Convert 1-to-n XML column to tabular data - sql-server

Question

I have a table on MS SQL server that holds information about reports in XML format. The table consists of two fields: the first has the business key, the second the entire report in XML format.
These reports include several pictures each. The XML holds information about these pictures, such as their filename, taken date, etc. I want to extract this information into a table, where every record holds information about exactly one photo. I've found ways to do this that come very close, but the problem I keep running into is that I need to create several records in this table for every record in my source table. How can I make this work?
The business key needs to be in the final table as well. This business key can be found in the XML data, but there is also a separate field in the source table (as mentioned before) where it can be found. The content of the XML column could look similar to this:
<Report>
<ReportKey>0000001</ReportKey>
[...]
<Photos>
<Photo>
<Filename>1.jpg</Filename>
<Date>01-01-2015</Date>
</Photo>
<Photo>
<Filename>2.jpg</Filename>
<Date>01-01-2016</Date>
</Photo>
[...]
</Photos>
[...]
</Report>
I want the final table to look like this:
+---------+----------+------------+
| Key | Filename | Date |
+---------+----------+------------+
| 0000001 | 1.jpg | 01-01-2015 |
| 0000001 | 2.jpg | 01-01-2016 |
+---------+----------+------------+

Answer 1

This is not an answer, but important enough not to end up in a comment:
Be very careful with date formats. I do not know how your XML is generated, but the date within an XML should be ISO 8601 (yyyy-mm-dd or yyyy-mm-ddThh:mm:ss).
Your format is culture dependant !!!
Try this:
set language french;
declare #xml as xml ='<x><Date>08-03-2015</Date></x>';
select #xml.value('(/x/Date)[1]','datetime');
set language english;
select #xml.value('(/x/Date)[1]','datetime');
You see, that the results differ?
Now try to set the date to the 13th of March. There's even a conversion exception!

Answer 2

According to comments the OP needs an approach to get this from table row data and the existing answer is not solution enough.
You might try this:
CREATE TABLE #YourTable(BusinessKey VARCHAR(10),ReportData XML);
INSERT INTO #YourTable VALUES
('0000001','<Report>
<ReportKey>0000001</ReportKey>
<Photos>
<Photo>
<Filename>1.jpg</Filename>
<Date>2015-01-01</Date>
</Photo>
<Photo>
<Filename>2.jpg</Filename>
<Date>2016-05-13</Date>
</Photo>
</Photos>
</Report>')
,('0000002','<Report>
<ReportKey>0000002</ReportKey>
<Photos>
<Photo>
<Filename>3.jpg</Filename>
<Date>2015-04-19</Date>
</Photo>
<Photo>
<Filename>4.jpg</Filename>
<Date>2016-12-10</Date>
</Photo>
</Photos>
</Report>');
SELECT BusinessKey AS Table_Key
,ReportData.value('(/Report/ReportKey)[1]','varchar(10)') AS XML_Key
,Photo.value('Filename[1]','varchar(max)') AS Photo_Filename
,Photo.value('Date[1]','date') AS Photo_Date
FROM #YourTable
CROSS APPLY ReportData.nodes('/Report/Photos/Photo') AS A(Photo);
GO
DROP TABLE #YourTable;

Answer 3

Maybe I misunderstood the question. However, try this.
create table t (
[Key] int,
[Filename] nvarchar(max),
[Date] date
)
declare #xml as xml = '<Report>
<ReportKey>0000001</ReportKey>
<Photos>
<Photo>
<Filename>1.jpg</Filename>
<Date>01-01-2015</Date>
</Photo>
<Photo>
<Filename>2.jpg</Filename>
<Date>01-01-2016</Date>
</Photo>
</Photos>
</Report>'
insert into t ([Key], [Filename], [Date])
select n.value('ReportKey[1]', 'int')
, x.value('Filename[1]', 'nvarchar(max)')
, x.value('Date[1]', 'date')
from #xml.nodes('Report') as r(n)
cross apply r.n.nodes('Photos/Photo') as t(x)
select * from t