public function beforSave($option = array()) {
if($this->columnName) {
// Statement
}
}
Something like that
if(!$this->loadModel($type)) {
// Statement
}
Get the model schema
$this->modelName->schema();
Check if my field is available or not
if (!empty($this->modelName->schema('date_created'))) {
// statement
}
Or
public function beforeSave($options = array()) {
if ($this->hasField('date_created')) {
$this->data[$this->alias]['date_created'] = date('Y-m-d H:i:s');
}
}
Try with getColumnType and array_key_exist;
getColumnTypes() Returns an associative array of field names and column
types.
$fileds = $this->YourModelName->getColumnTypes();
if(array_key_exists('columnName', $fileds)) {
// Statement
}
Related
I noticed that there is new afterMarshal event in 4.1.
Where to put it? In Table model? And how?
I want to do some work with results every time it's loaded.
Thanks for help
For Encryption and Decryption through model in 'CAKEPHP 4'
public $encryptedFields = ['first_name','last_name'];
public function beforeSave($event, $entity, $options)
{
foreach($this->encryptedFields as $fieldName)
{ if($entity->has($fieldName))
{ $entity->set($fieldName, encodeBeforeSave($entity->get($fieldName)));}
} return true;
}
public function beforeFind( $event, $query, $options)
{ $query->formatResults(
function ($results)
{ return $results->map(function ($row){
foreach($this->encryptedFields as $fieldName)
{
if(isset($row[$fieldName]) && !empty($row[$fieldName]) )
{
$row[$fieldName] = decodeBeforefind($row[$fieldName]);
}
}
return $row;
});
}
);
}
I want that when a record is saved and marked as active, all other records are marked INactive.
I've tried the following code in my model:
public function beforeSave($options = array()) {
if (!empty($this->data['Ticket']['is_active'])) {
$this->data['Ticket']['is_active'] = 0;
}
return true;
}
However this code is error
Use afterSave
Instead of using beforeSave, it's more appropriate to use afterSave, and updateAll like so:
public function afterSave($created) {
if (!empty($this->data[$this->alias]['is_active'])) {
$this->updateAll(
array('is_active' => 0),
array(
'id !=' => $this->id,
'is_active' => 1
)
);
}
}
I.e. after successfully saving a record, if it is active disable all the others.
Note: be sure to use the same method signature as the parent class. It varies depending on which version of CakePHP you are using.
You can write before save method like
public function beforeSave($options=array()){
if (!empty($this->data[$this->alias]['is_active'])) {
$this->data[$this->alias]['is_active'] = 0;
}
return true;
}
Whenever I call this function, I get the user_id correctly but the password isnt checked...
Model:
<?php
class Prometheus_model extends CI_Model {
var $tables = array(
'bots' => 'bots',
'users' => 'users'
);
function __construct() {
parent::__construct();
}
public function tablename($table = NULL) {
if(! isset($table)) return FALSE;
return $this->tables[$table];
}
public function get($table, $where = array(), $order = NULL) {
$this->db->where($where);
if(isset($order)) {
$this->db->order_by($order);
}
$q = $this->db->get_where($this->tablename($table),$where);
$result = $q->result_array();
// You should use $q->num_rows() to detect the number of returned rows
if($q->num_rows()) {
return $result[0];
}
return $result;
}
public function update($table, $where = array(), $data) {
$this->db->update($this->tablename($table),$data,$where);
return $this->db->affected_rows();
}
public function insert($table, $data) {
$this->db->insert($this->tablename($table),$data);
return $this->db->insert_id();
}
public function delete($table, $where = array()) {
$this->db->delete($this->tablename($table),$where);
return $this->db->affected_rows();
}
public function explicit($query) {
$q = $this->db->query($query);
if(is_object($q)) {
return $q->result_array();
} else {
return $q;
}
}
public function num_rows($table, $where = NULL) {
if(isset($where)){
$this->db->where($where);
}
$q = $this->db->get($table);
return $q->num_rows();
}
public function get_bot_data_by_hw_id($bot_hw_id) {
$q = $this->get('bots', array('bot_hw_id' => $bot_hw_id));
return $q;
}
public function check_user_data($user_incredials, $user_password) {
if($this->num_rows('users', array('user_name' => $user_incredials, 'user_password' => $this->encrypt->decode($user_password))) == 1){
$q = $this->get('users', array('user_name' => $this->security->xss_clean($user_incredials)));
return $q['user_id'];
}
return FALSE;
}
}
?>
My function-calling at the controller:
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Login extends CI_Controller {
public function index(){
if($this->input->post('user_login')){
var_dump($this->prometheus_model->check_user_data($this->input->post('user_incredials'), $this->input->post('user_password')));
}
$this->load->view('login_index');
}
}
How can i fixx this ?
In your check_user_data() method you are using
if($this->num_rows('users', array('user_name' => $user_incredials, 'user_password' => $this->encrypt->decode($user_password))) == 1)
I think (logically) following code
$this->encrypt->decode($user_password)
should be
$this->encrypt->encode($user_password)
because, you are calling num_rows() method and it is
public function num_rows($table, $where = NULL)
{
if(isset($where)){
$this->db->where($where);
}
$q = $this->db->get($table);
return $q->num_rows();
}
which is actually querying the data base something like, for example,
select * from USERS where user_name = 'heera' and password = decode('abcde12345')
In this case, the password you are trying to match is need to be encrypted using encode (not decode) method, because the user has given you a non-encrypted (plain) password and the password saved in the database is already encrypted, so encode the plain password using encode method before you query the database to match with already encoded passwords.
I have a form in my Plugin elements and what i would like to insert the checkbox value into a table named it_queries and field status_type and its giving me an error Undefined variable: variableValue [APP\Plugin\Feedback\View\Elements\comment_add.ctp, line 37] .I have declared the variable in my controller like this
$this->set('variableValueStatus', 'Pending');
and this is line 37 thats giving me the error
Below is the Controller code
App::uses('FeedbackAppController', 'Feedback.Controller');
class CommentsController extends FeedbackAppController
{
public $components = array('Feedback.Comments');
public function add($foreign_model = null, $foreign_id = null)
{
if (empty($foreign_model) ||
empty($foreign_id) ||
!$this->request->is('post')
)
{
foreach ($_POST['likebutton'] as $pageId => $likeFlag) {
$dbFlag = $likeFlag ? 'Yes' : 'No';
}
return $this->redirect('/');
}
App::uses($foreign_model, 'Model');
$Model = ClassRegistry::init($foreign_model);
if (!($Model instanceof Model))
{
return $this->redirect('/');
}
if ($Model->hasAny(array($Model->primaryKey => $foreign_id)) == false)
{
return $this->redirect('/');
}
if (!isset($this->request->data['Comment']['foreign_model']) ||
!isset($this->request->data['Comment']['foreign_id']) ||
$this->request->data['Comment']['foreign_model'] != $foreign_model ||
$this->request->data['Comment']['foreign_id'] != $foreign_id)
{
return $this->redirect('/');
}
$user_id = null;
if (isset($this->Auth))
{
$user_id = $this->Auth->user('id');
}
$this->request->data['Comment']['foreign_model'] = $Model->name;
$this->request->data['Comment']['foreign_id'] = $foreign_id;
$this->request->data['Comment']['user_id'] = $user_id;
$this->Comment->create();
if (!$this->Comment->save($this->request->data))
{
$this->set('validation_errors', $this->Comment->validationErrors);
return;
}
$this->redirect($this->request->referer().'#comment-'.$this->Comment->id);
}
}
and in the add view in my element here is how i am trying to accessing the variable value
echo $this->Form->checkbox('ItQuery.status_type', array('type' => 'hidden', 'value'=>$variableValueStatus));
If someone can show me how to fix this, that would be awesome
You are only passing the variable down on !post and if foreign model and foreign id are not set.
That will most likely not work in most of the cases.
You should be always passing down a variable if you do not check on it in the view prior to using it.
But it would still be wrong, anyway. You would have to use "default" instead of "value" if you dont want your form to fall back on the old value on POST (which it shouldnt).
Also, it is always better to use $this->request->data to properly fill the form with defaults:
if (!$this->request->is('post')) {
$this->request->data['ItQuery']['status_type'] = 'Pending';
}
See working-with-forms
In my model's beforeSave method, how can I check if the save operation is going to be an INSERT or an UPDATE?
I want to add to the model data, but only if it's inserting a new row.
You can just check in the data if the id exists:
function beforeSave($options = array())
{
if(empty($this->data[$this->alias]['id']))
{
//INSERT
}
else
{
//UPDATE
}
}
This is how you would do in Cakephp 4 (in case someone is looking for it)
EDIT it also applies to Cakephp 3 as BadHorsie stated
public function beforeSave(EventInterface $event, EntityInterface $entity, ArrayObject $options)
{
if ($entity->isNew()) {
//INSERT
}else{
//UPDATE
}
}
You can try this
public function beforeSave($options = array()) {
if($this->id) {
// Update
} else {
// Add
}
}