I'm trying to create a pipe between father and child process.
in this pipe, the child process will write data and the father will read and print it.
I don't know why but if I enter a big string the data got wrong, for strings with +- 7 words it still do fine.
I guess it is about the size of the buffer but can't fix it.
#include <sys/wait.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
/* in this code i will make a child process with fork command
then i will create pipe using pipe commands.
i will transfer data from the child process to the father process
omriziner code
*/
void main(int argc,char *argv[])
{
if(argc < 2){
printf("prototype error \n<Enter any data you wana write> \n");
return;
}
int fd[2]; // creating array with 2 places for 2 fd'stdio
// fd[0] is set to read file in the pipe
//fd[1] is set to write file in the pipe
int piperes;
pid_t childpid;
char buff[5];
char * data = "learning to the exam";
printf("father pid %d:\n",getpid());
printf ("size of data is %d \n",(int)sizeof(argv[1]));
printf ("size of buff is %d \n",(int)sizeof(buff));
piperes = pipe(fd);
if(piperes < 0){
perror("PIPE ERR");
exit(1);
}
printf("Pipe succeed \n");
if((childpid = fork()) == -1){ // fork will create a child process
perror("FORK ERR");
exit(1);
}
// when fork suceed - the pid of the child will return in the parent and 0 will return in the child
// when fork fail - the pid will be -1
printf("Fork succeed, fork return is %d and process pid is %d :\n",childpid,getpid());
if(childpid == 0){ // if pid zero , wer in the child prcs
close(fd[0]);
write(fd[1],argv[1],sizeof(argv[1])); // send data to the write fd of the pipe
printf("data was written to fd[1] by pid : %d \n",getpid());
exit(0);
}
else{ // in this case, we're in the father process
close(fd[1]);
read(fd[0],buff,sizeof(argv[1])+1);
printf("Recived data is ''%s''", buff);
printf("By pid : %d \n",getpid());
exit(1);
}
}
sizeof(argv[1])
This does not do what you think it does.
sizeof is evaluated at compile-time1, and in this case will return 8 (assuming you're on a 64-bit machine), because argv[1] is a pointer.
Because you want the length of the string (which can only be known at run-time), you should instead use:
strlen(argv[1])
1 - There are cases where sizeof is evaluated at run-time. This is not one of them.
Related
I want to create n child processes by fork () inside a for loop, and treat the child processes later once they have all been created.The child processes must be treated once the
execution of the parent process has been carried out.
int main(int argc, char *argv[])
{
char cadena[STRLONG];
pid_t pid;
for(int i =0; i<5; i++){
pid = fork();
if(pid == -1){
perror("Error\n");
exit(-1);
}
else if(pid == 0){
break;
}
}
if (pid > 0){
printf("I'm the parent, --> %d\n", getpid());
}
else if(pid == 0){
printf("I'm the child --> %d \n", getpid());
exit(0);
}
for(int i = 0; i<5; i++){
wait(NULL);
}
}
This is what I have done, but the child processes are executed before they are all created and I don't know how to solve it ...
When you fork(), the parent and child process will run in parallel immediately from the place where you fork().
time parent child
| |
| |
| fork()--------+
| | |
V | |
There is no way of telling which one of them that does something before the other - unless you synchronize their actions in some way.
To do proper synchronization between processes you can use semaphores or some other interprocess communication technique. For this simple case, you could use the old self-pipe trick.
Create a pipe
When a child is created, close the writing end of the pipe in the child - and try reading a byte from the pipe. This will hang until there is a byte or the pipe is closed.
When all children have been created, close the reading end in the parent.
The state at this point should be:
The parent only has the write end of the pipe open.
All the children only have the read end of the pipe open, eagerly waiting for something to happen in the pipe.
When the parent want all the children to start working, close the write end of the pipe in the parent. This will cause the read operation in all the children to unblock.
There's no error checking in this below, but it'll show the idea:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
enum { P_RD, P_WR }; // pipe indices, 0 and 1
int main() {
pid_t pid;
int pip[2];
pipe(pip); // create a pipe from pip[P_WR] to pip[P_RD]
for(int i = 0; i < 5; i++) {
pid = fork();
if(pid == -1) {
perror("Error\n");
exit(1);
} else if(pid == 0) {
close(pip[P_WR]); // close write end of pipe
char ch; // dummy buffer
read(pip[P_RD], &ch, 1); // hang here until closed
close(pip[P_RD]); // close read end of pipe
printf("I'm the child --> %d \n", getpid());
exit(0);
}
}
close(pip[P_RD]); // close read end of pipe
// The state at this point:
// * The parent only has the write end of the pipe open.
// * All the children only have the read end of the pipe open.
printf("I'm the parent --> %d\n", getpid());
close(pip[P_WR]); // close write end of pipe to start children
int wstatus;
while((pid = wait(&wstatus)) != -1) {
printf("%d died\n", pid);
}
}
There are already multiple answers to this question but none of them have been able to help me solve my problem. I am trying to understand IPC using an anonymous pipe in C.
From my understanding of pipes, they are a one way communication channel with one read end and one write end.
Assuming we have two c files one named parent.c and the other child.c. What I am trying to achieve is to be able to create 5 or more child processes. After this the parent and the child should communicate with the child processes through standard input and standard output, but since I want to be able to print what the parent receives from the child I'll instead tie the pipes to standard error output using dup2.
In summary
1. Run a parent program which spins up 5 or more child processes and runs them.
2. The child process waits for an input from the parent using scanf.
3. The parent sends a message to the child process.
4. The child process receives the message and sends a reply to the parent and exits.
5. The parent process prints the received message and prints it then exits.
parent.c
// Parentc
#include <stdio.h>
#include <stdlib.h>
#include <uinstd.h>
#include <sys/types.h>
#include <sys/wait.h>
int main(int argc, const char *argv[]){
// File descriptors for the pipes
int read_pipe[2]; // From child to parent
int write_pipe[2]; // From parent to child
pid_t process_id;
int exit_status;
// Try to fork 5 child processes
for(int i = 0; i < 5; i++){
if(pipe(write_pipe) == -1 || pipe(read_pipe) == -1){
perror("Pipe");
exit(1);
}
// Spin a child process
process_id = fork();
if(process_id == -1){
perror("Fork");
exit(1);
} else if(processId == 0) {
// The child process
// I don't know what to do here, The idea is to close the
// unneeded end of the pipes and wait for input from the parent
// process
// Start the ./child
execl("./child", "");
} else {
// The parent process
char recieved_data[1024];
// Send data to child since stderr is duplicated in the pipe
// It sends the pid of the child
fprintf(stderr, "Test data to %d ", process_id);
// Wait to recieve data from child
// Don't know how to do that
// Print the recieved data
printf("Parent recieved: \"%s\"\n", recieved_data);
wait(&exit_status); // Will wait till all children exit before exiting
}
}
return 0;
}
The child.c is a simple program as shown below
child.c
#include <stdio.h>
int main(int argc, const char *argv[]){
char data_buffer[1024];
// Wait for input from parent
scanf("%s", data_buffer);
// Send data back to parent
printf("Child process: %s", data_buffer);
return 0;
}
Expected output
$ ./parent
parent recived: "Child process: Test data to 12345"
parent recived: "Child process: Test data to 12346"
parent recived: "Child process: Test data to 12347"
parent recived: "Child process: Test data to 12348"
parent recived: "Child process: Test data to 12349"
Where 12345, 12346....12349 is the process id of the child process
Here you have a code i did, and i will use to explain to you:
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>
int main() {
char buff[1024];
int aux, i, count;
int fds[2], fdss[2];
pipe(fds); //Here we initialize the file descriptors
pipe(fdss);
mode_t fd_mode = S_IRWXU;
for (i = 0; i < 3; i++) {
aux = fork();
if (aux == 0)
break;
}
switch (i) {
case 0:
printf("Write something:\n");
scanf("%s[^\n]", buff);
i = 0;
count = 0;
while(buff[i] != '\0') {
count++;
i++;
}
dup2(fds[1], 1);
close(fds[1]);
close(fds[0]);
close(fdss[0]);
close(fdss[1]);
write (1, buff, sizeof(buff));
break;
case 1:
dup2(fds[0], 0);
dup2(fdss[1], 1);
close(fds[0]);
close(fds[1]);
close(fdss[0]);
close(fdss[1]);
//
if (execl("/bin/grep", "grep", "example", NULL) == -1) {
printf("Error\n");
exit (1);
}
break;
case 2:
aux = open("result.txt", O_RDWR | O_CREAT , S_IRWXU);
dup2(fdss[0], 0);
dup2(aux, 1);
close(fds[0]);
close(fds[1]);
close(fdss[0]);
close(fdss[1]);
close(aux);
if (execl("/usr/bin/wc", "wc", "-l", NULL) == -1) {
printf("Error \n");
exit (1);
}
}
close(fds[0]);
close(fds[1]);
close(fdss[0]);
close(fdss[1]);
for (i = 0; i < 3; i++) wait(NULL);
return 0;
}
Ok, let's start:
We create and initialize pipes with pipe()
Then we write our code and before execl() we change the file descriptors, in order to pass the text we will write in the console, through processes and finally write in a file called result.txt the result of the "grep example" command applied to the text we have written.
The function dup2(new_descriptor, old_descriptor) is copying the new descriptor into the old descriptor and closes the old descriptor. For example:
Before dup2(fds[1], 1) we have:
0 STDIN
1 STDOUT
2 STDERR
After dup2(fds[1], 1) we have:
0 STDIN
1 fds[1]
2 STDERR
NOTE: If you don't want to use 1, yo can simply write STDOUT_FILENO
So now we are able to write through processes and in my example to a file too
I want to do a program that first creates 3 processes (A) and later, creates one process more (B) and these first processes must write in a pipe that the last process read each time that process write.
I tried something but I don't know the way to do that because the process (B) is created after the processes (A)
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_CHILDREN 3
int main(int argc, char *argv[])
{
pid_t pid;
int fd[2];
char buffer[100];
char str[] = "Hello";
char str2[] = "Hello2";
char str3[] = "Hello3";
for(int num_process = 0; num_process < MAX_CHILDREN; num_process++)
{
if(pipe(fd) == -1)
{
perror( "pipe Failed" );
continue;
}
pid = fork();
if(pid < 0)
{
perror("fork failed");
exit(1);
}
if(pid == 0)
{ //child code
if(num_process == 0){
printf("Child %i (pid= %i) send string %s\n", num_process, getpid(),str);
write(fd[1],str,strlen(str));
}
if(num_process == 1){
printf("Child %i (pid= %i) send string %s\n", num_process, getpid(),str2);
write(fd[1],str2,strlen(str2));
}
if(num_process == 2){
printf("Child %i (pid= %i) send string %s\n", num_process, getpid(),str3);
write(fd[1],str3,strlen(str3));
}
exit(0);
}
else{//parent
printf("Im parent %i\n",getpid());
wait(NULL);
}
}
//Creating another child process from parent, this process recieves string sent from
//childs
pid = fork();
if(pid < 0)
{
perror("fork failed");
exit(1);
}
if(pid == 0){//child
printf("The new process %i read fd pipe\n",getpid());
if( read(fd[0],buffer,sizeof(buffer)) <= 0) //read pipe
{
perror("error read");
exit( EXIT_FAILURE );
}
printf("String readed : %s\n",buffer);
}
else{//parent
wait(NULL);
}
return 0;
}
You need to make a number of changes to the code. The parent shouldn't really wait on its children until after they're all launched. Since you create a new pipe for each of the first three children, you need to keep track of which file descriptors are in use. You should use arrays for that, and for the strings to be sent. Neither the read() nor the write() system calls null-terminates strings, and you don't tell it to write a null byte at the end, so you need to tell printf() to print the correct information.
Those changes and sundry others lead to:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#define MAX_CHILDREN 3
int main(void)
{
pid_t pid;
int fd[MAX_CHILDREN][2];
char buffer[100];
const char *str[MAX_CHILDREN] = { "Hello 1", "Hello 2", "Hello 3" };
for (int i = 0; i < MAX_CHILDREN; i++)
{
if (pipe(fd[i]) == -1)
{
perror("pipe Failed");
exit(1);
}
pid = fork();
if (pid < 0)
{
perror("fork failed");
exit(1);
}
if (pid == 0)
{
printf("Child %i (pid= %i) send string %s\n", i + 1, getpid(), str[i]);
write(fd[i][1], str[i], strlen(str[i]));
exit(i + 1);
}
}
pid = fork();
if (pid < 0)
{
perror("fork failed");
exit(1);
}
if (pid == 0)
{
printf("The new process %i read fd pipe\n", getpid());
for (int i = MAX_CHILDREN; i-- > 0; )
{
int nbytes;
if ((nbytes = read(fd[i][0], buffer, sizeof(buffer))) <= 0)
{
perror("error read");
exit(EXIT_FAILURE);
}
printf("String read: %.*s\n", nbytes, buffer);
}
exit(4);
}
int corpse;
int status;
while ((corpse = wait(&status)) >= 0)
printf("child %d exited with status 0x%.4X\n", corpse, status);
return 0;
}
When run, the output might be:
Child 1 (pid= 91027) send string Hello 1
Child 2 (pid= 91028) send string Hello 2
Child 3 (pid= 91029) send string Hello 3
The new process 91030 read fd pipe
String read: Hello 3
String read: Hello 2
String read: Hello 1
child 91027 exited with status 0x0100
child 91028 exited with status 0x0200
child 91029 exited with status 0x0300
child 91030 exited with status 0x0400
I reversed the order of the elements in the reading loop, mainly just for fun. You can use a conventional for (int i = 0; i < MAX_CHILDREN; i++) loop instead if you prefer.
Although it isn't crucial in this program, you aren't closing enough file descriptors in the children or the parent. The parent should close the write ends of the pipes; it isn't going to be using them. The children should close the read ends of the pipes; they aren't going to be using them. Further, the second and third children should close the pipes opened for the first, and the third should close the pipe for the second, as they aren't going to use those, either. If you don't do this and the fourth child looped waiting for EOF (0 bytes returned), it would hang.
Rule of thumb: If you
dup2()
one end of a pipe to standard input or standard output, close both of the
original file descriptors returned by
pipe()
as soon as possible.
In particular, you should close them before using any of the
exec*()
family of functions.
The rule also applies if you duplicate the descriptors with either
dup()
or
fcntl()
with F_DUPFD
Note that an alternative design for the program would create a single pipe outside the loop and the children would all write to the same pipe. You'd probably want to add a newline to the message strings so that the results are separate. You'd definitely want to think about looping the read in the fourth child, and you'd need to worry about the pipe being closed properly, and so on. It'd be a worthwhile sub-exercise to code that.
The program i am trying to write is trying to demonstrate how IPC works on Linux, but i keep getting a core dump error. It compiles fine and will run up until the last output statement in the parent process.
My code is as follows:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/wait.h>
#include <err.h>
#include <sysexits.h>
#include <sys/shm.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <string.h>
#define SHM_SIZE 15
int main (int argc, char ** argv[]) {
pid_t pid; //pid variable of type pid
int shmid; //shared memory id
int key = 1776; //randomly chosen key
char *shm; //shared memory name
int pipefd[2];
char buff;
pid = fork(); //creating child process
pipe(pipefd); //creating pipe
if (pid < 0) {
fprintf(stderr, "Fork Failed");
return -1;
} else if (pid == 0) {
shmid = shmget(key, SHM_SIZE, 0);
shm = shmat(shmid, 0, 0);
char *n = (char *) shm;
printf("hello i am the child process. my pid is %d. what is your name?: ", getpid());
scanf("%s", n);
printf("\n");
///////////////////////////////////////////////////////////////////////////////////////
close(pipefd[1]);
printf("pipe opened on child end");
printf("\n");
while(read(pipefd[0], &buff, 1) > 0) {
write(1, &buff, 1);
}
write(1, "\n", 1);
close(pipefd[0]);
printf("pipe successfully closed");
printf("\n");
exit(EXIT_SUCCESS);
} else {
shmid = shmget(key, SHM_SIZE, 0777 | IPC_CREAT);
shm = shmat(shmid, 0, 0);
wait(NULL);
printf("\nThis is Child's Parent. My pid is %d. Nice to me you %s.\n", getpid(), shm);
printf("\n");
//////////////////////////////////////////////////////////////////////////////////////
close(pipefd[0]);
printf("pipe open on parent end");
printf("\n");
write(pipefd[1], argv[1], strlen(argv[1]));
close(pipefd[1]);
printf("pipe successfully closed");
wait(NULL);
exit(EXIT_SUCCESS);
}
return 0;
}
Does it have something to do with my args[]? Such as could i be accessing memory out of reach? Or am trying to access some invalid pointer?
Many Thanks!
You have several problems in your code
Create the pipe before the fork. You create the pipe twice, once for
the parent process and one for the child process. That makes no sense, the pipe
that the child created cannot be used by the parent. The pipe must already
exists so that the child inherits the file descriptors when the child is
created.
Usually the parent creates the shared memory and the child gets the shmid
from the parent when it does the fork. Otherwise you will have to synchronize
the child and parent. So I would put the creation of the shared memory before
the fork, so that the child inherits the shmid from the parent.
In the line char *n = (char *) shm; the cast is not needed, shm is
already a char*.
In the parent block after the fork, you do wait(NULL); and then proceed to
write into the pipe. That makes no sense and you block both parent and child.
The child blocks on read because the parent hasn't send anything through the
pipe, yet. And the parent blocks on wait, because the child never exits and thus
cannot send anything through the pipe. The parent must first send data
through the pipe, then wait for the child to exit.
In the child block you do scanf("%s", n);, you are not protecting you
against buffer overflows. scanf("%14s", n) would be better. Also you are not
checking if scanf read anything at all. If the user presses
CtrlD then stdin is closed, scanf fails. In that case
n might not be '\0'-terminated and this would lead to undefined behaviour
when the parent tries to print it. So it would be better:
if(scanf("%14s", n) != 1) // avoid buffer overflow
{
fprintf(stderr, "Child: cannot read from stdin\n");
n[0] = 0; // 0-terminating
}
In the parent block after the fork, you do wait twice, why?
Your main is wrong, it should be
int main(int argc, char **argv);
The parent sends the contents of argv[1] to the child through the pipe, but
you fail to check if argv[1] is not NULL. Use this at the start of the
program:
if(argc != 2)
{
fprintf(stderr, "usage: %s string\n", argv[0]);
return 1;
}
So the correct version would be:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/wait.h>
#include <err.h>
#include <sysexits.h>
#include <sys/shm.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <string.h>
#define SHM_SIZE 15
int main (int argc, char **argv) {
pid_t pid; //pid variable of type pid
int shmid; //shared memory id
char *shm; //shared memory name
if(argc != 2)
{
fprintf(stderr, "usage: %s string\n", argv[0]);
return 1;
}
int pipefd[2];
char buff;
// create shared memory before the fork,
// otherwise you will need to syncronize parent
// and child
pipe(pipefd); //creating pipe before the fork
// parent creates shared memory, child inherits shmid
// after fork
shmid = shmget(IPC_PRIVATE, SHM_SIZE, IPC_CREAT | 0666);
pid = fork(); //creating child process
if (pid < 0) {
fprintf(stderr, "Fork Failed");
return 1; // return -1 would be the same as return 255
} else if (pid == 0) {
shm = shmat(shmid, 0, 0);
char *n = shm; // shm is already a char*
printf("hello i am the child process. my pid is %d. what is your name?: ", getpid());
if(scanf("%14s", n) != 1) // avoid buffer overflow
{
fprintf(stderr, "Child: cannot read from stdin\n");
n[0] = 0; // 0-terminating
}
printf("\n");
///////////////////////////////////////////////////////////////////////////////////////
close(pipefd[1]);
printf("pipe opened on child end");
printf("\n");
printf("Parent sends: ");
fflush(stdout);
while(read(pipefd[0], &buff, 1) > 0) {
write(1, &buff, 1);
}
write(1, "\n", 1);
close(pipefd[0]);
printf("pipe successfully closed");
printf("\n");
exit(EXIT_SUCCESS);
} else {
shm = shmat(shmid, 0, 0);
close(pipefd[0]);
printf("pipe open on parent end");
printf("\n");
write(pipefd[1], argv[1], strlen(argv[1]));
close(pipefd[1]);
printf("pipe successfully closed");
// not we wait for child to exit
wait(NULL);
printf("\nThis is Child's Parent. My pid is %d. Nice to me you %s.\n", getpid(), shm);
printf("\n");
//////////////////////////////////////////////////////////////////////////////////////
exit(EXIT_SUCCESS);
}
return 0;
}
And the output is:
$ ./b "message to child: stop playing video games!"
pipe open on parent end
hello i am the child process. my pid is 10969. what is your name?: Pablo
pipe opened on child end
Parent sends: message to child: stop playing video games!
pipe successfully closed
pipe successfully closed
This is Child's Parent. My pid is 10968. Nice to me you Pablo.
You are reading and writing from the same end of the pipe you create. Common practice is to read from end [1] and write to end [0]. Tell me if that helps. Additionally, it is also common practice to not have too much going on between the child and parent processes. Attempting to execute code in between segments (parent and child) usually ends up with a segmentation fault, even if your code compiles.
I want to create a IPC c program to create one parent and two child's processes. My code is:
#include <stdio.h>
void main()
{
int pid, status;
pid = fork();
if(pid == -1) {
printf(“fork failed\n”);
exit(1);
}
if(pid == 0) { /* Child */
if (execlp(“/bin/ls”, “ls”, NULL)< 0) {
printf(“exec failed\n”);
exit(1);
}
}
else { /* Parent */
wait(&status);
printf(“Well done kid!\n”);
exit(0);
}
}
I want to show you an other code snippet to create one parent and two child process. This is what I am looking for. Now I want to write shell script for IPC, first take look of this code.
Note: there is an other code with same logic but different process names UP, uc1, uc2 e.g in this way we have two parent VP and UC and there childs vp1 vp2 and uc1 uc2.
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <unistd.h>
#define MAX_BUF 1024
int main(){
int mypipe_c1[2];
int ret_c1;
char buf_c1[6];
ret_c1 =pipe(mypipe_c1);
int mypipe_c2[2];
int ret_c2;
char buf_c2[6];
ret_c2 =pipe(mypipe_c2);
if(ret_c1 == -1)
{
perror("pipe");
exit(1);
}
pid_t vc1;
pid_t vc2;
vc1 = fork ();
if (vc1 == 0)
{
read(mypipe_c1[0], buf_c1 , 37);
printf("PIPE1 :%s\n", buf_c1);
printf (" vc1 : I'm the child! My pid is (%d)\n", getpid ());
close(ret_c1);
int fd;
char * fifo1 = "/tmp/fifo1";
char buf[MAX_BUF];
/* open, read, and display the message from the FIFO */
fd = open(fifo1, O_RDONLY);
read(fd, buf, MAX_BUF);
printf("FIFO1: %s\n", buf);
close(fd);
exit(0);
}
if(vc1 < 0)
{
perror ("Ouch! Unable to fork() child process!\n");
exit (1);
}
vc2 = fork ();
if (vc2 == 0)
{
printf ("vc2 : I'm the child! My pid is (%d)\n", getpid ());
read(mypipe_c2[0], buf_c2 , 37);
printf("PIPE2 %s\n", buf_c2);
int fd;
char * fifo2 = "/tmp/fifo2";
/* create the FIFO (named pipe) */
mkfifo(fifo2, 0666);
/* write "Hi" to the FIFO */
fd = open(fifo2, O_WRONLY);
write(fd, " assignment VU 2 ", sizeof(" assignment VU 2 "));
close(fd);
/* remove the FIFO */
unlink(fifo2);
exit(0);
}
else if (vc2 < 0)
{
perror ("Ouch! Unable to fork() child process!\n");
exit (1);
}
printf ("I'm the parent! My pid is (%d)!\n",getpid());
write(mypipe_c1[1], "I am going to close you carry on UC1 \n", 37);
write(mypipe_c2[1], "I am going to close you carry on UC2 \n", 37);
exit(0);
}
Now I want shell script such that VP and UP should be started when users types … script.sh start VP or UP. vc1, vc2, uc1,uc2 should be stoppable only using script.sh stop vc1 or vc2 or uc1 or uc2
script.sh connect command should create two fifo and connect processes as shown in figure.
So you are asking for methods for IPC, with the sample code you provided, I think the best one is the use of pipes.
From the pipe() man page:
A pipe is a unidirectional data channel that can be used for interprocess communication
Basically, it is handled like a pair of file descriptors. First, you must init the pipe, and then create the childs using the fork() call, so both parents and childs share the resource. Then, using write and read methods, you can send data between them.
In this example I create a child which reads some data from the parent process:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main() {
int pid;
char buffer[255];
int fd[2]; // channel 0 for reading and 1 for writing
pipe(fd);
pid = fork();
if(pid == 0) {
close(fd[1]); // close fd[1] since child will only read
read(fd[0], &buffer, sizeof(buffer));
close(fd[0]);
exit(0);
} else { // parent
close(fd[0]) // close fd[0] since parent will only write
// init buffer contents
write(fd[1], &buffer, sizeof(buffer));
close(fd[1]);
}
return 0;
}
As you can see pipe creates a pair of file descriptors, one for writing (number 1) and one for reading (number 0).
In my sample code, the child process closes the writing one, since it will only read, and the parent closes the reading one, since it will only write data.
Note that pipes are unidirectional, so if you want that both the childs and the parent write and read data from it, you should create two pipes (so 4 file descriptors) for each of the childs. An example of how to handle that situation:
int pipeA[2], pipeB[2];
pid = fork();
if (pid == 0) { // child will write to pipeB and read from pipeA
close(pipeA[1]); // closing pipeA writing fd
close(pipeB[0]); // closing pipeB reading fd
write(pipeB[1],&buffer, sizeof(buffer));
read(pipeA[0], &buffer2, sizeof(buffer2));
close(pipeA[0]);
close(pipeB[1]);
exit(1);
} else { // parent will write to pipeA and read from pipeB
close(pipeA[0]); // closing pipeA reading fd
close(pipeB[1]); // closing pipeB writing fd
read(pipeB[0], &buffer, sizeof(buffer));
write(pipeA[1], &buffer2, sizeof(buffer2));
close(pipeA[1]);
close(pipeB[0]);
}
If you want more info about pipes you can check the man page here.
Also, other simple ways of IPC would be the use of Unix Sockets, although I think that for the example you presented pipes will be enough.
You'r code create one parent and one child, not two child, so you need to add another fork into child block :
#include <stdio.h>
void main()
{
int pid,status;
pid = fork();
if(pid == -1) {
printf(“fork failed\n”);
exit(1);
}
if(pid == 0) { /* Child */
fork();// another child
if (execlp(“/bin/ls”, “ls”, NULL)< 0) {
printf(“exec failed\n”);
exit(1);
}
}
else { /* Parent */
wait(&status);
printf(“Well done kid!\n”);
exit(0);
}
}