How to filter groups? - sql-server

Question

I have a table like this:
Address AccountName AccountId
-------------------------------------------------------
10007 Cougar Country Smith 107
90026 Hunters Pond Scott 106
10008 Indigo Run Mary 108
70023 Kopplin Road John 102
70023 Kopplin Road John 103
70023 Kopplin Road Peter 104
70023 Kopplin Road Steve 105
70018 Oaks Drive Joe 100
70018 Oaks Drive Lisa 101
This is a result of joining two tables actually
with OrderBy Address. Table has records where
Address and/or AccountName columns
can have identical values among multiple rows,
while AccountId column would always be different.
How to get record groups where:
a) Address is same and AccountName is different
b) Address is same and AccountName is same
Also number of records in a group > 1.
I need all fields from table.
Here is the output I need to have:
a) Address is same and AccountName is different:
Address AccountName AccountId
-------------------------------------------------------
70023 Kopplin Road Peter 104
70023 Kopplin Road Steve 105
70018 Oaks Drive Joe 100
70018 Oaks Drive Lisa 101
b) Address is same and AccountName is same:
Address AccountName AccountId
-------------------------------------------------------
70023 Kopplin Road John 102
70023 Kopplin Road John 103
Thanks a lot

Answer 1

Perhaps something like this? It's certainly possible this could be improved if we knew more about your base query.
with data as (
<yourQuery>
)
select
case when count(*) over (partition by Address, AccountName) > 1
then 'Same Address and AccountName' else 'Same Address only'
end as Tag,
from data
where Address in (
select Address
from data
group by Address
having count(*) > 1
)
order by Tag, Address, AccountName
According to a comment on another answer it appears you may also want to handle repeated account names with different addresses. The question as posted describes something different. If you need this requirement to be incorporated into an answer you'll need to update the question accordingly.
Edit per your comment
with data as (
<yourQuery>
), dups as (
select *,
case when count(*) over (partition by Address, AccountName) > 1
then 'Same Address and AccountName' else 'Same Address only'
end as Tag,
from data
where Address in (
select Address
from data
group by Address
having count(*) > 1
)
)
select * from dups
where Tag = 'Same Address and AccountName' -- or 'Same Address only'
order by Tag, Address, AccountName

Answer 2

It still isn't totally clear what you want but this should get you close.
with SortedResults as
(
select Address
, AccountName
, AccountId
, ROW_NUMBER() over (partition by Address, AccountName order by AccountId) as RowNum
from SomeTable
)
select *
from SortedResults
where RowNum > 1

Answer 3

Declare #YourTable table (Address varchar(150),AccountName varchar(50),AccountID varchar(50))
Insert Into #YourTable values
('10007 Cougar Country','Smith','107'),
('90026 Hunters Pond' ,'Scott','106'),
('10008 Indigo Run' ,'Mary' ,'108'),
('70023 Kopplin Road' ,'John' ,'102'),
('70023 Kopplin Road' ,'John' ,'103'),
('70023 Kopplin Road' ,'Peter','104'),
('70023 Kopplin Road' ,'Steve','105'),
('70018 Oaks Drive' ,'Joe' ,'100'),
('70018 Oaks Drive' ,'Lisa' ,'101')
;with cteBase as (Select *,RowNr=Row_Number() over (Partition By Address,AccountName Order by AccountID) from #YourTable)
,cteLvl1 as (Select Address,GrpLvl1=IIF(count(*)>1,1,0) From cteBase Group by Address)
,cteLvl2 as (Select Address,AccountName,GrpLvl2=IIF(max(RowNr)>1,1,0) From cteBase Group by Address,AccountName)
Select Class=IIF(GrpLvl1+GrpLvl2=0,'None',IIF(GrpLvl1+GrpLvl2=1,'Group','Sub-Group'))
,A.Address
,A.AccountName
,A.AccountID
From cteBase A
Join cteLvl1 B on (A.Address=B.Address)
Join cteLvl2 C on (A.Address=B.Address and A.AccountName=C.AccountName)
Where GrpLvl1+GrpLvl2>=1
Order By GrpLvl1+GrpLvl2,2,3,4
Returns
Class Address AccountName AccountID
Group 70018 Oaks Drive Joe 100
Group 70018 Oaks Drive Lisa 101
Group 70023 Kopplin Road Peter 104
Group 70023 Kopplin Road Steve 105
Sub-Group 70023 Kopplin Road John 102
Sub-Group 70023 Kopplin Road John 103