How to create pandas dataframes with more than 2 dimensions? - arrays

I want to be able to create n-dimensional dataframes. I've heard of a method for 3D dataframes using panels in pandas but, if possible, I would like to extend the dimensions past 3 dims by combining different datasets into a super dataframe
I tried this but I cannot figure out how to use these methods with my test dataset ->
Constructing 3D Pandas DataFrame
Also, this did not help for my case -> Pandas Dataframe or Panel to 3d numpy array
I made a random test dataset with arbitrary axis data trying to mimic a real situation; there are 3 axis (i.e. patients, years, and samples). I tried adding a bunch of dataframes to a list and then making a dataframe with that but it didn't work :( I even tried a panel as in the 2nd link above but I couldn't get it to work either.
Does anybody know how to create a N-dimensional pandas dataframe w/ labels?
The first way I tried:
#Reproducibility
np.random.seed(1618033)
#Set 3 axis labels/dims
axis_1 = np.arange(2000,2010) #Years
axis_2 = np.arange(0,20) #Samples
axis_3 = np.array(["patient_%d" % i for i in range(0,3)]) #Patients
#Create random 3D array to simulate data from dims above
A_3D = np.random.random((years.size, samples.size, len(patients))) #(10, 20, 3)
#Create empty list to store 2D dataframes (axis_2=rows, axis_3=columns) along axis_1
list_of_dataframes=[]
#Iterate through all of the year indices
for i in range(axis_1.size):
#Create dataframe of (samples, patients)
DF_slice = pd.DataFrame(A_3D[i,:,:],index=axis_2,columns=axis_3)
list_of_dataframes.append(DF_slice)
# print(DF_slice) #preview of the 2D dataframes "slice" of the 3D array
# patient_0 patient_1 patient_2
# 0 0.727753 0.154701 0.205916
# 1 0.796355 0.597207 0.897153
# 2 0.603955 0.469707 0.580368
# 3 0.365432 0.852758 0.293725
# 4 0.906906 0.355509 0.994513
# 5 0.576911 0.336848 0.265967
# ...
# 19 0.583495 0.400417 0.020099
# DF_3D = pd.DataFrame(list_of_dataframes,index=axis_2, columns=axis_1)
# Error
# Shape of passed values is (1, 10), indices imply (10, 20)
2nd way I tried:
DF = pd.DataFrame(axis_3,columns=axis_2)
#Error:
#Shape of passed values is (1, 3), indices imply (20, 3)
# p={}
# for i in axis_1:
# p[i]=DF
# panel= pd.Panel(p)
I could do something like this I guess, but I really like pandas and would rather use one of their methods if one exists:
#Set data for query
query_year = 2007
query_sample = 15
query_patient = "patient_1"
#Index based on query
A_3D[
(axis_1 == query_year).argmax(),
(axis_2 == query_sample).argmax(),
(axis_3 == query_patient).argmax()
]
#0.1231212416981845
It would be awesome to access the data in this way:
DF_3D[query_year][query_sample][query_patient]
#Where DF_3D[query_year] would give a list of 2D arrays (row=sample, col=patient)
# DF_3D[query_year][query_sample] would give a 1D vector/list of patient data for a particular year, of a particular sample.
# and DF_3D[query_year][query_sample][query_patient] would be a particular sample of a particular patient of a particular year

Rather than using an n-dimensional Panel, you are probably better off using a two dimensional representation of data, but using MultiIndexes for the index, column or both.
For example:
np.random.seed(1618033)
#Set 3 axis labels/dims
years = np.arange(2000,2010) #Years
samples = np.arange(0,20) #Samples
patients = np.array(["patient_%d" % i for i in range(0,3)]) #Patients
#Create random 3D array to simulate data from dims above
A_3D = np.random.random((years.size, samples.size, len(patients))) #(10, 20, 3)
# Create the MultiIndex from years, samples and patients.
midx = pd.MultiIndex.from_product([years, samples, patients])
# Create sample data for each patient, and add the MultiIndex.
patient_data = pd.DataFrame(np.random.randn(len(midx), 3), index = midx)
>>> patient_data.head()
0 1 2
2000 0 patient_0 -0.128005 0.371413 -0.078591
patient_1 -0.378728 -2.003226 -0.024424
patient_2 1.339083 0.408708 1.724094
1 patient_0 -0.997879 -0.251789 -0.976275
patient_1 0.131380 -0.901092 1.456144
Once you have data in this form, it is relatively easy to juggle it around. For example:
>>> patient_data.unstack(level=0).head() # Years.
0 ... 2
2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 ... 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009
0 patient_0 -0.128005 0.051558 1.251120 0.666061 -1.048103 0.259231 1.535370 0.156281 -0.609149 0.360219 ... -0.078591 -2.305314 -2.253770 0.865997 0.458720 1.479144 -0.214834 -0.791904 0.800452 0.235016
patient_1 -0.378728 -0.117470 -0.306892 0.810256 2.702960 -0.748132 -1.449984 -0.195038 1.151445 0.301487 ... -0.024424 0.114843 0.143700 1.732072 0.602326 1.465946 -1.215020 0.648420 0.844932 -1.261558
patient_2 1.339083 -0.915771 0.246077 0.820608 -0.935617 -0.449514 -1.105256 -0.051772 -0.671971 0.213349 ... 1.724094 0.835418 0.000819 1.149556 -0.318513 -0.450519 -0.694412 -1.535343 1.035295 0.627757
1 patient_0 -0.997879 -0.242597 1.028464 2.093807 1.380361 0.691210 -2.420800 1.593001 0.925579 0.540447 ... -0.976275 1.928454 -0.626332 -0.049824 -0.912860 0.225834 0.277991 0.326982 -0.520260 0.788685
patient_1 0.131380 0.398155 -1.671873 -1.329554 -0.298208 -0.525148 0.897745 -0.125233 -0.450068 -0.688240 ... 1.456144 -0.503815 -1.329334 0.475751 -0.201466 0.604806 -0.640869 -1.381123 0.524899 0.041983
In order to select the data, please refere to the docs for MultiIndexing.

You should consider using xarray instead. From their documentation:
Panel, pandas’ data structure for 3D arrays, was always a second class data structure compared to the Series and DataFrame. To allow pandas developers to focus more on its core functionality built around the DataFrame, pandas removed Panel in favor of directing users who use multi-dimensional arrays to xarray.

An alternative approach (to Alexander) that is derived from the structure of the input data is:
np.random.seed(1618033)
#Set 3 axis labels/dims
years = np.arange(2000,2010) #Years
samples = np.arange(0,20) #Samples
patients = np.array(["patient_%d" % i for i in range(0,3)]) #Patients
#Create random 3D array to simulate data from dims above
A_3D = np.random.random((years.size, samples.size, len(patients))) #(10, 20, 3)
# Reshape data to 2 dimensions
maj_dim = 1
for dim in A_3D.shape[:-1]:
maj_dim = maj_dim*dim
new_dims = (maj_dim, A_3D.shape[-1])
A_3D = A_3D.reshape(new_dims)
# Create the MultiIndex from years, samples and patients.
midx = pd.MultiIndex.from_product([years, samples])
# Note that Cartesian product order is the same as the
# C-order used by default in ``reshape``.
# Create sample data for each patient, and add the MultiIndex.
patient_data = pd.DataFrame(data = A_3D,
index = midx,
columns = patients)
>>>> patient_data.head()
patient_0 patient_1 patient_2
2000 0 0.727753 0.154701 0.205916
1 0.796355 0.597207 0.897153
2 0.603955 0.469707 0.580368
3 0.365432 0.852758 0.293725
4 0.906906 0.355509 0.994513

Related

How to sampling Data Frame?

The goal is to subsample a data frame.
code:
# 1 date is in type datatime
dg.Yr_Mo_Dy = pd.to_datetime(dg.Yr_Mo_Dy, format='%Y%m%d')
# 2 date is in index
dg = dg.set_index(dg.Yr_Mo_Dy, drop = True)
# 3 to group by 10
dg.resample('1AS').mean().mean()
That gives:
RPT 14.847325
VAL 12.914560
ROS 13.299624
KIL 7.199498
SHA 11.667734
BIR 8.054839
DUB 11.819355
CLA 9.512047
MUL 9.543208
CLO 10.053566
BEL 14.550520
MAL 18.028763
dtype: float6
The code takes every 10 values the 10 intermediate values and the average.
Similarly, it is also possible to sum these 10 values by replacing mean() with sum().
However, what I want to do is not an average but a sampling. That is, to take all the values and only one without averaging, without summing the intermediate values.
For example, the data: 1,2,3,4,5,6.. sampled by 0.5 gives 2,4,6... et non 1.5,2.5,3.5,5.5...

How to check df rows that has a difference between 2 columns and then send it to another table to verify information

I’m very new to python and am trying really hard these last few days on how to go through a df row by row, and check each row that has a difference between columns dQ and dCQ. I just said != 0 since there could be a pos or neg value. Now if this is true, I would like to check in another table whether certain criteria are met. I'm used to working in R, where I could store the df into a variable and call upon the column name, I can't seem to find a way to do it in python. I posted all of the code I’ve been playing with. I know this is messy, but any help would be appreciated. Thank you!
I've tried installing different packages that wouldn't work, I tried making a for loop (I failed miserably), maybe a function? I’m not sure where to even look. I've never learned Python, I’m really doing my best watching videos online and reading on here.
import pyodbc
import PyMySQL
import pandas as pd
import numpy as np
conn = pyodbc.connect("Driver={ODBC Driver 17 for SQL Server};"
"Server=***-***-***.****.***.com;"
"Database=****;"
"Trusted_Connection=no;"
"UID=***;"
"PWD=***")
# cur = conn.cursor()
# cur.execute("SELECT TOP 1000 tr.dQ, po.dCQ,
tr.dQ - po.dCQ as diff FROM [IP].[dbo].
[vT] tr (nolock) JOIN [IP].[dbo].[vP] po
ON tr.vchAN = po.vchCustAN WHERE tr.dQ
!= po.dCQ")
# query = cur.fetchall()
query = "SELECT TOP 100 tr.dQ, po.dCQ/*, tr.dQ -
po.dCQ as diff */FROM [IP].[dbo].[vT]
tr (nolock) INNER JOIN [IP].[dbo].[vP] po ON
tr.vchAN = po.vchCustAN WHERE tr.dQ !=
po.dCQ"
df = pd.read_sql(query, conn)
#print(df[2,])
cursor = conn.cursor(PyMySQL.cursors.DictCursor)
cursor.execute("SELECT TOP 100 tr.dQ, po.dCQ/*,
tr.dQ - po.dCQ as diff */FROM [IP].[dbo].
[vT] tr (nolock) INNER JOIN [IP].[dbo].
[vP] po ON tr.vchAN = po.vchCustAN
WHERE tr.dQ != po.dCQ")
result_set = cursor.fetchall()
for row in result_set:
print("%s, %s" % (row["name"], row["category"]))
# if df[3] != 0:
# diff = df[1]-df[2]
# print(diff)
# else:
# exit
# cursor = conn.cursor()
# for row in cursor.fetchall():
# print(row)
#
# for record in df:
# if record[1] != record[2]:
# print(record[3])
# else:
# record[3] = record[1]
# print(record)
# df['diff'] = np.where(df['dQ'] != df["dCQ"])
I expect some sort of notification that there's a difference in row xx, and now it will check in table vP to verify we received this data's details. I believe i can get to this point, if i can get the first part working. Any help is appreciated. I'm sorry if this question is not clear, i will do my best to answer any questions someone may have. Thank you!
One solution could be to make a new column where you store the result of the diff between df[1] and df[2]. One note first. It might be more precise to either name your columns when you make the df, then reference them with df['name1'] and df['name2'], or use df.iloc[:,1] and df.iloc[:,2]. Also note that column numbers start with zero, so these would refer to the second and third columns in the df. The reason to use iloc is and the colons is to explicitly state that you want all rows and and column numbers 1 and 2. Otherwise, with df[1] or df[2] if your df was transposed that may actually refer to what you think of as the index. Now, on to a solution.
You could try
df['diff']=df.iloc[:,1]-df.iloc[:,2]
df['diff_bool']=np.where(df['diff']==0,False, True)
or you could combine this into one method
df['diff_bool']==np.where(df.iloc[:,1]-df.iloc[:,2]==0,False, True)
This will create a column in your df that says if there is a difference between columns one and two. You don't actually need to loop through row by row because pandas functions work like matrix math, so df.iloc[:,1]-df.iloc[:,2] will apply the subtraction row by row automatically.

Is there a more effective way to combine 24 columns into a single column as an array in R

I have a code below that works to take 24 columns (hours) of data and combine it into a single column array for each row in a dataframe:
# Adds all of the values into column twentyfourhours with "," as the separator.
agg_bluetooth_data$twentyfourhours <- paste(agg_bluetooth_data[,1],
agg_bluetooth_data[,2], agg_bluetooth_data[,3], agg_bluetooth_data[,4],
agg_bluetooth_data[,5], agg_bluetooth_data[,6], agg_bluetooth_data[,7],
agg_bluetooth_data[,8], agg_bluetooth_data[,9], agg_bluetooth_data[,10],
agg_bluetooth_data[,11], agg_bluetooth_data[,12], agg_bluetooth_data[,13],
agg_bluetooth_data[,14], agg_bluetooth_data[,15], agg_bluetooth_data[,16],
agg_bluetooth_data[,17], agg_bluetooth_data[,18], agg_bluetooth_data[,19],
agg_bluetooth_data[,20], agg_bluetooth_data[,21], agg_bluetooth_data[,22],
agg_bluetooth_data[,23], agg_bluetooth_data[,24], sep=",")
However, after this I still have to write more lines of code to remove spaces, add brackets around it, and delete the columns. None of this is difficult to do, but I feel like there should be a shorter/cleaner code to use to get the results I am looking for. Does anyone have any suggestions?
There is a built-in function to do rowSums. It looks like you want an analogous rowPaste function. We can do this with apply:
# create example dataset
df <- data.frame(
v=1:10,
x=letters[1:10],
y=letters[6:15],
z=letters[11:20],
stringsAsFactors = FALSE
)
# rowPaste columns 2 through 4
apply(df[, 2:4], 1, paste, collapse=",")
Another option, using #Dan Y's data (might be helpful if you posted a subset of your data using dput though).
library(tidyr)
library(dplyr)
df %>%
unite('new_col', v, x, y, z, sep = ',')
new_col
1 1,a,f,k
2 2,b,g,l
3 3,c,h,m
4 4,d,i,n
5 5,e,j,o
6 6,f,k,p
7 7,g,l,q
8 8,h,m,r
9 9,i,n,s
10 10,j,o,t
You can then perform the neccessary edits with mutate. There's also a fair amount of flexibility in the column selections within the unite call. Check out the "Useful Functions" section of the select documentation.

Replace Null Values of a Column with mean of another Categorcial Column in Spark Dataframe

I have a dataset like this
id category value
1 A NaN
2 B NaN
3 A 10.5
5 A 2.0
6 B 1.0
I want to fill the NAN values with the mean of their respective category. As shown below
id category value
1 A 4.16
2 B 0.5
3 A 10.5
5 A 2.0
6 B 1.0
I tried to calculate first mean values of each category using group by
val df2 = dataFrame.groupBy(category).agg(mean(value)).rdd.map{
case r:Row => (r.getAs[String](category),r.get(1))
}.collect().toMap
println(df2)
I got map of each category and their respective mean values.output: Map(A ->4.16,B->0.5)
Now i tried update query in Sparksql to fill column but it seems spqrkSql dosnt support update query. I tried to fill null values with in dataframe but failed to do so.
What can i do? We can do the same in pandas as shown in Pandas: How to fill null values with mean of a groupby?
But how can i do using spark dataframe
The simplest solution would be to use groupby and join:
val df2 = df.filter(!(isnan($"value"))).groupBy("category").agg(avg($"value").as("avg"))
df.join(df2, "category").withColumn("value", when(col("value").isNaN, $"avg").otherwise($"value")).drop("avg")
Note that if there is a category with all NaN it will be removed from the result
Indeed, you cannot update DataFrames, but you can transform them using functions like select and join. In this case, you can keep the grouping result as a DataFrame and join it (on category column) to the original one, then perform the mapping that would replace NaNs with the mean values:
import org.apache.spark.sql.functions._
import spark.implicits._
// calculate mean per category:
val meanPerCategory = dataFrame.groupBy("category").agg(mean("value") as "mean")
// use join, select and "nanvl" function to replace NaNs with the mean values:
val result = dataFrame
.join(meanPerCategory, "category")
.select($"category", $"id", nanvl($"value", $"mean")).show()
I stumbled upon same problem and came across this post. But tried a different solution i.e. using window functions. The code below is tested on pyspark 2.4.3 (Window functions are available from Spark 1.4). I believe this is bit cleaner solution.
This post is quiet old, but hope this answer will be helpful for others.
from pyspark.sql import Window
from pyspark.sql.functions import *
df = spark.createDataFrame([(1,"A", None), (2,"B", None), (3,"A",10.5), (5,"A",2.0), (6,"B",1.0)], ['id', 'category', 'value'])
category_window = Window.partitionBy("category")
value_mean = mean("value0").over(category_window)
result = df\
.withColumn("value0", coalesce("value", lit(0)))\
.withColumn("value_mean", value_mean)\
.withColumn("new_value", coalesce("value", "value_mean"))\
.select("id", "category", "new_value")
result.show()
Output will be as expected (in question):
id category new_value
1 A 4.166666666666667
2 B 0.5
3 A 10.5
5 A 2
6 B 1

Renaming arrays of varying sizes

In Step 1, I find what type of data exists in Database.
In step 2, I retrieve all data from Database and try to store into arrays of varying sizes
1. Accessing data from MongoDB
mong <- mongo(collection = "mycollection", db = "dbname", url = "mongodb://localhost")
agg_df <- mong$aggregate('[{ "$group" :
{ "_id" : "$tagname",
"number_records" : { "$sum" : 1}
}
}]')
print(agg_df)
OUTPUT:
_id number_records
1 raees 100
2 DearZindagi 100
3 FAN 100
4 DDD 21
NOTE: Step 1 output indicates that there are 4 types of categories with records of 100,100,100,21 each.
2. From STEP 1, I need to create 4 arrays consisting of 1 column and varying nos. of rows(100,100,100,21) and give names to those array as Raees,DearZindagi,FAN,DDD
Dataset <- mong$find('{}','{"text":1}')
Dataset$text <- sapply(Dataset$text,function(row) iconv(row, "latin1", "ASCII", sub=""))
typeof(Dataset$text)
> [1] "character"
3. The arrays and their sizes(in rows) to be created is dependent on output of Step 1. There would never be a case where the output of step 1 would be more than 15 rows.
How should i do this?.
The split function would splits the Dataset into arrays, how shall i rename these arrays:
rows <- nrow(agg_df)
for (i in 1:rows){
array<- split(Dataset$text, rep(1:rows, c(agg_df[i,2])))
}

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