I can not input the names into the char array using scanf - c

Question

I can not use scanf to enter a name in stdnames array.
when compiled it had no error , but as soon as i enter a name and
then press enter to write the other name it gives an error and shuts the program.
How should I go about it ?
int main(int argc, char* argv[])
{
float marks[50];
/*char *stdnames[100]={"Arvind Thillainathan","Robert Lang"};*/
//I want to stores names like the above one
char *stdnames[100];
int totalNames = 0;
int i = 0, w=0,h=0;
printf("How many names do you want to enter ??\n");
scanf("%d",&totalNames);
assert(totalNames != 0);
for(int count = 0; count < totalNames; count++)
{
printf("Enter name of student\n");
scanf("%s",stdnames[count]);
//From here the problem starts
}
getres(marks,totalNames);
for(i = 0; i < totalNames; i++)
{
int v = 1;
printf("\n");
printf("IELTS Marks of %s\n\n",stdnames[i]);
for(h = w; h < w+5; h++)
{
if(v==1)
{
printf("Listening : %0.1f\n", marks[h]);
}
else if(v==2)
{
printf("Reading : %0.1f\n", marks[h]);
}
else if(v==3)
{
printf("Writing : %0.1f\n", marks[h]);
}
else if(v==4)
{
printf("Speaking : %0.1f\n", marks[h]);
}
else
{
printf("Overall : %0.1f\n\n", marks[h]);
}
v++;
//if(h==10)
//{
// break;
//}
}
w+=5;
}
return 0;
}

Answer 1

By
char *stdnames[100];
you got an array of (pointers to char).
The NEXT BIG QUESTION is
Who will allocate memory for each of these pointers?
A small answer would be - You have to do it yourself like below :
stdnames[count]=malloc(100*sizeof(char)); // You may replace 100 with desired size
or
stdnames[count]=malloc(100); // sizeof(char) is almost always 1
You need to put this line before the scanf statement.
Note: Don't forget to free the allocated memory once these variables become irrelevant. Do it like :
free(stdnames[count]);