C - mkfifo , ls - don't stop - c

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <errno.h>
int main(void) {
if(mkfifo("fifo", S_IRWXU) < 0 && errno != EEXIST) {
perror("Fifo error");
exit(EXIT_FAILURE);
}
pid_t pid = fork();
if(pid == 0) /*dziecko*/
{
int fifo_write_end = open("fifo", O_WRONLY);
if(fifo_write_end < 0)
{
perror("fifo_write_end error");
exit(EXIT_FAILURE);
}
if(dup2(fifo_write_end, STDOUT_FILENO) < 0)
{
perror("dup2 fifo_write_end error");
exit(EXIT_FAILURE);
}
if(execlp("/bin/ls", "ls", "-al", NULL) < 0)
{
perror("execlp error");
exit(EXIT_FAILURE);
}
}
if(pid > 0) /*rodzic*/
{
int fifo_read_end = open("fifo", O_RDONLY);
if(fifo_read_end < 0)
{
perror("fifo_read_end error");
exit(EXIT_FAILURE);
}
if(dup2(fifo_read_end, STDOUT_FILENO) < 0)
{
perror("dup2 fifo_read_end error");
exit(EXIT_FAILURE);
}
int atxt = open("a.txt", O_WRONLY|O_CREAT, S_IRWXU);
if(atxt < 0)
{
perror("a.txt open error");
exit(EXIT_FAILURE);
}
if(dup2(atxt,STDOUT_FILENO) < 0)
{
perror("dup2 atxt error");
exit(EXIT_FAILURE);
}
if(execlp("/usr/bin/tr", "tr", "a-z", "A-Z", NULL) < 0)
{
perror("tr exec error");
exit(EXIT_FAILURE);
}
}
if(pid < 0)
{
perror("Fork error");
exit(EXIT_FAILURE);
}
return 0;
}
Program doesn't stop . I have no idea why . It should execute ls -al | tr a-z A-Z and write it in file a.txt.
And if someone can , please explain me how to do ls-al | tr a-z A-Z | tr A-Z a-z > a.txt . For another tr I need second mkfifo right ? I'm not sure how it's working and if should i close write or read descriptor here . With "pipe" it was nesesery.
Thanks for any help !

The read end of the pipe won't report EOF until the pipe is closed. And a pipe isn't closed until all the descriptors that refer to it are closed. After you call dup2, the pipe is referenced by both the original FD and the descriptor that you duped it to. You need to close the original FD.
if(dup2(fifo_write_end, STDOUT_FILENO) < 0)
{
perror("dup2 fifo_write_end error");
exit(EXIT_FAILURE);
}
close(fifo_write_end);
if(execlp("/bin/ls", "ls", "-al", NULL) < 0)
{
perror("execlp error");
exit(EXIT_FAILURE);
}
Another problem is that the process running tr needs to dup the FIFO to stdin, not stdout. So
if(dup2(fifo_read_end, STDOUT_FILENO) < 0)
{
perror("dup2 fifo_read_end error");
exit(EXIT_FAILURE);
}
should be
if(dup2(fifo_read_end, STDIN_FILENO) < 0)
{
perror("dup2 fifo_read_end error");
exit(EXIT_FAILURE);
}

Related

How to send broadcast messages with named pipe using C?

I want to write a program with 1 sender and 3 receivers. The sender can send individual message to each receivers and group message to all receivers. I am using named pipes to achieve this but can't send group message to all receivers synchronously. Any idea to send broadcast message with named pipe?
Sender program:
/* Sender */
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
int main()
{
char pipename1[] = "/tmp/pipe1";
char pipename2[] = "/tmp/pipe2";
char pipename3[] = "/tmp/pipe3";
char pipename4[] = "/tmp/pipe4";
char buf1[80];
char buf2[80];
char buf3[80];
char buf4[80];
int fd1, fd2, fd3, fd4;
int select1, select2;
int n,pid;
/* Pipe Creation */
if (access(pipename1, F_OK) == -1) {
fd1 = mkfifo(pipename1, 0700);
if (fd1 != 0) {
printf("Pipe creation error\n");
exit(1);
}
}
if (access(pipename2, F_OK) == -1) {
fd2 = mkfifo(pipename2, 0700);
if (fd2 != 0) {
printf("Pipe creation error\n");
exit(1);
}
}
if (access(pipename3, F_OK) == -1) {
fd3 = mkfifo(pipename3, 0700);
if (fd3 != 0) {
printf("Pipe creation error\n");
exit(1);
}
}
if (access(pipename4, F_OK) == -1) {
fd4 = mkfifo(pipename4, 0700);
if (fd4 != 0) {
printf("Pipe creation error\n");
exit(1);
}
}
pid = fork();
if (pid < 0) {
printf("Fork failed\n");
exit(1);
} else if (pid == 0) {
printf("1. Send individual message\n");
printf("2. Send group message\n");
printf("Please select an option: ");
scanf("%d", &select1);
switch(select1) {
case 1:
printf("1. Receiver 1 (Mary)\n");
printf("2. Receiver 2 (John)\n");
printf("3. Receiver 3 (Peter)\n");
printf("Please select a receiver: ");
scanf("%d", &select2);
switch(select2) {
case 1:
/* Open pipe for writing */
if ((fd1 = open(pipename1, O_WRONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while (1) {
printf("Send message to Mary: \n");
n = read(STDIN_FILENO,buf1,80);
if (n <= 0) break;
buf1[--n] = 0;
printf("Sending message [%s] to Mary\n",buf1);
write(fd1,buf1,n);
}
close(fd1);
break;
case 2:
/* Open pipe for writing */
if ((fd2 = open(pipename2, O_WRONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while (1) {
printf("Send message to John: \n");
n = read(STDIN_FILENO,buf2,80);
if (n <= 0) break;
buf2[--n] = 0;
printf("Sending message [%s] to John\n",buf2);
write(fd2,buf2,n);
}
break;
case 3:
/* Open pipe for writing */
if ((fd3 = open(pipename3, O_WRONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while (1) {
printf("Send message to Peter: \n");
n = read(STDIN_FILENO,buf3,80);
if (n <= 0) break;
buf3[--n] = 0;
printf("Sending message [%s] to Peter\n",buf3);
write(fd3,buf3,n);
}
break;
default:
printf("Receiver not found\n");
break;
}
case 2:
/* Open pipe for writing */
if ((fd4 = open(pipename4, O_WRONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while (1) {
printf("Send message to Group: \n");
n = read(STDIN_FILENO,buf4,80);
if (n <= 0) break;
buf4[--n] = 0;
printf("Sending message [%s] to Group\n",buf4);
write(fd4,buf4,n);
}
break;
default:
printf("Wrong Input!\n");
break;
}
} else {
wait(NULL);
}
unlink(pipename1);
unlink(pipename2);
unlink(pipename3);
unlink(pipename4);
exit(0);
}
Receiver1 program:
/* Receiver1 */
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
int main()
{
char pipename1[] = "/tmp/pipe1";
char pipename4[] = "/tmp/pipe4";
char buf1[80];
char buf4[80];
int fd1, fd4;
int n, pid;
printf("Mary is online\n");
pid = fork();
if (pid < 0) {
printf("Fork failed\n");
exit(1);
} else if (pid == 0) {
/* Open pipe for reading */
if ((fd1 = open(pipename1, O_RDONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while ((n = read(fd1, buf1, 80)) > 0) {
buf1[n] = 0;
printf("[Message received:] %s\n", buf1, n);
}
close(fd1);
exit(0);
} else {
/* Open pipe for reading */
if ((fd4 = open(pipename4, O_RDONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while ((n = read(fd4, buf4, 80)) > 0) {
buf4[n] = 0;
printf("[Message received:] %s\n", buf4, n);
}
close(fd4);
wait(NULL);
exit(0);
}
}
Receiver2 program:
/* Receiver2 */
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
int main()
{
char pipename2[] = "/tmp/pipe2";
char pipename4[] = "/tmp/pipe4";
char buf2[80];
char buf4[80];
int fd2, fd4;
int n, pid;
printf("John is online\n");
pid = fork();
if (pid < 0) {
printf("Fork failed\n");
exit(1);
} else if (pid == 0) {
/* Open pipe for reading */
if ((fd2 = open(pipename2, O_RDONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while ((n = read(fd2, buf2, 80)) > 0) {
buf2[n] = 0;
printf("[Message received:] %s\n", buf2, n);
}
close(fd2);
exit(0);
} else {
/* Open pipe for reading */
if ((fd4 = open(pipename4, O_RDONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while ((n = read(fd4, buf4, 80)) > 0) {
buf4[n] = 0;
printf("[Message received:] %s\n", buf4, n);
}
close(fd4);
wait(NULL);
exit(0);
}
}
Receiver3 program:
/* Receiver3 */
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
int main()
{
char pipename3[] = "/tmp/pipe3";
char pipename4[] = "/tmp/pipe4";
char buf3[80];
char buf4[80];
int fd3, fd4;
int n, pid;
printf("Peter is online\n");
pid = fork();
if (pid < 0) {
printf("Fork failed\n");
exit(1);
} else if (pid == 0) {
/* Open pipe for reading */
if ((fd3 = open(pipename3, O_RDONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while ((n = read(fd3, buf3, 80)) > 0) {
buf3[n] = 0;
printf("[Message received:] %s\n", buf3, n);
}
close(fd3);
exit(0);
} else {
/* Open pipe for reading */
if ((fd6 = open(pipename4, O_RDONLY)) < 0) {
printf("Pipe open error\n");
exit(1);
}
while ((n = read(fd4, buf4, 80)) > 0) {
buf4[n] = 0;
printf("[Message received:] %s\n", buf4, n);
}
close(fd4);
wait(NULL);
exit(0);
}
}

Two pipes in c program and the second one does not work as expected

I am currently making some tests with the pipes and forks in C.
I am trying to copy the behavior of this shell command in my program:
cat < test | wc
The test file contains only a little text.
Here is my program's code:
#include <stdio.h>
#include <unistd.h>
#include <fcntl.h>
#include <sys/types.h>
#include <sys/uio.h>
#include <sys/wait.h>
#include <stdlib.h>
// cat < test | wc
int main(int ac, char **av)
{
int p1[2];
int pid1;
printf("\nBegin of the test...\n");
if (pipe(p1) == -1)
{
perror("Pipe1");
exit(1);
}
else
{
pid1 = fork();
if (pid1 > 0)
{
int p2[2];
int pid2;
close(p1[0]);
if (pipe(p2) == -1)
{
perror("Pipe1");
exit(1);
}
else
{
pid2 = fork();
if (pid2 > 0)
{
int pid3;
close(p1[1]);
pid3 = fork();
if (pid3 > 0)
{
close(p2[1]);
wait(0);
printf("All is done !\n");
}
else if (pid3 == 0)
{
close(p2[1]);
dup2(p2[0], 0);
execve("/usr/bin/wc", av, NULL);
}
wait(0);
}
else if (pid2 == 0)
{
int fd;
char buffer[20];
int ret;
close(p2[0]);
dup2(p2[1], 1);
fd = open("test", O_RDONLY);
if (fd >= 0)
{
while ((ret = read(fd, buffer, 20)) > 0)
write(p1[1], buffer, ret);
close(fd);
close(p1[1]);
}
else
{
perror("Open file error");
exit(1);
}
close(p1[1]);
exit(1);
}
}
wait(0);
}
else if (pid1 == 0)
{
close(p1[1]);
dup2(p1[0], 0);
execve("/bin/cat", av, NULL);
}
}
printf("\nEnd of the program.\n");
return (1);
}
The output is:
Begin of the test...
All is done !
Content of the test file
0 0 0
End of the program.
Can someone explain to me why the cat output is not redirected to the wc through the pipe 2?

Need to implement a pipe, dup2 function to perform "ls | tr a-z A-Z > file.txt"

I have the following C code which does "ls | tr a-z A-Z" but I don't know how to make the output go to file.txt. Do I need to create another pipe or fork thrice? Do I need to use open() function at all since I am saving the output to a file?
int main() {
pid_t child_pid_one, child_pid_two;
int pipe_fd[2]; /* pipe */
/* Before the fork, we need to create the pipe */
/* (otherwise no sharing of pipe) */
if (pipe(pipe_fd) < 0) {
err(EX_OSERR, "pipe error");
}
if ((child_pid_one = fork()) < 0) {
err(EX_OSERR, "fork error");
}
if (child_pid_one == 0) { /* CHILD #1's code (ls code) */
close(pipe_fd[0]); /* we don't need pipe's read end */
/* Redirecting standard output to pipe write end */
if (dup2(pipe_fd[1], STDOUT_FILENO) < 0) {
err(EX_OSERR, "dup2 error");
}
execlp("/bin/ls", "/bin/ls", NULL);
err(EX_OSERR, "exec error");
} else { /* parent's code */
/* Creating second child */
if ((child_pid_two = fork()) < 0) {
err(EX_OSERR, "fork error");
}
if (child_pid_two == 0) { /* CHILD #2's code (tr a-z A-Z) */
close(pipe_fd[1]); /* we don't need pipe's write end */
/* Redirecting standard input to pipe read end */
if (dup2(pipe_fd[0], STDIN_FILENO) < 0) {
err(EX_OSERR, "dup2 error");
}
execlp("/usr/bin/tr", "/usr/bin/tr","a-z","A-Z", NULL);
err(EX_OSERR, "exec error");
} else {
/* Parent has no need for the pipe */
close(pipe_fd[0]);
close(pipe_fd[1]);
/* Reaping each children */
wait(NULL);
wait(NULL);
}
}
return 0;
}
Just redirect STDOUT_FILENO of the tr process to a newly opened file:
// write-only (as is stdout), truncate to zero length
int file_fd = open("file.txt", O_WRONLY | O_TRUNC);
if (file_fd < 0) {
// error handling
}
if (dup2(file_fd, STDOUT_FILENO) < 0) {
err(EX_OSERR, "dup2 error");
}

I'm building a small shell. How do I set the standard in- and output of two processes to a pipe, so they can communicate?

I'm trying to implement a very small shell of my own. I have to be able to handle pipes, like
ls -l | wc -l
but only for two programs at a time. Right now, I have this:
#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
#include <unistd.h>
#include <string.h>
#include <sys/types.h>
#include <sys/wait.h>
#define BUFFER_SIZE 256
#define NO_PARAMS 32
void split_string(char **params, char *string){
char *arg;
int i;
arg = strtok(string, " ");
params[0] = arg;
i = 1;
while(arg != NULL){
arg = strtok(NULL, " ");
params[i] = arg;
i++;
}
}
int main(int argc, char **argv){
char string[BUFFER_SIZE];
char *prog1, *prog2;
int i, err;
int fd[2];
pid_t pid1, pid2;
size_t buffer = BUFFER_SIZE;
char *params1[NO_PARAMS], *params2[NO_PARAMS];
int pipe_exists = 0;
memset(string,0,buffer);
while(1){
/*Read command*/
fgets(string, BUFFER_SIZE-1, stdin);
if(string == NULL){
perror("Error reading input:\n");
exit(1);
}
/*replace linefeed character with end of line character*/
for(i=0;i<BUFFER_SIZE;i++){
if(string[i] == 10){
string[i] = 0;
}
}
/*check if command is "exit"*/
if(strcmp(string,"exit") == 0){
return 0;
}
/*split command into different program calls*/
prog1 = strtok(string, "|");
prog2 = strtok(NULL,"\0");
if(prog2 != NULL){
pipe_exists = 1;
printf("PIPE!\n");
err = pipe(fd);
if(err<0){
perror("Error creating pipe:\n");
exit(1);
}
}
/*split string into arguments*/
split_string(params1, prog1);
if(pipe_exists){
split_string(params2, prog2);
}
/*fork child process*/
pid1 = fork();
if(pid1==0){ /*child 1*/
if(pipe_exists){
close(fd[0]); /*close read-end*/
err = dup2(fd[1], 1);
if(err<0){
perror("Error with dup in child 1!\n");
exit(1);
}
}
execvp(params1[0],params1);
perror("Error calling exec()!\n");
exit(1);
}else{ /*parent*/
if(pipe_exists){
pid2 = fork();
if(pid2==0){ /*child 2*/
close(fd[1]); /*close pipe write-end*/
err = dup2(fd[0], 0);
if(err<0){
perror("Error with dup in child 2!\n");
exit(1);
}
execvp(params2[0],params2);
perror("Error calling exec()!\n");
exit(1);
}else{ /*parent with 2 children*/
waitpid(pid1,0,0);
waitpid(pid2,0,0);
}
}else{ /*parent with 1 child*/
waitpid(pid1,0,0);
}
}
}
}
Right now, it'll handle single commands fine, but when I input something like the command above, nothing happens!
Thanks!
Oh! I've already figured it out. I had to close the pipe in the parent program as well :)
To start with, you should loop as long as you find the pipe character. Then you need to create a pipe for each "piping".
Real shells usually forks and exec itself for each command in the pipeline. This is so it should be able to handle internal commands.
There are 3 main parts in a command with pipes.
The begining, that takes stdin and pipes its output something |
The middle, optionnal or repeated at will with two pipes | something |
The end, that outputs to stdout | something
Then use three functions, one for each of those:
#define PIPE_INPUT 0
#define PIPE_OUTPUT 1
execute_pipe_start(t_cmdlist *commands)
{
int pid;
int fd[2];
if (!commands)
return;
if (commands->next)
{
if (pipe(fd) < 0)
{
perror("pipe failed");
exit(1);
}
pid = fork();
if (!pid)
{
close(fd[PIPE_INPUT]);
if (dup2(fd[PIPE_OUTPUT, 1) < 0)
{
perror("dup2 failed");
exit(1);
}
parse_and_exec_cmd(commands->cmd);
}
else
{
waitpid(...); //what you put here is a bit tricky because
//some shells like tcsh will execute all
//commands at the same time (try cat | cat | cat | cat)
}
if (commands->next->next != null) //If you have 2 commands in line there is a middle
execute_pipe_middle(commands->next, fd);
else // no middle
execute_pipe_end(commands->next, fd);
}
else
parse_and_exec_cmd(commands->cmd);
}
execute_pipe_middle(t_cmdlist *commands, int fd_before[2])
{
int pid;
int fd_after[2];
if (pipe(fd_after) < 0)
{
perror("pipe failed");
exit(1);
}
pid = fork();
if (!pid)
{
close(fd_before[PIPE_OUTPUT]);
close(fd_after[PIPE_INPUT]);
if (dup2(fd_after[PIPE_OUTPUT, 1) < 0)
{
perror("dup2 failed");
exit(1);
}
if (dup2(fd_before[PIPE_INPUT, 0) < 0)
{
perror("dup2 failed");
exit(1);
}
parse_and_exec_cmd(commands->cmd);
}
else
waitpid(...);
if (commands->next->next != null) //More than two following commands : a middle again
execute_pipe_middle(commands->next, fd_after);
else // No more repetition
execute_pipe_end(commands->next, fd_after);
}
execute_pipe_end(t_cmdlist *commands, int fd_before[2])
{
int pid;
if (!commands)
return;
if (commands->next)
{
pid = fork();
if (!pid)
{
close(fd_before[PIPE_OUTPUT]);
if (dup2(fd_before[PIPE_INPUT, 0) < 0)
{
perror("dup2 failed");
exit(1);
}
parse_and_exec_cmd(commands->cmd);
}
else
waitpid(...);
}
}

Fork-exec pipe redirection issue

Could anyone tell me what's wrong with this code?
In summary, it creates input and output pipes and fork-exec's the sort program. The parent reads the dictionary /usr/share/dict/words and writes it to the pipe that is dup2()'d to sort's standard in and, likewise, reads the output from it, printing it to the terminal (the standard output of the parent). Or, at least, that's what's supposed to be happening.
A backtrace says that the parent hangs at the read() on line 130 (marked with the comment 'XXX'). It's almost as though sort isn't aware of the end-of-file, but closing the write end of pipeIn should 'signal' this, right?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <errno.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <unistd.h>
int main(int argc, char** argv)
{
int pipeIn[2];
int pipeOut[2];
if ((pipe(pipeIn)) == -1)
{
perror("pipe");
exit(EXIT_FAILURE);
}
if ((pipe(pipeOut)) == -1)
{
perror("pipe");
exit(EXIT_FAILURE);
}
pid_t child = fork();
if (child == 0)
{
// This is child!
if ((dup2(pipeIn[0], STDIN_FILENO)) == -1)
{
perror("dup2");
exit(EXIT_FAILURE);
}
if ((dup2(pipeOut[1], STDOUT_FILENO)) == -1)
{
perror("dup2");
exit(EXIT_FAILURE);
}
if ((dup2(pipeOut[1], STDERR_FILENO)) == -1)
{
perror("dup2");
exit(EXIT_FAILURE);
}
if ((close(pipeIn[0])) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}
if ((close(pipeOut[1])) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}
if ((execlp("sort", "-r", NULL)) == -1)
{
perror("execlp");
exit(EXIT_FAILURE);
}
}
else if (child == -1)
{
perror("fork");
exit(EXIT_FAILURE);
}
else
{
// This is parent!
if ((close(pipeIn[0])) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}
if ((close(pipeOut[1])) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}
int dict = open("/usr/share/dict/words", O_RDONLY);
if (dict == -1)
{
perror("open");
exit(EXIT_FAILURE);
}
char buf[1024];
int count;
while ((count = read(dict, buf, sizeof(char) * 1024)) > 0)
{
putchar('.');
if ((write(pipeIn[1], buf, count)) == -1)
{
perror("write 1");
exit(EXIT_FAILURE);
}
}
if (count == -1)
{
perror("read");
exit(EXIT_FAILURE);
}
if ((close(dict)) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}
if ((close(pipeIn[1])) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}
while ((count = read(pipeOut[0], buf, sizeof(char) * 1024)) > 0) // XXX
{
putchar('!');
if ((write(STDOUT_FILENO, buf, count)) == -1)
{
perror("write 2");
exit(EXIT_FAILURE);
}
}
if (count == -1)
{
perror("read");
exit(EXIT_FAILURE);
}
if ((close(pipeOut[0])) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}
}
return EXIT_SUCCESS;
}
Thank you for any input (pardon the pun).
Your problem is that you are not closing the unused ends of your pipe in the chile process. So you need to add the following code somewhere before the exec
if ((close(pipeIn[1])) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}
if ((close(pipeOut[0])) == -1)
{
perror("close");
exit(EXIT_FAILURE);
}

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