Open files with argv gives me file NULL - c

Question

I have a program that should take the file's name from command line using argc and argv. Printing argv[1] and argv[2] show me the exactly names I passed, but passing argv[1] and argv[2] as parameters to open the files in another function just show the error line I put if can't open the file.
My main:
int main(int argc, char* argv[])
{
if (argc != 4)
{
puts("Incorrect number of parameters.");
return 1;
}
else
{
Image *a, *b;
a = OpenFile(argv[1]);
b = OenFile(argv[2]);
} /* else */
return 0;
} /* main */
The function OpenFile will return a struct filled with information from the file. Here's the first part of the function:
Image *OpenFile(char* name)
{
FILE* f = fopen(name, "r");
Image* imagem;
int temp, i, cont, data[MAX];
char aux[2];
if(f == NULL)
{
puts("Error opening file.");
return NULL;
} /* if */
...
}
I'm passing the correct names but I receive the "Error opening file." line for each file I try to open.
Edit: It's giving me "No such file or directory", but I copied the files to the directory where the .exe is placed. It's not the first time I use the file's name from command line, but it's the first time I pass as parameters to another function.

Answer 1

From fopen man page:
RETURN VALUE
Upon successful completion fopen(), fdopen() and freopen() return a FILE pointer. Otherwise, NULL is returned and
errno is set to indicate the error.
So You could change:
if(f == NULL)
{
puts("Error opening file.");
return NULL;
} /* if */
With:
if(f == NULL)
{
perror("fopen");
return NULL;
} /* if */
And you ll get a pretty descriptive message on the reason fopen failed.
You should include errno.h in order to use perror