How to create try counter in C? - c

Question

So, I've just started to learn C. I decided to make a basic number guessing game, where it tells you if you were too high or too low, and gives you up to 5 tries. I've got it working, but I can't figure out how to do the 5 tries. Any tips or help would be appreciated.
#include <stdio.h> /* printf, NULL */
#include <stdlib.h> /* srand, rand */
#include <time.h> /* time */
int main()
{
srand(time(NULL));
int r = ( rand() % 10 ) + 1; /* generates "random" number */
int number;
int c = 0;
printf( "Guess a number from one to ten!\n" );
do {
scanf( "%d", &number);
if (number == r) {
printf( "Correct! You win!!!\n" );
c = 1; /* ends loop if correct */
}
else if (number > r) {
printf( "Too high! Try again!\n" );
}
else {
printf( "Too low! Try again!\n" );
}
}
while ( c == 0 );
return 0;
}

Answer 1

Add a counter to your loop condition:
int counter = 0;
do {
....
counter++;
}
while ( c == 0 && counter < 5 );

Answer 2

Change c == 0 to c != 5. Everytime they guess incorrect increment c by 1. Also if they guess correctly either do c = 5 or use the keyword break to break out of the do-while loop. You are quite close though.

Answer 3

you can add a loop outside the origin loop in your program.
for (i=0;i<5;i++)
{ ...
if (number=r)
{ printf("you win.");
return 0;
}
else if ...

Answer 4

Preferably, do like this, for best readability:
const int MAX = 5;
bool found = false;
for(int tries=0; !found && tries<MAX; tries++)
{
scanf( "%d", &number);
if (number < r)
{
// ...
}
else if(number > r)
{
// ...
}
else // number == r
{
found = true;
}
}
if(found)
{
// ...
}
else
{
// ...
}
As a rule of thumb, always use a for loop when the number of iterations are known in advance.

Answer 5

Mainteining your do while loop you can do
#include <stdio.h> /* printf, NULL */
#include <stdlib.h> /* srand, rand */
#include <time.h> /* time */
#define MAX_TRY 5
int main()
{
srand(time(NULL));
int r = ( rand() % 10 ) + 1; /* generates "random" number */
int number;
int c = 0;
printf( "Guess a number from one to ten!\n" );
do
{
scanf( "%d", &number);
// Count the new inserted value
c++;
if (number > r)
{
printf( "Too high! Try again!\n" );
}
else if (number < r)
{
printf( "Too low! Try again!\n" );
}
else
{
printf( "Correct! You win!!!\n" );
c = MAX_TRY; /* ends loop if correct */
}
}
while ( c < MAX_TRY );
return 0;
}
As you can see
I changed the while condition to check that max tries are as stated.
I inverted your if-else sequence to make the loop able to exit
immediately after the correct value is inserted.

Answer 6

try this. I defined another variable int n=0 and used it just before your conditional sentence starts and in loop I used and operator.
#include <stdio.h> /* printf, NULL */
#include <stdlib.h> /* srand, rand */
#include <time.h> /* time */
int main()
{
srand(time(NULL));
int r = ( rand() % 10 ) + 1; /* generates "random" number */
int number;
int c = 0,n=0; /* new int variable defined */
printf( "Guess a number from one to ten!\n" );
do {
n+=1;
scanf( "%d", &number);
if (number == r) {
printf( "Correct! You win!!!\n" );
c = 1; /* ends loop if correct */
}
else if (number > r) {
printf( "Too high! Try again!\n" );
}
else {
printf( "Too low! Try again!\n" );
}
}
while ( c == 0 && n != 5);
return 0;
}
i hope it helps.

Answer 7

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main()
{
srand(time(NULL));
int r = ( rand() % 10 ) + 1; /* generates "random" number */
int number;
int c = 0; /* new int variable defined */
printf( "Guess a number from one to ten!\n" );
do {
c+=1;
scanf( "%d", &number);
if (number == r) {
printf( "Correct! You win!!!\n" );
break;
}
else if (number > r) {
printf( "Too high! Try again!\n" );
}
else {
printf( "Too low! Try again!\n" );
}
} while ( c<5);
if(c==5)
printf("You lose\n");
return 0;
}