The question might sound a little bit confusing but I don't know how to explain it better in one sentence.
This describes basically what the problem is:
I have a Users table which can contain 2 types of users. I know how I can separate by role. But here's the thing, users with role 1(editor_in_chief) have different attributes than users with role 2(reviewer).
My idea was to create a table named 'reviewer_attributes' and 'editor_in_chief_attributes' and create a one-to-one relation with this table to hold the attributes for the users table.
Maybe you have a better idea, that would be great as well. But for this scenario, I would like to know if it is possible to make a call to the database and to get these users' properties from the other table as properties of the User object.
When using a DB call using relations laravel will give me something like this:
user {
id: 1,
name: "Name",
reviewer_attributes: {
attribute_1: 'attribute_1',
attribute_2: 'attribute_2',
attribute_3: 'attribute_3',
}
}
But this is what I want to object to obtain look like:
user {
id: 1,
name: "Name",
attribute_1: 'attribute_1',
attribute_2: 'attribute_2',
attribute_3: 'attribute_3',
}
I want to achieve this by a single database call instead of setting the properties after the call.
I find this a very interesting topic, I hope you could help!
If I got your problem right, you may call somthing like this:
DB::table('users')
->join('reviewer_attributes', 'users.id', '=', 'reviewer_attributes.user_id')
->find($id);
you may add select to get specific attributes of each table:
DB::table('users')
->join('reviewer_attributes', 'users.id', '=', 'reviewer_attributes.user_id')
->select('users.id', 'users.name', 'reviewer_attributes.*')
->find($id);
Update: You can also use collections to restructure your results returned by Eloquent:
$result = User::with('reviewerAttributes')->find($id);
$result = $result->get('reviewer_attributes')
->merge($result->forget('reviewer_attributes')->all())
->all();
You need export model to Json?
If so, override toArray method
public function toArray()
{
$arr = parent::toArray();
$reviewer_attributes = $this->getReviewerAttributesSomeHow();
return array_merge($arr, $reviewer_attributes);
}
Related
I working on an application that has its own database and gets user information from another serivce (an LDAP is this case, through an API package).
Say I have a tables called Articles, with a column user_id. There is no Users table, instead a user or set of users is retrieved through the external API:
$user = LDAPConnector::getUser($user_id);
$users = LDAPConnector::getUsers([1, 2, 5, 6]);
Of course I want retrieving data from inside a controller to be as simple as possible, ideally still with something like:
$articles = $this->Articles->find()->contain('Users');
foreach ($articles as $article) {
echo $article->user->getFullname();
}
I'm not sure how to approach this.
Where should I place the code in the table object to allow integration with the external API?
And as a bonus question: How to minimise the number of LDAP queries when filling the Entities?
i.e. it seems to be a lot faster by first retrieving the relevant users with a single ->getUsers() and placing them later, even though iterating over the articles and using multiple ->getUser() might be simpler.
The most simple solution would be to use a result formatter to fetch and inject the external data.
The more sophisticated solution would a custom association, and a custom association loader, but given how database-centric associations are, you'd probably also have to come up with a table and possibly a query implementation that handles your LDAP datasource. While it would be rather simple to move this into a custom association, containing the association will look up a matching table, cause the schema to be inspected, etc.
So I'll stick with providing an example for the first option. A result formatter would be pretty simple, something like this:
$this->Articles
->find()
->formatResults(function (\Cake\Collection\CollectionInterface $results) {
$userIds = array_unique($results->extract('user_id')->toArray());
$users = LDAPConnector::getUsers($userIds);
$usersMap = collection($users)->indexBy('id')->toArray();
return $results
->map(function ($article) use ($usersMap) {
if (isset($usersMap[$article['user_id']])) {
$article['user'] = $usersMap[$article['user_id']];
}
return $article;
});
});
The example makes the assumption that the data returned from LDAPConnector::getUsers() is a collection of associative arrays, with an id key that matches the user id. You'd have to adapt this accordingly, depending on what exactly LDAPConnector::getUsers() returns.
That aside, the example should be rather self-explanatory, first obtain a unique list of users IDs found in the queried articles, obtain the LDAP users using those IDs, then inject the users into the articles.
If you wanted to have entities in your results, then create entities from the user data, for example like this:
$userData = $usersMap[$article['user_id']];
$article['user'] = new \App\Model\Entity\User($userData);
For better reusability, put the formatter in a custom finder. In your ArticlesTable class:
public function findWithUsers(\Cake\ORM\Query $query, array $options)
{
return $query->formatResults(/* ... */);
}
Then you can just do $this->Articles->find('withUsers'), just as simple as containing.
See also
Cookbook > Database Access & ORM > Query Builder > Adding Calculated Fields
Cookbook > Database Access & ORM > Retrieving Data & Results Sets > Custom Finder Methods
I have got myself a bit confused with relationships, I am not sure if I am splitting things up too much? I am dealing with a reporting system where there can be different types of reports. So, I have my standard reports table and model, and within the model, I define that a report can have one report type.
public function reportType() {
return $this->hasOne('App\ReportType');
}
Now a reportType can be one of three different Types, lets call them A, B and C. Each reportType collects different data. As such, within the ReportType model, I define a has one relationship with the type it has
public function reportTypeA() {
return $this->hasOne('App\ReportTypeA');
}
So the above states that a reportType can have one reportTypeA. I also have in this Model that it can have one reportTypeB and C. Now within reportTypeA model, I state that reportTypeA can have one set of reportTypeAData
public function reportTypeAData() {
return $this->hasOne('App\ReportTypeAData');
}
I have the inverse relationships in all Models. So essentially, I have
Report->ReportType->ReportTypeA->ReportTypeAData
ReportTypeB->ReportTypeBData
ReportTypeBData2
ReportTypeC->ReportTypeCData
Reason I have the data models is because some reports have more than one set of data. So the above shows that Report B has 2 sets of data, each with its own structure.
So the above works, but it seems very "waterfall" approach to me. I will clean this up at some point to hopefully make it more structured.
This is where I am confused though, with the above approach, how can I get the data for a Report? So in my controller, I have something like
$report = Report::where('user_id', Auth::user()->id)->first();
This will get me the first report for the logged in User. I can then get the report data doing something like this
$reportData = $report->reportType->reportTypeA->reportTypeAData->all()->toArray();
Which seems proper overkill having to go through all relationships. My main problem is this, I want to chunk the data back to the frontend, so I will have something like this
DB::table("report_type_a_data")->chunk(100, function ($data) use ($handle) {
foreach ($data as $row) {
// Add a new row with data
fputcsv($handle, [
$row->id,
$row->name
]);
}
});
Now obviously that will loop all data, where I only want the data for the report I am dealing with. Additionally, when I try this, I get an error
You must specify an orderBy clause when using this function
Why am I getting this? Any help with organising things better and how I can process a specific reports data is highly appreciated.
Thanks
You need orderBy() when you use chunk().
For example.
DB::table('users')->orderBy('id')->chunk(100, function ($users) {
foreach ($users as $user) {
//
}
});
or you can use chunkById().
DB::table('users')->where('active', false)
->chunkById(100, function ($users) {
foreach ($users as $user) {
//
}
});
Please refer to the document
I am new to code igniter data mapper. I have a table called user, and I am trying to retrieve data from the database table and show them to the user.
Here is what I have in the model:
$u=new User();
$results=$u->get_by_user_id($id);
//$results here will be set to huge bunch of none sense data( which also includes the row that I am looking for as well)
if ($u->exists())
{
foreach ($results->all as $row){
$data['user']['first_name']=($row->user_first); //this where I am stuck ..
$data['user']['last_name']=($row->user_last);//this is also where I am stuck..
}
I don't know how to treat results to get a required fields I am looking for and store them in the $data I am passing to the user to view.
Thanks!
When you call get_by_x() on the model, the fields will be populated with data and you can access them like this:
$u = new User();
$u->get_by_user_id($id);
if($u->exists())
{
// you can access the table columns as object fields
$data['user']['first'] = $u->first;
$data['user']['last'] = $u->last;
}
else
{
$data['error'] = 'No such user!';
}
Have a look at the documentation which is really helpful: see Get and Get By.
Also, DataMapper expects all tables to have an id column: see Table Naming Rules. If your column is named id you should then call $u->get_by_id($id) instead of $u->get_by_user_id($id).
In my CakePHP application, I have a model like this:
class Duck extends AppModel {
var $name = 'Duck';
function get_table_name() {
$tbl_name = //compute default table name for this model
}
}
I would like to write the function get_table_name() that outputs the default table name for the model. For the example above, it should output ducks.
EDIT:
Several people have pointed out the use of $this->table.
I did small testing and found out the following:
In the question as I have put above, $this->table indeed contains the table name.
However, actually, my code looked more like this:
class Duck extends Bird {
var $name = 'Duck';
function get_table_name(){
$tbl_name = //comput default table name for this model
}
}
class Bird extends AppModel {
}
In this case $this->table is empty string.
I went with this approach because I wanted to share some code between two of my models. Looks like this is not a good way to share code between models which need some common functionality.
You're looking for the Inflector class.
Inflector::tableize($this->name)
(tableize calls two Inflector methods to generate the table name: underscore() and pluralize())
Edit:
According to the source code, $this->table should contain the name of the table that CakePHP will use for the model, but in my experience this isn't always set. I'm not sure why.
To get the name of the table that the model is currently using, you can use: $this->table. If you don't manually change the model's table conventions, this may be the most useful in the case of CakePHP ever changing its conventions to use table names using something other than Inflector.
CakePHP's Inflector
function get_table_name() {
$tbl_name = Inflector::pluralize($this->name);
}
OR the tableize method
function get_table_name() {
$tbl_name = Inflector::tableize($this->name);
}
Edit
This also addresses the apparent "ghost" issue with $this->table in the Model.
Digging around in the __construct for Model I discovered two things:
Cake uses Inflector::tableize() to get the table name. This alone is enough to warrant using tableize over pluralize. You'll get consistent results.
$this->table is not set by the Model::__construct() unless $this->useTable === false AND $this->table === false.
It appears that if you know you haven't set $this->useTable to false you should be able to use this over $this->table. Admittedly though I only briefly scanned the source and I haven't really dug deep enough to say why $this->table isn't working sometimes.
To get the full table name for a model you have to take the table prefix into account.
$table = empty($this->table) ? Inflector::tableize($this->name) : $this->table;
$fullTableName = $this->tablePrefix . $table;
I used to use inflector to get the table name from model's name
$tableName = Inflector::pluralize(Inflector::underscore($model));
but this is not really universal, using useTable looks better, by default it will contain table's name by convention, and if you have a table that does not match the conventions, then you should manually specify it by useTable. So, in both cases the result will be correct
$this->User->useTable
I want to implement some kind of tagging functionality to my app. I want to do something like...
class Item(db.Model):
name = db.StringProperty()
tags = db.ListProperty(str)
Suppose I get a search that have 2 or more tags. Eg. "restaurant" and "mexican".
Now, I want to get Items that have ALL, in this case 2, given tags.
How do I do that? Or is there a better way to implement what I want?
I believe you want tags to be stored as 'db.ListProperty(db.Category)' and then query them with something like:
return db.Query(Item)\
.filter('tags = ', expected_tag1)\
.filter('tags = ', expected_tag2)\
.order('name')\
.fetch(256)
(Unfortunately I can't find any good documentation for the db.Category type. So I cannot definitively say this is the right way to go.) Also note, that in order to create a db.Category you need to use:
new_item.tags.append(db.Category(unicode(new_tag_text)))
use db.ListProperty(db.Key) instead,which stores a list of entity's keys.
models:
class Profile(db.Model):
data_list=db.ListProperty(db.Key)
class Data(db.Model):
name=db.StringProperty()
views:
prof=Profile()
data=Data.gql("")#The Data entities you want to fetch
for data in data:
prof.data_list.append(data)
/// Here data_list stores the keys of Data entity
Data.get(prof.data_list) will get all the Data entities whose key are in the data_list attribute