netezza sql, how to come true? - netezza

create table p(pid int, st int, v int,hid int,ht varchar(2));
data:
insert into p(pid,st,hid, ht,v )
select 1 ,20160131 ,100 ,'FO' ,10
union select 1 ,20160131 ,101 ,'FO' ,20
union select 1 ,20160131 ,102 ,'FO' ,30
union select 1 ,20160131 ,103 ,'ST' ,40
union select 1 ,20160229 ,104 ,'ST' ,50
union select 207 ,20160229 ,301 ,'ST' ,80
union select 207 ,20160229 ,302 ,'ST' ,20
union select 207 ,20160331 ,303 ,'FO' ,40
union select 102 ,20160229 ,205 ,'ST' ,60
union select 102 ,20160229 ,206 ,'ST' ,20
union select 102 ,20160229 ,207 ,'FO' ,20
union select 100 ,20160131 ,201 ,'ST' ,50
union select 100 ,20160131 ,202 ,'ST' ,50
union select 101 ,20151231 ,203 ,'ST' ,50
union select 101 ,20151231 ,204 ,'ST' ,50
result:
pid v hid ht path pre_st next_st st
1 40 103 ST 1 NULL NULL 20160131
100 50 201 ST 1--->100 NULL NULL 20160131
100 50 202 ST 1--->100 NULL NULL 20160131
101 50 203 ST 1--->101 20151231 NULL 20160131
101 50 204 ST 1--->101 20151231 NULL 20160131
102 20 206 ST 1--->102 NULL 20160229 20160131
102 60 205 ST 1--->102 NULL 20160229 20160131
207 20 302 ST 1--->102--->207 NULL 20160331 20160229
207 80 301 ST 1--->102--->207 NULL 20160331 20160229
303 99 304 ST 1--->102--->207--->303 NULL 20160720 20160331
I can do it in SQLServer first.
select pid,v,hid,ht, path=cast(pid as varchar) ,
(select max(st) from p where pid = a.pid and st < a.st) as pre_st,
(select max(st) from p where pid = a.pid and st > a.st) as next_st,
a.st into #t1
from p a where pid=? and st=?
but netezza cannot support this grammer.
I need to according by pid,st as parameter to do it. assumption we use pid=1 and st=20160131, I will save the parameter set in one table.
create table i(pid int, st int)
insert into i(pid,st)
select 1,20160131
how to come true the above result?


If you're just looking to create a temporary table (the equivalent of your SQL Server syntax), then it's this:
create temporary table t1 as
select pid,v,hid,ht, path=cast(pid as varchar) ,
(select max(st) from p where pid = a.pid and st < a.st) as pre_st,
(select max(st) from p where pid = a.pid and st > a.st) as next_st,
a.st
from p a where pid=? and st=?
I'm going to assume that the ? values you have there are because you're using ODBC parameters. If you're trying to get Netezza to prompt you for something, you can't.

Related

Pivot Records in TSQL

My Current tables looks like this for 1 User.
NewCustomerID OldCustomerID RowID Date
111 NULL 1 2016-01-01
222 111 321 2016-02-05
333 222 5433 2017-03-01
444 333 95312 2017-04-03
Table below is what I need for end result. Needs to be TSQL.
NewCustomerID OldCustomerID
444 111
444 222
444 333
I will be using the table above to update all the OldCustomerID's to the latest NewCustomerID

You are looking for a recursive cte:
with cte as (
select t.NewCustomerID, t.OldCustomerID
from t
where not exists (select 1 from t t2 where t2.OldCustomerId = t.NewCustomerID)
union all
select cte.NewCustomerId, t.OldCustomerID
from cte join
t
on t.NewCustomerID = cte.OldCustomerID
)
select *
from cte;
Here is an example of it working.

Try this
DECLARE #SampleDAta AS TABLE
(
NewCustomerID int,
OldCustomerID int
)
INSERT INTO #SampleDAta VALUES (111, NULL),(222,111),(333,222),(444,333),(1111, NULL),(2222,1111),(3333,2222),(4444,3333),(5555,4444)
;with reTbl as (
select t.NewCustomerID, t.OldCustomerID, 1 as lev, t.NewCustomerID AS RootId
from #SampleDAta t
where t.OldCustomerID IS NULL
union all
select t.NewCustomerId, t.OldCustomerID, reTbl.lev +1, reTbl.RootId
from reTbl join
#SampleDAta t
on t.OldCustomerID = reTbl.NewCustomerID
),
LastestId AS
(
SELECT c.RootId, max(c.lev) AS MaxLevel
FROM reTbl c
GROUP BY c.RootId
)
select reTbl.NewCustomerID, reTbl1.NewCustomerID AS OldCustomerID
from reTbl
INNER JOIN reTbl reTbl1 ON reTbl.RootId = reTbl1.RootId
INNER JOIN LastestId t ON reTbl.RootId = t.RootId AND reTbl.lev = t.MaxLevel
WHERE reTbl.NewCustomerID != reTbl1.NewCustomerID
ORDER BY reTbl.NewCustomerID

How to get all numbers between a range

I have a table as below
Id RFrom RTo
.... ....... .....
1 10 14
1 22 25
2 100 102
2 176 180
I want to get all numbers between each RFrom and RTo for each Id. My expected result is as follows
Id NUMS
.... ......
1 10
1 11
1 12
1 13
1 14
1 22
1 23
1 24
1 25
2 100
2 101
2 102
2 176
2 177
2 178
2 179
2 180
Do I have to use cursor to achieve this?

Here is your sample table
SELECT * INTO #TEMP FROM
(
SELECT 1 ID, 10 RFROM, 14 RTO
UNION ALL
SELECT 1, 22, 25
UNION ALL
SELECT 2, 100, 102
UNION ALL
SELECT 2, 176, 180
)TAB
You need to use recursion for each Id to get the result
;WITH CTE AS
(
SELECT ID,RFROM RFROM1,RTO RTO1
FROM #TEMP
UNION ALL
SELECT T.ID,RFROM1+1,RTO1
FROM #TEMP T
JOIN CTE ON CTE.ID = T.ID
WHERE RFROM1 < RTO1
)
SELECT DISTINCT ID,RFROM1 NUMS
FROM CTE
SQL FIDDLE

Another option would be to use a numbers table with a join -- recursion can be time consuming.
There are several options to create a numbers table (I'd recommend creating a permanent one), but here's a temp one created with a common-table-expression:
with numberstable as (
select top 10000 row_number() over(order by t1.number) as number
from master..spt_values t1
cross join master..spt_values t2
)
select yt.id,
nt.number
from yourtable yt
join numberstable nt on nt.number between yt.rfrom and yt.rto
SQL Fiddle Demo

Create a tally table using stacked CTE which will have better performance when compared to recursive CTE
declare #min int
select #min= min(RFrom) from yourtable
;WITH e1(n) AS
(
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), -- 10
e2(n) AS (SELECT 1 FROM e1 CROSS JOIN e1 AS b), -- 10*10
e3(n) AS (SELECT 1 FROM e1 CROSS JOIN e2) -- 10*100
SELECT b.id,
a.n
FROM yourtable b
JOIN (SELECT n = Row_number()OVER (ORDER BY n)+ #min-1
FROM e3)a
ON a.n BETWEEN b.RFrom AND b.RTo
ORDER BY n;
Check here for info

SQL Server 2008 Find row based on 1 unique column and duplicates in a second column

Can you please suggest how I can write a query to retrieve the following?
I need to find any rows where the value in A is duplicated but the value in B is different
A B
4567 2
852125 9
444 8
2547 25
255 4
256 1
2547 25
2547 27
259 4
2547 25
Should return
2547 27
2547 25
As 2547 has two non identical values in column B
Thanks in anticipation
P

with cte1 as (
select distinct A, B from Table1
), cte2 as (
select A, B, count(*) over(partition by A) as cnt from cte1
)
select
A, B
from cte2
where cnt > 1
sql fiddle demo
or
with cte as (
select distinct
A, B, min(B) over(partition by A) as m1, max(B) over(partition by A) as m2
from Table1
)
select
A, B
from cte
where m1 <> m2
sql fiddle demo

Try this
With DemoTable AS
(
Select 4567 A,2 B
Union All Select 852125 ,9
Union All Select 444 ,8
Union All Select 2547 ,25
Union All Select 255 ,4
Union All Select 256 ,1
Union All Select 2547 ,25
Union All Select 2547 ,27
Union All Select 259 ,4
Union All Select 2547 ,25
)
Select Distinct A, B
From DemoTable
Where A In
(
Select A
From DemoTable
Group By A
Having Count (Distinct B) > 1
)
Output
A B
----------- -----------
2547 25
2547 27
(2 row(s) affected)

it's simple just use a nested select statement which one of them has count, group by and having statements.
select distinct tbl.A,tbl.B from table_name tbl
where tbl.A in (select A from (
select tb.A, count(tb.B)
from table_name tb group by tb.A having count(tb.B)>1))
order by tbl.A

How to get common value for two records from msSQL

catId DealId
1 668
2 668
3 669
1 669
3 671
11 671
12 671
7 669
12 672
13 673
Suppose it's a table. If I give two values for catId as input, a query should return all the records that contain same DealId.

SQL Statement
;WITH CatIDs (catID) AS (
SELECT 1
UNION ALL SELECT 2
)
SELECT mt.*
FROM MyTable mt
INNER JOIN CatIDs cid ON cid.catID = mt.catID
INNER JOIN (
SELECT mt.DealID
FROM MyTable mt
INNER JOIN CatIDs ids ON ids.catID = mt.catID
GROUP BY
mt.DealID
HAVING COUNT(mt.DealID) = (SELECT COUNT(*) FROM CatIDs)
) did ON did.DealID = mt.DealID
Test script
;WITH MyTable (catID, DealID) AS (
SELECT 1, 668
UNION ALL SELECT 2, 668
UNION ALL SELECT 3, 669
UNION ALL SELECT 1, 669
UNION ALL SELECT 3, 671
UNION ALL SELECT 11, 671
UNION ALL SELECT 12, 671
UNION ALL SELECT 7, 669
UNION ALL SELECT 12, 672
UNION ALL SELECT 13, 673
)
, CatIDs (catID) AS (
SELECT 1
UNION ALL SELECT 2
)
SELECT mt.*
FROM MyTable mt
INNER JOIN CatIDs cid ON cid.catID = mt.catID
INNER JOIN (
SELECT mt.DealID
FROM MyTable mt
INNER JOIN CatIDs ids ON ids.catID = mt.catID
GROUP BY
mt.DealID
HAVING COUNT(mt.DealID) = (SELECT COUNT(*) FROM CatIDs)
) did ON did.DealID = mt.DealID

Try this (hopping that's what you need):
SELECT DealId, catId, count(catId) AS tot
FROM your_table
WHERE catId = your_cat1 OR catId = your_cat2
GROUP BY DealId
HAVING tot > 1

I don't understand your question,hope bellow syntax help you .
CREATE PROCEDURE [spName]
#Parameter1 INT,
#Parameter2 INT
AS
BEGIN
SELECT * FROM TableName WHERE
DealId FROM TableName WHERE catId=#Parameter1
AND
DealId FROM TableName WHERE catId=#Parameter2
END

Sql Recursive query to identify relation between 2 users of family tree

Users Data
UserId DisplayName
12 Rahul
13 Anjali
14 Faruk
15 Shabina
16 Shakira
17 Ali
18 Ronak
19 Dali
20 Bali
21 Kali
22 Katrina
23 Sita
24 Gita
25 Ram
26 Shyam
27 Suhana
28 Suhas
29 Raj
30 Taslim
31 Ritik
32 Tejas
33 Dipika
34 Bush
35 Dyna
36 Bushiar
37 Salman
38 Ruksana
39 Khushi
40 Tazz
41 Miki
42 Krish
43 Kumbh
Family Tree Data
ID UserID RelativeId Relation
1 12 13 Spouse
3 12 15 Daughter
4 12 16 Daughter
5 12 17 Son
6 12 18 Son
7 13 12 Spouse
9 13 15 Daughter
10 13 16 Daughter
11 13 17 Son
12 13 18 Son
13 14 15 Spouse
14 14 20 Son
15 14 21 Daughter
16 14 19 Daughter
17 15 12 Father
18 15 13 Mother
19 15 14 Spouse
20 15 16 Sister
21 15 18 Brother
22 15 20 Son
23 15 19 Daughter
24 15 21 Daughter
25 16 12 Father
26 16 13 Mother
27 16 17 Spouse
28 16 14 Brother
29 16 18 Brother
30 16 23 Daughter
31 16 24 Daughter
32 16 25 Son
33 16 26 Son
34 17 16 Spouse
35 17 23 Daughter
36 17 24 Daughter
37 17 25 Son
38 17 26 Son
39 18 12 Father
40 18 13 Mother
41 18 19 Spouse
42 18 27 Daughter
43 18 28 Son
44 18 29 Son
45 18 15 Sister
46 18 16 Sister
47 19 14 Father
48 19 15 Mother
49 19 18 Spouse
50 19 27 Daughter
51 19 28 Son
52 19 29 Son
53 19 20 Brother
54 19 21 Sister
55 20 14 Father
56 20 15 Mother
57 20 21 Sister
58 20 19 Sister
59 20 40 Spouse
60 20 42 Son
61 20 43 Son
62 21 14 Father
63 21 15 Mother
64 21 25 Spouse
65 21 40 Daughter
66 21 41 Son
67 21 20 Brother
68 21 19 Sister
102 22 28 Spouse
103 22 31 Son
69 23 16 Mother
70 23 17 Father
71 23 24 Sister
72 23 25 Brother
73 23 26 Brother
74 24 16 Mother
75 24 17 Father
76 24 23 Sister
77 24 25 Brother
78 24 26 Brother
79 25 16 Mother
80 25 17 Father
81 25 23 Sister
82 25 24 Sister
83 25 26 Brother
84 25 21 Spouse
85 25 40 Daughter
86 25 41 Son
87 26 16 Mother
88 26 17 Father
89 26 23 Sister
90 26 24 Sister
91 26 25 Brother
92 26 27 Spouse
93 26 34 Son
94 26 31 Daughter
95 27 18 Father
96 27 19 Mother
97 27 26 Spouse
98 27 28 Brother
99 27 29 Brother
100 27 34 Son
101 27 35 Daughter
104 28 18 Father
105 28 19 Mother
106 28 27 Sister
107 28 29 Brother
108 28 22 Spouse
109 28 31 Son
110 29 18 Father
111 29 19 Mother
112 29 27 Sister
113 29 28 Brother
114 29 30 Spouse
115 29 32 Son
116 30 29 Spouse
117 30 32 Son
118 31 28 Father
119 31 22 Mother
120 31 34 Spouse
121 31 36 Son
122 32 29 Father
123 32 30 Mother
124 32 33 Spouse
125 32 35 Spouse
126 32 37 Son
127 32 38 Daughter
128 33 32 Spouse
129 33 38 Daughter
130 34 26 Father
131 34 27 Mother
132 34 35 Sister
133 34 31 Spouse
134 34 36 Son
135 35 26 Father
136 35 27 Mother
137 35 32 Spouse
138 35 34 Brother
139 35 37 Son
140 36 34 Father
141 36 31 Father
142 37 35 Mother
143 37 32 Father
144 37 38 Spouse
145 37 39 Daughter
146 38 32 Father
147 38 33 Mother
148 38 37 Spouse
149 38 39 Daughter
150 39 37 Father
151 39 38 Mother
152 40 21 Mother
153 40 25 Father
154 40 41 Brother
155 40 20 Spouse
156 40 42 Son
157 40 43 Son
158 41 21 Mother
159 41 25 Father
160 41 40 Sister
161 42 20 Father
162 42 40 Mother
163 42 43 Brother
164 43 20 Father
165 43 40 Mother
166 43 42 Brother
want to find path to find relation between Rahul(Id=12) and Tejas(Id=32)
thanks for the help in advance....
Chart for the above Data:
query provided by astander:
DECLARE #Users TABLE(
UserID INT,
UserName VARCHAR(50)
)
DECLARE #FamilyTree TABLE(
UserID INT,
RelationID INT,
Relation VARCHAR(50)
)
INSERT INTO #Users (UserID,UserName) SELECT 1 ,'Rahul'
INSERT INTO #Users (UserID,UserName) SELECT 2 ,'Anjli'
INSERT INTO #Users (UserID,UserName) SELECT 3 ,'Ronak'
INSERT INTO #Users (UserID,UserName) SELECT 4 ,'Rutu'
INSERT INTO #Users (UserID,UserName) SELECT 5 ,'Riya'
INSERT INTO #Users (UserID,UserName) SELECT 6 ,'Rishi'
INSERT INTO #Users (UserID,UserName) SELECT 7 ,'Harry'
INSERT INTO #Users (UserID,UserName) SELECT 8 ,'Dyna'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 1, 2 ,'Wife'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 2, 1 ,'Rahul'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 1, 3 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 3, 4 ,'Wife'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 3, 5 ,'Daughter'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 4, 5 ,'Daughter'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 4, 6 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 3, 6 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 1, 7 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 2, 7 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 7, 8 ,'Wife'
DECLARE #UserID1 INT,
#UserID2 INT
SELECT #UserID1 = 1,
#UserID2 = 6
DECLARE #Table TABLE(
cnt INT,
cpath VARCHAR(50)
)
;WITH fam AS(
SELECT *,
1 AS CntLevel,
CAST('/' + CAST(ft.UserID AS VARCHAR(10)) + '/' AS VARCHAR(50)) AS CLevel
FROM #FamilyTree ft
WHERE ft.UserID = #UserID1
UNION ALL
SELECT ft.*,
fam.CntLevel + 1 AS CntLevel,
CAST(fam.Clevel + CAST(ft.UserID AS VARCHAR(10)) + '/'AS VARCHAR(50)) AS CLevel
FROM #FamilyTree ft INNER JOIN
fam ON ft.UserID = fam.RelationID
WHERE ft.UserID != #UserID1
)
INSERT INTO #Table(cnt, cpath)
SELECT CntLevel,
CAST(fam.Clevel + CAST(fam.RelationID AS VARCHAR(10)) + '/'AS VARCHAR(50))
FROM fam
WHERE CAST(fam.Clevel + CAST(fam.RelationID AS VARCHAR(10)) + '/'AS VARCHAR(50)) LIKE ('/' + CAST(#UserID1 AS VARCHAR(10)) + '/%')
AND CAST(fam.Clevel + CAST(fam.RelationID AS VARCHAR(10)) + '/'AS VARCHAR(50)) LIKE ('%/' + CAST(#UserID2 AS VARCHAR(10))+ '/')
SELECT DISTINCT
ft.*
FROM #Table t INNER JOIN
#FamilyTree ft ON PATINDEX('%/' + CAST(ft.UserID AS VARCHAR(10)) + '/%',t.cpath) > 0
AND PATINDEX('%/' + CAST(ft.RelationID AS VARCHAR(10)) + '/%',t.cpath) > 0

Well, complicated family. Try this.
Work with finally output for customize.
DECLARE #Users TABLE(
UserID INT,
UserName VARCHAR(50)
)
DECLARE #FamilyTree TABLE( [ID] int,
UserID INT,
RelativeId INT,
Relation VARCHAR(50)
)
INSERT INTO #Users
select 12,'Rahul' union
select 13,'Anjali' union
select 14,'Faruk' union
select 15,'Shabina' union
select 16,'Shakira' union
select 17,'Ali' union
select 18,'Ronak' union
select 19,'Dali' union
select 20,'Bali' union
select 21,'Kali' union
select 22,'Katrina' union
select 23,'Sita' union
select 24,'Gita' union
select 25,'Ram' union
select 26,'Shyam' union
select 27,'Suhana' union
select 28,'Suhas' union
select 29,'Raj' union
select 30,'Taslim' union
select 31,'Ritik' union
select 32,'Tejas' union
select 33,'Dipika' union
select 34,'Bush' union
select 35,'Dyna' union
select 36,'Bushiar' union
select 37,'Salman' union
select 38,'Ruksana' union
select 39,'Khushi' union
select 40,'Tazz' union
select 41,'Miki' union
select 42,'Krish' union
select 43,'Kumbh'
INSERT INTO #FamilyTree ([ID],UserID,RelativeId,Relation)
select 1,12,13,'Spouse' union
select 3,12,15,'Daughter' union
select 4,12,16,'Daughter' union
select 5,12,17,'Son' union
select 6,12,18,'Son' union
select 7,13,12,'Spouse' union
select 9,13,15,'Daughter' union
select 10,13,16,'Daughter' union
select 11,13,17,'Son' union
select 12,13,18,'Son' union
select 13,14,15,'Spouse' union
select 14,14,20,'Son' union
select 15,14,21,'Daughter' union
select 16,14,19,'Daughter' union
select 17,15,12,'Father' union
select 18,15,13,'Mother' union
select 19,15,14,'Spouse' union
select 20,15,16,'Sister' union
select 21,15,18,'Brother' union
select 22,15,20,'Son' union
select 23,15,19,'Daughter' union
select 24,15,21,'Daughter' union
select 25,16,12,'Father' union
select 26,16,13,'Mother' union
select 27,16,17,'Spouse' union
select 28,16,14,'Brother' union
select 29,16,18,'Brother' union
select 30,16,23,'Daughter' union
select 31,16,24,'Daughter' union
select 32,16,25,'Son' union
select 33,16,26,'Son' union
select 34,17,16,'Spouse' union
select 35,17,23,'Daughter' union
select 36,17,24,'Daughter' union
select 37,17,25,'Son' union
select 38,17,26,'Son' union
select 39,18,12,'Father' union
select 40,18,13,'Mother' union
select 41,18,19,'Spouse' union
select 42,18,27,'Daughter' union
select 43,18,28,'Son' union
select 44,18,29,'Son' union
select 45,18,15,'Sister' union
select 46,18,16,'Sister' union
select 47,19,14,'Father' union
select 48,19,15,'Mother' union
select 49,19,18,'Spouse' union
select 50,19,27,'Daughter' union
select 51,19,28,'Son' union
select 52,19,29,'Son' union
select 53,19,20,'Brother' union
select 54,19,21,'Sister' union
select 55,20,14,'Father' union
select 56,20,15,'Mother' union
select 57,20,21,'Sister' union
select 58,20,19,'Sister' union
select 59,20,40,'Spouse' union
select 60,20,42,'Son' union
select 61,20,43,'Son' union
select 62,21,14,'Father' union
select 63,21,15,'Mother' union
select 64,21,25,'Spouse' union
select 65,21,40,'Daughter' union
select 66,21,41,'Son' union
select 67,21,20,'Brother' union
select 68,21,19,'Sister' union
select 102,22,28,'Spouse' union
select 103,22,31,'Son' union
select 69,23,16,'Mother' union
select 70,23,17,'Father' union
select 71,23,24,'Sister' union
select 72,23,25,'Brother' union
select 73,23,26,'Brother' union
select 74,24,16,'Mother' union
select 75,24,17,'Father' union
select 76,24,23,'Sister' union
select 77,24,25,'Brother' union
select 78,24,26,'Brother' union
select 79,25,16,'Mother' union
select 80,25,17,'Father' union
select 81,25,23,'Sister' union
select 82,25,24,'Sister' union
select 83,25,26,'Brother' union
select 84,25,21,'Spouse' union
select 85,25,40,'Daughter' union
select 86,25,41,'Son' union
select 87,26,16,'Mother' union
select 88,26,17,'Father' union
select 89,26,23,'Sister' union
select 90,26,24,'Sister' union
select 91,26,25,'Brother' union
select 92,26,27,'Spouse' union
select 93,26,34,'Son' union
select 94,26,31,'Daughter' union
select 95,27,18,'Father' union
select 96,27,19,'Mother' union
select 97,27,26,'Spouse' union
select 98,27,28,'Brother' union
select 99,27,29,'Brother' union
select 100,27,34,'Son' union
select 101,27,35,'Daughter' union
select 104,28,18,'Father' union
select 105,28,19,'Mother' union
select 106,28,27,'Sister' union
select 107,28,29,'Brother' union
select 108,28,22,'Spouse' union
select 109,28,31,'Son' union
select 110,29,18,'Father' union
select 111,29,19,'Mother' union
select 112,29,27,'Sister' union
select 113,29,28,'Brother' union
select 114,29,30,'Spouse' union
select 115,29,32,'Son' union
select 116,30,29,'Spouse' union
select 117,30,32,'Son' union
select 118,31,28,'Father' union
select 119,31,22,'Mother' union
select 120,31,34,'Spouse' union
select 121,31,36,'Son' union
select 122,32,29,'Father' union
select 123,32,30,'Mother' union
select 124,32,33,'Spouse' union
select 125,32,35,'Spouse' union
select 126,32,37,'Son' union
select 127,32,38,'Daughter' union
select 128,33,32,'Spouse' union
select 129,33,38,'Daughter' union
select 130,34,26,'Father' union
select 131,34,27,'Mother' union
select 132,34,35,'Sister' union
select 133,34,31,'Spouse' union
select 134,34,36,'Son' union
select 135,35,26,'Father' union
select 136,35,27,'Mother' union
select 137,35,32,'Spouse' union
select 138,35,34,'Brother' union
select 139,35,37,'Son' union
select 140,36,34,'Father' union
select 141,36,31,'Father' union
select 142,37,35,'Mother' union
select 143,37,32,'Father' union
select 144,37,38,'Spouse' union
select 145,37,39,'Daughter' union
select 146,38,32,'Father' union
select 147,38,33,'Mother' union
select 148,38,37,'Spouse' union
select 149,38,39,'Daughter' union
select 150,39,37,'Father' union
select 151,39,38,'Mother' union
select 152,40,21,'Mother' union
select 153,40,25,'Father' union
select 154,40,41,'Brother' union
select 155,40,20,'Spouse' union
select 156,40,42,'Son' union
select 157,40,43,'Son' union
select 158,41,21,'Mother' union
select 159,41,25,'Father' union
select 160,41,40,'Sister' union
select 161,42,20,'Father' union
select 162,42,40,'Mother' union
select 163,42,43,'Brother' union
select 164,43,20,'Father' union
select 165,43,40,'Mother' union
select 166,43,42,'Brother'
DECLARE #UserID1 INT,
#UserID2 INT
SELECT #UserID1 = 12,
#UserID2 = 32
--descendants of user1
;with famDes
as
(
select * ,
cast(ltrim(userid) as varchar(max)) as [path],
cast(relation as varchar(max)) as [path2]
from #FamilyTree
where UserID=#UserID1 and Relation in ('Son','Daughter')
union all
select ft.*,
cast([path]+'.'+ltrim(ft.userid) as varchar(max)),
cast([path2]+'.'+ft.relation as varchar(max))
from #FamilyTree ft
inner join famDes on ft.UserID=famDes.RelativeId and ft.Relation in ('Son','Daughter')
),
--ascendants of user1
famAsc
as
(
select * ,
cast(ltrim(userid) as varchar(max)) as [path],
cast(relation as varchar(max)) as [path2]
from #FamilyTree
where UserID=#UserID1 and Relation in ('Father','Mother')
union all
select ft.*,
cast([path]+'.'+ltrim(ft.userid) as varchar(max)),
cast([path2]+'.'+ft.relation as varchar(max))
from #FamilyTree ft
inner join famAsc on ft.UserID=famAsc.RelativeId and ft.Relation in ('Father','Mother')
)
select
*
from
famDes
where
relativeID=#UserID2
union all
select
*
from
famAsc
where
relativeID=#UserID2
union all
--if user1 and user2 are brothers or Spouses
select
* ,
cast(ltrim(userid) as varchar(max)) as [path],
cast(relation as varchar(max)) as [path2]
from #FamilyTree
where
UserID in (#UserID1,#UserID2)
and Relation in ('Brother','Sister','Spouse')
and relativeID in (#UserID2 ,#UserID1 )

You can try something like this
DECLARE #Users TABLE(
UserID INT,
UserName VARCHAR(50)
)
DECLARE #FamilyTree TABLE(
UserID INT,
RelationID INT,
Relation VARCHAR(50)
)
INSERT INTO #Users (UserID,UserName) SELECT 1 ,'Rahul'
INSERT INTO #Users (UserID,UserName) SELECT 2 ,'Anjli'
INSERT INTO #Users (UserID,UserName) SELECT 3 ,'Ronak'
INSERT INTO #Users (UserID,UserName) SELECT 4 ,'Rutu'
INSERT INTO #Users (UserID,UserName) SELECT 5 ,'Riya'
INSERT INTO #Users (UserID,UserName) SELECT 6 ,'Rishi'
INSERT INTO #Users (UserID,UserName) SELECT 7 ,'Harry'
INSERT INTO #Users (UserID,UserName) SELECT 8 ,'Dyna'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 1, 2 ,'Wife'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 2, 1 ,'Rahul'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 1, 3 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 3, 4 ,'Wife'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 3, 5 ,'Daughter'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 4, 5 ,'Daughter'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 4, 6 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 3, 6 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 1, 7 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 2, 7 ,'Son'
INSERT INTO #FamilyTree (UserID,RelationID,Relation) SELECT 7, 8 ,'Wife'
DECLARE #UserID1 INT,
#UserID2 INT
SELECT #UserID1 = 1,
#UserID2 = 6
DECLARE #Table TABLE(
cnt INT,
cpath VARCHAR(50)
)
;WITH fam AS(
SELECT *,
1 AS CntLevel,
CAST('/' + CAST(ft.UserID AS VARCHAR(10)) + '/' AS VARCHAR(50)) AS CLevel
FROM #FamilyTree ft
WHERE ft.UserID = #UserID1
UNION ALL
SELECT ft.*,
fam.CntLevel + 1 AS CntLevel,
CAST(fam.Clevel + CAST(ft.UserID AS VARCHAR(10)) + '/'AS VARCHAR(50)) AS CLevel
FROM #FamilyTree ft INNER JOIN
fam ON ft.UserID = fam.RelationID
WHERE ft.UserID != #UserID1
)
INSERT INTO #Table(cnt, cpath)
SELECT CntLevel,
CAST(fam.Clevel + CAST(fam.RelationID AS VARCHAR(10)) + '/'AS VARCHAR(50))
FROM fam
WHERE CAST(fam.Clevel + CAST(fam.RelationID AS VARCHAR(10)) + '/'AS VARCHAR(50)) LIKE ('/' + CAST(#UserID1 AS VARCHAR(10)) + '/%')
AND CAST(fam.Clevel + CAST(fam.RelationID AS VARCHAR(10)) + '/'AS VARCHAR(50)) LIKE ('%/' + CAST(#UserID2 AS VARCHAR(10))+ '/')
SELECT DISTINCT
ft.*
FROM #Table t INNER JOIN
#FamilyTree ft ON PATINDEX('%/' + CAST(ft.UserID AS VARCHAR(10)) + '/%',t.cpath) > 0
AND PATINDEX('%/' + CAST(ft.RelationID AS VARCHAR(10)) + '/%',t.cpath) > 0

i found one good article from there i am able to make my query
link for the article
Query :
DECLARE #From_Node int,
#To_Node int
SET #From_Node = 100035
SET #To_Node = 100046
SELECT *,
edges = 5 - ( CASE WHEN p2 = -1 THEN 4 WHEN p3 = -1 THEN 3 WHEN p4 = -1 THEN 2 WHEN p5 = -1 THEN 1 ELSE 0 END )
FROM (
SELECT p0 = p1.From_Node,
p1 = COALESCE( p1.To_Node, -1 ),
p2 = COALESCE( p2.To_Node, -1 ),
p3 = COALESCE( p3.To_Node, -1 ),
p4 = COALESCE( p4.To_Node, -1 ),
p5 = COALESCE( p5.To_Node, -1 )
FROM paths AS p1
OUTER APPLY tvfn_get_nodes_for( p1.To_Node, #From_Node, #To_Node ) AS p2
OUTER APPLY tvfn_get_nodes_for( p2.To_Node, #From_Node, #To_Node ) AS p3
OUTER APPLY tvfn_get_nodes_for( p3.To_Node, #From_Node, #To_Node ) AS p4
OUTER APPLY tvfn_get_nodes_for( p4.To_Node, #From_Node, #To_Node ) AS p5
WHERE p1.From_Node = #From_Node
) AS d
WHERE ( p1 = #To_Node OR p2 = #To_Node OR p3 = #To_Node OR p4 = #To_Node OR p5 = #To_Node )
AND ( p1 NOT IN ( p2, p3, p4, p5 )
OR p1 = -1 )
AND ( p2 NOT IN ( p1, p3, p4, p5 )
OR p2 = -1 )
AND ( p3 NOT IN ( p1, p2, p4, p5 )
OR p3 = -1 )
AND ( p4 NOT IN ( p1, p2, p3, p5 )
OR p4 = -1 )
AND ( p5 NOT IN ( p1, p2, p3, p4 )
OR p5 = -1 )
ORDER BY edges

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