I have my table like this :
Id Name Country
1 Vaibhav India
2 Amit UK
3 Pranav US
I want to read all the records by counting the max number of records present using count(id) ,3 in this case and just increment the counter by 1 for each records processed .Simultaneously i wanted to print the result of my counter variable.
Can anyone suggest how to do it???
You already have the values 1,2,3?
You might want a ROW_NUMBER:
Select Name, Country,
ROW_NUMBER() OVER (ORDER BY Id) -- or whatever column you want
from tab
Related
I'm trying to understand the behavior of
select ..... ,MIN(count(*)) over (partition by hotelid)
VS
select ..... ,count(*) over (partition by hotelid)
Ok.
I have a list of hotels (1,2,3)
Each hotel has departments.
On each departments there are workers.
My Data looks like this :
select * from data
Ok. Looking at this query :
select hotelid,departmentid , cnt= count(*) over (partition by hotelid)
from data
group by hotelid, departmentid
ORDER BY hotelid
I can perfectly understand what's going on here. On that result set, partitioning by hotelId , we are counting visible rows.
But look what happens with this query :
select hotelid,departmentid , min_cnt = min(count(*)) over (partition by hotelid)
from data
group by hotelid, departmentid
ORDER BY hotelid
Question:
Where are those numbers came from? I don't understand how adding min caused that result? min of what?
Can someone please explain how's the calculation being made?
fiddle
The 2 statements are very different. The first query is counting the rows after the grouping and then application the PARTITION. So, for example, with hotel 1 there is 1 row returned (as all rows for Hotel 1 have the same department A as well) and so the COUNT(*) OVER (PARTITION BY hotelid) returns 1. Hotel 2, however, has 2 departments 'B' and 'C', and so hence returns 2.
For your second query, you firstly have the COUNT(*), which is not within the OVER clause. That means it counts all the rows within the GROUP BY specified in your query: GROUP BY hotelid, departmentid. For Hotel 1, there are 4 rows for department A, hence 4. Then you take the minimum of 4; which is unsurprisingly 4. For all the other hotels, they have at least 1 entry with only 1 row for a hotel and department and so returns 1.
I am facing 1 prob in implementing business solution. Any help would be much appreciated.
There is 1 table with 3 columns.
Table Employee
(
Id, Name, Salary
)
Values -
(1,John,10000),
(2,Rey, 15000),
(3,John,20000)
Expected Output -
It should fetch only distinct employees and for duplicate records of employee, it should fetch sum of salary.
So, output should be like this -
(1,john,30000),
(2,Rey,15000)
Please help
Check the basic sintaxis for GROUP BY
SELECT MIN(ID), Name, SUM(Salary)
FROM Employee
GROUP BY Name
The interesting part here is aggregation functions doesnt need to be at the end. As are usually show in the examples
I have data that returns the same value multiple times in one column, I only want to include the first value or even average the group, since they are all the same value. The group itself might have 3 rows of payments, but the payments are the same. I just want the three rows to show, but only the one payment in its own column.
In the data below I would like to add another column that averages Rich and Bob's value and inputs the amount in the top row for Rich and Bob.
Sample Data:
1 Rich 300
2 Rich 300
3 Rich 300
4 Bob 250
5 Bob 250
You probably want something like this:
Just paste this into an empty query window and exectue. Adapt to your needs...
DECLARE #tbl TABLE(ID INT, PersonName VARCHAR(100),Amount DECIMAL(6,2))
INSERT INTO #tbl VALUES
(1,'Rich',300)
,(2,'Rich',300)
,(3,'Rich',300)
,(4,'Bob',250)
,(5,'Bob',250);
WITH NumberedPerson AS
(
SELECT tbl.*
,ROW_NUMBER() OVER(PARTITION BY PersonName ORDER BY ID) PersonID
,AVG(Amount) OVER(PARTITION BY PersonName) PersonAvg
FROM #tbl AS tbl
)
SELECT *
,CASE WHEN PersonID=1 THEN PersonAvg ELSE NULL END AS AverageInFirstRow
FROM NumberedPerson
ORDER BY ID
But - to be honest - that is absolutely not the way how this should be done...
Please suggest an SQL query to find duplicate customers across different stores, e.g. customer table has id, name, phone, storeid in it, I need to write queries for the following:
Duplicate customers within a store
Duplicate customers across different stores
Table data:
id name phone storeid
-----------------------------------
1 abc 123 4
2 abc 123 4
3 abc 123 5
The first query should show only first 2 records, and the second query should show all 3 records.
You can do something like the following:-
SELECT Name,Phone, COUNT(Id) NumberOfTimes, StoreID
FROM Customers
GROUP BY Name,Phone,StoreID
HAVING COUNT(Id) > 1
ORDER BY StoreID
Hope this helps.
Solution
You can try this for the first query:
SELECT *
FROM customer,
WHERE 1 < (
SELECT COUNT(name)
FROM customer
WHERE name IN (
SELECT name FROM customer
)
) AND
1 < (
SELECT COUNT(storeid)
FROM customer
WHERE storeid IN (
SELECT storeid FROM customer
)
);
Now, for the second query, use the above one, but remove everything after and including the AND.
Explanation
Let's look at the query step-by-step:
SELECT *
FROM customer
This is stating you want all the columns from the customers table.
WHERE 1 < (
SELECT COUNT(name)
FROM customer
WHERE name IN (
SELECT name FROM customer
)
)
This is a pretty long query, so let's look from inside-outward.
WHERE name IN (
SELECT name FROM customer
)
This time we're getting all the names of customers and checking if their is match in our curret table. To be truthful, we might not need this whole section....
SELECT COUNT(name)
FROM customer
This is stating we want the total number of times each name appears (count) in the customers table that matches the where clause.
WHERE 1 < (
....
)
Here, we are comparing the result from the subquery (the number of duplicated names) and checking to see if it is greater than l (i.e., there is a duplicate).
AND
.....
The AND keyword indicates that this second condition must be true in addition to the previous conditions.
The full query should return all entries where both the names and store ids are duplicated; if you remove everything including and after the AND, that will result in all entries which have the same name, but not neccessarily the right store id.
Notes
The other two answers are suggesting grouping duplicated data, but in your particular case, I think you do want the duplicated entries as per your expected results (albeit you should add more expected output info than that).
SELECT storeName, customerName FROM customer
WHERE id IN (
SELECT c.storeid
FROM customer 'c'
RIGHT JOIN store 's' ON (c.storeid = s.id)
GROUP BY c.storeid
HAVING COUNT(*) > 1
)
Basically, we are grouping by storeids, which allows us to count the times they occur in the customer table. We get the id of a case where there are multiple occurrences, and we select the storeName and CustomerName from the customer table that contains the id we got from the inner query.
How can I show the number of rows in a table in a way that when a new record is added the number representing the row goes higher and when a record is deleted the number gets updated accordingly?
To be more clear,suppose I have a simple table like this :
ID int (primary key) Name varchar(5)
The ID is set to get incremented by itself (using identity specification) so it can't represent the number of row(record) since if I have for example 3 records as:
ID NAME
1 Alex
2 Scott
3 Sara
and I delete Alex and Scott and add a new record it will be:
3 Sara
4 Mina
So basically I'm looking for a sql-side solution for doing this so that I don't change anything else in the source code in multiple places.
I tried to write something to get the job done but it failes. Here it is :
SELECT COUNT(*) AS [row number],Name
FROM dbo.Test
GROUP BY ID, Name
HAVING (ID = ID)
This shows as:
row number Name
1 Alex
1 Scott
1 Sara
while I want it to get shown as:
row number Name
1 Alex
2 Scott
3 Sara
If you just want the number against the rows while selecting the data and not in the database then you can use this
select row_number() over(order by id) from dbo.Test
This will give the row number n for nth row.
Try
SELECT id, name, ROW_NUMBER() OVER (ORDER BY id) AS RowNumber
FROM MyTable
What you want is called an auto increment.
For SQL-Server this is achieved by adding the IDENTITY(1,1) attribute to the table definition.
Other RDBMS use a different syntax. Firebird for example has generators, which do the counting. In a BEFORE-INSERT trigger you would assign the ID-field to the current value of the generator (which will be increased automatically).
I had this exact problem a while ago, but I was using SQL Server 2000, so although row number() is the best solution, in SQL Server 2000, this isn't available. A workaround for this is to create a temporary table, insert all the values with auto increment, and replace the current table with the new table in T-SQL.