Recursive way of display alphabet in c - c

Question

I am quite newbie in c, so I just starting off with some code, experimenting some stuff, right now I am stuck with this problem in C, creating a function that displays the alphabet in lowercase, on a single line, by ascending order, starting from the letter ’a’.
This is where I am stuck:
#include <stdio.h>
int alfabet(unsigned int i) {
if(i <= 122) {
char litera = i;
return litera;
}
return alfabet(i+1);
}
int main() {
int i = 97;
printf(alfabet(i));
return 0;
}

Answer 1

Here, you won't print anything really interesting. In fact, your application will crash because printf() require at least a char * parameter (a string).
Your alfabet() function seems not so bad, but you should print the letter in it :
int alfabet(unsigned int i)
{
if (i > 'z') {
// Here is the stop condition.
// If the value is higher than 122 ('z' character), we stop recursivity)
return;
}
printf("%c ", i);
// Otherwise, let's call this function with another character
return alfabet(i+1);
}

Answer 2

Target simplicity
void alfabet(int c) {
printf("%c", c);
if (c < 'z') alfabet(c+1);
}
called from main as
alfabet('a');
You may add a printf("\n");
the function prints the character given as parameter
you only call recursively the function with the next character to be printed if necessary, i.e. if the current character is below z.

Answer 3

Something like that:
#include <stdio.h>
void alfabet(char i) {
if(i < 'z')
{
alfabet(i+1);
}
printf("%c", i);
}
int main() {
char i = 'a';
alfabet(i);
return 0;
}
to print zyxwvutsrqponmlkjihgfedcba. Or:
#include <stdio.h>
void alfabet(char i) {
printf("%c", i);
if(i < 'z')
{
alfabet(i+1);
}
}
int main() {
char i = 'a';
alfabet(i);
return 0;
}
to print abcdefghijklmnopqrstuvwxyz

Answer 4

As you are new in this language, the basic thing to know is that each and every character on the keyboard has its own ASCII value ranging from 000 to 127 (i.e. total 128).
Now if you want to print a to z in a single line, the ASCII value for 'a' is 97 and that for 'z' is 122.
So, for printing this on screen you need to learn the basic for loop structure.The syntax for basic for loop is as follows :-
for(expr1;expr2;expr3)
{
Body of the loop;
}
Here, expr1 refers to the initial value of the variable, expr2 refers to the exit condition of the loop and expr3 refers to the increment or decrement value.
So, the code to print a to z is as follows :-
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
print_alpha();
getch();
}
void print_alpha()
{
int i;
for(i=97;i<+122;i++)
{
printf("%c",i);
}
}

Answer 5

int main() {
int i = 97;
printf("%c",alfabet(i));
return 0;
}
You Have to provide format specifier in printf (i.e. %c for character, %d for integer) Just check man printf in terminal.
And for printing a to z you can use for loop suggested by #Michel Jord, for printing in one line just put space in place of \n

Answer 6

#include <stdio.h>
void print_alphabets(char i) {
if(i>='a' && i<='z')
{
print_alphabets(i+1);
printf("%c ", i);
}
}
int main() {
char i;
scanf("%c",&i);
print_alphabets (i);
return 0;
}