C double pointer realloc error - c

hello friends :) i'm practicing C programming. in this program i have a task to make array of string. i have no idea what's wrong here...probably something about realloc, error i get is _crtisvalidheappointer
#define _CRT_SECURE_NO_WARNINGS
#define MAX 100
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void readString(char **s)
{
int i = 0;
char c;
printf("\nInput string: ");
while ((c = getchar()) != '\n')
{
i++;
*s = realloc(*s, i*sizeof(char*));
if (*s == NULL) { printf("Memory allocation failed!"); exit(1); }
(*s)[i - 1] = c;
}
*s = realloc(*s, (i + 1)*sizeof(char));
if (*s == NULL) { printf("Memory allocation failed!"); exit(1); }
(*s)[i] = '\0';
}
char **load_words()
{
int cnt=0,wordcnt=0,i=0;
char **words = NULL, *input = NULL;
readString(&input);
while (input[cnt] != '\0' && cnt < strlen(input))
{
words = realloc(words, ++wordcnt);//errors in second repeat of the loop
words[wordcnt] = malloc(MAX);
i = 0;
while (input[cnt] != ' ')
{
words[wordcnt][i++] = input[cnt++];
}
words[wordcnt][i] = '\0';
realloc(words[wordcnt], (i + 1)*sizeof(char));
}
realloc(words, wordcnt);
free(input);
return words;
}
void main()
{
int i;
char **words = NULL;
words = load_words();
scanf("%d", &i);
}
can someone help me and tell me what did i do wrong here? this function should return array of strings but array should be double pointer(string matrix)

You need to change
words = realloc(words, ++wordcnt);
to
words = realloc(words, ++wordcnt * sizeof(*words));
Otherwise you are not allocating enough memory.
words[wordcnt] = malloc(MAX);
This also is not correct, you should access words[wordcnt-1].

You are using realloc but you're not saving its return value anywhere. This means the pointers you have still point to the memory that was freed and the newly allocated memory is leaked.
Look at the working function and you'll see how to use it properly.

One thing to realize when reallocating a double-pointer is that the size of type to realloc is always the sizeof (a pointer). It will be the same on any given system no matter the data type at issue. You can generically reallocate a double-pointer as follows:
/** realloc array of pointers ('memptr') to twice current
* number of pointer ('*nptrs'). Note: 'nptrs' is a pointer
* to the current number so that its updated value is preserved.
* no pointer size is required as it is known (simply the size
* of a pointer)
*/
void *xrealloc_dp (void *ptr, size_t *n)
{
void **p = ptr;
void *tmp = realloc (p, 2 * *n * sizeof tmp);
if (!tmp) {
fprintf (stderr, "xrealloc_dp() error: virtual memory exhausted.\n");
exit (EXIT_FAILURE); /* or break; to use existing data */
}
p = tmp;
memset (p + *n, 0, *n * sizeof tmp); /* set new pointers NULL */
*n *= 2;
return p;
}
note: the memset call is optional, but useful if you have initialized all non-assigned pointers to NULL (such as when using NULL as a sentinel)
note2: you are free to pass a parameter setting the exact number of pointers to increase (elements to add) or change the multiplier for the current allocation as needed for your code.

Related

memory corruption when manipulating a long string

I am writing a program to print out any line input that is longer than 3.
It works for some fairly long input lines, but for the string that is too long, I got a error message of memory corruption
*** Error in `./print-80': malloc(): memory corruption (fast): 0x00000000022ff030 ***
I don't know where the error is from. Can anyone explain me why there is the error and how to fix it?
Below is the program
#include <stdio.h>
#include <stdlib.h>
#define LIMIT 3
#define LEAST_LENGTH 3
//function prototype
void copy(char* from, char* to);
int getline(char* s, int capacity);
int increase_capacity(char* s, int capacity);
int main(void)
{
int length, i;
char* line = calloc(LIMIT, sizeof(char));
while ((length = getline(line, LIMIT)) > 0)
{
if (length > LEAST_LENGTH)
printf("Output: %s\n", line);
//reset the line
for (i = 0; i < length; i++)
*(line + i) = 0;
}
free(line);
return 0;
}
int getline(char* line, int capacity)
{
int c, length;
length = 0;
while ((c = getchar()) != EOF && c != '\n')
{
if (length > (capacity - 1))
{
capacity = increase_capacity(line, capacity);
printf("Address of line after increasing cap: %p\n", line);
}
line[length++] = c;
}
if (c == '\n')
line[length++] = '\0';
return length;
}
int increase_capacity(char* s, int capacity)
{
int i;
capacity *= 2;
char *new_s = calloc(capacity, sizeof(char));
copy(s, new_s);
s = new_s;
free(new_s);
return capacity;
}
void copy(char* from, char* to)
{
int i = 0;
while ((to[i] = from[i]) != '\0')
++i;
}
Your increase_capacity function can change the address at which the data is stored. But it doesn't return this information to its caller. So getline will write to the old buffer address. Similarly, main has no way to get the new address, so it will access the old address and free a block that may already be freed.
Also, your increase_capacity function allocates memory to hold the data and then frees that memory. That leaves no place to hold the data!
int increase_capacity(char* s, int capacity)
{
int i;
capacity *= 2;
char *new_s = calloc(capacity, sizeof(char)); // allocate a larger block
copy(s, new_s); // copy the data into the larger block
s = new_s; // stash a pointer to the larger block in a local
free(new_s); // free the block?!
return capacity;
}
So we allocate a new block, copy the data into it, and then free it. That makes no sense, we need to keep the larger block since that's the whole point of a function to increase capacity. We also don't return the address of the new block, so even if we didn't free it, no other code could access it and we'd just wind up leaking it. Double oops.
I suggest you create a struct that holds both the pointer to the block and its size. Pass a pointer to that struct to functions like increase_capacity so it can modify the pointer and the size in the structure and callers can see the changes.

Reprogramming Calloc / Realloc in C Using void pointers

I'm actually learning C programming and my school actually doesn't allow us to use calloc / realloc without reprogramming them. That's why I'm asking for help.
Here is my problem :
I want to use void * to make my code reusable but I encounter the problem "dereferencing void * pointer" when I try to run through my array. I'm unable to pick up the type of the final pointer.
Here is my functions :
#include <stdlib.h>
void *my_calloc(size_t size, size_t n) //n = number of bytes your type : sizeof(<whatever>)
{
void *ptr = NULL;
if (size < 1 || n < 1)
return (NULL);
ptr = malloc(n * (size + 1));
if (ptr == NULL)
return (NULL);
for (int i = 0; i != (n * (size + 1)); i++) {
*ptr = NULL; //Here is my problem
ptr++;
}
return (ptr);
}
void *my_realloc(void *src, size_t size, size_t n)
{
void *dst = NULL;
int dst_len = 0;
if (src == NULL || size < 0 || n < 1)
return (NULL);
dst_len = my_strlen(src) + size;
if (dst_len == my_strlen(src))
return (src);
dst = my_calloc(dst_len, n);
if (dst == NULL)
return (NULL);
for (int i = 0; src[i] != NULL;i++)
dst[i] = src[i]; //Here is the same problem...
free(src);
return (dst);
}
I just find a problem while I was writing my post, my my_strlen function can only take a char *... so I would need a function my_strlen looking like :
int my_strlen(void *str)
{
int len = 0;
while (str[len] != NULL) { //same problem again...
len++;
}
return (len);
}
A typical function where i call calloc / malloc would be :
int main(void)
{
char *foo = NULL;
int size = 0;
int size_to_add = 0;
size = <any size>;
//free(foo); //only if foo has been malloc before
foo = my_calloc(size, typeof(*foo));
//something
size_to_add = <any size>;
foo = my_realloc(foo, size_to_add, sizeof(*foo))
//something
free(foo);
return (0);
}
Thank you for trying to help me.
my_calloc() has various troubles:
Attemptted pointer math on a void *
This is undefined behavior (UB).
Instead make ptr a character pointer.
// void *ptr = NULL;
unsigned char *ptr = NULL;
...
ptr++;
Attempt to de-reference a void *
This is also UB.
Instead make ptr a character pointer.
// void *ptr = NULL;
unsigned char *ptr = NULL;
...
// *ptr = NULL;
*ptr = '\0';
my_calloc() allocates more memory than calloc()
To do the same as calloc(), do not add one.
// ptr = malloc(n * (size + 1));
ptr = malloc(n * size);
No overflow protection
my_calloc() does not detect overflow with n * (size + 1). A test is
// Note: it is known n > 0 at this point
if (SIZE_MAX/n > size+1) return NULL;
// or if OP drop the + 1 idea,
if (SIZE_MAX/n > size) return NULL;
my_realloc() has various troubles:
Different signature
I'd expect the goal of "school actually doesn't allow us to use calloc / realloc without reprogramming them" was meant to create a realloc() substitute of which my_realloc() is not. If a different function is desired, consider a new name
void *my_realloc(void *src, size_t size, size_t n)
// does not match
void *realloc(void *ptr, size_t size);
Failure to handle a shrinking allocation
The copying of data does not take into account that the new allocation may be smaller than the prior one. This leads to UB.
Unneeded code
size < 0 is always false
Memory leak
The below code does not free src before returning. Further, it does not allocate anything when n>0. This differs from calloc(pit, 0) and calloc(NULL, 42).
// missing free, no allocation
if (src == NULL || size < 0 || n < 1) {
return (NULL);
}
Assumed string
my_strlen(src) assume src points to a valid string. calloc() does not assume that.
void is an incomplete type, so you can't dereference a void *. What you can do however is cast it to a char * or unsigned char * to access individual bytes.
So my_calloc can do this:
((char *)ptr)[i] = 0;
And my_realloc can do this:
((char *)dst)[i] = ((char *)src)[i];

Adding string to array, pointer being realloc'd was not allocated

I am trying implement a method that adds a given string to an array that ends with a NULL pointer. This is what I have so far but I am getting an error saying that the pointer being realloc'd was not allocated.
int main(void)
{
char **strings = init_array();
strings = add_string(strings, "one");
strings = add_string(strings, "two");
return 1;
}
char **init_array(void)
{
char **array = malloc(sizeof(char *));
array[0] = NULL;
return array;
}
char **add_string(char **array, const char *string)
{
unsigned int size = 0;
while (*array) {
size++;
array++;
}
char **newarr = (char **)realloc(array, sizeof(char *) * (size + 2));
newarr[size] = malloc(strlen(string)+1);
strcpy(newarr[size], string);
newarr[size+1] = NULL;
return newarr;
}
The issue is array++. You have to pass realloc the same value malloc returned (your array argument), but you modify it during the loop, so it'll work only the first time (because *array will immediately false). You could use:
size_t size;
for(size = 0; array[size]; size++);
And leave the rest untouched.
In your while (*array) loop you are incrementing not only the size, but also the array pointer itself. As a result, at the end of the loop size contains the length of the array, and the array pointer points to the last (NULL) element. This pointer was never allocated, (it points within an allocated block,) therefore it is not a valid pointer to reallocate. (And definitely that's not what you intended to do.)
So, just don't do array++ within that loop.
Your loop that calculates the number of strings in the array also advances the variable itself. You could use a temporary variable instead:
char **temp = array;
while (*temp)
...
Or separate the counting into a function.
BTW you don't need a casting when using realloc, for the same reason you don't do the casting with malloc. This is not a bug, but it better be consistent.
Summarizing all other answers given so far, adding some best practise tweaks, the relevant code should look like this:
char **add_string(char **array, const char *string)
{
char ** newarr;
size_t size = 0;
assert (NULL != string); /* Need to include assert.h */
if (NULL != array)
{
while (NULL != array[size])
{
++size; /* Just count, do not touch the pointer value allocated. */
}
}
newarr = realloc(array, (size + 2) * sizeof *newarr);
if (NULL == newarr) /* Test the outcome of reallocation. */
{
perror("realloc() failed"); /* Need to include stdio.h */
return NULL;
}
newarr[size] = malloc(strlen(string) + 1);
if (NULL == newarr[size])
{
perror("malloc() failed"); /* Need to include stdio.h */
/* Might want to clean up here and indicate the failure to the
caller by returning NULL. */
}
else
{
strcpy(newarr[size], string);
}
newarr[size+1] = NULL;
return newarr;
}
Or even tighter:
char **add_string(char **array, const char *string)
{
assert (NULL != string); /* Need to include assert.h */
{
size_t size = 0;
if (NULL != array)
{
while (NULL != array[size])
{
++size; /* Just count, do not touch the pointer value allocated. */
}
}
{
char ** newarr = realloc(array, (size + 2) * sizeof *newarr);
if (NULL == newarr)
{
perror("realloc() failed"); /* Need to include stdio.h */
}
if (NULL != newarr)
{
newarr[size] = malloc(strlen(string) + 1);
if (NULL == newarr[size])
{
perror("malloc() failed"); /* Need to include stdio.h */
}
else
{
strcpy(newarr[size], string);
}
newarr[size+1] = NULL;
}
return newarr;
}
}
}
The easiest way would be to preserve initial array pointer and use it to realloc memory.
int main(void)
{
char **strings = init_array();
strings = add_string(strings, "one");
strings = add_string(strings, "two");
return 1;
}
char **init_array(void)
{
char **array = malloc(sizeof(char *));
array[0] = NULL;
return array;
}
char **add_string(char **array, const char *string)
{
char** cache = array;
unsigned int size = 0;
while (*array) {
size++;
array++;
}
char **newarr = (char **)realloc(cache, sizeof(char *) * (size + 2));
newarr[size] = malloc(strlen(string)+1);
strcpy(newarr[size], string);
newarr[size+1] = NULL;
return newarr;
}
Another note - main function should return 0 on success.

pointer to dynamic array of pointers to dynamic array of pointer that points to strings

i have a problem with the initialization of the values inside the first dynamic array of pointers
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char*** GetIndexes()
{
int n = 0;
char ***index;
printf("please insert the number of words you want to add to dictionary\n");
scanf("%d", &n);
index = (char***)calloc(n, sizeof(char));
if (index == NULL)
{
printf("allocation Failed");
return;
}
return index;
}
char** GetDefinitions()
{
int n = 0;
char **definition;
printf("please insert the number of defintions you want to add to the word\n");
scanf("%d", &n);
definition = (char**)calloc(n+1, sizeof(char));
if (definition == NULL)
{
printf("allocation failed");
return;
}
return definition;
}
int main()
{
char *** dptr = GetIndexes();
if (dptr == NULL)
{
printf("memory Allocation failed");
}
int indexcount = sizeof(dptr) / sizeof(char),i;
for (i = 0; i < indexcount; i++)
{
printf("word number %d\n", i + 1);
*dptr[i] = GetDefinitions();
}
printf("%p",dptr);
}
i tried running the debugger in VS2013 and after i enter the number of defintions i want it crashed with this message:
Unhandled exception at 0x01103FB0 in ConsoleApplication1.exe: 0xC0000005: Access violation writing location 0x00000000.
i missed an allocation of something but i cant quite figure out what i missed,
thanks in advance
Your program is very broken
You allocate n char ***s but only request space for n chars and also do it for char **, to prevent this kind of mistake you may use the sizeof operator this way
char ***index;
index = calloc(n, sizeof(*index));
and
char **definition;
definition = calloc(n, sizeof(*definition));
and as you see casting calloc makes it harder and it's not necessary.
You have a return statement that doesn't return anything an GetIndexes() as well as one in GetDefinitions.
They should return NULL if you want to handle failure in the caller function
return NULL;
You erroneously use the sizeof operator to determine the number of char *** pointer allocated in
int indexcount = sizeof(dptr) / sizeof(char)
this will be either 4 or 8 depending on the architecture i.e. the size of a pointer divided by 1 sizeof(char) == 1 always.
You can't compute that value, you simply have to keep track of it. The size
You dereference the triple pointer twice and try to assign a double pointer to it
*dptr[i] = GetDefinitions();
here the operator precedence is also an issue, but regardless of that, this is wrong, may be what you meant was
dptr[i] = GetDefinitions();
This is not going to make your program crash, but it's certainly important to free all malloced pointers before exiting the program.
Here is a suggestion for your code to work, ignore it's purpose since it's not clear what you are trying to do
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char ***GetIndexes(unsigned int *count)
{
char ***index;
printf("please insert the number of words you want to add to dictionary > ");
scanf("%u", count);
index = calloc(*count, sizeof(*index));
if (index == NULL)
{
printf("allocation Failed");
return NULL;
}
return index;
}
char **GetDefinitions(unsigned int *count)
{
char **definition;
printf("please insert the number of defintions you want to add to the word > ");
scanf("%u", count);
definition = calloc(*count + 1, sizeof(*definition));
if (definition == NULL)
{
printf("allocation failed");
return NULL;
}
return definition;
}
int main()
{
unsigned int indexCount, i;
char ***dptr = GetIndexes(&indexCount);
if (dptr == NULL)
{
printf("memory Allocation failed");
}
for (i = 0; i < indexCount; i++)
{
unsigned int definitionsCount;
printf("Word number %u\n", i + 1);
dptr[i] = GetDefinitions(&definitionsCount);
if (dptr[i] != NULL)
{
/* use dptr[i] here or maybe somewhere else, but when you finish */
free(dptr[i]);
}
}
printf("%p", dptr);
/* now if you are done using dptr */
free(dptr);
return 0;
}
As already mentioned in the comment this is a very bad idea and just using double pointers is good here. But the below fixes should be done if you want to use pointers to allocate memory
index = calloc(n, sizeof(char));
should be
index = calloc(n, sizeof(char **));
and
definition = calloc(n+1, sizeof(char));
should be
definition = calloc(n+1, sizeof(char *));

realloc() invalid nxt size

I use this code, with this structure, im trying to make function to add item into array of this structure
typedef struct goods{
char *name;
int num;
} goods;
void addWord(char *what, goods *where, int pnr, int *arrsize, int n){
if (pnr >= *arrsize){
where = (goods*)realloc(where,*arrsize*2*sizeof(goods*));
*arrsize*=2;
}
where[pnr].name = (char*)malloc(strlen(what)*sizeof(char));
strcpy(where[pnr].name,what);
where[pnr].num = n;
}
in main function i have this:
int extstore = 1;
goods *store = (goods*)malloc(1*sizeof(goods*));
addWord(line, store, nr, &extstore, n);
Why am I getting an "invalid next size" runtime-error on the line where = (goods*)realloc(where,*arrsize*2*sizeof(goods*)); in addWord()?
EDIT:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct goods{
char *name;
int r;
} goods;
int main()
{
int linelen, i, nr = 0, current_r;
char *line = NULL;
size_t len = 0;
int extstore = 1;
goods *store;
store = malloc(extstore*sizeof(goods*));
while (1){
while ((linelen = getline(&line, &len, stdin)) != -1){
if (line[linelen - 1] == '\n'){
line[linelen - 1] = '\0';
}
linelen = strlen(line);
if (line[0] == '#'){
if (sscanf(line,"#%d",&current_r) != 1){
printf("bad input.");
return 0;
} else continue;
}
if (nr >= extstore){
store = realloc(store,extstore * sizeof(goods*) * 2);
extstore*=2;
}
store[nr].name = malloc(strlen(line)*sizeof(char));
strcpy(store[nr].name,line);
store[nr].r = current_r;
nr++;
}
if (linelen == -1) break;
}
printf("\n");
for (i = 0;i < nr;i++){
printf("%s, [id:%d]\n", store[i].name, store[i].r);
}
return 0;
}
extstore * sizeof(goods*) * 2
should be extstore * sizeof(goods) * 2 because the space for structures should be allocated - not just for pointers.
There is a fundamental problem in your code. You are passing pointer by value, which means that any change made to a pointer (not the variable pointed to, but the pointer itself) will not be visible from outside the function. You should pass a pointer by pointer instead, and you should check the result returned from realloc. Secondly, don't assign result of realloc back to same pointer - in case of failure you will lost pointer to memory -> thus, memory leak will occur.
To pass pointer by pointer:
void addWord( char *what, goods **where, size, ...) {
if ( *where == NULL) return; // nothing to do
if ( size < 1) return; // it would result in realloc=free call
goods *res = NULL;
res = realloc( *where, size * sizeof( goods));
if ( res != NULL) {
*where = res;
}
else {
// Error (re)allocating memory
// If realloc() fails the original block is left untouched,
// it is not freed or moved, so here *where is unchanged
}
And there is no need in C to cast a result from malloc.
* Error in `path': realloc(): invalid next size: 0x0000000000ec8010 *
This failure must be because "where" is invalid due to a heap corruption earlier in the execution.
C is pass-by-value.
Which means changing an argument in the function does not change the expression it was initialized from.
Thus, the first time realloc moves the memory, the pointer in main will be bad.
To correct that, either use an extra level of indirection, or preferably return the new value as the result.
(Anyway, you should check for allocation failure (malloc and realloc),
and you should not cast from void* to any pointer-type in C.)

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