How to replace a character in a string using T-SQL - sql-server

Question

In my table column, i have below sample data
Test1 145, Area 1
Test2 146,
Test3 145, Area 2, Plot 10
What i want to achieve is to replace "," in the string but only if it is the last character. If i have more characters after "," then the replace should leave the string as it is.
In the example above, the replace would only work in line 2.
The expected out put would be like below
Test1 145, Area 1
Test2 146
Test3 145, Area 2, Plot 10
In line 2 above, "," has been replaced with empty space.
I have tried this Replace(column1, ', ', '') AS ColName but this replaces all the "," in Test1 and Test3.

Answer 1

You can try this:
DECLARE #value VARCHAR(1024) = 'Test2 146,';
SELECT IIF(RIGHT(#value,1) = ',', LEFT(#value, LEN(#value) - 1), #value);
For column it looks like below:
DECLARE #DataSource TABLE
(
[value] VARCHAR(1024)
);
INSERT INTO #DataSource ([value])
VALUES ('Test1 145, Area 1')
,('Test2 146,')
,('Test3 145, Area 2, Plot 10');
SELECT IIF(RIGHT([value],1) = ',', LEFT([value], LEN([value]) - 1), [value])
FROM #DataSource;

Answer 2

You can also do this will LIKE and IIF :
SELECT IIF(t.Column LIKE '%,' , LEFT(t.column, LEN(t.column) - 1) , t.column) as new_val
FROM YourTable t
For older versions: You can use CASE EXPRESSION since IIF is only available since 2012+ version(Link by #gotqn)
SELECT CASE WHEN t.Column LIKE '%,'
THEN LEFT(t.column, LEN(t.column) - 1)
ELSE t.column
END as new_val
FROM YourTable t

Answer 3

I am pretty sure IIF isn't available in SQL Server 2005. This is basically the same logic as the previous answer using CASE instead.
declare #MyString varchar(50)
set #MyString = 'Test2 146,'
select
case
when right(rtrim(#MyString), 1) = ',' then
substring(#MyString, 1, len(rtrim(#MyString)) - 1)
else
#MyString
end

Answer 4

Something like this:
SELECT CASE
WHEN Column1 LIKE '%,' THEN STUFF(column1, LEN(column1), 1, '')
ELSE Column1
END

Answer 5

This shows one way to do it.
DECLARE #test VARCHAR(30);
SET #test = 'Test1, 145, Area 1';
SELECT #test;
IF CHARINDEX(',', #test, LEN(RTRIM(#test))) > 0
BEGIN
SET #test = Replace(#test, ',', '');
END
SELECT #test;
SET #test = 'Test2 146,';
SELECT #test;
IF CHARINDEX(',', #test, LEN(RTRIM(#test))) > 0
BEGIN
SET #test = Replace(#test, ',', '');
END
SELECT #test;
SET #test = 'Test3 145, Area 2, Plot 10';
SELECT #test;
IF CHARINDEX(',', #test, LEN(RTRIM(#test))) > 0
BEGIN
SET #test = Replace(#test, ',', '');
END
SELECT #test;
-- How to work into a SELECT statement
SET #test = 'Test2 146,';
SELECT CASE WHEN CHARINDEX(',', #test, LEN(RTRIM(#test))) > 0 THEN SUBSTRING(#test, 1, LEN(#test) - 1) ELSE #test END AS 'Converted Value';