((_tempini.Length) / 2) - 1)
Dim _newiniline As String
_newiniline = ""
For countrow As Integer = 0 To (((_tempini.Length) / 2) - 1)
For countcol As Integer = 0 To 1
_newiniline = _newiniline & _tempini(countrow, countcol)
If countcol = 0 Then
_newiniline = _newiniline & "="
End If
_ini(countrow) = _newiniline.Split("="c)
Next
_newiniline = Nothing
Next
I have 3 one dimensional arrays.
Each contains information that corresponds to the other 2 arrays.
e.g Array 1 contains a customer first name
Array 2 contains a customer last name
Array 3 contains the customer phone number.
This is not my actual example but is easiest to explain.
How do I sort all three arrays so that they are sorted in order by say customer last name.
If Mr Smith is sorted and has moved from position 10 to position 5 in the lastname array, I would expect his phone number and first name to also be in position 5 in the respective arrays.
I am dealing with arrays with 10,000's of items so I would like to avoid looping (my current method) as this is incredibly slow.
Hoping to use the array.sort methods.
Can someone help me?
Ok - So I have tried to use a new data Type but am still at a loss how I can instantly filter using this. Below is my sample code which has a couple of issues. If someone can resolve - it would love to learn how you did it.
The purpose of the code is to return an array containing grouped issues.
For simplicity I have assumed in the example that each constant found is an issue.
If an issue is found, combine it with other issues found on that same worksheet.
e.g The number 2 is found in both cells A1 and A2 on sheet 1. The array should return A1:A2.
If the issues are found in A1 on sheet 1 and A2 in sheet 2, two seperate array entries would be returned.
Test File and Code Here
Public Type Issues
ws_Sheet As Integer
rng_Range As String
s_Formula As String
s_Combined As String
d_ItemCount As Double
End Type
Sub IssuesFound()
Dim MyIssues() As Issues
Dim i_SheetCount As Integer
Dim s_Formula As String
Dim rng_Range As Range
Dim d_IssueCounter As Double
Dim s_SearchFor As String
Dim a_TempArray() As Issues
Dim d_InsertCounter As Double
d_IssueCounter = -1
' Loop All Sheets Using A Counter Rather Than For Each
For i_SheetCount = 1 To ActiveWorkbook.Sheets.Count
' Loop all Constants On Worksheet
For Each rng_Range In Sheets(i_SheetCount).Cells.SpecialCells(xlCellTypeConstants, 23)
If d_IssueCounter = -1 Then
' First Time and Issue Is Found, Start Recording In An Array
d_IssueCounter = d_IssueCounter + 1
ReDim MyIssues(0)
MyIssues(0).ws_Sheet = i_SheetCount
MyIssues(0).rng_Range = rng_Range.AddressLocal
MyIssues(0).s_Formula = rng_Range.Value
MyIssues(0).s_Combined = i_SheetCount & "#" & rng_Range.Value
MyIssues(0).d_ItemCount = 0
Else
' Going To Look For Issues Found On The Same Sheet with The Same Constant Value
s_SearchFor = i_SheetCount & "#" & rng_Range.Value
' HELP HERE: Need To Ideally Return Whether The Above Search Term Exists In The Array
' Without looping, and I want to return the position in the array if the item is found
a_TempArray = MyIssues 'Filter(MyIssues.s_Combined, s_SearchFor, True, vbTextCompare)
If IsVarArrayEmpty(a_TempArray) = True Then
' New Issue Found - Increase Counter By + 1
d_IssueCounter = d_IssueCounter + 1
' Increase The Array By 1
ReDim Preserve MyIssues(d_IssueCounter)
' Record The Information About The Constant Found. Sheet Number, Constant, Range, and also a combined string for searching and the array position
MyIssues(0).ws_Sheet = i_SheetCount
MyIssues(0).rng_Range = rng_Range.AddressLocal
MyIssues(0).s_Formula = rng_Range.Value
MyIssues(0).s_Combined = i_SheetCount & "#" & rng_Range.Value
MyIssues(0).d_ItemCount = 0
Else
' Get The Array Position Where Other Issues With The Same Worksheet and Constant are Stored
d_InsertCounter = a_TempArray.d_ItemCount
' Add The New Found Constant To The Range Already Containing The Same Constants on This Worksheet
MyIssues(d_InsertCounter).rng_Range = Union(rng_Range, Range(MyIssues(d_InsertCounter).rng_Range)).AddressLocal
End If
End If
Next
Next
End Sub
Function IsVarArrayEmpty(ByRef anArray As Issues)
Dim i As Integer
On Error Resume Next
i = UBound(anArray, 1)
If Err.Number = 0 Then
IsVarArrayEmpty = False
Else
IsVarArrayEmpty = True
End If
End Function
Sample Test File and Code Here
As suggested, you should not be using concurrent arrays at all. You should be defining a type with three properties and then creating a single array or collection of that type.
To answer your question though, there is no way to sort three arrays in concert but there is a way to sort two. What that means is that you can create a copy of the array that you want to use as keys and then use the copy to sort one of the other arrays and the original to sort the other. Check out the documentation for the Array.Copy overload that takes two arrays as arguments.
That said, copying the array and then sorting twice is a big overhead so you may not gain much, if anything, from this method. Better to just do it the right way in the first place, i.e. use a single array of a complex type rather than concurrent arrays of simple types. It's not 1960 any more, after all.