Oracle based PIVOT with multiple columns group - database

Question

Using the following tables,
Productivity:
PRODUCTIVITYID PDATE EMPLOYEEID ROOMID ROOMS_SOLD SCR
81 03/26/2016 7499 21 56 43
82 03/26/2016 7566 42 - -
102 03/26/2016 7499 22 434 22
101 03/26/2016 7566 21 43 53
ProductivityD:
PRODUCTIVITYID WORKHRS MEALPANELTY DESCRIPTION
2 50 4 -
21 6.4 1 -
102 6 - -
81 1.32 - -
101 3.6 - -
Rooms:
ID ROOM PROPERTCODE
22 102 6325
41 103 6325
42 104 6325
43 105 6325
EMP:
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7566 JONES MANAGER 7839 04/02/1981 2975 - 20
7788 SCOTT ANALYST 7566 12/09/1982 3000 - 20
7902 FORD ANALYST 7566 12/03/1981 3000 - 20
7369 SMITH CLERK 7902 12/17/1980 800 - 20
7499 ALLEN SALESMAN 7698 02/20/1981 1600 300 30
The following query is generating below output but I need to group employees and sum workhrs and then pivot RM_ROOM and RM_SCR
WITH pivot_data AS (
SELECT eNAME,workhrs,room, 'RM' as RM,SCR from PRODUCTIVITY p,PRODUCTIVITYd d, emp e, ROOMS R
where p.PRODUCTIVITYID=d.PRODUCTIVITYID and e.empno=p.employeeid
AND R.ID=P.ROOMID
)
SELECT *
FROM pivot_data
PIVOT (
MIN(room) as room,min(scr) as SCR --<-- pivot_clause
FOR RM--<-- pivot_for_clause
IN ('RM') --<-- pivot_in_clause
)
Current Output:
ENAME WORKHRS 'RM'_ROOM 'RM'_SCR
JONES 3.6 101 53
ALLEN 6 102 22
ALLEN 1.32 101 43
Desired Output:
ENAME WORKHRS 'RM'_ROOM 'RM'_SCR 'RM'_ROOM 'RM'_SCR
JONES 3.6 101 53 - -
ALLEN 7.32 101 43 102 22

Answer 1

You are pivoting on a fixed value, the string literal 'RM', so you're really not doing anything useful in the pivot - the output is the same as you'd get from running the 'pivot_data' query on its own:
SELECT eNAME,workhrs,room, SCR from PRODUCTIVITY p,PRODUCTIVITYd d, emp e, ROOMS R
where p.PRODUCTIVITYID=d.PRODUCTIVITYID and e.empno=p.employeeid
AND R.ID=P.ROOMID;
ENAME WORKHRS ROOM SCR
----- ---------- ---------- ----------
JONES 3.6 101 53
ALLEN 1.32 101 43
ALLEN 6 102 22
You want the aggregate workhrs for each employee, and a pivot of the rooms they sold. If you change that query to get the analytic sum of workhrs and a ranking of the room/scr values (and using modern join syntax) you get:
select e.ename, r.room, p.scr,
sum(d.workhrs) over (partition by e.ename) as wrkhrs,
rank() over (partition by e.ename order by r.room, p.scr) as rnk
from productivity p
join productivityd d on d.productivityid = p.productivityid
join emp e on e.empno=p.employeeid
join rooms r on r.id = p.roomid;
ENAME ROOM SCR WRKHRS RNK
----- ---------- ---------- ---------- ----------
ALLEN 101 43 7.32 1
ALLEN 102 22 7.32 2
JONES 101 53 3.6 1
You can then pivot on that generated rnk number:
with pivot_data as (
select e.ename, r.room, p.scr,
sum(d.workhrs) over (partition by e.ename) as wrkhrs,
rank() over (partition by e.ename order by r.room, p.scr) as rnk
from productivity p
join productivityd d on d.productivityid = p.productivityid
join emp e on e.empno=p.employeeid
join rooms r on r.id = p.roomid
)
select *
from pivot_data
pivot (
min(room) as room, min(scr) as scr --<-- pivot_clause
for rnk --<-- pivot_for_clause
in (1, 2, 3) --<-- pivot_in_clause
);
ENAME WRKHRS 1_ROOM 1_SCR 2_ROOM 2_SCR 3_ROOM 3_SCR
----- ---------- ---------- ---------- ---------- ---------- ---------- ----------
ALLEN 7.32 101 43 102 22
JONES 3.6 101 53
You need to know the maximum number of rooms any employee may have - i.e. the highest rnk could ever be - and include all of those in the in clause. Which means you're likely to end up with empty columns, as in this example where there is no data for 3_room or 3_scr. You can't avoid that though, unless you get an XML result or generate the query dynamically.

Answer 2

What you are saying makes no sense. What do you mean by "pivot RM_ROOM"? So I have to guess. I am guessing you want to group employees and sum workhrs, and then pivot the result. The "Output" you show seems to be the output for pivot_data, your subquery.
Your answer will only have eNAME and for each of them, a count of hours worked. So you don't need to SELECT the room numbers in the pivot_data subquery. You only need eNAME and workhrs. Then it is a simple matter of using the PIVOT syntax:
WITH pivot_data AS (
SELECT eNAME, workhrs FROM PRODUCTIVITY p,PRODUCTIVITYd d, emp e, ROOMS R
where p.PRODUCTIVITYID=d.PRODUCTIVITYID and e.empno=p.employeeid
AND R.ID=P.ROOMID
)
SELECT *
FROM pivot_data
PIVOT (
SUM(workhrs)
FOR eNAME IN ('JONES', 'ALLEN')
)
/
Output:
'JONES' 'ALLEN'
---------- ----------
3.6 7.32