Comparing AD users with File Names - file

Question

I'm trying to find files that are named after members of a specific AD group with a foreach loop using the code below. The script seems to have a problem which causes the loop to stop after the first exception. I think I need to throw the exception because there seems to be no default return value or error if no file for one of the group members is found.
$ErrorActionPreference = "Stop"
$BVAU = Get-ADGroupMember ADGroupName | Select-Object -Property Name
foreach($entry in $BVAU) {
trap [System.IO.DirectoryNotFoundException]{
Write-Host $_.Exception.Message
continue
}
}
if (-not (Get-ChildItem "\\samplepath" -Recurse | Where-Object FullName -like "*$entry*")) {
throw [System.IO.DirectoryNotFoundException] "$entry not found"
}
}
I only want to display the group members that don't have an equally named file. (A PDF form that legally qualifies the AD group membership)

Answer 1

The if statement belongs inside the loop, and the trap should be defined before the loop. However, you don't need the trap in the first place, because it's pointless to throw exceptions just for echoing a username. Simply echo the name right away and continue. Also, avoid running code multiple times if it doesn't need to.
$files = Get-ChildItem "\\samplepath" -Recurse |
Select-Object -Expand Basename -Unique
Get-ADGroupMember ADGroupName |
Select-Object -Expand Name |
Where-Object { $files -notcontains $_ } |
ForEach-Object { "$_ not found" }
The above is assuming that the usernames aren't just partial matches of the file basenames. Otherwise the Where-Object filter becomes slightly more complicated:
...
Where-Object { $n = $_; -not ($files | Where-Object {$_ -like '*$n*'}) } |
...