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Good Day
I am trying to convert a short date i.e 780506 to a date i.e 1978/05/06 , I have tried CASTING the date CAST(CONVERT(VARCHAR, 78) + '-' + CONVERT(VARCHAR, 05) + '-' + CONVERT(VARCHAR, 06)
AS DATETIME) but this is not working. I tried Converting the date:CONVERT(VARCHAR(6), 780506), 12) and also not working. Is there am easy way to do this? The reason I need this is that the first 6 digits of out countries ID number = Date of Birth, I am just trying to convert it into a workable date.
Thanks
Convert to date type:
DECLARE #s VARCHAR(10) = '780506'
SELECT convert(DATE, #s)
For the column:
SELECT CONVERT(DATE, ColumnName) FROM TableName
You can use CAST or CONVERT. Like this:
DECLARE #shortdate VARCHAR(10) = '780506'
SELECT CONVERT(DATE, #shortdate)
SELECT CAST(#shortdate AS DATE)
Result:
1978-05-06
Ok, I'm running query builder out of visual studio 2008. I'm trying to filter the results of the query by time; that is, I want to pull everything from the start of yesterday to noon yesterday.
I've been using GETDATE()-1 for yesterday, which pulls up a timestamp mm/dd/yyyy hh:mm:ss
however, it pulls the current time. to get it to run from the start of the day I appended the timestamp to remove the time itself, so it started at the beginning of the day:
convert(varchar(10), getdate()-1, 120)
so I'm using between to find the range, I have:
BETWEEN convert(varchar(10), getdate()-1, 120) AND // this is where I need it to cut off at noon.
I'm understanding that datetime is a data type here, so I tried subtracting the hours/minutes/seconds using date part, but datepart() only returns ints and doesn't affect the time.
thoughts? how do I get this to cut off at noon
Try this:
--Variables
declare #now datetime = getdate(),
#yesterday datetime
--Yesterday starting datetime
select #yesterday = convert(datetime, convert(date, dateadd(day,-1,#now)))
--Your query to filter between y'day start and y'day noon
--Note that between means inclusive boundary values. (or use >= and <=)
select * from yourTable
where dateCol between #yesteray and dateadd(hour,12,#yesterday)
DECLARE
#Min DATETIME
, #Max DATETIME
SELECT
#Min = DATEADD(DAY, -1, CAST(FLOOR(CAST(GETDATE() AS FLOAT)) AS DATETIME))
, #Max = DATEADD(HOUR, 12, CAST(FLOOR(CAST(GETDATE() AS FLOAT)) AS DATETIME))
SELECT *
FROM <Table> x
WHERE x.[Date] BETWEEN #Min AND #Max
SELECT * FROM T WHERE YourDate BETWEEN CAST(GETDATE()-1 As DATE) AND DATEADD(Hour, -12, CAST(CAST(GETDATE() As DATE) As DATETIME) )
Beware because BETWEEN will include lower and upper boundaries, so you can simply replace BETWEEN with x >= y and y < z if you don't want yesterday at 12:00 to be taken in account
between DateAdd(day, -1, cast(getdate() as date)) and DateAdd(hour, -12, cast(getdate() as date))
Edit: As mentioned in the comments, you can't use hours with a date, you have to cast it back to a datetime, thus:
between DateAdd(day, -1, cast(getdate() as date)) and DateAdd(hour, -12, cast(cast(getdate() as date) as datetime))
If you want to get the results from last 30 mins you need to use this. You can change MINUTE to HOUR too.
--Get now, hour and second included
DECLARE #NOW DATETIME = GETDATE()
--Get 30 mins from now
DECLARE #TranDate DATETIME
SET #TranDate = CONVERT(DATETIME, CONVERT(DATETIME, DATEADD(MINUTE,-30,#NOW)))
After That, add below code to your where statement,
AND TK.TransactionDate >= #TranDate
We have a field by name target_date. It's a string. We need to extract the month and year from that field.
Example:
1/10/2011(dd/mm/yyyy)
we are trying with
substring(target date,findstring(targetdate,"/",1)+1,(findstring(targetdate,"/",2)-findstring(targetdate,"/",1)+1)).
Please help me.
Thanks.
Well, first issue here is that you are storing datetime as string. I will assume that for whatever reason you can't fix that...
What I would do in this case is use convert() function
convert(datetime, target_date, 103)
and then extract needed values using month() and year()
Description
Use CAST and CONVERT (Transact-SQL) to convert your string to datetime.
Use DATEPART (Transact-SQL) to extract month and year.
Sample
-- this will give you the month of your target_date
datePart(mm, convert(datetime, target_date, 103))
-- this will give you the year of your target_date
datePart(yyyy, convert(datetime, target_date, 103)) -- 2011
-- or
datePart(yy, convert(datetime, target_date, 103)) -- 11
declare #date varchar(10)
set #date = '1/10/2011'
select DATEPART(yyyy, CONVERT(datetime, #date, 103)), DATEPART(mm, CONVERT(datetime, #date, 103))
Try this :
Month : left(right(target_date , 7),2)
Year: right(target_date , 4)
This is if the format of target_date is always the same (ie. dd/mm/yyyy)
How do I retrieve a date from SQL Server in YYYY-MM-DD format? I need this to work with SQL Server 2000 and up. Is there a simple way to perform this in SQL Server or would it be easier to convert it programmatically after I retrieve the result set?
I've read the CAST and CONVERT on Microsoft Technet, but the format I want isn't listed and changing the date format isn't an option.
SELECT CONVERT(char(10), GetDate(),126)
Limiting the size of the varchar chops of the hour portion that you don't want.
SELECT convert(varchar, getdate(), 100) -- mon dd yyyy hh:mmAM
SELECT convert(varchar, getdate(), 101) -- mm/dd/yyyy – 10/02/2008
SELECT convert(varchar, getdate(), 102) -- yyyy.mm.dd – 2008.10.02
SELECT convert(varchar, getdate(), 103) -- dd/mm/yyyy
SELECT convert(varchar, getdate(), 104) -- dd.mm.yyyy
SELECT convert(varchar, getdate(), 105) -- dd-mm-yyyy
SELECT convert(varchar, getdate(), 106) -- dd mon yyyy
SELECT convert(varchar, getdate(), 107) -- mon dd, yyyy
SELECT convert(varchar, getdate(), 108) -- hh:mm:ss
SELECT convert(varchar, getdate(), 109) -- mon dd yyyy hh:mm:ss:mmmAM (or PM)
SELECT convert(varchar, getdate(), 110) -- mm-dd-yyyy
SELECT convert(varchar, getdate(), 111) -- yyyy/mm/dd
SELECT convert(varchar, getdate(), 112) -- yyyymmdd
SELECT convert(varchar, getdate(), 113) -- dd mon yyyy hh:mm:ss:mmm
SELECT convert(varchar, getdate(), 114) -- hh:mm:ss:mmm(24h)
SELECT convert(varchar, getdate(), 120) -- yyyy-mm-dd hh:mm:ss(24h)
SELECT convert(varchar, getdate(), 121) -- yyyy-mm-dd hh:mm:ss.mmm
SELECT convert(varchar, getdate(), 126) -- yyyy-mm-ddThh:mm:ss.mmm
Starting with SQL Server 2012 (original question is for 2000):
SELECT FORMAT(GetDate(), 'yyyy-MM-dd')
The form you are after is listed in the books online documentation.
http://msdn.microsoft.com/en-us/library/aa226054(SQL.80).aspx
For example, try the following:
select convert(varchar,getDate(),120)
select convert(varchar(10),getDate(),120)
The convert function with the format specifier 120 will give you the format "yyyy-MM-dd HH:mm:ss", so you just have to limit the length to 10 to get only the date part:
convert(varchar(10), theDate, 120)
However, formatting dates is generally better to do in the presentation layer rather than in the database or business layer. If you return the date formatted from the database, then the client code has to parse it to a date again if it needs to do any calculations on it.
Example in C#:
theDate.ToString("yyyy-MM-dd")
For YYYYMMDD try
select convert(varchar,getDate(),112)
I have only tested on SQLServer2008.
I'm not sure why the simplest way has been ignored/omitted in the answers above:
SELECT FORMAT(GetDate(),'yyyy-MM-dd');--= 2020-01-02
SELECT FORMAT(GetDate(),'dd MMM yyyy HH:mm:ss');-- = 02 Jan 2020 08:08:08
I prefer the second one because whichever language you speak, you will understand what date it is!
Also SQL Server always 'understands' it when you send that to your save procedure, regardless of which regional formats are set in the computers - I always use full year (yyyy), month name (MMM) and 24 hour format (capital HH) for hour in my programming.
One other way...
CONVERT(varchar, DATEPART(yyyy, #datetime)) + '/' + CONVERT(varchar, DATEPART(mm, #datetime)) + '/' + CONVERT(varchar, DATEPART(dd, #datetime))
For those who would want the time part as well (I did), the following snippet may help
SELECT convert(varchar, getdate(), 120) -- yyyy-mm-dd hh:mm:ss(24h)
SELECT convert(varchar, getdate(), 121) -- yyyy-mm-dd hh:mm:ss.mmm
SELECT convert(varchar, getdate(), 126) -- yyyy-mm-ddThh:mm:ss.mmm
--example -- 2008-10-02T10:52:47.513
replace(convert(varchar, getdate(), 111), '/','-')
Will also do trick without "chopping anything off".
In case someone wants to do it the other way around and finds this.
select convert(datetime, '12.09.2014', 104)
This converts a string in the German date format to a datetime object.
Why 104? See here: http://msdn.microsoft.com/en-us/library/ms187928.aspx
In your cast and convert link, use style 126 thus:
CONVERT (varchar(10), DTvalue, 126)
This truncates the time. Your requirement to have it in yyyy-mm-dd means it must be a string datatype and datetime.
Frankly though, I'd do it on the client unless you have good reasons not to.
You may also use. This is by using the new datatype DATE. May not work in all previous versions, but greatly simplified to use in later version.
SELECT CAST(getdate() AS DATE)
SELECT LEFT(CAST(getdate() AS DATE), 7)
If you want to use it as a date instead of a varchar again afterwards, don't forget to convert it back:
select convert(datetime,CONVERT(char(10), GetDate(),126))
From SQL Server 2008 you can do this: CONVERT(date,getdate())
SELECT CONVERT(NVARCHAR(20), GETDATE(), 23)
I would use:
CONVERT(char(10),GETDATE(),126)
SELECT Code,Description FROM TABLE
-- This will Include only date part of 14th March 2010. Any date with date companents will not be considered.
WHERE ID= 1 AND FromDate >= CONVERT(DATETIME, '2010-02-14', 126) AND ToDate <= DATEADD(dd, 1, CONVERT(DATETIME, '2010-03-14', 126))
-- This will Include the whole day of 14th March 2010
--WHERE ID= 1 AND FromDate >= CONVERT(DATETIME, '2010-02-14', 126) AND ToDate < DATEADD(dd, 1, CONVERT(DATETIME, '2010-03-14', 126))
Using a CASE statement for each of the convert / cast functions always works for me:
Please replace tableXXXXY with your table name, and issueDate_dat with the name of your datetime field in that table:
SELECT issueDate_dat, CONVERT(varchar, DATEPART(yyyy, issuedate_dat)) AS issueDateYYYY
, CASE WHEN (len(CONVERT(varchar, DATEPART(mm, issuedate_dat))) < 2) THEN '0' +CONVERT(varchar, DATEPART(mm, issuedate_dat)) ELSE CONVERT(varchar, DATEPART(mm, issuedate_dat)) END AS issueDateMM
, CASE WHEN (len(CONVERT(varchar, DATEPART(dd, issuedate_dat))) <2) THEN '0' +CONVERT(varchar, DATEPART(dd, issuedate_dat)) ELSE CONVERT(varchar, DATEPART(dd, issuedate_dat)) END AS issueDateDD
FROM tableXXXXY
Hope this was helpful. chagbert.
This solution works for me, simple and effective (with 126 too)
CONVERT(NVARCHAR(MAX), CAST(GETDATE() as date), 120)
IFormatProvider culture = new System.Globalization.CultureInfo("fr-FR", true);
cmdGetPaymentStatement.Parameters.AddWithValue("#pStartDate", DateTime.Parse("22/12/2017", culture, System.Globalization.DateTimeStyles.AssumeLocal)).IsNullable = true;
Seems unnecessary to do any strange things, if you want your date to be seperated by slash.
Just escape it with a backslash. Otherwise you will end up with a dot.
SELECT FORMAT(GETDATE(),'yyyy\/MM');
Tested on SQL Server 2016
If your source date format is all messed up, try something along the lines of:
select
convert(nvarchar(50),year(a.messedupDate))+'-'+
(case when len(convert(nvarchar(50),month(a.messedupDate)))=1
then '0'+ convert(nvarchar(50),month(a.messedupDate))+'-'
else convert(nvarchar(50),month(a.messedupDate)) end)+
(case when len(convert(nvarchar(50),day(a.messedupDate)))=1
then '0'+ convert(nvarchar(50),day(a.messedupDate))+'-'
else convert(nvarchar(50),day(a.messedupDate)) end)
from messytable a
As string processing is expensive, and FORMAT more so, I am surprised that Asher/Aaron Dietz response is not higher, if not top; the question is seeking ISO 8601 date, and isn't specifically requesting it as a string type.
The most efficient method would be any of these (I've included the answer Asher/Aaron Dietz have already suggested for completeness):
All versions
select cast(getdate() as date)
select convert(date, getdate())
2008 and higher
select convert(date, current_timestamp)
ANSI SQL equivalent 2008 and higher
select cast(current_timestamp as date)
References:
https://sqlperformance.com/2015/06/t-sql-queries/format-is-nice-and-all-but
https://en.wikipedia.org/wiki/ISO_8601
https://www.w3schools.com/sql/func_sqlserver_current_timestamp.asp
https://learn.microsoft.com/en-us/sql/t-sql/functions/current-timestamp-transact-sql?view=sql-server-ver15
change GetDate() to any format as String:
SELECT FORMAT(GetDate(), 'yyyy-MM-dd HH:mm:ss')
In SQL Server I have a DATETIME column which includes a time element.
Example:
'14 AUG 2008 14:23:019'
What is the best method to only select the records for a particular day, ignoring the time part?
Example: (Not safe, as it does not match the time part and returns no rows)
DECLARE #p_date DATETIME
SET #p_date = CONVERT( DATETIME, '14 AUG 2008', 106 )
SELECT *
FROM table1
WHERE column_datetime = #p_date
Note: Given this site is also about jotting down notes and techniques you pick up and then forget, I'm going to post my own answer to this question as DATETIME stuff in MSSQL is probably the topic I lookup most in SQLBOL.
Update Clarified example to be more specific.
Edit Sorry, But I've had to down-mod WRONG answers (answers that return wrong results).
#Jorrit: WHERE (date>'20080813' AND date<'20080815') will return the 13th and the 14th.
#wearejimbo: Close, but no cigar! badge awarded to you. You missed out records written at 14/08/2008 23:59:001 to 23:59:999 (i.e. Less than 1 second before midnight.)
Technique 1:
DECLARE #p_date DATETIME
SET #p_date = CONVERT( DATETIME, '14 AUG 2008', 106 )
SELECT *
FROM table1
WHERE column_datetime >= #p_date
AND column_datetime < DATEADD(d, 1, #p_date)
The advantage of this is that it will use any index on 'column_datetime' if it exists.
In SQL Server 2008, you could use the new DATE datatype
DECLARE #pDate DATE='2008-08-14'
SELECT colA, colB
FROM table1
WHERE convert(date, colDateTime) = #pDate
#Guy. I think you will find that this solution scales just fine. Have a look at the query execution plan of your original query.
And for mine:
Just compare the year, month and day values.
Declare #DateToSearch DateTime
Set #DateToSearch = '14 AUG 2008'
SELECT *
FROM table1
WHERE Year(column_datetime) = Year(#DateToSearch)
AND Month(column_datetime) = Month(#DateToSearch)
AND Day(column_datetime) = Day(#DateToSearch)
Something like this?
SELECT *
FROM table1
WHERE convert(varchar, column_datetime, 111) = '2008/08/14'
Technique 2:
DECLARE #p_date DATETIME
SET #p_date = CONVERT( DATETIME, '14 AUG 2008', 106 )
SELECT *
FROM table1
WHERE DATEDIFF( d, column_datetime, #p_date ) = 0
If the column_datetime field is not indexed, and is unlikely to be (or the index is unlikely to be used) then using DATEDIFF() is shorter.
Good point about the index in the answer you accepted.
Still, if you really search only on specific DATE or DATE ranges often, then the best solution I found is to add another persisted computed column to your table which would only contain the DATE, and add index on this column:
ALTER TABLE "table1"
ADD "column_date" AS CONVERT(DATE, "column_datetime") PERSISTED
Add index on that column:
CREATE NONCLUSTERED INDEX "table1_column_date_nu_nci"
ON "table1" ( "column_date" ASC )
GO
Then your search will be even faster:
DECLARE #p_date DATE
SET #p_date = CONVERT( DATE, '14 AUG 2008', 106 )
SELECT *
FROM table1
WHERE column_date = #p_date
I normally convert date-time to date and compare them, like these:
SELECT 'Same Date' WHERE CAST(getDate() as date) = cast('2/24/2012 2:23 PM' as date)
or
SELECT 'Same Date' WHERE DATEDIFF(dd, cast(getDate() as date), cast('2/24/2012 2:23 PM' as date)) = 0
This function Cast(Floor(Cast(GetDate() As Float)) As DateTime) returns a datetime datatype with the time portion removed and could be used as so.
Select
*
Table1
Where
Cast(Floor(Cast(Column_DateTime As Float)) As DateTime) = '14-AUG-2008'
or
DECLARE #p_date DATETIME
SET #p_date = Cast('14 AUG 2008' as DateTime)
SELECT *
FROM table1
WHERE Cast(Floor(Cast(column_datetime As Float)) As DateTime) = #p_date
How to get the DATE portion of a DATETIME field in MS SQL Server:
One of the quickest and neatest ways to do this is using
DATEADD(dd, DATEDIFF( dd, 0, #DAY ), 0)
It avoids the CPU busting "convert the date into a string without the time and then converting it back again" logic.
It also does not expose the internal implementation that the "time portion is expressed as a fraction" of the date.
Get the date of the first day of the month
DATEADD(dd, DATEDIFF( dd, -1, GetDate() - DAY(GetDate()) ), 0)
Get the date rfom 1 year ago
DATEADD(m,-12,DATEADD(dd, DATEDIFF( dd, -1, GetDate() - DAY(GetDate()) ), 0))
I know this isn't exactly how you want to do this, but it could be a start:
SELECT *
FROM (SELECT *, DATEPART(yy, column_dateTime) as Year,
DATEPART(mm, column_dateTime) as Month,
DATEPART(dd, column_dateTime) as Day
FROM table1)
WHERE Year = '2008'
AND Month = '8'
AND Day = '14'
SELECT *
FROM table1
WHERE CONVERT(varchar(10),columnDatetime,121) =
CONVERT(varchar(10),CONVERT('14 AUG 2008' ,smalldatetime),121)
This will convert the datatime and the string into varchars of the format "YYYY-MM-DD".
This is very ugly, but should work
Date can be compared in sqlserver using string comparision:
e.g.
DECLARE #strDate VARCHAR(15)
SET #strDate ='07-12-2010'
SELECT * FROM table
WHERE CONVERT(VARCHAR(15),dtInvoice, 112)>= CONVERT(VARCHAR(15),#strDate , 112)
DECLARE #Dat
SELECT *
FROM Jai
WHERE
CONVERT(VARCHAR(2),DATEPART("dd",Date)) +'/'+
CONVERT(VARCHAR(2),DATEPART("mm",Date)) +'/'+
CONVERT(VARCHAR(4), DATEPART("yy",Date)) = #Dat
The best way is to simply extract the date part using the SQL DATE() Function:
SELECT *
FROM table1
WHERE DATE(column_datetime) = #p_date;
SELECT * FROM tablename
WHERE CAST(FLOOR(CAST(column_datetime AS FLOAT))AS DATETIME) = '30 jan 2012'
SELECT CONVERT(VARCHAR(2),DATEPART("dd",doj)) +
'/' + CONVERT(VARCHAR(2),DATEPART("mm",doj)) +
'/' + CONVERT(VARCHAR(4),DATEPART("yy",doj)) FROM emp
There are many formats for date in SQL which are being specified. Refer https://msdn.microsoft.com/en-in/library/ms187928.aspx
Converting and comparing varchar column with selected dates.
Syntax:
SELECT * FROM tablename where CONVERT(datetime,columnname,103)
between '2016-03-01' and '2016-03-03'
In CONVERT(DATETIME,COLUMNNAME,103) "103" SPECIFIES THE DATE FORMAT as dd/mm/yyyy
In sqlserver
DECLARE #p_date DATE
SELECT *
FROM table1
WHERE column_dateTime=#p_date
In C#
Pass the short string of date value using ToShortDateString() function.
sample:
DateVariable.ToShortDateString();