How do I extract specific field for display in a taxonomy page?
I have a custom content type called "film" and each film has a Term Reference field called "casting". As expected I can click on a "casting" (tag) it brings me a page where all films are listed wherever this tag is associated. For expample if I click on "Kate Winslet" from movie Titanic, I land on a page http://localhost/mysite/tags/kate-winslet where other movies of Kate Winslet are listed. Up to this point everything is just fine.
I do not want Drupal to pull in and show default fields like just Title and Body in its own display format. Rather I want it so that I can display a photo from each film, year of release and of course the title and trimmed version of the body. I only want to customize the content of this page so that I have the control over What to Show and Where To Show a specific field value.
This is what I tried:
I cloned and put page.tpl.php in my theme's template folder. Renamed it as page--vocabulary--tags.tpl.php. Then I took out the following line of code (<?php print render($page['content']);?>) from my page--vocabulary--tags.tpl.php. The intention was to check whether the overridden template is actually being accessed by Drupal or not. It does!
But I am not been able to extract fields like field_photo or field_release_date from $page['content]. To get an idea about defined variables and how they are placed I used the following line of code:
<pre><?php /*print var_export(get_defined_vars(), TRUE);*/ ?></pre>. But even from there I could not extract a particular field like I mentioned above. The fields look to be somewhere inside $page['content']['system_main']['nodes'], but I don't know how to get to a specific field directly.
I also created a template.php with the following preprocess hook function:
<?php
function introduction_preprocess_page(&$vars) {
if (arg(0) == 'taxonomy' && arg(1) == 'term' && is_numeric(arg(2))) {
$term = taxonomy_term_load(arg(2));
$vars['theme_hook_suggestions'][] = 'page__vocabulary__' . $term->vocabulary_machine_name;
$vars['content'] = $vars['page']['content']['system_main']['nodes'];
}
}
?>
Both <?php print render($content) ?> and <?php print render($page['content']) ?> print the same result but I want something like <?php render($content['photo_field'])?> which I am not been able to.
I am sorry for making this too long. I have just stepped into Drupal. So wanted to make sure that what I am trying to explain matches exactly what I want to accomplish.
You are probably trying the long way to this.
You can use Views module. It allows to create custom listings querying the database, but also override existent ones, like the case of the taxonomy term page listing.
Once you have the module installed (if it's not yet), particularly the Views UI module, go to /admin/structure/views and scroll to bottom, where disabled views (grayed rows) are. You'll find one called Taxonomy term, described as 'A view to emulate Drupal core's handling of taxonomy/term.'
Click Enable on the right of it and then go to the same place where the Enable link is, click the arrow to unfold and choose Edit.
Once you're in the view edit page, you can manipulate the listing at your convenience, adding/removing fields or whatever you want to do in your particular case. If you are not familiar with Views, I recommend you to learn about it, there is a lot of related content on the web and it is close to essential for Drupal development.
Also, if you want to add more customisation to the page, you can use the same approach with the Panels module, who allows to override system pages (not just listings like Views).
Related
I just can't seem to wrap my head around Drupal relationships. I have been reading and watching tutorials, but as soon as I try to get my own project done - I fail. I think it's very basic, so I would love to understand it. Maybe someone here can help me understand how it works :)
On my drupal site, I want to keep track of some private game tournaments.
I have created a content type called contestant, which has fields like: Tournament date, Player name, Final Position. I can then create a view that list the information from one tournament. I used the help I got from this thread: drupal views dynamic filter
I would like to have the view described above as a block. And then place that block-view on a "tournament description" page. I could do this, by simply creating a new block each time, and then manually place it on the page it should be shown (structure-->Blocks-->configure), but that is not an elegant way to do it. I am pretty sure this is where Relationships should be used. But I fail to understand how to create this relationship, so that the specific block view, that matches the specific tournament description page will be displayed together.
Use a Content:Nid as a Contextual filter.
WHEN the Filter value is not in the URL >>
Provide default value
Content ID from URL
I use taxonomy terms to address my menus(these taxonomy terms show the structure of my site) so when I create a view I should use the taxonomy path (instead of alias) for the page setting (the only way that I can link the view to my taxonomy address path as far as I know :P ). whenever I see the page URL I can see the alias. now I'm trying to set up a page that has 2 tabs. I have set it up but the problem is when I click in the tab I see the taxonomy path instead of alias ? (for example taxonomy/term/6/digital instead of CCTV/digital However default menu tab still work correctly and show the alias CCTV)
Is there any way to show the alias instead of taxonomy term address ?
I assume that you have a view that is filtering your taxonomy terms. If you render the results as fields, each field can have it's formatter. If you need a custom form of the output, you can define your own formatter or generate one via GUI with help of: custom formatters.
In case that you render your output as rendered entity, you need to find the right template file and use the drupal_get_path_alias() function within it.
As last I would hint you a great module that also might help you: taxonomy menu
I'm working on a Drupal site an need to implement the following:
I have created an about us page template (page--about.tpl.php) and a custom content type for the about us page and linked the 2 using suggestions. I also have a custom content type for staff profiles that I need to add on the about us page in a tabbed format.
I can't seem to find a way to get the staff content to display in the about us page. I would ideally like it to render it the same manner as blog posts would display in a blog page.
So my question is, what code do I use to render all the nodes of the staff profiles content type in the about template page?
p.s I'm a bit of a Drupal noob, done a lot of reading but come up empty on this one.
If you already created content type About us (that is what i understood from mockup and explanation) then maybe you could use Views with EVA. That will enable you to have view as field in content type.
You can set it up with manage display or print it in template as all other fields. For example:
<?php print render($content['your_view_entity_view_1']); ?>
Other way would be to embed view in template. For example:
<?php print views_embed_view('your_view', 'block'); ?>
You can use the excellent Views module to create a block to list all your staffs.
Then you need to place the block that you had created with the help of view module in about-us page.
The Views module will give you suggestions to about which template to use.
EDIT: After the op provided the following image.
After you create a view to show all the Team member nodes you could simply print the view in your about us specific page template using following code.
$view = views_get_view('view name');
print $view->render('display_id');
Another option to do the same thing is, make blocks for all the content, viz. The Firm, The Team, Awards, Technonogly, Services and use quicktabs to display the content.
Yet another option to show a view as a field for a node is use EVA
Going the quicktabs way you can provide a lot of flexibility of showing teaser in about us page and leading to details about the same. For example each award can be a node in itself.
I have a custom module in DNN 7 that has a data structure where items belong to categories (called "sections", not DNN taxonomy, just a simple list of section names). The module edit screens work so that on the view control you may click on an edit link on each category, which loads the category edit screen (passing the category id). This works great, and when you save I use Globals.NavigateURL() to return to the view screen. This all works as intended.
On each category edit screen I also have a list of the items within that category, each with an edit link. Clicking the edit link opens the item edit screen, passing the correct item id, and allowing me to edit that item. This all works great, until you save. The save works properly, but when I want to send the user back to the edit screen for the category it doesn't work. When I use:
Response.Redirect(EditUrl("SectionId", sectionid.ToString(), "EditSections"), true);
...nothing happens. It simply doesn't redirect anywhere. This is exactly the same URL I'm using to get to the category edit page in the first place:
EditUrl("SectionId", Eval("SectionId").ToString(), "EditSections")
And then I use a similar URL to get to the item edit page:
EditUrl("ItemId", Eval("ItemId").ToString(), "EditItems")
I don't understand why using the same URL to navigate to the same page I already navigated to would simply not do anything. For now I am sending them all the way back to the view, but it's painful if you need to add several items to the same category to have to navigate back into the category and add another item, only to be sent back to the view.
Anyone see anything like this before?
Have you tried to use the overload of NavigateUrl instead of EditUrl?
Globals.NavigateURL(TabId, "EditSections", "mid", ModuleId.ToString(), "SectionId", Eval("SectionId").ToString())
I haven't seen that myself but I would have to assume that somehow the context is being lost with EditURL and you're not getting sent to the proper location due to that.
I would suggest you try one of two things (or both).
Debug the URL that EditURL is returning and see if you can find the
difference.
Use NavigateURL for all your links and pass in MID=## for your
moduleid as a querystring parameter, to ensure that the proper
values are being passed.
UPDATE: If you're trying to have multiple edit views, and move between them, you might look at using a "loader" instead of having separate module definitions for the edit controls. Basically have a single Edit.ascx file defined, and it loads other ASCX files within it, injecting into a Panel. The View control on this module http://dnnsimplearticle.codeplex.com/ does that, but I haven't tried it with an edit control before.
I would insert some custom article in drupal. That every article,
some fields that I decided.
Then I would like these article are displayed with a graphic set from CSS.
So I would take for each article, the fields with php.
How do I post article with the graphics set to css? and how to take php variables?
Thank you.
From your answer to my comment it sounds like you would like to edit the article content type and then "theme" the resulting page.
You can add fields to any content type (or add new content types) in "Content Types" in the admin. Select the type you want (article) and click "Manage fields". Here you can add as many fields or whatever type as you like. Each field will be given a machine name, widget and there will be a wizard to follow that explains all the relevant options.
Once all your fields are added, click "Manage Display" to change the order and way the fields are displayed.
To add a template to your theme, create a folder in your themes folder called "templates". Then copy node.tpl.php from root/modules/node/ to this new folder. Rename the copied file to node--machine_name.tpl.php. So for the content type "article" you would change the file to node--article.tpl.php.
Clear your cache (admin/config/development/performance) and that content type will be using that new template. By default all fields will be displayed by this line of code print render($content); If you comment that line out you can display fields individually but taking the fields machine name and doing <?php print render($content['field_page_image']); ?>
Read up on Drupal theming, there are a lot of good docs out there.